I NEED HELP!! PLEASE HELP ME

Answer:

P = VI = (IR)I = I2R

Explanation:

What the equation means is that if you double the current you end up with 4 times the power loss. It's like the area of carpet you need for a room - if you make the room twice as long and twice as wide you need 4x as much carpet. The physical explanation is that the voltage difference along a wire depends on the current - more current flowing with a resistance means more voltage (pressure of electricity if you like) is built up.

This extra voltage means more power. So if you double the current your would double the power, but you also double the voltage which doubles the power again = 4x as much power. P = VI = (IR)I = I2R

I hope this helps you out, if I'm wrong, just tell me.

As I mentioned earlier, Ohm's law gives us the formula P = IV, where V is the voltage ( also known as the electrical potential difference ) and I is the current. It is confusing that P = I²R and P = IV are one in the same - so I want to go a bit deeper on that.

We have three formulas, P = IV, P = I²R, and P = V² / R. Each are considered the same. The two formulas P = I²R, and P = V² / R are derived from the statement that P = IV, under the condition V = IR. Substitute the value of V from this second condition V = IR into P = IV. You would get the following -

P = I( IR ),

P = I²R

That is how one can derive the formula P = I²R, and how P = IV and P = I²R are thought to be one in the same. If you would like, take a look at how to get the formula " P = V² / R, "

V = IR, P = IV

I = V / R, P = IV

P = ( V / R )V,

P = V² / R

Hope that helps!

Answer:

v = 2.22 m/s

Explanation:

First we apply the second equation of motion to the vertical motion of the body:

s = Vi t + (1/2)gt²

where,

s = y = vertical distance covered = 200 m - 100 m = 100 m

Vi = V₀y = Vertical Component of Initial Velocity = 0 m/s  (because spider man jumps horizontally, thus his velocity has no vertical component initially)

t = Time Taken to Land on 100 m high building = ?

g = 9.8 m/s²

Therefore,

100 m = (0 m/s)t + (0.5)(9.8 m/s²)t²

t² = (100 m)/(4.9 m/s²)

t = √(20.4 s²)

t = 4.5 s

Now, we analyze the horizontal motion. Neglecting air friction, the horizontal motion is uniform with uniform velocity. Therefore,

s = vt

where,

s = x = horizontal distance covered = 10 m

v = V₀ₓ = Horizontal Component of Initial Velocity = Initial Velocity = ?

Therefore,

10 m = v(4.5 s)

v = 10 m/4.5 s

v = 2.22 m/s

Answer:

15m/s

Explanation:

500 ÷ 50 = 10m/s

1500 ÷ 75 = 20m/s

10 + 20 = 30

30 ÷ 2 = 15m/s

Answer: 16 miles per second

Explanation:

Find the total distance traveled and the total time.

[tex]\text{average rate}=\dfrac{1500+500}{75+50}=\dfrac{2000\ miles}{125\ second}=\large\boxed{16\ mps}[/tex]

Answer:  25.2 km

Explanation:

3 blocks east and four blocks east = 7 blocks

1 block = 0.3 km  --> 7 blocks = 2.1 km

12 times 2.1 km = 25.2 km

Answer:

we should not drop a magnet on the floor because the magnets tend to lose magnetism gradually and become weak over a period of time if they are not stored properly.

Answer:

Well depending on the floor like say if it was a wooden floor the magnet might lose it magnetism, if concrete floor the magnetic brake and still lose it magnetism, if a metal floor the magnet would stick not sure if it wood lose it magnetism or not but the possibilities still there, basically what I'm saying is the magnet would lose its magnetism if it were to interact with the floor maybe temporary or maybe permanently.

for those with with a learning disability it's a

Explanation:

Answer:

A  mercury barometer is a device use to measure stomspheric pressure and is constructed as following:

The position of tube creates vacuum between the closed end of the tube and liquid surface and the Mercury has high density that is why used as the liquid to measure pressure.

Answer: 20 minutes

Explanation:

Given the following :

Average speed of train = 120km/hr

Distance = 40km.

The time take by the train moving at an average speed of 120km/hr to cover a distance of 40km due is ;

Recall:

Speed = distance / time

Therefore,

Time taken = distance covered / speed

Time taken = 40km / 120km/hr

Time taken = 1/ 3 hr

Therefore, 1/3 rd of an hour equals

1/3 × 60 = 20 minutes.

Time taken) 20 minutes

Time taken by tain to cover distance is 20 minutes as:

Distance= 40 km

Speed= 120 km/h

Time= distance/speed

= 40/120

= 1/3 hour

= 20 min

or  =0.33 hrs

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Answer:

  t = 376.99 s

Explanation:

We must solve this problem with the equations and kinematics, let's start by looking for the speed of the vehicle,

         v = d / t

         v = 7/40

         v = 0.175 m / s

Since the speed e remains constant, we must find the length of the circle is

          L = 2π r

          L = 2π 21

          L = 131.95 m

In the problem it does not specify clearly, but in general the curves of the road correspond to half a circle, so the length of the road is

         L ’= L / 2

         L ’= 131.95 / 2 = 65.97 m

as the speed is constant

          t = L ’/ v

          t = 65.97 / 0.175

          t = 376.99 s

Answer:

Net displacement = 3.2 m

Explanation:

Given:

Mass of man = 80 kg

Mass of trolley = 320 kg

Speed = 1 m/s

Time = 4 sec

Computation:

Displacement by man = 1 m/s × 4 sec

Displacement by man = 4 m

Net ext force (trolley) = com at rest

So,

320 × X = 80(4 - X)

32X = 32 - 8X

40X = 32

X = 0.8 m

Net displacement = 4 m - 0.8 m

Net displacement = 3.2 m

Answer:

3) 3.2 m

Explanation:

The computation of the displacement relative to the ground after 4 seconds is shown below:

Let us assume the following

Starting x coordinate is at the origin

As it does not involve any external force so x coordinated would remain unchanged

Now the separation between the man and the trolley is

[tex]= 4 \times 1[/tex]

= 4 m

And, we assume the displacement of man be x

So, for trolley it would be (4 -x)

Now we develop the equation which is

[tex]80 \times x = 320 \times (4 - x)[/tex]

x = 16 - 4x

Therefore x = 3.2 m

Answer:

25kg

Explanation:

The formula for acceleration due to gravity is:

[tex]g=\dfrac{GM}{r^2}[/tex]

Here, G represents a constant and M represents the mass of the object. We don't need to know the actual values to solve this, then: We can just multiply by the amount they are multiplied relative to earth.

[tex]g=\dfrac{G(0.9M)}{(1.2r)^2}=0.625g[/tex]

Multiplying this by the weight of the person on Earth of 40kg, you get 0.625*40=25kg.

Hope this helps!

Explanation:

100 m / (1.20 m) = 83.3

100 m / (0.75 m) = 133.3

Rounded up, the first sprinter takes 84 steps, and the second sprinter takes 134 steps.

Answer:

the following image will make you understand

Explanation:

Answer:

for every action thete is an equal and opposite reaction

Answer:

Newton’s third law of motion says that for every action there is a(n)

equal and opposite reaction.

Explanation:

just got it right edg 1928

Given that,

Distance = 10 m

Time = 1.0 sec

Acceleration a =20 m/s²

We need to calculate the baboon's initial velocity

Using equation of motion

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Where, s = distance

t = time

a = acceleration

Put the value in to the formula

[tex]10=u\times1+\dfrac{1}{2}\times20\times1^2[/tex]

[tex]u=10-10[/tex]

[tex]u=0\ m/s[/tex]

Hence, The baboon's initial velocity is zero.

Answer:

a = 1.07 m/s^2

Explanation:

The computation of the acceleration is shown below:

As we know that

[tex]v_f^{2} - v_i^{2} = 2 ad[/tex]

where,

v_i = 0 m/s  = initial speed

v f = 8 m/s  = final speed

d = 30m = distance

Now placing these values to the above equation

[tex]8^{2} - 0 = 2 \times a \times 30[/tex]

64 = 60a

a = 1.07 m/s^2

We simply applied the above formula so that we could able to determine the acceleration

Answer:

B. A large number of atoms move from one place to another

Explanation:

Convection is heat transfer by the movement of atoms of a substance from one region to another across a temperature gradient. Since atoms of solids are rigidly held in place, convection only occurs in liquids and gases since they flow.

Convection occurs when the temperature of one region of a fluid (liquid or gas) is higher than its other region. There is thus a mass movement of atoms from one region to the other due to a temperature difference. The atoms will continue to move to the region of lower temperature until the temperature of both regions are the same at an equilibrium temperature.

Answer:

Part A)

Since all of the resistors have equal resistance, hence for finding even only 1 branch It will be fine because current will be the same for all branches.

=> [tex]I = \frac{V}{R_{1} }[/tex]

=> [tex]I = \frac{30}{15}[/tex]

=> I = 2 A

Part B)

Equivalent resistance for parallel circuits is the sum of reciprocals of each resistor.

=> [tex]\frac{1}{R} = \frac{1}{R_{1}}+\frac{1}{R_{2}} +\frac{1}{R_{3}}[/tex]  

=> [tex]\frac{1}{R} = \frac{1}{15}+ \frac{1}{15}+\frac{1}{15}[/tex]

=> [tex]\frac{1}{R} = \frac{3}{15}[/tex]

=> R = 15/3

=> R = 5 ohms

Part C)

I = V/R

Where I is current, V is voltage and R is the equivalent resistance

=> I = 30/5

=> I = 6 A

Answer:

[tex]t_{1/2}=6 h[/tex]

Explanation:

Let's use the decay equation.

[tex]A=A_{0}e^{-\lambda t}[/tex]

Where:

We know that [tex]\lambda=\frac{ln(2)}{t_{1/2}}[/tex]

So we have:

[tex]\lambda=\frac{ln(A/A_{0})}{t}[/tex]

[tex]\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}[/tex]

[tex]t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}[/tex]

[tex]t_{1/2}=6 h[/tex]

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

Answer:

It is not a uniform velocity, because his velocity increases for 5 m every second (acceleration = 5m/s2), meaning his velocity always changes.

When he starts at rest, his velocity is 0 m/s. But in 1 second later, his velocity is already 5m/s. At 2 seconds, his velocity will be 10 m/s.

Answer:

B

Explanation:

Answer:

[tex]k=784 N/m[/tex]

[tex]\Delta x=8,8 cm[/tex]

Explanation:

Usando la ley de Hook tenemos:

[tex]F=k\Delta x[/tex]

Solving it for k we have:

[tex]k=\frac{F}{\Delta x}[/tex]

[tex]k=\frac{39,2}{0,05}[/tex]

[tex]k=784 N/m[/tex]

Usando la misma ecuación y sabiendo k tenemos:

[tex]\Delta x=\frac{F}{k}[/tex]

[tex]\Delta x=\frac{68,6}{784}[/tex]

[tex]\Delta x=8,8 cm[/tex]

Espero esto te ayude!

Answer:

Approximately [tex]480\; \rm kPa[/tex], assuming that this gas is an ideal gas.

Explanation:

By Boyle's Law, the pressure of a sealed ideal gas at constant temperature will be inversely proportional to its volume. Assume that this gas is ideal. By this ideal gas law:

[tex]\displaystyle \frac{P(\text{Final})}{P(\text{Initial})} = \frac{V(\text{Initial})}{V(\text{Final})}[/tex].

Note that in Boyle's Law, [tex]P[/tex] is inversely proportional to [tex]V[/tex]. Therefore, on the two sides of this equation, "final" and "initial" are on different sides of the fraction bar.

For this particular question:

Rearrange the equation to obtain:

[tex]\displaystyle P(\text{Final}) = \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})[/tex].

Before doing any calculation, think whether the pressure of this gas will go up or down. Since the gas is compressed, collisions between its particles and the container will become more frequent. Hence, the pressure of this gas should increase.

[tex]\begin{aligned}P(\text{Final}) &= \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})\\ &= \frac{1.0\; \rm m^{3}}{0.25\; \rm m^{3}} \times 120\; \rm kPa = 480\; \rm kPa\end{aligned}[/tex].

Answer:

they are,

1. scissor = they are very useful for cutting papers, clothes, etc. if there wouldn't be sicssor than we would not be able to cut various things . it has made easier to cut tgings.

2. nailcutter= it is also one type of simple machine. it is used to trim our nails. if there would be no nailcutter then our nail would be so dirty and long.

hope it helps..

Answer:

276 days

Explanation:

1/4 th of the original means 2 half lives

1 half life = 138 days

So,

2 half lives = 276 days

Answer: B

Explanation:

Displacement is a vector quantity. it is the distance covered in a specific direction.

Whereas, Velocity = displacement/time

Make displacement the subject of formula

Displacement = velocity × time

From the graph, velocity is constant which is equal to 1 m/s

Displacement in the last two seconds will be velocity multiply by 2. Since time = 2s. Therefore,

Displacement = 1 × 2 = 2 m

So, the particle displacement in the last two seconds will be 2 metres

Answer:

1,600 km

Explanation:

since the acceleration due to gravity reduces by 36%, it means that (1 - 36%) of acceleration still remains:

g' = 64g/100

using the acceleration formula:

g' = g x [R² / (R + height)²]

64g/100 = g x [R² / (R + height)²]

64/100 = R² / (R + height)²

√(64/100) = √[R² / (R + height)²]

8/10 = R / (R + height)

8 (R + height) = 10R

8R + 8height = 10R

8height = 2R

height = 2R / 8 = R / 4

R = 6,400 km

height = 6,400 km / 4 = 1,600 km

Answer:

Answer:

force on brake shoes is 10 N

Explanation:

for the master cylinder;

force applied = 140 N

diameter = 14d

for brake cylinder;

force applied on the brake shoe by the brake cylinder f = ?

diameter = d

The pressure will be transmitted undiminished from the master cylinder to the brake cylinder according to pascals pressure law.

pressure = force/area

but cross sectional area is proportional to diameter of the cylinder

therefore

[tex]\frac{140}{14d } = \frac{f}{d }[/tex]

the diameters will cancel out, and we're left with

force on brake shoes = 10 N

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Waves and it's motion.

So we here apply the formula as,

Velocity = frequency*wavelength

so here we get as,

340 = 500 * Lambda

Lambda = 340/500

so we get the distance as,

L = 0.68 m

Answer:

λ = 0.68 m

Explanation:

Distance between a point of rarefaction and the next compression point is actually the wavelength (λ)

So, we'll find wavelength here:

Given:

Frequency = f = 500 Hz

Speed = v = 340 m/s

Required:

Wavelength = λ = ?

Formula:

v = f λ

Solution:

λ = v/f

λ = 340/500

λ = 0.68 m

Answer:

1. 19.28 secs

2. 154.22 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 16 m/s

Final velocity (v) = 0

Force (F) = 1000 N

Mass (m) = 1200 Kg

Time (t) =..?

Distance (s) =...?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Force (F) = 1000 N

Mass (m) = 1200 Kg

Acceleration (a) =.?

Force (F) = mass (m) x acceleration (a)

F = ma

1000 = 1200 x a

Divide both side by 1200

a = 1000/1200

a = 0.83 m/s²

Since the car is coming to rest, it means it is decelerating. Therefore, the acceleration is – 0.83 m/s²

1. Determination of time taken for the car to halt i.e stop. This can be obtained as follow:

Initial velocity (u) = 16 m/s

Final velocity (v) = 0

acceleration (a) = – 0.83 m/s²

Time (t) =.?

v = u + at

0 = 16 + (–0.83 x t)

0 = 16 – 0.83t

Rearrange

0.83t = 16

Divide both side by 0.83

t = 16/0.83

t = 19.28 secs.

Therefore, the time taken for the car to halt is 19.28 secs.

2. Determination of the distance travelled by the car before coming to rest. This can be obtained as follow:

Initial velocity (u) = 16 m/s

Final velocity (v) = 0

acceleration (a) = – 0.83 m/s²

Distance (s) =..?

v² = u² + 2as

0 = 16² + (2 x –0.83 x s)

0 = 256 – 1.66s

Rearrange

1.66s = 256

Divide both side by 1.66

s = 256/1.66

s = 154.22 m

Therefore, the distance travelled by the car before coming to rest is 154.22 m.

Answer:

218 N

Explanation:

edge2020

The table shows data for the planet Uranus, the weight of a 25.0 kg rock on Uranus would be approximately 218 N.

In physics, weight refers to the force imposed on an item owing to gravity. It is the gravitational force exerted on the mass of an item.

The gravitational acceleration value supplied in the table may be used to calculate the weight of a 25.0 kilogramme rock on Uranus.

Uranus' gravitational acceleration is given at 8.7 metres per second squared.

The weight of an object is derived by multiplying its mass (m) by its gravitational acceleration (g):

Weight = mass * gravitational acceleration

Weight = 25.0 kg * 8.7 m/s^2

Weight = 217.5 N

The weight of a 25.0 kg rock on Uranus would be approximately 218 N.

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