hydrocarbon.
4-ethyl-3-methyloctane

Answer:

Is this question multiple choice if it is i can most likely answer it!

Explanation:

Answer:

mass of chlorine = 10.4 grams

Explanation:

Mass of the solution = 5.20 × 10⁶ g

ppm chlorine by mass = 2.00

Recall that:

[tex]ppm = \dfrac{mass \ of \ chorine \ gas (solute)}{ mass of the solution }\times 10^6[/tex]

[tex]2 = \dfrac{mass \ of \ chorine \ gas (solute)}{ 5.20\times 10^6}\times 10^6[/tex]

mass of chlorine = 5.20 × 2.0

mass of chlorine = 10.4 grams

Answer:

-846 kJ

Explanation:

Using Henderson Hasselbach's law,

2Al + 3/2 O2 -> Al2O3    H = -1670 kJ

-(2Fe + 3/2 O2 -> Fe2O3) = Fe2O3 -> 2Fe + 3/2 O2    H = 824 kJ

-1670 kJ + 824kJ = -846 kJ

Answer:

thank uuuuuuu for freeeee pointssssss!!!!!..

Explanation:

hope it is helpful to you

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 4.67 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer: The element B will have ONE unpaired electron in the p orbital.

Explanation:

The electronic configuration of each given element is as follows.

Atomic number of calcium (Ca) is 20.

Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]

Atomic number of nitrogen (N) is 7.

N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]

Atomic number of boron (B) is 5.

B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]

Atomic number of argon (Ar) is 18.

Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]

Atomic number of bromine (Br) is 35.

Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]

Therefore, boron is the only element that have one unpaired electron in the p-orbital.

Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.

Answer:  There are 0.5 grams of barium sulfate are present in 250 of 2.0 M [tex]BaSO_{4}[/tex] solution.

Explanation:

Given: Molarity of solution = 2.0 M

Volume of solution = 250 mL

Convert mL int L as follows.

[tex]1 mL = 0.001 L\\250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L[/tex]

Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given [tex]BaSO_{4}[/tex] solution is as follows.

[tex]Molarity = \frac{mass}{Volume (in L)}\\2.0 M = \frac{mass}{0.25 L}\\mass = 0.5 g[/tex]

Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M [tex]BaSO_{4}[/tex] solution.

Answer:

14.4g

Explanation:

Answer:

96.92 K

Explanation:

Applying,

V/T = V'/T'..................... Equation 1

Where V = Initial Volume, T = Initial Temperature, V' = Final Volume, T' = Final Temperature.

Make T the subject of the equation

T = VT'/V'................. Equation 2

From the question,

Given: V = 268 mL, V' = 824 mL, T' = 25°C = (25+273) = 298 K

Substitute these values into equation 2

T = (268×298)/824

T = 96.92 K

Hence the Initial temperature of Nitrogen gas is 96.92 K

Answer: 114.22852 grams

HOPE THIS HELPS

Answer:

-0.276 Degrees C

Explanation:

kf of water is 1.86

Freezing point depression= m x kf x i

i= ions present ( K+ Cl-) 1=2

1.86x2X.743= .276

Since its freezinf point depression the freezing point will lower

so

0-.276= -.276

Answer: -2.764

Explanation:

Solution :

Compound                      Ksp

[tex]$PbF_2$[/tex]                               [tex]$3.3 \times 10^{-8}$[/tex]

[tex]$Ni(CN)_2$[/tex]                        [tex]$3 \times 10^{-23}$[/tex]

FeS                                [tex]$8 \times 10^{-19}$[/tex]

[tex]$CaSO_4$[/tex]                           [tex]$4.93 \times 10^{-5}$[/tex]

[tex]$Mg(OH)_2$[/tex]                      [tex]$5.61 \times 10^{-12}$[/tex]

Ksp of [tex]$Ni(CN)_2 << Ksp \text{ of}\ \ Mg(OH)_2$[/tex] and both compounds dissociate the same way. Hence [tex]$Mg(OH)_2$[/tex] is more soluble than [tex]$(B). \ Ni(CN)_2$[/tex]

[tex]$Mg(OH)_2$[/tex]  is less soluble than [tex]$(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$[/tex]

It is not possible to determine CD - [tex]$FeS \text{ or} \ CaSO_4$[/tex]  is more or less soluble than [tex]$Mg(OH)_2$[/tex]  as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.

[tex]$Ni(OH)_2$[/tex]  can be directly compared with PbS, [tex]$AlPO_4, MnS$[/tex]

[tex]$\text{For } \ Ni(OH)_2$[/tex]

[tex]$AB_2(s) \rightarrow A^{2+} + 2B^{-}$[/tex]

[tex]$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$[/tex]

100

1-s s 2s

Ksp = [tex][A2+][B-]^2 = s \times (2s)^2 = 4s^3[/tex]

Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

For Silver Chloride

[tex]$AB(s) \rightarrow A^{x+}+B^{x-}$[/tex]

[tex]$AgCl(s) \rightarrow Ag^+ + Cl^-$[/tex]

1 0 0

1 - s s s

Ksp [tex]$=[A^{x+}][B^{x-}]=s \times s = s^2$[/tex]

Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

Answer:

A. Mass

Explanation:

If it takes up space it has to have mass. Not everything that is matter has a color, certain length or width.

Answer:

1) some of the gas maybe metal but non metal directly refers it self to not begin metal

2) gases are present in only air . non metals are available in solid form too

Answer:

%m/m = 0.9975%

Xₐ = 0.0039

Explanation:

In order to do this, we need various data. First to all, we need tje molecular mass of the ethanol. this can be obtained in handbooks, or simply taking the atomic weights of carbon (12 g/mol), Hydrogen (1 g/mol) and oxygen (16 g/mol) and summing those values:

MM C₂H₆O = (2*12) + (6*1) + (16*1) = 46 g/mol

Now, there is an expression that is commonly used to determine the molarity of a solution given the mass percent and density, and assuming of course, 1 liter of solution:

M = d * %m/m * 1000 / MM * 100     (1)

From here, we can solve for %m/m:

%m/m = M * MM * 100 / d * 1000

As the problem is not saying the volume of solution, we can easily assume we have 1 liter of solution. Therefore, the %m/m replacing the given data is:

%m/m = 0.216 *46 * 100 / 0.996 * 1000

To get the mole fraction, we first need to get the volume of solvent. From the density, we can get the mass of solution:

m = V * d

m = 1000 * 0.996 = 996 g of solution.

The mass of solute is:

m = 0.216 mol/L * 46 g/mol

m = 9.936 g/L, or simply we have 9.936 g of ethanol in 1 L of solution.

The mass of solvent:

solvent = 996 - 9.936 = 986.064 g

The molecular mass of water, so we can get the moles is 18 g/mol so:

moles water = 986.064 / 18 = 54.78

Finally the mole fraction:

Xₐ = 0.216 / (0.216 + 54.78)

Hope this helps

Answer:

UK stop spending a lot on clothes if u don't wear half of them

Answer:

Beta emission

Explanation:

In beta emission, a neutron is converted into a proton thereby emitting an electron and a neutrino. A neutrino is a particle that serves to balance the spins.

When a nucleus undergoes beta emission, the mass number of the parent and daughter nuclei remain the same while the atomic number of the daughter nucleus is greater than that of its parent by one unit.

Hence, in beta emission, the daughter nucleus is found one pace to the right of the parent in the periodic table.

Explanation:

Na=23

cl2=35.5×2=71

NaCl=23+35.5=58.5

2Na + Cl2== 2NaCl

2. : 1

20/23=2(x)/71

(71×20)/(23×2)=x

x=30.87g

Explanation:

HCL you can do it yourself .try again

Answer:

No

Explanation:

Rust is an iron oxide, a usually reddish-brown oxide formed by the reaction of iron and oxygen in the catalytic presence of water or air moisture.

Answer:

(NH 4) 3P Ionic fu ammonium phosphide 3) Ca 3N 2 Ionic fu calcium nitride 4) Al( NO B) ... If there is a multi-valent metal present, write both the stock and classical name. ... 66 * 10^(23)"atoms of H" The first thing to do here is write the chemical ...

Explanation:

just follow the instructions below.

hope it helps.

#CARRYONLEARNING

Answer:

4NH3 + 3O2 → 2N2 + 6H2O

a. 2 moles

b. 4 moles

c. 3 moles

Explanation:

a. 4 mol NH3

4NH3 + 3O2 → 2N2 + 6H2O

  4      :     3    :    2     :    6

  4                                        (mol)

⇒[tex]n_{N2}[/tex] = 4 × 2 ÷ 4 = 2

b. 4 mol N2

c. 4.5 mol O2

4NH3 + 3O2 → 2N2 + 6H2O

4      :     3    :    2     :    6

           4.5                          (mol)

⇒[tex]n_{N2}[/tex] = 4.5 × 2 ÷ 3 = 3