How many grams of methane gas occupy a volume of 11.2 liters at stp

Answers

Answer 1

Answer:

see the pic for the answer

How Many Grams Of Methane Gas Occupy A Volume Of 11.2 Liters At Stp
Answer 2

7.91 grams of methane gas occupy a volume of 11.2 liters at STP.

What is STP?

Standard temperature and pressure, abbreviated STP, refers to nominal conditions in the atmosphere at sea level.

First, we need to calculate the number of moles:

STP is 0 °C and 1 bar.

One mole of a gas at STP has a volume of 22.71 L .

Moles of CH₄ = 11.2 L × ([tex]\frac{1 mol}{22.71 L}[/tex])

Moles of CH₄ = 0.4932 mol

Now we will calculate the mass of CH₄

Moles = [tex]\frac{mass}{molar \;mass}\\[/tex]

Mass of CH₄ = 0.4932 × 16.03

Mass of CH₄ = 7.91 g

Hence, 7.91 grams of methane gas occupy a volume of 11.2 liters at STP.

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Related Questions

what is a stethoscope

Answers

Explanation:

A stethoscope is used to listen to sounds that the heart , lungs , blood flow , intestines make.

a medical instrument for listening to the action of someone’s heart or breathing

1.
10
2.
3.
4.
60
Which polygons are similar?
110
60
10
01
02
03
04

Answers

Answer:

The answer is "1 and 4 polygons were similar".

Explanation:

In the given question, in both figures 1 and 4, it's measure angle were 10, 60, 110. In figure number 4, its angle is 10, 60, and on the third side, its value is equal to 110, which is (180 - 70).

Be sure to answer all parts. How many moles of O are needed to combine with 0.276 mole of C to form CO

Answers

Answer:

0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Explanation:

Given data:

Moles of oxygen needed = ?

Moles of carbon present = 0.276 mol

Solution:

Chemical equation:

2C  + O₂      →        2CO

Now we will compare the moles of carbon with oxygen.

              C            :          O₂  

              2            :            1

             0.276     :        1/2×0.276  = 0.138 mol

Thus, 0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Which is an example of a effect of geotropism

Answers

Answer:

An example of geotropism is the movement of nutrients. minerals and water in a plant. This transport is accomplished by specialized parts of the plant, the xylem which is pronounced zylem and the phloem which is pronounced flowem are the straw like parts of a plant’s stem that move the stuff up and down.

Explanation:

Which of the following elements can only form single covalent bonds when forming molecular compounds?

a) Nitrogen
b) Hydrogen
c) Carbon
d) Oxygen

Answers

B. Since Hydrogen only has one electron, it can only form a single bond.

Hydrogen can only form single covalent bonds when forming molecular compounds. Therefore, option B is correct.

What is covalent bond?

A covalent bond is a type of chemical bond formed between two or more atoms in which electrons are shared between them. Covalent bonds usually occur between nonmetal atoms and are formed by the sharing of valence electrons.

Hydrogen can only form a single covalent bond because it has only one valence electron and needs one more electron to complete its valence shell, making it stable.

Nitrogen can form triple covalent bonds, carbon can form multiple covalent bonds, and oxygen can form double covalent bonds in molecular compounds.

Thus, option B is correct.

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How many milliliters of 2.00 M H2SO4 will react with 28.0 g of NaOH?

Answers

Taking into account the reaction stoichiometry and the definition of molarity, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.

Reaction stoichiometry

In first place, the balanced reaction is:

H₂SO₄ + 2 NaOH  → Na₂SO₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂SO₄: 1 moleNaOH: 2 moles  Na₂SO₄: 1 moleH₂O: 2 moles

The molar mass of the compounds is:

H₂SO₄: 98 g/moleNaOH: 40 g/moleNa₂SO₄: 142 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂SO₄: 1 mole× 98 g/mole= 98 gramsNaOH: 2 moles× 40 g/mole= 80 gramsNa₂SO₄: 1 mole× 142 g/mole= 142 gramsH₂O: 2 moles× 18 g/mole= 36 grams

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity= \frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Moles of H₂SO₄ required

The following rule of three can be applied: If by reaction stoichiometry 80 grams of NaOH react with 1 mole of H₂SO₄, 28 grams of NaOH react with how many moles of H₂SO₄?

[tex]moles of H_{2}S O_{4} =\frac{28 grams of NaOHx1 mole ofH_{2}S O_{4} }{80 grams of NaOH}[/tex]

moles of H₂SO₄= 0.35 moles

Volume of H₂SO₄ required

In this case, you know:

Molarity= 2 M= 2 [tex]\frac{moles}{liter}[/tex]amount of moles= 0.35 moles

Replacing in the definition of molarity:

[tex]2 \frac{moles}{liter}= \frac{0.35 moles}{volume}[/tex]

Solving:

2 [tex]\frac{moles}{liter}[/tex] × volume= 0.35 moles

volume= 0.35 moles ÷ 2 [tex]\frac{moles}{liter}[/tex]

volume= 0.175 liters= 175 mL (being 1 L= 1000 mL)

Finally, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.

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The volume of a sample of hydrogen gas was decreased from 11.95 L to 5.24 L at constant temperature. If the final pressure exerted by the hydrogen gas sample was 9.31 atm, what pressure did the hydrogen gas exert before its volume was decreased?

Answers

Answer:

P1 = 21.23 atm

Explanation:

Initial Volume V1 = 11.95 L

Final Volume V2 = 5.24L

Final Pressure P2 = 9.31 atm

Initial Pressure P1 = x

The relationship between these values is given as;

P1 / V1 = P2 / V2

P1 / 11.95 = 9.31 / 5.24

P1 = 21.23 atm

Ammonia, NH3 is a common base with Kb of 1.8 X 10-5. For a solution of 0.150 M NH3:
Write the equation for the ionization of ammonia in water.


List all species present in the solution AND determine the concentrations of each.





Determine the pH of this solution.

Answers

The concentrations : 0.15 M

pH=11.21

Further explanation

The ionization of ammonia in water :

NH₃+H₂O⇒NH₄OH

NH₃+H₂O⇒NH₄⁺ + OH⁻

The concentrations of all species present in the solution = 0.15 M

Kb=1.8 x 10⁻⁵

M=0.15

[tex]\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}[/tex]

[tex]\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21[/tex]

9. What are the advantages of using an indicator to inform pH measurements? What are the advantages of using a pH meter?

Answers

Answer:

The advantages of using an indicator to inform pH measurements:

It gives a mathematically result of the pH, in addition, it gives the precise pH of solvent, and it also gives an idea of the straight of the solution also.

Now, the advantage of using a pH meter:

It is a rapid method to characterize between acids, bases. However, this method does not show how strong acid or base actually are, plus it tends to gives a range of acidity or basicity not quite accurate as a result.


The unbalanced equation below shows the combustion of methane.
CH4 +02 —CO2 + H2O
Which series of numbers represents the coefficients necessary to balance the equation?

A-1, 1, 1, 2
B-1, 2, 1, 2
C-2, 2, 1, 4
D-0, 3, 2, 2

Answers

B. 1, 2, 1, 2. You balance the equation by making sure there are equal elements on both sides.

The series of numbers 1, 2, 1, 2 represents the coefficients necessary to balance the equation of combustion of methane. Therefore, option (B) is correct.

What is the combustion reaction?

A combustion reaction can be described as a reaction that produces fire and takes place at an elevated temperature. A combustion reaction is an exothermic, redox reaction that occurs between a fuel and mostly oxygen in the atmosphere.

Oxygen is the most important part of the combustion reaction because combustion never happens in the absence of oxygen. Complete combustion is the one where a fuel burns entirely to produce carbon dioxide and heat with oxygen.

The combustion of methane reacts with two moles of oxygen gas to give two moles of water and carbon dioxide.

CH₄ (g)  +  2O₂ (g)  → CO₂ (g)  +  2H₂O (g)

Therefore, the series of numbers of coefficients is 1, 2, 1, 2.

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In a classroom, which comparison would a teacher most likely use for describing a mole?
a cup of water and a liter of oil
a dozen eggs and a dozen jellybeans
a jar of jellybeans and a gram of salt crystals
20 marbles in a bag and 10 large ice cubes

Answers

B That the answer (hope this helps)

Answer:

B

Explanation:

a mole is "a chemist's dozen" lol

compare the size of I, I+ and I-

Answers

umm explanation pls so i answee

I'm confused on this question. Could anyone tell me how to go about doing it ASAP. I will give brainliest.

One fuel used to power the main engines of rockets is liquid hydrogen. It reacts in the presence of oxygen to produce water in this reaction: H2 + O2 --> H2O
If an rockets main engine can hold 1.44 x 106 grams of hydrogen, how much oxygen would be needed to fully react all of it?
How much water would be produced if all of the hydrogen above reacted?

Answers

Answer:

3.57 × 10⁵ mol O₂

7.13 × 10⁵ mol H₂O

Explanation:

Step 1: Write the balanced equation

2 H₂ + O₂ ⇒ 2 H₂O

Step 2: Calculate the moles corresponding to 1.44 × 10⁶ g of hydrogen

The molar mass of hydrogen is 2.02 g/mol.

1.44 × 10⁶ g × (1 mol/2.02 g) = 7.13 × 10⁵ mol

Step 3: Calculate the moles of oxygen needed to react with 7.13 × 10⁵ moles of hydrogen

The molar ratio of H₂ to O₂ is 2:1. The reacting moles of oxygen are 1/2 × 7.13 × 10⁵ mol = 3.57 × 10⁵ mol.

Step 4: Calculate the moles of water produced from 7.13 × 10⁵ moles of hydrogen

The molar ratio of H₂ to H₂O is 2:2. The moles of water formed are 2/2 × 7.13 × 10⁵ mol = 7.13 × 10⁵ mol.

what is the source of the force that moves the tectonic plates along this plate boundary

Answers

Answer:

Mantle convection

Explanation:

The source of the force that moves tectonic plates along plate boundaries is as a result of the mantle convection.

Heat energy produced in the mantle especially from radioactive decay is a very important source of internal heat that drives plate motion. Denser and cold materials close to the over-riding lithosphere above sinks deep into the mantle. Hotter and lighter materials rises to the surface. This sets up a convection cell by which the plates above are driven.

Why is Mg++ smaller than Mg atom?​

Answers

Answer:

The magnesium ion is much smaller than the magnesium atom because magnesium atom contains more electrons as compared to magnesium ion. Explanation: ... Whereas when an atom tends to lose an electron then it acquires a positive charge and size of the atom tends to increase.

Answer:

Because it looses it two electrons to form a stable octet Ionic form..........

What happens to the gravitational potential energy of an object if you bring it higher with respect to the ground? *

Answers

Answer:

Increases

Explanation:

The gravitational potential energy of an object increases as you bring it higher with respect to the ground.

Gravitational potential energy depends on the mass, height and gravity between two bodies;

   Gravitational potential energy  = mgh

m is the mass

g is the height

h is the height

We can clearly see that the higher the elevation, the more the value of the gravitational potential energy.

a certain quantity of gas occupies 20l at 50°c and pressure of 2 atm.at what pressure will the volume of the gas will be occupy 2L,if the temperature does not change?​

Answers

Answer:

20atm

Explanation:

according to boyles law P1V1= P2V2

(Question) : What is the specific gravity of liquid sample with a mass
of 35.0 g and a volume of. 14.00 mL ?

Answers

Answer:

48.0g is the specific gravity of liquid sample with a mass of 35.0g and a volume of 14.00 mL

Consider the balanced equation.


CuSO4 + Zn Right arrow. ZnSO4 + Cu


If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper?
1.253 g
50.72 g
79.63 g
194.3 g

Answers

Answer: 1.253 g
Explanation:

Answer:

79.63

Explanation:

how many elements are present No and NO

Answers

For the first one No: 1
For the second one NO: 2

Can someone please help me quick !!!

Answers

2 and 4 is the answer. Because (NO3)2 means you multiply the o3 by 2 giving you 6 oxygen. And then number 2 has O6 which equals 6 oxygen.

what mass of potassium chlorate should be required to produce 113 L of oxygen O2. measured at STP g

Answers

Answer:

411.6 g

Explanation:

The equation for the decomposition of potassium chlorate to produce oxygen is given as;

2KClO3 --> 2KCl + 3O2

From the stochiometry of the reaction 2 mole of KClO3 produces 3 mol of O2

At STP,

1 mol = 22.4L

3 mol = x

x = 67.2L

2 mole of KClO3 produces 67.2L of O2

How many moles would produce 113L?

2 = 67.2

x = 113

x = 3.36 moles

Moles can be converted to mass using;

Mass = moles * Molar mass

Mass = 3,36 * 122.5 g/mol

Mass = 411.6 g

What happens to the stability of atoms when they form covalent bonds?

Answers

Answer

The two types of chemical bonds that atoms can form to achieve stability are called ionic bonds and covalent bonds. In ionic bonds, atoms donate or receive electrons to achieve stability. In covalent bonds, atoms share electrons to achieve stability.

Chlorine (Cl) is 76% chlorine-35 and 24% chlorine-37. Determine the average atomic mass of chlorine. Show/Explain work.

Answers

Answer:

Average atomic mass of chlorine is 35.48 amu.

Explanation:

Given data:

Percent abundance of Cl-35 = 76%

Percent abundance of Cl-37 = 24%

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (76×35)+(24×37) /100

Average atomic mass =  2660 + 888 / 100

Average atomic mass  = 3548/ 100

Average atomic mass = 35.48 amu

Average atomic mass of chlorine is 35.48 amu.

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this information?

a. They are in the same group because they have similar atomic masses, but they are in different periods because they have different chemical properties.

b. They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

c. They are in the same group because their atomic numbers are each multiples of four, but they are in different periods because they have different chemical properties.

d. They are in the same group because they have similar atomic masses, but they are in different periods because they have very different atomic numbers.

Answers

The answer is b) similar chemical properties but very different atomic numbers

Answer:

B: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation:

I took the Unit test on EDG and I got it correct

Pls mark me brainliest

PLS HURRY
What methods are you using to test this (or each) hypothesis?

Answers

you use a thesis to state your hypothesis and to think what would happen to the experiment

Answer:

Fair test.

PLS GIVE BRAINLIEST

HELLPPPPP!
Each employee should be responsible for keeping his or her work station clean throughout the work shift.
True
False

Answers

Answer:

true

Explanation:

Rank the following chemical species from largest ionic radius to smallest ionic radius
V^3+, V^5+, V^4+, V^2+

Answers

Answer:

Biggest Radii     V²⁺ > V³⁺ > V⁴⁺ > V⁵⁺     Smallest Radii

General Formulas and Concepts:

Periodic Trends: Atomic/Ionic RadiiCoulomb's Law

Explanation:

The Periodic Trend for Atomic Radii is down and to the left. Therefore, the element with the largest radius would be in the bottom left corner of the Periodic Table.

Anions will always have a bigger radii than the parent radii. When we add e⁻ to the element, we are increasing the e⁻/e⁻ repulsions. This will cause e⁻ to repel themselves more and thus create more space, increasing the radii size.

Cations will always have smaller radii than the parent radii. When we remove e⁻ from the element, we are decreasing e⁻/e⁻ repulsions. Since there are less e⁻, there is no need for more space and thus decreases the radii size.

Since Cations are smaller than the parent radii, the more e⁻ we remove, the smaller it will become.

Therefore, the least removed e⁻ Vanadium would be the largest and the most removed e⁻ Vanadium would be the smallest.

Graphite is sometimes used to reduce the friction between
two surfaces that are rubbing together.
Explain how it does this.

Answers

Because of gravity influence

Graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. Therefore, this happen because of weak covalent bond.

What is graphite?

Graphite is among the most prevalent carbon allotropes. It is also the stable allotrope for carbon, and as such, it is employed in electrochemistry to define the heat of synthesis of carbon compounds. With a hardness of 2.09-2.23 g/cm3, graphite is an excellent conductor of electricity and heat.

Graphite is a large covalent structure in which each carbon atom is covalently linked to three other carbon atoms. Graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. This happen because of weak covalent bond.

Therefore, graphite is sometimes used to reduce the friction between two surfaces that are rubbing together. This happen because of weak covalent bond.

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How many grams are in 1.50 moles of KMnO4?

A. 165.06
B. 660.24
C. 178.41
D. 237.06
E. 484.29

Answers

Explanation:

mole=mass/Molar mass

mass= mole×molar mass

m= 1.5 × (39+55+64)

m= 1.5 × 158

m= 237g

There are 237.06 grams in 1.50 moles of KMnO4.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass. That is;

mass of KMnO4 = no. of moles × molar mass of KMnO4

Molar mass of KMnO4 = 39 + 55 + 16(4)

= 158g/mol

mass of KMnO4 = 158g/mol × 1.5mol

Mass of KMnO4 = 237g

Therefore, there are 237.06 grams in 1.50 moles of KMnO4.

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