i need an answer asap please, it’s the last question

Answer:

$20 was how much money he had before he spent any money.

Step-by-step explanation:

So, with any problem like this, all you have to do to figure out the answer is to add how much money is left and how much was spent. So, like this:

Amount left + Amount spent = Original Amount

Answer:

£510

Step-by-step explanation:

Simple interest = (principal × rate × time) / 100

Principal = £1700

Rate = 10%

Time = 3 years

Simple interest = (principal × rate × time) / 100

= (1700 × 10 × 3) / 100

= 51,000/100

= 510

Simple interest = £510

Answer:

5

Step-by-step explanation

Answer: 5

Step-by-step explanation:

aₙ = a + (n - 1) d

n = the term of the sequence that you're looking for (2)

a = 1st term of sequence (2)

d = common difference (3)

a₂ = 2 + (2 - 1) 3

a₂ = 2 + (1 × 3)

a₂ = 2 + 3

a₂ = 5

It's also given btw but in case you wanted to find other terms of the sequence.

Answer:

[tex] \sf8 \: \frac{newspapers}{plie}\: or\: \text{8 newspapers per pile} [/tex]

Step-by-step explanation:

according to the question

Answer:

Solution given:

48 newspaper in 6 pile=48news paper per 6 piles

=48/6=8 news paper per pile

the unit rate of 48 newspapers in 6 piles is 8 news paper per pile

Answer:

5/6

4/5

6/7

Step-by-step explanation:

Answer:

6 and 7; 1 and 4; 4 and 5

Step-by-step explanation:

a supplementary angle is when two angles added together equal 180 degrees. In other words, if two angles make a straight line when put together, they are supplementary.

Answer:

9

Step-by-step explanation:

here you go!

Answer:

i think 18 since 11+7=18

i think this it is not corect 100%100

Answer:

90 clockwise (or counterclockwise) rotation and then a reflection over the axis between the two shape (those two steps go in any order)

Step-by-step explanation:

for this lets mark the innermost point of each shape a (blue or A) and a' (red or B)* and the second point b and b'

here we see that the two shapes are in a position to where they seem reflected over a non-existent third diagonal axis, though this is not the case, we need to bring the shape into a position where it can be transformed to the quadrant of shape B and overlap the shape

so when you have a reflection over a diagonal axis, we can rotate or reflect the shape to a new quadrant, and perform the step thats not the first, so say we made a reflection over the X-axis, the shape is now in the lower half of the graph with shape B, from here we perform our last step wich is to rotate the shape into the quadrant of shape B in a clockwise motion, now a and a' overlap and b and b' overlap, same for c, c',d and d'

(*the ' in this case is called a prime symbol, when used, distinguishes two points or lines on a graph, A' = A prime)

Answer:

m∠A = 45⁰

m∠B = 75⁰

Step-by-step explanation:

Given question 4;

m∠A = x + 51

m∠B = 81 + x

m∠C = 60⁰

The value of the missing angles can be determined by the finding the value of x first;

m∠A  +  m∠B  + m∠C = 180⁰ (sum of angles in a triangle)

(x + 51)  +  (81 + x)  +  60⁰ = 180

(x + x) + (51 + 81 + 60) = 180

2x + 192 = 180

2x = 180 - 192

2x = -12

x = -12/2

x = -6

Thus, the values of the angles are calculated as follows;

m∠A = x + 51

         = -6 + 51  

          = 45⁰

m∠B = 81 + x

        = 81 - 6

         = 75⁰

Answer:

y = 25x – 300

Step-by-step explanation:hope I helped

Answer:

139.36

Step-by-step explanation:

first you do 8*8 because that would be the area of the square part

8*8=64

then find the area of the semicircle

first the Radis of it is 4 because 8/2=4

A=3.14R^2/2

3.14*4^2/2

3.14*16/2

50.24/2

25.12

now because there are 3 of the semicircles you do

25.12*3

75.36

then you add the 64 from the square to get your answer

75.36+64

139.36

Answer:

388

Step-by-step explanation:

i looked it up

Answer:

[tex] \purple {\bold {m\angle PTR=136\degree}} [/tex]

[tex] \orange {\bold {m\angle PQR=68\degree}}[/tex]

Step-by-step explanation:

PS and RS are tangents to the circle with center T at points P and R. (given)

TP and TR are radii of the given circle.

[tex] \therefore PS\perp TP\: \&\: RS\perp TR[/tex]

(radius is perpendicular to the tangent)

[tex] \therefore m\angle TPQ= m\angle TRS =90\degree [/tex]

In quadrilateral SPTR

[tex] m\angle TPQ+ m\angle TRS+m\angle PSR +m\angle PTR=360\degree [/tex]

[tex] 90\degree+ 90\degree+44\degree +m\angle PTR=360\degree [/tex]

[tex] 224\degree +m\angle PTR=360\degree [/tex]

[tex] m\angle PTR=360\degree - 224\degree[/tex]

[tex] \purple {\bold {m\angle PTR=136\degree}} [/tex]

By inscribed angle theorem:

[tex] m\angle PQR=\frac{1}{2} \times m\angle PTR[/tex]

[tex] m\angle PQR=\frac{1}{2} \times 136\degree[/tex]

[tex] \orange {\bold {m\angle PQR=68\degree}}[/tex]

Answer:

Step-by-step explanation:

Area formula:

Find h (not drawn, it would be segment AD, where AD⊥CB):

Find area:

Answer:

area of triangle =1/2×sin42×AC×BC

=1/2×sin42×4×7=18.74/2=9.36in²

Step-by-step explanation:

is area.

Answer: 2.11 s

Step-by-step explanation:

Given

Equation of rockets height is given by

[tex]\Rightarrow h(t)=-8t^2+16+2[/tex]

Height will be zero once the rocket lands on the ground

So, we can write

[tex]\Rightarrow h(t)=0\ \text{or}\ -8t^2+16t+2=0\\\Rightarrow 8t^2-16t-2=0\\\\\Rightarrow t=\dfrac{16\pm \sqrt{(-16)^2-4(8)(-2)}}{2\times 8}\\\\\Rightarrow t=\dfrac{16\pm \sqrt{320}}{16}\\\\\text{Neglecting negative value of t}\\\\\Rightarrow t=\dfrac{16+17.888}{16}=2.11\ s[/tex]

The rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

The given equation is  [tex]\rm h(t)=-8t^2+16t+2\\[/tex], where h(t) is the rocket's height in meters t seconds after launch.

In algebra, a quadratic equation is an equation that can be written in standard form as

[tex]\rm ax^{2}+bx+c=0}[/tex]

where x represents variable, and a, b, and c represent coefficient.

The given equation is

h(t) = 0

[tex]\rm h(t)=-8t^2+16t+2\\h(t)=-8t^2+16t+2 = 0\\[/tex][tex]\rm h(t)=-8t^2+16t+2\\[/tex]

The roots will be

[tex]\rm {\displaystyle t={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}.}[/tex]

[tex]\rm {\displaystyle t={\frac {16\pm {\sqrt {(-16)^{2}-4\times 8\times 2}}}{16}}.}\\\rm {\displaystyle t={\frac {16\pm {\sqrt{320} }}{16}}}\\\rm {\displaystyle t={\frac{16+17.88}{16}\\[/tex]

Here, we have neglected the negative value of t

t = 2.1 seconds

So, the rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

Here learn more about quadratic equations here:

https://brainly.com/question/2263981

Answer:

Odel has sold 84 Pizzas and Sam has sold 42

Step-by-step explanation:

:p

Answer:

90 cm^3

5*4*3=90

2x+4<10

Subtract 4 from both sides to cancel it out.

2x+4<10

   -4   -4

2x<6

Now divide 2 from both sides to cancel that out.

2x<6

/2  /2

x<3

So that's the answer.

---

hope it helps

Answer:

[tex]\huge\boxed{\tt{x = 50}}[/tex]

Step-by-step explanation:

3x + 30 = 180 (Angles on a straight line add up to 180 degrees)

Subtract 30 to both sides

3x = 180 - 30

3x = 150

Divide 3 to both sides

x = 150 / 3

x = 50

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

[tex]\Large \boxed{\sf x=50}[/tex]

Step-by-step explanation:

Angles on a straight line add up to 180°

[tex]30+3x=180[/tex]

Solve for x

[tex]3x=150[/tex]

[tex]x=50[/tex]

Answer:

B x

C 20

E 100

Step-by-step explanation:

Answer:

I am pretty sure there equivalent

Answer:

5/7

Step-by-step explanation:

Multiply the numerator with the numerator and the denominator with the denominator. This makes the fraction 30/42. Simplify this to get 15/21. You can simplify it again to get 5/7.

Hope this helps

Answer:

code lazar

Step-by-step explanation:

Answer:

The answer is 91.

Step-by-step explanation:

If p = -3, then your equation is 64 + (-9 × -3).

-9 times -3 is 27.

27 + 64 = 91

Answer: it will be subtract try all things possible

Step-by-step explanation:

dude the answer is 36828337

Answer:

The measure of A is 93

Step-by-step explanation:

Here, we want to get the measure of angle A

we can start by getting the measure of angle C

Mathematically, we can use sine rule

It states that the ratio of the length of a side of a triangle and the sine of the angle it faces is constant

So to get C, we have the following;

9/sin 38 = 11/sin C

sin C = 11sin 38/9

sin C = 0.7525

C = sin^-1(0.7525)

C = 48.80

This is approximately 49

To get A,

we know that if we added the measure of interior angles of a triangle, the addition is 180 degrees

Thus, we have it that:

38 + 49 + A = 180

A = 180-38-49

A = 93