Your cardiovascular system gets better when you increase the time and intensity of your workouts. What should the word in italics be replaced with to make this sentence more precise?

Answer:

centripetal force

Explanation:

because this force always compels the body to move in circle

Answer:

Mass

Explanation: the more mass the more GPE

Apart from the height above the ground, the object's mass on which the amount of gravitational potential depends.

The law of gravity gives rise to the generic term for gravitational potential energy, which is equal to the effort made to defy gravity in order to move a mass to a specific location in space. It makes logical to choose the gravitational potential energy zero at an infinite distance away because, due to the inverse square nature of the gravity force, the force approaches zero for huge distances. Since gravity performs positive work as a mass approaches a planet, the gravitational potential energy is then negative. When a mass approaches a huge body, it enters a "bound state," where it is trapped until an external source of energy enables it to break free.

There is gravitational potential energy in any object raised above the earth ( or GPE). The mass and height of an object above the surface of the Earth determine how much gravitational potential energy it has.

To get more information about gravitational potential energy :

https://brainly.com/question/13003047

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Answer:

Newton Second

Explanation:

The SI unit of impulse in Newton Second (N.s)

Answer:

The time taken for the light to travel from the earth to the sun = 496.67 seconds

Explanation:

Estimated distance of the earth to the sun = 149000000km

Speed of light =  300000km/s

Time taken for the light to travel from the sun to the earth = ?

Speed = Distance/time

time = Distance/speed

time = 149000000/300000

time = 496.67 s

The time taken for the light to travel from the earth to the sun = 496.67 seconds

Answer:

a) F = 40 N

b) It is acting towards left

c) a = 10 m/s²

Explanation:

As the block of mass and its forces are not shown, the question is incomplete.

First we attach the diagram of the attached question (See below)

We can see in the diagram that there are total of 5 forces acting on that block. Consider the forces acting towards right to be positive and the forces acting towards left be negative (or vice versa, the answer would be same). Let them be:

F₁ = 10 N

F₂ = 17 N

F₃ = 21 N

F₄ = -35 N

F₅ = -53 N

To find resultant force, we'll add all of the 5 forces.

Resultant Force = F₁ + F₂ + F₃ + F₄ + F₅

Resultant Force = 10 + 17 +21 - 35 - 53

Resultant Force = -40 N

As the resultant force has a negative sign, and previously we stated that the forces acting towards left are negative, so the Resultant Force is acting in the left direction.

We know that

F = (m)(a)

Where F is the resultant force we found. Resultant Force was -40N , where negative sign only represents the direction. We'll consider only the magnitude which is 40N, where m is the mass of the block which is 4 kg. Substitute in the equation.

40 = (4)(a)

a = (40)(4)

a = 10 m/s² (in left direction)

Answer:

B. Cant stop things from going wrong.

Explanation:

To me it's the only reasonable answer...

Answer:

60

Explanation:

60secs = 1 minute

if you want to show you work further then

10 divided by 10 = 1

so each second is 1 heart beat

so then just 60 divided by 10 equals 6

so then just do 6 times 10 equals 60 beats

Answer:

Net force = 21.12 N

angle for the force α = 45°

Explanation:

In this problem, we will take the left as the negative x-axis, the right as the positive x-axis, and the upward direction as the positive y-axis.

The 20 N force to the left has an x component of -20 N, and y component of 0 N

The 35 N force to the right has a x component of 35 N, and a y component of 0 N

The 15 N upwards has an x component of 0 N, and a y component of 15 N

We resolve the forces into the x and y components.

for the x component Fx

Fx = -20 + 35 + 0 = 15 N

For the y component Fy

Fy = 0 + 0 + 15 = 15 N

Net force Fn = [tex]\sqrt{Fx^{2} + Fy^{2} }[/tex]

[tex]Fn = \sqrt{(15)^{2} + (15^{2} ) }[/tex]

Net force Fn = 21.21 N

for the angle,

[tex]tan\alpha = \frac{Fy}{Fx} = \frac{15}{15}[/tex]

[tex]tan\alpha = 1[/tex]

α = [tex]tan^{-1}[/tex] 1

angle for force α = 45°

Answer:

Explanation:

Here,

m = 3 Kg

a = 0 m/s^2 (velocity is constant so the acceleration is zero)

We have,

F = ma

or, F = 3 x 0

or, F = 0 N

Constant velocity can always be associated with a zero net force.

Explanation:

Newton's first law: Inertia

"An object in motion stays in motion, and an object at rest stays at rest, until acted upon by an unbalanced force."

This means that an object does not speed up, slow down, or change direction, unless the forces acting on it are unbalanced.

Newton's second law: Net force

∑F = ma

The net force (the sum of the forces acting on an object) is equal to the object's mass times its acceleration.

Newton's third law: Action/reaction

"For every action, there is an opposite and equal reaction."

This means that when one object pushes on another object (action), the second object pushes back with an equal and opposite force (reaction).

Answer:

(a) 4.82 m/s

(b) The simmer need to head 57.05° upstream of the river to reach a point directly opposite the river

(c) 4.024 seconds

Explanation:

The parameters given are;

The speed of the swimmer = 5.75 m/s

The direction of the resultant motion = 40° downstream

The speed of the current = x m/s

Therefore in a given second, we have that the swimmer moves 5.75 meters across the river while the current moves x meters downstream

Which gives;

[tex]tan(40^{\circ}) = \dfrac{x}{5.75}[/tex]

x = 5.75 × tan(40°) = 4.82 m/s

The speed of the current = 4.82 m/s

(b) If the swimmer swims at a direction θ to reach a point, p, directly opposite the river, we have;

The resultant speed across the river will be the swimmer's swimming speed which is 5.75 m/s

5.75² = y² + 4.82²

y = √(5.75² - 4.82²) = √9.78

tan(θ) = 4.82/(√9.78) = 1.54

θ = tan⁻¹(1.54) = 57.05°

The simmer need to swim 57.05° upstream to reach a point directly opposite the river

(c) If the river is 15 m wide, we have;

Time (t) = Distance/speed

The component of the swimmer's speed directly across the river = 5.75/(tan(57.05°)

The component of the swimmer's speed directly across the river = 3.73 m/s

The time, t, to cross the river is therefore;

t = 15/3.73 = 4.024 seconds

Answer:

Energy

Explanation:

The stronger the force it has the more quickly the bonds will break

As there will be more energy they will vibrate more and the bonds will separate easily..

Answer:

Diffraction of light shows that light behaves like a wave. It involves the change in the direction of waves while passing through any obstacle. Diffracted light can produce fringes of light, dark or colored bands (Just like the rainbow which is also a light wave). Diffracted light has certain wavelength, amplitude , frequency and speed which are the basic characteristics of being a wave which shows that light actually behaves like a wave.

Answer:

 total energy is 14.12kj

energy at 85% is 12kJ

Explanation:

Answer:

Explanation:

distance = speed * time  

distance = 21000 * 5 = 105000 km

please mark me as Brainliest

Answer:

Acceleration of the apple towards the earth is: 9.7705 m/s2.

Acceleration produced on earth towards the apple

[tex]0.325*10^{-24} \ \ m/s2.[/tex]

Explanation:

Given :

[tex]m = 200 g[/tex]

We have to convert into the kg ,

so

[tex]m=0.2 kg[/tex]

M=[tex]6*10^{24}[/tex] kg

[tex]R=6.4*10^{6} m[/tex]

[tex]G= 6.67*10^{-11} \ Nm^{2} kg-2[/tex]

As the gravitational force is existing among the earth and the apple

so

[tex]F=\frac{GMm}{R^{2} }[/tex]

Putting the value of G,M,m and [tex]R^{2}[/tex], we get

[tex]\frac{6.67*10^{-11} *6*10^{24} *0.2 }{(6.4*10^{6} )^{2} } \\\\F= 1.9541\ N[/tex]

Consider a1 and a2 be a acceleration due to the gravitational force of earth attraction created on the apples

F= a1 *m

[tex]a1\ =\ \frac{F}{m}[/tex]

a1=[tex]\frac{1.9541}{0.2}[/tex]

[tex]a1=9.7705 \ m/s2[/tex]

Acceleration of the apple towards the earth is: 9.7705 m/s2.

again

[tex]F= a2 *M[/tex]

a2=[tex]\frac{F}{M}[/tex]

[tex]a2=\frac{ 1.9541}{6**10^{24} } \\a2=0.325* 10^{-24}\ m/s2[/tex]

So, Acceleration produced on earth towards the apple

[tex]0.325*10^{-24} \ \ m/s2.[/tex]

Answer:

A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N.

Explanation:

This is because at terminal velocity, the ball stops accelerating and the net force on the ball is zero. For the net force to be zero, equal and opposite forces must act on the ball, so that their resultant force is zero. That is F₁ + F₂ = 0 ⇒ F₁ = -F₂

Since F₁ = 20 N, then F₂ = -F₁ = -20 N

So, if F₁ points upwards since it is positive, then F₂ points downwards since it is negative.

So, a free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N best describes the ball falling at terminal velocity.

Answer:

b

Explanation:

Answer:

Explanation:

MASS of a body indicates the quantity or amount of matter contained in it.S.I, unit of mass is kg

Answer:

Metre, kilogram, second, ampere, kelvin, candela, and mole

Explanation:

A base unit (also referred to as a fundamental unit) is a unit adopted for measurement of a base quantity

[tex]answer \\ = 50 \: m / s \\ solution \\ distance \: travelled\: by \: bus = 1.5 \: km \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1.5 \times 1000 \: m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1500 \: m \\ time \: = 30 \: seconds \\ speed = \frac{distance}{time} \\ \: \: \: \: \: \: \: \: \: \: = \frac{1500m}{30s } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 50 \: m/s \\ hope \: it \: helps[/tex]

Answer:

C. 50 m/s

Explanation:

Given:

Distance = 1.5 km = 1500 m

Time = 30 sec

Required:

Speed = ?

Formula

Speed = Distance / Time

Solution:

Putting the given in the formula

Speed = 1500/30

Speed = 50 m/s

Answer: A) O N

Explanation:

An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.

Answer: 5.96m/s

Explanation:

Given the following :

Mass of car (m) = 1500kg

Velocity (V) = 5.25m/s

Forward force of engine = 1250N

Diatance moved = 4.8m

Final Velocity =?

Final kinetic energy = Initial kinetic energy + work done by engine

Initial kinetic energy = 0.5 × mass × velocity^2

Initial kinetic energy = 0.5 × 1500 × 5.25^2

Initial kinetic energy = 20671.875 J

Work done by engine = Force × distance

Work done by engine = 1250 × 4.8 = 6000J

Final kinetic energy = (20671.875 + 6000) J

= 26671.875 J

From kinetic energy = 0.5mv^2

26671.875 = 1/2 × 1500 × v^2

53343.75 = 1500v^2

v^2 = 35.5625

v = sqrt(35.5625)

v = 5.96m/s

Answer:

9.93 m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 1500 Kg

Initial velocity (u) = 5.25 m/s

Force (F) = 1250 N

Distance (s) = 42.8 m

Final velocity (v) =...?

Next, we shall determine the acceleration of car. This can be achieved as shown below:

Force (F) = mass (m) x acceleration (a)

1250 = 1500 x a

Divide both side by 1500

a = 1250/1500

a = 0.83 m/s²

Therefore, the acceleration of the car is 0.83 m/s²

Now, we can determine the final velocity of car as shown below:

Initial velocity (u) = 5.25 m/s

Distance (s) = 42.8 m

Acceleration (a) = 0.83 m/s²

Final velocity (v) =...?

v² = u² + 2as

v² = (5.25)² + 2 x 0.83 x 42.8

v² = 27.5625 + 71.048

v² = 98.6105

Take the square root of both side

v = √98.6105

v = 9.93 m/s

Therefore, the final velocity of the car is 9.93 m/s

Answer:

9.93

Explanation:

too easy, just use a calculator lol

Answer:

Geographical location, and time and weather conditions

Answer:

Georgraphical location and weather conditions

Explanation:

Setting is where the story takes place so the location would be vital and same with weather conditions because it determines what the character(s) do

They are used to see round dangerous bends

Answer:

4

Explanation:

hope this helps

Answer:

The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.

Explanation:

Edge 2021

Answer:

The second law of motion states that the force of an object is equal to its mass times its

acceleration.

o A change in motion occurs only if a net force is exerted on an object.

o A net force changes the velocity of the object, and causes it to accelerate.

o If an object is acted upon by a net force, the change in velocity will be in the

direction of the net force.

o The acceleration of an object depends on its mass.

o The more mass an object has or the more inertia it has, the harder it is to

accelerate.

o More mass means less acceleration if the force acting on the objects is the same.

Explanation:

Explanation:

The force exerted by the earth on a falling baseball is smaller than the force exerted by the earth on a falling bowling ball.  However, since the baseball has less mass than the bowling ball, the two accelerate at the same rate.  This is known as Galileo's gravity experiment, but it also demonstrates Newton's second law.

When a bowling ball hits a pin, the pin pushes back with equal and opposite force.  Because the bowling ball has a large mass, the acceleration caused by the force is small.  Since the pin has a small mass, the acceleration caused by the force is large.

Answer:

A) 0 V

B) -117 kV

C) -0.468 J

Explanation:

q1=+2.00μC  q2=−2.00μC q3 = -4.00 μC

A) The electric potential at point a due to q1 and q2 ([tex]V_a[/tex]) is given as:

[tex]V_a=k\Sigma \frac{q}{r_i} = k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )\\ but\ r_2=r_1=d.\ Therefore\\V_a=k(\frac{q_1}{d}+\frac{q_2}{d} )=k(\frac{2}{d}-\frac{2}{d} )=0[/tex]

B) he electric potential at point b due to q1 and q2 ([tex]V_b[/tex]) is given as:

[tex]V_b=k\Sigma \frac{q}{r_i} = k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )\\ but\ r_2=4.5 cm=0.045m,\ r_1=\sqrt{0.045^2+0.045^2}= 0.0636.\ Therefore\\V_b= k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )= 9*10^{9}(\frac{2*10^{-6}}{0.0636}-\frac{2*10^{-6}}{0.045} )=-117\ kV[/tex]

C) The work done on q3 by the electric forces exerted by q1 and q2 (W) is given by:

[tex]W=q_3(V_a - V_b)=-4*10^{-6}(0-(-117*10^3))=-0.468\ J[/tex]

Answer: 1.5 × 10^-17

Explanation:

Given the following :

Frequency(f) = 2.2 × 10^16 Hz

Planck's constant(h) = 6.63 × 10^-34

The energy of a photon 'E' is given as the product of frequency and the planck's constant

E = hf

E = (6.63 × 10^-34) × (2.2 × 10^16)

E = 6.63 × 2.2 × 10^(-34 +16)

E = 14.586 × 10^-18

E = 1.4586 × 10^-17

E = 1.5 × 10-17 (2 S. F)

Answer:

C. 1.5 × 10–16 J

Explanation:

Answer:

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

Explanation:

El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:

Distancia horizontal (en metros)

[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \theta[/tex]

Donde:

[tex]x_{o}[/tex] - Posición horizontal inicial, medida en metros.

[tex]t[/tex] - Tiempo, medido en segundos.

[tex]v_{o}[/tex] - Velocidad inicial, medida en metros por segundo.

[tex]\theta[/tex] - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.

Distancia vertical (en metros)

[tex]y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}[/tex]

Donde:

[tex]y_{o}[/tex] - Posición vertical inicial, medida en metros.

[tex]g[/tex] - Constante gravitacional, medida en metros por segundo al cuadrado.

Partiendo de la primera ecuación, se despeja el tiempo:

[tex]t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}[/tex]

Si [tex]x = 31\,m[/tex], [tex]x_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex] and [tex]\theta = 33^{\circ}[/tex], entonces:

[tex]t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}[/tex]

[tex]t = 0.924\,s[/tex]

La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si [tex]y_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]t = 0.924\,s[/tex] y [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], entonces:

[tex]y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}[/tex]

[tex]y = 15.943\,m[/tex]

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.