How many different strings can be made from the letters in HAPPINESS, using all the letters?

Answers

Answer 1

Answer:

20 different strings

Step-by-step explanation:

Let the lines in the alphabets be the strings. So, each alphabet has many strings. Counting them would make them 20 strings.


Related Questions

Assume A, B, P, and D are n times n matrices. Determine whether the following statements are true or false. Justify each answer.
A matrix A is diagonalizable if A has n eigenvectors.
The statement is false. A matrix is diagonalizable if and only if it has n -1 linearly independent eigenvectors.
The statement is true. A diagonalizable matrix must have more than one linearly independent eigenvector.
The statement is true. A diagonalizable matrix must have a minimum of n linearly independent eigenvectors.
The statement is false. A diagonalizable matrix must have n linearly independent eigenvectors.
If A is diagonalizable, then A has n distinct eigenvalues.
The statement is false. A diagonalizable matrix can have fewer than n eigenvalues and still have n linearly independent eigenvectors.
The statement is true. A diagonalizable matrix must have n distinct eigenvalues.
The statement is false. A diagonalizable matrix must have more than n eigenvalues.
The statement is true. A diagonalizable matrix must have exactly n eigenvalues.
If AP = PD, with D diagonal, then the nonzero columns of P must be eigenvectors of A.
The statement is true. AP = PD implies that the columns of the product PD are eigenvalues that correspond to the eigenvectors of A.
The statement is false. If P has a zero column, then it is not linearly independent and so A is not diagonalizable.
The statement is true. Let v be a nonzero column in P and let lambda be the corresponding diagonal element in D. Then AP = PD implies that Av = lambda v, which means that v is an eigenvector of A.
The statement is false. AP = PD cannot imply that A is diagonalizable, so the columns of P may not be eigenvectors of A.

Answers

Answer:

The correct answers are (1) Option d (2) option a (3) option a

Step-by-step explanation:

Solution

(1) Option (d) The statement is false. A diagonalizable matrix must have n linearly independent eigenvectors: what it implies is that a matrix is diagnostic if it has linearity independent vectors.

(2) Option (a) The statement is false. A diagonalizable matrix can have fewer than n eigenvalues and still have n linearly independent eigenvectors: what this implies is that a diagonalizable matrix  can have repeated eigenvalues.

(3) option (a) The statement is true. AP = PD implies that the columns of the product PD are eigenvalues that correspond to the eigenvectors of A : this implies that P is an invertible matrix whose column vectors are the linearity independent vectors of A.

f(x) =3x+4=g(x)=2x+1 /x_4:find the (fog)?

Answers

Answer:

Step-by-step explanation:

0.5(repeated)+0.1(repeated)-0.3(repeated)?

Answers

Answer:

  [tex]\dfrac{1}{3}=0.\overline{3}[/tex]

Step-by-step explanation:

Since a single digit is repeated in each case, and since the repeat starts at the decimal point, the fraction corresponding to the repeated digit is that digit divided by 9.

  [tex]0.\overline{5}+0.\overline{1}-0.\overline{3}=\dfrac{5}{9}+\dfrac{1}{9}-\dfrac{3}{9}=\dfrac{5+1-3}{9}=\dfrac{3}{9}\\\\=\boxed{\dfrac{1}{3}}[/tex]

_____

Comment on equivalents to repeating decimals

The number of 9s in the denominator equals the number of repeated digits.

  0.2727(repeated) = 27/99 = 3/11 . . . . . 2 repeated digits


How many of these equations have the solution
x
=
12
x
=
12
?

x

2
=
10
x

2
=
10
x
2
=
24
x
2
=
24
10

x
=
2
10

x
=
2
2x1=25
2x−1=25

Answers

Answer:

a)x−2=10

b) 2x=24

Two equations have have the solution

x = 12

Question:

How many of these equations have the solution x=12 ?

x−2=10

2x=24

10−x=2

2x−1=25

Step-by-step explanation:

To determine which of the above equations have x= 12, we would solve for x in each of the equations.

a) x−2=10

Collecting like terms

x = 10+2

x = 12

This equation has x= 12 as a solution

b) 2x =24

Divide through by coefficient of x which is 2

2x/2 = 24/2

x = 12

This equation has x= 12 as a solution

c) 10−x=2

Collecting like terms

10-2 - x = 0

8 - x = 0

x = 8

d) 2x−1=25

Collecting like terms

2x = 25+1

2x = 26

Divide through by coefficient of x which is 2

2x/2 = 26/2

x = 13

Note: that (b) x2 = 24 from the question isn't clear enough. I used 2x = 24.

If x2 = 24 means x² = 24

Then x = √24 = √(4×6)

x = 2√6

Then the number of equations that have the solution x = 12 would be 1. That is (a) x−2=10 only

Answer:

1/2x + 12 >10

Step-by-step explanation:

Helen wants to buy 8 boxes of crayons at $1.94 per box for the day care center that she runs estimate the total cost of the crayons

Answers

Answer: $16

Step-by-step explanation:

1.94 * 8 = 15.52

$15.52 rounds up to $16

In the diagram below, AABC ~ ADEC. What is the value of x?

Answers

Answer:

c is the answer just did the quiz

The value of x in the triangle is 26.

Option D is the correct answer.

What is a triangle?

A  triangle is a 2-D figure with three sides and three angles.

The sum of the angles is 180 degrees.

We can have an obtuse triangle, an acute triangle, or a right triangle.

We have,

If two triangles are similar,

The ratio of its corresponding sides is equal.

This means,

ΔABC and ΔCDE

AB/AC = ED/CD

42/x = 8/(32 - x)

42 (32 - x) = 8x

1344 - 42x = 8x

1344 = 50x

x = 1344/50

x = 26.88

x = 26

Thus,

The value of x in the triangle is 26.

Learn more about triangles here:

https://brainly.com/question/25950519

#SPJ7

What is the slope-intercept form of the equation 6x-3y=18

Answers

Answer:

2

Step-by-step explanation:

Given,

6x-3y=18

or, -3y=18-6x

dividing by 3 into both sides and multiply by -1

we get,

y=2x-6

comparing above eq with linear equation y=mx+c

we get,

m=2 Ans.

That’s the answer if this was older if it’s still here

A professional employee in a large corporation receives an average of μ = 39.8 e-mails per day. Most of these e-mails are from other employees in the company. Because of the large number of e-mails, employees find themselves distracted and are unable to concentrate when they return to their tasks. In an effort to reduce distraction caused by such interruptions, one company established a priority list that all employees were to use before sending an e-mail. One month after the new priority list was put into place, a random sample of 38 employees showed that they were receiving an average of x = 33.1 e-mails per day. The computer server through which the e-mails are routed showed that σ = 16.2. Has the new policy had any effect? Use a 10% level of significance to test the claim that there has been a change (either way) in the average number of e-mails received per day per employee.

Answers

Answer:

The policy has an effect because the null hypothesis rejected since P-value < significance level.

Step-by-step explanation:

Since (P-value = 0.0108) < 0.1 significance level, we have sufficient evidence to show that the mean is not equal to 39.8. This means that the policy has an effect on the average number of the emails received per day.

The workings are clearly written in the file attached below. Please check.

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: number of emails a profession employee receives per day

This variable has an average of μ= 39.8 emails/day and the standard deviation is known to be δ= 16.2 emails/day

A company considers that the large amount of emails creates distraction, reducing the employees concentration and thus their efficiency, so they established a new priority list that all employees were to use before sending an e-mail. After one month they took a random sample of employees obtaining:

n= 38

X[bar]= 33.1 emails/day

If the company's new policy worked, then the company would expect the mean number of emails an employee receives per day to decrease, symbolically: μ < 39.8

The hypotheses are:

H₀: μ ≥ 39.8

H₁: μ < 39.8

α: 0.10

To analyze the population mean you need as condition that the variable of interest is at least normal.

There is no information about the population distribution, but the sample size is big enough for it to be valid to apply the Central Limit Theorem. This states that for variables of unknown distribution, if a sample large enough is taken (normally n≥30 is considered ok) you can approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;σ²/n)

This allows you to use the standard normal as statistic for the test:

Z= (X[bar] - μ)/(σ/n) ≈ N(0;1)

[tex]Z_{H_0}= \frac{33.1-39.8}{\frac{16.2}{\sqrt{38} } }= -2.549= -2.55[/tex]

Using the critical value approach, this test is one tailed to the left, meaning that you will reject the null hypothesis to low values of Z.

The critical value is:

[tex]Z_{\alpha }= Z_{0.10}= -1.283[/tex]

The decision rule is:

If [tex]Z_{H_0}[/tex] ≤ -1.283, reject the null hypothesis.

If [tex]Z_{H_0}[/tex] > -1.283, do not reject the null hypothesis.

The calculated value is less than the critical value so the decision is to reject the null hypothesis.

At a 10% significance level, the null hypothesis was rejected. You can conclude that the new policy reduced the average number of emails a professional employee receives per day.

I hope this helps!

Question 6 of 25
2 Points
Which of the following would be a good name for the function that takes the
weight of a box and returns the energy needed to lift it?
A. Box(cost)
B. Weight(energy)
C. Weight(box)
D. Energy(weight)

Answers

Answer:

C

Step-by-step explanation:

because you need the energy of the box to lift it, as my old professor used to say " you can only push on somthing as much as it can push you back "

Answer:

D. energy(weight) is the correct answer

hope this helps

A company makes concrete bricks shaped like rectangular prisms. Each brick is 13 inches long, 5 inches wide, and 4 inches tall. If they used 11,700 in^3 of concrete, how many bricks did they make?

Answers

Answer:

45 bricks

Step-by-step explanation:

First we need to find the volume of one brick. The bricks are rectangular prisms. The volume formula for rectangular prisms is:

V=l*w*h

The bricks are 13 inches long, 5 inches wide and 4 inches high.

l=13 inches

w=5 inches

h=4 inches

V= 13 inches * 5 inches * 4 inches

V=65 inches^2 * 4 inches

V=260 inches ^3

Each brick has a volume of 260 inches^3. We know they used a total of 11,700 inches^3 of concrete. The question asks us to find how many bricks they made. We must divide the volume of concrete used by the volume of one brick.

concrete volume / one brick volume

concrete volume= 11,700 in^3

one brick volume= 260 in^3

11,700 in^3 / 260 in^3

11,700/260

45

They made 45 bricks.

find the product of 4025 multiply 5 by using properties

Answers

Answer:

Change 4020 to 4000 + 25.

Then use the distributive property.

4025 * 5 = (4000 + 25) * 5 = 4000 * 5 + 25 * 5 = 20,000 + 125 = 20,125

Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

Answers

Answer:

A = 1.02 P

Step-by-step explanation:

A = P + 0.02P

Formula in Factorized form

(Taking P common)

A = P(1+0.02) [The required factorized from]

Then,

A = 1.02 P

Please answer this correctly

Answers

Answer:

5/7

Step-by-step explanation:

There are 7 cards, all of which have an equal chance of being chosen.

And in this case, because there are 7 cards in total, they each have a 1/7 chance of being chosen. Because there are 5 cards greater than 4, you have a 5x1/7 chance =5/7 chance of choosing a number greater than 4.

P.S. If you need it as a percentage, then it is 71.428571%.

P.P.S. Remember if you like the answer then mark as brainliest thank you!

100 POINTS!!!!! PlZ help Find all possible values of the digits Y, E, A, R if YYYY - EEE + AA - R = 1234, and different letters represent different digits.

Answers

Answer:

Y = 1, E = -1, A= 1, R = -1

Step-by-step explanation:

YYYY - EEE + AA - R = 1234

First we would break down the digits in the whole numbers into their place value (thousands, hundreds, tens and units).

YYYY = 1000Y + 100Y +10Y + Y

EEE = 100E + 10E + E

-EEE = -100E - 10E - E

AA = 10A + A

R = R

-R = -R

1234 = 1000+200+30+4

Let's equate each place value for each of the numbers.

Thousands: 1000Y = 1000

Y = 1000/1000 = 1

Hundreds: 100Y - 100E = 200

100(1) - 100E = 200

-100E = 200-100

-100E= 100

E = -1

-EEE = -E(111)

Tens: 10Y - 10E + 10A = 30

10(1) - 10(-1) + 10A = 30

20+ 10A = 30

A = 10/10

A= 1

Units: Y - E + A - R = 4

1 - (-1) + 1 - R = 4

3-R = 4

R = 3-4 = -1

YYYY - EEE + AA - R = 1234

1111 - (-111) + 11 - (-1) = 1111+111+11+1 = 1234

All possible values of the digits Y, E, A, R are Y = 1, E = -1, A= 1, R = -1

Answer:

Y=2

E=9

A=1

R=0

Step-by-step explanation:

Let's check our work.

2,222 - 999 + 11 - 0

1,223 + 11 - 0

1,234 - 0

1,234

Also previous answerer how can digits be negative?

HELP ME PLS I DO NOT UNDERSTAND A random number generator is used to create a real number between 0 and 1, equally likely to fall anywhere in this interval of values. (For the instance, 0.3794259832... is a possible outcome). a. Sketch a curve of the probability distribution of this random variable, which is the continuous version of the uniform distribution. b. What is the mean of this probability distribution?

Answers

f(x)=1, 0 < x < 1 is the probability density function of the random variable x.

generally, it is f(x)=1/(b-a)  a < x < b;

where b=1 and a=0.

b) mean = integral (0 to 1) xdx  =  (0 to 1)  = 1/2

c)integral( 0.35 to 0.6) dx  =x (between 0.35 and 0.6)  = 0.6-0.35=0.25

d) integral(less than 0.82)dx = x (between 0 and 0.81) = 0.81 - 0 = 0.81

Please mark me brainliest!

Find the length of a rectangle with a diagonal of 10 and a height of 8.

Answers

Answer:

The length of the rectangle is 6.

Step-by-step explanation:

Given: The diagonal of a rectangle is 10 and the height is 8.

Please understand, that a diagonal, divides the rectangle into two tringles.

To find the length of the rectangle, you can use Pythagoras on one of the right sided triangles, because the length of the triangle, is also the length of the rectangle!

EXTRA:

If you know the special 3 4 5 triangle, a so called Pythagorean Triple, then you can "see" the simularity between the numbers.

Instead of 5, a diagonal of 10 is given (factor of 2 bigger).

Instead of 4, the height of 8 is given (factor of 2 bigger). By scaling the Pythagorean Triple 3 4 5 by a factor of 2, you get the numbers 6 8 10. Could it be, that the number we need to find, is six?

Try to verify, by calculating the missing number (which is the length of the rectangle we are looking for).

a² + b² = c²

a = length (and is unknown)

b = height = 8

c = hypothenusa/diagonal = 10

Substitute the numbers given:

a² + 8² = 10²

Subtract 8² left and right of the = sign.

a² +8² -8² = 10² - 8²

a² + 0 = 100 - 64

a² = 36

a = + - √36

a = + - 6

EXTRA:

You can ignore the -√36 = -6 part of the solution, because a length of -6 has no meaning here.

a = 6

So, the length of the triangle is 6 and thus, the length of the rectangle is also 6.

Suppose the speeds of vehicles traveling on a highway are normally distributed and have a known population standard deviation of 7 miles per hour and an unknown population mean. A random sample of 32 vehicles is taken and gives a sample mean of 64 miles per hour. Find the margin of error for the confidence interval for the population mean with a 98% confidence level.

Answers

Answer:

2.88

Step-by-step explanation:

Data provided in the question

[tex]\sigma[/tex] = Population standard deviation = 7 miles per hour

Random sample = n = 32 vehicles

Sample mean = [tex]\bar X[/tex] = 64 miles per hour

98% confidence level

Now based on the above information, the alpha is

= 1 - confidence level

= 1 - 0.98

= 0.02

For [tex]\alpha_1_2[/tex] = 0.01

[tex]Z \alpha_1_2[/tex] = 2.326

Now the margin of error is

[tex]= Z \alpha_1_2 \times \frac{\sigma}{\sqrt{n}}[/tex]

[tex]= 2.326 \times \frac{7}{\sqrt{32}}[/tex]

= 2.88

hence, the margin of error is 2.88

Answer:

2.879 (rounded 3 decimal places)

Step-by-step explanation:

Suppose that the thickness of one typical page of a book printed by a certain publisher is a random variable with mean 0.1 mm and a standard deviation of 0.002 mm. A new book will be printed on 500 sheets of this paper. Approximate the probability that the

Answers

Answer:

The probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm is 0.97.

Step-by-step explanation:

The complete question is:

Suppose that the thickness of one typical page of a book printed by a certain publisher is a random variable with mean 0.1 mm and a standard deviation of 0.002 mm Anew book will be printed on 500 sheets of this paper. Approximate the probability that the thicknesses at the entire book (excluding the cover pages) will be between 49.9 mm and 50.1 mm. Note: total thickness of the book is the sum of the individual thicknesses of the pages Do not round your numbers until rounding up to two. Round your final answer to the nearest hundredth, or two digits after decimal point.

Solution:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e S, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 [tex]\mu_{S}=n\mu[/tex]

And the standard deviation of the distribution of the sum of values of X is given by,  

[tex]\sigma_{S}=\sqrt{n}\sigma[/tex]

The information provided is:

[tex]n=500\\\mu=0.1\\\sigma=0.002[/tex]

As n = 500 > 30, the central limit theorem can be used to approximate the total thickness of the book.

So, the total thickness of the book (S) will follow N (50, 0.045²).

Compute the probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm as follows:

[tex]P(49.9<S<50.1)=P(\frac{49.9-50}{0.045}<\frac{S-E(S)}{SD(S)}<\frac{50.1-50}{0.045})[/tex]

                               [tex]=P(-2.22<Z<2.22)\\\\=P (Z<2.22)-P(Z<-2.22)\\\\=0.98679-0.01321\\\\=0.97358\\\\\approx 0.97[/tex]

Thus, the probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm is 0.97.

Fill in the blanks.

In a normal distribution, ____________ percent of the data are above the mean, and___________ percent of the data are below the mean. Similarly, _____________ percent of all data points are within 1 standard deviation of the mean, ___________percent of all data points are within 2 standard deviations of the mean, and___________ percent are within 3 standard deviations of the mean.

Answers

Answer:

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Also:

The normal distribution is symmetric, which means that 50% of the data is above the mean and 50% is below.

Then:

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.9 percent are within 3 standard deviations of the mean.

The normal distribution is a probability distribution that is important in many areas. It is, in fact, a family of distributions of the same form, each with different location and scale parameters: the mean and standard deviation respectively. The standard normal distribution is the normal distribution with mean equal to zero, and standard deviation equal to one. The shape of its probability density function is similar to that of a bell.

Learn more in https://brainly.com/question/12421652

A large school district notices that about 26% of its sophomore students fail Algebra I. An online education supplier suggests the district try its new technology software, which is designed to improve Algebra 1 skills and, thus, decrease the number of students who fail the course. The new technology software is quite expensive, so the company offers a free, one-year trial period to determine whether the Algebra 1 pass rate improves. If it works, the district will pay for continued use of the software. What would happen if the school district makes a Type I error

Answers

Answer:

In the case of a Type I error, the null hypothesis would be wrongly rejected and the school district will conclude that the new technology is effective when it is not.

They will start to pay for the software when in fact it does not improve Algebra 1 skills.

Step-by-step explanation:

A Type I error happens when a true null hypothesis is rejected.

The probability of a Type I error is equal to the significance level, as it is the probabilty of getting an sample result with low probability but only due to chance, as the null hypothesis is in fact true.

In this scenario, the null hypothesis would represent the claim that the new technology does not make significant improvement.

In the case of a Type I error, this null hypothesis would be wrongly rejected and the school district will conclude that the new technology is effective when it is not.

They will start to pay for the software when in fact it does not improve Algebra 1 skills.

7. Defects in poured metal caused by contamination follows a Poisson distribution with average number of occurrences being 2 per cubic millimeter. What is the probability that there will be at least three defects in a randomly selected cubic millimeter of this metal

Answers

Answer:

[tex]P(x\geq 3)=0.3233[/tex]

Step-by-step explanation:

If the number of defects in poured metal follows a Poisson distribution, the probability that x defects occurs is:

[tex]P(x)=\frac{e^{-m}*(m)^{x}}{x!}[/tex]

Where x is bigger or equal to zero and m is the average. So replacing m by 2, we get that the probability is equal to:

[tex]P(x)=\frac{e^{-2}*(2)^{x}}{x!}[/tex]

Finally, the probability that there will be at least three defects in a randomly selected cubic millimeter of this metal is equal to:

[tex]P(x\geq 3)=1-p(x\leq 2)\\[/tex]

Where [tex]P(x\leq 2)=P(0)+P(1)+P(2)[/tex]

So, P(0), P(1) and P(2) are equal to:

[tex]P(0)=\frac{e^{-2}*(2)^{0}}{0!}=0.1353\\P(1)=\frac{e^{-2}*(2)^{1}}{1!}=0.2707\\P(2)=\frac{e^{-2}*(2)^{2}}{2!}=0.2707[/tex]

Finally, [tex]P(x\leq2)[/tex] and [tex]P(x\geq3)[/tex] are equal to:

[tex]P(x\leq 2)=0.1353+0.2707+0.2707=0.6767\\P(x\geq 3)=1-0.6767=0.3233[/tex]

a personality test maybe given to assess what

Answers

Answer:

A personality test may be given to assess individual behavior patterns. A personality test may be given to assess individual behavior patterns. This answer has been confirmed as correct and helpful.

Step-by-step explanation:

hopes this helps

Answer:

Interests, values, skill set and basic personality

Step-by-step explanation:

Personality tests are mostly used as an assessment tool be HR managers and employers during the interview process. They can provide a potential employer with information about your interests, values, skill set and even basic personality, which can be very useful to help an employer make a decision about whether you are the best fit for a position.

I hope this helped. I am sorry if you get this wrong.

Help asap giving branlist!!

Answers

Answer:

the answer is right below the picture sir ;-;

Step-by-step explanation:

The amount of saturated fat in a daily serving of a particular brand of breakfast cereal is normally distributed with mean 25 g and standard deviation 4 g.

a. Find the sampling distribution of the daily average saturated fat intake over a 30-day period (one month). Include the mean and standard deviation in your answer, as well as the name of the distribution.

b. What is the probability that the average daily saturated fat intake for the month was more than 27 g?

Answers

Answer:

a) [tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [/tex]

And replacing we got:

[tex]\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730) [/tex]

b) [tex] z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739[/tex]

And using the normal standard distribution table and the complement rule we got:

[tex] P(z>2.739) =1- P(z<2.739) = 1-0.997= 0.003[/tex]

Step-by-step explanation:

From the info given if we define the random variable X as "amount of saturated fat in a daily serving of a particular brand of breakfast cereal " we know that the distribution of X is given by:

[tex] X \sim N(\mu =25, \sigma =4)[/tex]

Part a

For this case the sample size would be n =30 and then the distribution for the sample mean would be given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [/tex]

And replacing we got:

[tex]\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730) [/tex]

Part b

We want to find this probability:

[tex] P(\bar X >27)[/tex]

And we can use the z score formula given by:

[tex] z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And replacing we got:

[tex] z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739[/tex]

And using the normal standard distribution table and the complement rule we got:

[tex] P(z>2.739) =1- P(z<2.739) = 1-0.997= 0.003[/tex]

Flight 4581 travels daily from Pittsburgh to San Antonio. The flight is due into San Antonio at 5:07 p.m. The following list gives the Flight 4581 arrival time relative to 5:07 p.m. (in minutes) for a selection of 9 days. (A negative number means that the flight arrived early.) 21, 39, 37, 25, 6,-6, -4, 40, 37 Send data to Excel
(a) What is the mean of this data set? If your answer is not an integer, round your answer to one decimal place. an integer, round your answer to one decimal place.
zero modes
(b) How man ndicate the number of mo vasluers) of the mode modes does the data set have, and what are eir values?

Answers

Question:

Flight 4581 travels daily from Pittsburgh to San Antonio. The flight is due into San Antonio at 5:07 p.m. The following list gives the Flight 4581 arrival time relative to 5:07 p.m. (in minutes) for a selection of 9 days. (A negative number means that the flight arrived early.) 21, 39, 37, 25, 6,-6, -4, 40, 37 Send data to Excel

(a) What is the mean of this data set? If your answer is not an integer, round your answer to one decimal place. an integer, round your answer to one decimal place.

b) How many modes does the data set have? and what are their values

Answer:

a) 21.2

b) Value of mode = 37

It contains just one mode

Step-by-step explanation:

Given:

x = 21, 39, 37, 25, 6,-6, -4, 40, 37

n = 9

a) Find the mean

Mean is the average value of a dataset.

Mean = Σx/n

Mean = [tex] \frac{21+39+37+25+6+(-6)+(-4)+40+37}{n} [/tex]

[tex] = \frac{195}{9} [/tex]

[tex] = 21.667 [/tex]

The question says one decimal place.

Therefore, mean = 21.7

b) The mode of a dataset is the value that appears most frequently.

We have the following datasets:

21, 39, 37, 25, 6,-6, -4, 40, 37

The value that appears most frequently here is 37.

37 appeared twice while the rest appeared just once.

Therefore the dataset contains just one mode

EXREAMLY URGENT!! WILL FOREVER THANK YOU!!!! PLS JUST TAKE A LOOK!!!!!

17. Find the measure of DE

A) 14.5
B) 13.4
C) 12.3
D) 15.9

Answers

Answer:

C. 12.3

Step-by-step explanation:

We should use Law of Cosines: c² = a² + b² -2abcosC

If that is the case, then EF is a, DF is b, and ∠F is c. We then plug the known variables in:

c² = 12² + 13² - 2(12)(13)cos59°

Plug that into the calc and you should get 12.2313, rounded to 12.3 as your final answer!

There are 748 identical plastic chips numbered 1 through 748 in a box. What is the probability of reaching into the box and randomly drawing the chip numbered 513? Express your answer as a simplified fraction or a decimal rounded to four decimal places.

Answers

Answer:

1/748 or about 0.0013

Step-by-step explanation:

Since there is an exactly equal probability of drawing any of the chips, the probability of drawing the one numbered 513 is:

[tex]\dfrac{1}{748}\approx 0.0013[/tex]

Hope this helps!

The weight of an organ in adult males has a bell shaped distribution with a mean of 325 grams and a standard deviation of 50 grams. (A) about 99.7% of organs will be between what weights? (B) what percentage of organs weighs between 275 grams and 375? (C) what percentage of organs weighs between 275 grams and 425 grams?

Answers

Answer:

A)

The number of weights of an organ in adult males = 374.85

B)

The percentage of organs weighs between 275 grams and 375

P(275≤x≤375) = 0.6826 = 68%

C)

The percentage of organs weighs between 275 grams and 425

P(275≤x≤375) = 0.8185 = 82%

Step-by-step explanation:

A)

Step(i):-

Given mean of the normal distribution = 325 grams

Given standard deviation of the normal distribution = 50 grams

Given Z- score = 99.7% = 0.997

[tex]Z = \frac{x-mean}{S.D} = \frac{x-325}{50}[/tex]

[tex]0.997 = \frac{x-325}{50}[/tex]

Cross multiplication , we get

[tex]0.997 X 50= x-325[/tex]

x - 325 = 49.85

x = 325 + 49.85

x = 374.85

The number of weights of an organ in adult males = 374.85

Step(ii):-

B)

Let X₁ = 275 grams

[tex]Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{275-325}{50} = -1[/tex]

Let X₂ = 375 grams

[tex]Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{375-325}{50} = 1[/tex]

The probability of organs weighs between 275 grams and 375

P(275≤x≤375) = P(-1≤Z≤1)

                       = P(Z≤1)- P(Z≤-1)

                      =  0.5 + A(1) - ( 0.5 - A(-1))

                     = A(1) + A(-1)

                    = 2 A(1)

                    = 2 × 0.3413

                    = 0.6826

The percentage of organs weighs between 275 grams and 375

P(275≤x≤375) = 0.6826 = 68%

C)

Let X₁ = 275 grams

[tex]Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{275-325}{50} = -1[/tex]

Let X₂ = 425 grams

[tex]Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{425-325}{50} = 2[/tex]

The probability of organs weighs between 275 grams and 425

P(275≤x≤425) = P(-1≤Z≤2)

                       = P(Z≤2)- P(Z≤-1)

                      =  0.5 + A(2) - ( 0.5 - A(-1))

                     = A(2) + A(-1)

                    = A(2) + A(1)       (∵A(-1) =A(1)

                    = 0.4772 + 0.3413

                    = 0.8185

The percentage of organs weighs between 275 grams and 425

P(275≤x≤375) = 0.8185 = 82%

Please answer this correctly

Answers

Answer:

New mean will be( 8 + 3 + 4 + 2 + 8) / 2

= 25/5 = 5 (old was 6)

New median will be 4 (old was 8)

Answer:

Mean, Mean would change the most the original mean was 28.4, after replacing 9 with 4 it changed to 23.4. With the difference of 5.

Step-by-step explanation:

Mode will stay the same with the repetition of 8, median will be a 4 difference from 8 to 4

how many lines of symmetry can a parallelogram have? explain.

Answers

Answer:

0

Step-by-step explanation:

The lines of symmetry of a parallelogram must either be a diagonal of the parallelogram or must be bisectors of opposite sides. There is no way to draw such lines through a general parallelogram and have it produce mirror images on either side of the line. Thus, it has no lines of symmetry.

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