Answer:
find 2 then from 2 and 3 find about 2/3 of the way from 2-3 and plot it there
Step-by-step explanation:
We can plot 2 2/3 on a number line by using the given method.
To plot 2 2/3 on a number line, we have to :
Determine the interval on the number line. For example, if the number line spans from -5 to 5, you need to identify where 2 2/3 falls within that range.
Divide the whole number part of the mixed number, which is 2, into equal intervals on the number line.
In this case, if the number line spans from -5 to 5, divide it into 10 equal intervals.
Place a point on the number line at the appropriate interval corresponding to the whole number part of the mixed number. In this case, place a point at the interval labeled 2.
Move to the right from the point corresponding to the whole number part. Now, focus on the fractional part, which is 2/3.
Divide the space between two intervals into three equal parts since the fractional part is 2/3. Each part represents 1/3 of the interval.
Count two of the three equal parts from the point corresponding to the whole number part (2). Place a point at this location.
The point you placed in step 6 represents 2 2/3 on the number line.
You can label it as 2 2/3 or use a decimal approximation if necessary.
By following these steps, you can plot 2 2/3 on a number line accurately.
To learn more on number line click:
brainly.com/question/29162579
#SPJ2
Please answer this correctly
Answer:
The number of employees classified into groups as shown below:
1 - 10: 3 6 (2companies)
11-20: 16 (1 company)
21-30: 25, 26, 27 (3 companies)
31-40: 34, 35, 35, 35, 36 (5 companies)
41-50: 41, 43, 48, 48 (4 companies)
Hope this helps!
Answer:
11-20 is 1
31-40 is 5
Step-by-step explanation:
Just count the amount
Hope that helps :D
determine whether these two functions are inverses.
Answer:
No The reactions are not inverses to each other
Step-by-step explanation:
f(x) = 3x + 27
Let f(x) be y
y= 3x+27
subtracting 27 on both sides
3x = y - 27
x= (y-27)/3
= y/3 - 9
inverse function is x/3 -9 not x/3 + 9
Therefore, not an inverse
Hope it helps...
Pls help marking Brainliest! (x-1)(x-1)=?
Answer:
Brainleist!Step-by-step explanation:
x^2-2x+1thats the answer...
just: Expand the polynomial using the FOIL method.
Answer:
(x-1)(x-1)=(x-1)² because it's the same thing multiplied by itself
Using FOIL method:
(x-1)(x-1)=
x²-x-x+1=
x²-2x+1
Justin spent $23 on fruit at grocery store. He spent a total of $25 at the store. What percentage of the total did he spend on fruit?
Step-by-step explanation:
In my opinion maybe he has spent 98%
At the U.S. Open Tennis Championship a statistician keeps track of every serve that a player hits during the tournament. The statistician reported that the mean serve speed was 100 miles per hour (mph) and the standard deviation of the serve speeds was 15 mph. Assume that the statistician also gave us the information that the distribution of serve speeds was mound- shaped and symmetric. What percentage of the player's serves were between 115 mph and 145 mph
Answer:
15.74% of the player's serves were between 115 mph and 145 mph
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 100, \sigma = 15[/tex]
What percentage of the player's serves were between 115 mph and 145 mph
This is the pvalue of Z when X = 145 subtracted by the pvalue of Z when X = 115.
X = 145
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{145 - 100}{15}[/tex]
[tex]Z = 3[/tex]
[tex]Z = 3[/tex] has a pvalue of 0.9987
X = 115
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{115 - 100}{15}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a pvalue of 0.8413
0.9987 - 0.8413 = 0.1574
15.74% of the player's serves were between 115 mph and 145 mph
In general, shopping online is supposed to be more convenient than going to stores. However, according to a recent Harris Interactive poll, 87% of people have experienced problems with an online transaction (The Wall Street Journal, October 2, 2007). Forty-two percent of people who experienced a problem abandoned the transaction or switched to a competitor′s website. Fifty-three percent of people who experienced problems contacted customer-service representatives.
a. What percentage of people did not experience problems with an online transaction?
b. What percentage of people experienced problems with an online transaction and abandoned the transaction or switched to a competitor′s website?
c. What percentage of people experienced problems with an online transaction and contacted customer-service representatives?
Answer:
a) 13% of people did not experience problems with an online transaction.
b) 36.54% of people experienced problems with an online transaction and abandoned the transaction or switched to a competitor′s website
c) 46.11% of people experienced problems with an online transaction and contacted customer-service representatives.
Step-by-step explanation:
a. What percentage of people did not experience problems with an online transaction?
87% of people have experienced problems with an online transaction. So 100 - 87 = 13% of people did not experience problems with an online transaction.
b. What percentage of people experienced problems with an online transaction and abandoned the transaction or switched to a competitor′s website?
87% of people have experienced problems with an online transaction. Forty-two percent of people who experienced a problem abandoned the transaction or switched to a competitor′s website.
Then:
0.87*0.42 = 0.3654
36.54% of people experienced problems with an online transaction and abandoned the transaction or switched to a competitor′s website.
c. What percentage of people experienced problems with an online transaction and contacted customer-service representatives?
87% of people have experienced problems with an online transaction. Fifty-three percent of people who experienced problems contacted customer-service representatives.
Then:
0.87*0.53 = 0.4611
46.11% of people experienced problems with an online transaction and contacted customer-service representatives.
B
Round your answer to the nearest hundredth.
A
9
B
5
Answer:
56.25°
Step-by-step explanation:
The definition of the cosine function tells you that
cos(B) = BC/BA
B = arccos(BC/BA) = arccos(5/9)
B ≈ 56.25°
A restaurant chain is measuring the levels of arsenic in chicken from its suppliers. The question is whether there is evidence that the mean level of arsenic is greater than 80 ppb, so we are testing vs , where represents the average level of arsenic in all chicken from a certain supplier. It takes money and time to test for arsenic so samples are often small. A sample of chickens from one supplier is tested, and the resulting sample mean is . Subtracting 11 from the sample data to move the mean down to the null mean of results in the following data: .
57, 64, 70, 82, 84, 123
Use StatKey or other technology to create the randomization distribution for this test. Find the p-value.
Answer:
The p-value of the test is 0.1515.
Step-by-step explanation:
The hypothesis for the test can be defined as follows:
H₀: The mean level of arsenic is 80 ppb, i.e. μ = 80.
Hₐ: The mean level of arsenic is greater than 80 ppb, i.e. μ > 80.
As the population standard deviation is not known we will use a t-test for single mean.
It is provided that the sample mean was, [tex]\bar X=91[/tex].
The adjusted sample provided is:
S = {57, 64, 70, 82, 84, 123}
Compute the sample standard deviation as follows:
[tex]\bar x=\farc{57+64+70+82+84+123}{6}=80\\\\s=\sqrt{\frac{1}{6-1}\times [(57-80)^{2}+(64-80)^{2}+(70-80)^{2}+...+(123-80)^{2}]}=23.47[/tex]
Compute the test statistic value as follows:
[tex]t=\frac{\bar X-\mu}{\s/\sqrt{n}}=\frac{91-80}{23.47/\sqrt{6}}=1.148[/tex]
Thus, the test statistic value is 1.148.
Compute the p-value of the test as follows:
[tex]p-\text{value}=P(t_{n-1}<t)[/tex]
[tex]=P(t_{6-1}<1.148})\\\\=P(t_{5}<1.148})\\\\=0.1515[/tex]
*Use a t-table.
Thus, the p-value of the test is 0.1515.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
p-value = 0.1515 > α = 0.05
The null hypothesis will not be rejected at 5% level of significance.
Thus, concluding that the mean level of arsenic in chicken from the suppliers is 80 ppb.
How do I solve this problem I am so confused. I would appreciate the help
Answer:
The volume formula for a cylinder is V = πr²h. We are solving for h and we know that V, π and r are 86, 3.14, 3 respectively so we can write:
86 = 3.14 * 3² * h
86 = 28.26 h
h = 3.04
State the size of angle 'n' in the triangle illustrated below.
Answer:
Option B
Step-by-step explanation:
<r = 32 degrees (alternate angles )
<r = <n = 32 degrees (vertical angles)
Find the fifth term of an=(-1)^n/2n-1
a.-1/7 b.-1/9 c.1/9 d.1/7
Answer:
b) -1/9
Step-by-step explanation:
Given
[tex]a_{n} = \frac{(-1)^{n} }{2n-1}[/tex]
First term
[tex]a_{1} = \frac{(-1)^{1} }{2(1)-1} = -1[/tex]
second term
[tex]a_{2} = \frac{(-1)^{2} }{2(2)-1} = \frac{1}{3}[/tex]
Third term
[tex]a_{3} = \frac{(-1)^{3} }{2(3)-1} = \frac{-1}{5}[/tex]
Fourth term
[tex]a_{4} = \frac{(-1)^{4} }{2(4)-1} = \frac{1}{7}[/tex]
Fifth term
[tex]a_{5} = \frac{(-1)^{5} }{2(5)-1} = \frac{-1}{9}[/tex]
Answer:
B
Step-by-step explanation:
right on edge 2021
Margo borrows $1700, agreeing to pay it back with 4% annual interest after 6 months. How much interest
will she pay?
Round your answer to the nearest cent, if necessary.
Answer:
$1733.67
Step-by-step explanation:
Simple interest rate formula: A = P(1 + r)^t
Simply plug in your known variables
A = 1700(1 + 0.04)^0.5
A = 1733.67
Remember that t is time in years.
The length of a human pregnancy is normally distributed with a mean of 270 days with a standard deviation of 8 days. How many days would a pregnancy last for the shortest 15%? Round answer to 2 decimal places. Answer
Answer:
261.71
Step-by-step explanation:
The calculation of days is shown below:-
[tex]X = \mu + Z\sigma[/tex]
where,
Mean = 270
standard deviation is 8
And, the normsinv is -1.036
Now placing these values to the above formula
So, the number of days is
= 270 + (-1.036433389) × 8
= 270 + (-8.29146711)
= 261.708533
or
= 261.71
Therefore for computing the number of days we simply applied the above formula and for (-1.036433389) please find in the attachment.
Where is my phone? I seem to have lost my phone. I know where I last saw it but it has been moved since then and I need help to locate it. It started at the following coordinates A (14, -12); B (14, -19); C (10, -19); D (10, -14); E (13, -14); F (13, -12). My Mom told me she translated it 6 units to the left Then my little brother said he had reflected it over the Y-axis My friend many found it and translated it 9 units up Dad said he tripped over it and reflected it over the X-axis My sister then rotated it 900 clockwise Uncle Jose translated it 5 units left and 4 units down Cousin Michelle then said she rotated it 900 clockwise Finally my dog picked it up and translated it 5 units down and 10 units to the right Where is my phone? Using the scenario on this page do the following. Graph the preimage using the given points. Label points (A, B, C, ...) Transform the objects using the information provided. Show each transformation and label. (A', B', C', ...) Determine the final location. Write a 2 to 3 sentence explain on how you found the phone location.
Answer:
see attached
Step-by-step explanation:
The attachments show the initial (brown) and final (blue) positions of the phone. The spreadsheet shows all the intermediate locations and the formulas used to determine them.
The two reflections cancel the total of 180° of CW rotation, so the net result is simply a translation. That translation is up by 9 units.
__
Translation up adds to the y-coefficient; translation right adds to the x-coefficient. Down or left use negative values.
90° CW does this: (x, y) ⇒ (y, -x)
Reflection across y does this: (x, y) ⇒ (-x, y)
Reflection across x does this: (x, y) ⇒ (x, -y)
. A foreman for an injection-molding firm admits that on 23% of his shifts, he forgets to shut off the injection machine on his line. Failure to shut down at night causes the machine to overheat, increasing the probability that a defective molding will be produced during the early morning run from 5% to 15%. The plant manager randomly selects a molding from the early morning run and discovers it is defective. What is the probability that the foreman forgot to shut off the machine the previous night?
Answer:
P(F | D) = 47.26%
There is a 47.26% probability that the foreman forgot to shut off the machine the previous night.
Step-by-step explanation:
A foreman for an injection-molding firm admits that on 23% of his shifts, he forgets to shut off the injection machine on his line.
Let F denote the event that foreman forgets to shut off the machine.
Failure to shut down at night causes the machine to overheat, increasing the probability that a defective molding will be produced during the early morning run from 5% to 15%.
Let D denote the event that the mold is defective.
If the foreman forgets to shut off the machine then 15% molds get defective.
P(F and D) = 0.23×0.15
P(F and D) = 0.0345
If the foreman doesn't forget to shut off the machine then 5% molds get defective.
P(F' and D) = (1 - 0.23)×0.05
P(F' and D) = 0.77×0.05
P(F' and D) = 0.0385
The probability that the mold is defective is
P(D) = P(F and D) + P(F' and D)
P(D) = 0.0345 + 0.0385
P(D) = 0.073
The probability that the foreman forgot to shut off the machine the previous night is given by
∵ P(B | A) = P(A and B)/P(A)
For the given case,
P(F | D) = P(F and D)/P(D)
Where
P(F and D) = 0.0345
P(D) = 0.073
So,
P(F | D) = 0.0345/0.073
P(F | D) = 0.4726
P(F | D) = 47.26%
According to the National Association of Theater Owners, the average price for a movie in the United States in 2012 was $7.96. Assume the population standard deviation is $0.50 and that a sample of 30 theaters was randomly selected.
Required:
a. Calculate the standard error of the mean.
b. What is the probability that the sample mean will be less than $7.75?
c. What is the probability that the sample mean will be less than $8.10?
d. What is the probability that the sample mean will be more than $8.20?
Answer:
(a) The standard error of the mean is 0.091.
(b) The probability that the sample mean will be less than $7.75 is 0.0107.
(c) The probability that the sample mean will be less than $8.10 is 0.9369.
(d) The probability that the sample mean will be more than $8.20 is 0.0043.
Step-by-step explanation:
We are given that the average price for a movie in the United States in 2012 was $7.96.
Assume the population standard deviation is $0.50 and that a sample of 30 theaters was randomly selected.
Let [tex]\bar X[/tex] = sample mean price for a movie in the United States
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean price for a movie = $7.96
[tex]\sigma[/tex] = population standard deviation = $0.50
n = sample of theaters = 30
(a) The standard error of the mean is given by;
Standard error = [tex]\frac{\sigma}{\sqrt{n} }[/tex] = [tex]\frac{0.50}{\sqrt{30} }[/tex]
= 0.091
(b) The probability that the sample mean will be less than $7.75 is given by = P([tex]\bar X[/tex] < $7.75)
P([tex]\bar X[/tex] < $7.75) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{7.75-7.96}{\frac{0.50}\sqrt{30} } }[/tex] ) = P(Z < -2.30) = 1 - P(Z [tex]\leq[/tex] 2.30)
= 1 - 0.9893 = 0.0107
The above probability is calculated by looking at the value of x = 2.30 in the z table which has an area of 0.9893.
(c) The probability that the sample mean will be less than $8.10 is given by = P([tex]\bar X[/tex] < $8.10)
P([tex]\bar X[/tex] < $8.10) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{8.10-7.96}{\frac{0.50}\sqrt{30} } }[/tex] ) = P(Z < 1.53) = 0.9369
The above probability is calculated by looking at the value of x = 1.53 in the z table which has an area of 0.9369.
(d) The probability that the sample mean will be more than $8.20 is given by = P([tex]\bar X[/tex] > $8.20)
P([tex]\bar X[/tex] > $8.20) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{8.20-7.96}{\frac{0.50}\sqrt{30} } }[/tex] ) = P(Z > 2.63) = 1 - P(Z [tex]\leq[/tex] 2.63)
= 1 - 0.9957 = 0.0043
The above probability is calculated by looking at the value of x = 2.63 in the z table which has an area of 0.9957.
Rod's quiz grades are 72, 74, 89, and90. What score on a fifth quiz will make his average woz grade at least 84?
Answer: He would need at least a 95
Step-by-step explanation:
First I found the current average by adding 72, 74, 89, and 90 which equals 325.
Second, I worked backwards to see what the sum of his grades had to be by multiplying 84 times 5. 84 times 5 = 420
Now that we have both the current and the target sum, we find the difference by doing 420-325 which equals 95.
Simplify the expression by combining like terms
15 + 12x – 5.2 + 4y - 7
9.8 +12x+y-7
2.8+12x+4y
Select a composite number to break into factors. Continue factoring until all factors are prime
Answer:
2*2 * 2*2 * 2*3
Step-by-step explanation:
96 =16 *6
Break these down, since neither 16 nor 6 are prime
= 4*4 * 2*3
4 in not prime, but 2 and 3 are prime
= 2*2 * 2*2 * 2*3
All of these are prime
Answer:
22, 23
Step-by-step explanation:
Just got it right on edge 2021
Any help would be great
Hey there! :)
Answer:
[tex]-25m^{6}n^{9}[/tex]
Step-by-step explanation:
The product rule means that when multiplying variables with exponents, the exponents must be added together. Therefore:
[tex](-5m^{5}n^{6})(5mn^{3}) =[/tex]
[tex]-25m^{5+1}n^{6+3} =[/tex]
Simplify:
[tex]-25m^{6}n^{9}[/tex]
This is your answer!
What is the equation of the line with an X intercept of negative 2 and Y intercept of one
Answer:
y = 1/2x + 1
Step-by-step explanation:
Step 1: Find slope
(1-0)/(0+2) = 1/2
Step 2: Write equation
y = 1/2x + 1
There are 88 black balls and 88 red balls in an urn. If 33 balls are drawn without replacement, what is the probability that exactly 11 black ball is drawn? Express your answer as a fraction or a decimal number rounded to four decimal places.
Answer:
0.0164 probability that exactly 11 black balls are drawn
Step-by-step explanation:
The balls are drawn without replacement, so we use the hypergeometric distribution to solve this question.
Hypergeometric distribution:
The probability of x sucesses is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of sucesses.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
Total of 88 + 88 = 176 balls, so [tex]N = 176[/tex]
33 balls are drawn, so [tex]n = 33[/tex]
We want 11 black balls(sucesses), so [tex]n = 11[/tex]
There are 88 black balls, so [tex]k = 88[/tex]
Then
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 11) = h(11,176,88,33) = \frac{C_{88,11}*C_{88,22}}{C_{176,33}} = 0.0164[/tex]
0.0164 probability that exactly 11 black balls are drawn
N
Write the rate as a unit rate
729 riders in 9 subway cars
А
The unit rate is
This
(Simplify your answ
riders/car
Answer:
Unit rate = 81 riders/ car.
Step-by-step explanation:
Given
729 riders in 9 cars
we have to find unit rate in terms of riders per car
let the the riders per car (i.e rate) be x.
If there are 9 cars then
total no. of riders in 9 cars = no. of cars * riders per car = 9*x = 9x
given that 729 riders in 9 cars
then
9x = 729
=> x = 729/9 = 81
Thus, riders per car = x = 81.
Unit rate is 81 riders per car.
2.
√3x + 7 + √x + 1 =2
Answer:
x = -1
Step-by-step explanation:
The usual approach to these is to square the radicals until they are gone.
[tex]\displaystyle\sqrt{3x+7}+\sqrt{x+1}=2\\\\(3x+7) +2\sqrt{(3x+7)(x+1)}+(x+1) = 4\qquad\text{square both sides}\\\\2\sqrt{(3x+7)(x+1)}=-4x-4\qquad\text{subtract $4x+8$}\\\\(3x+7)(x+1)=(-2x-2)^2\qquad\text{divide by 2, square again}\\\\3x^2+10x +7=4x^2+8x+4\qquad\text{simplify}\\\\x^2-2x-3=0\qquad\text{subtract the left expression}\\\\(x-3)(x+1)=0\qquad\text{factor}\\\\x=3,\ x=-1\qquad\text{solutions to the quadratic}[/tex]
Each time the equation is squared, the possibility of an extraneous root is introduced. Here, x=3 is extraneous: it does not satisfy the original equation.
The solution is x = -1.
_____
Using a graphing calculator to solve the original equation can avoid extraneous solutions. The attachment shows only the solution x = -1. Rather than use f(x) = 2, we have rewritten the equation to f(x)-2 = 0. The graphing calculator is really good at showing the function values at the x-intercepts.
What is the distance between (8, -3) and (4, - 7)?
Answer:
[tex]distance=\sqrt{32}[/tex] , which agrees with answer "c" in your list of possible options
Step-by-step explanation:
Use the formula for distance between two points [tex](x_1,y_1)[/tex], and [tex](x_2,y_2)[/tex] on the plane:
[tex]distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\distance= \sqrt{(4-8)^2+(-7-(-3))^2} \\distance= \sqrt{(-4)^2+(-4)^2} \\distance=\sqrt{16+16}\\distance=\sqrt{32}[/tex]
In a large population, 81% of the households have cable tv. A simple random sample of 144 households is to be contacted and the sample proportion computed. What is the probability that the sampling distribution of sample porportions is less than 77%
Answer:
The probability that the sampling distribution of sample porportions is less than 77% is P(p<0.77)=0.1106.
Step-by-step explanation:
We know that the population proportion is π=0.81.
We want to know the probability that the sampling distribution of sample proportions, with sample size n=144, is less than 0.77.
The sampling distributions of sampling proportions has a mean and standard deviation calculated as:
[tex]\mu_p=\pi=0.81\\\\\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.81\cdot 0.19}{144}}=\sqrt{0.001068}=0.0327[/tex]
Then, we calculated the z-score for p=0.77:
[tex]z=\dfrac{p-\pi}{\sigma_p}=\dfrac{0.77-0.81}{0.0327}=\dfrac{-0.04}{0.0327}=-1.2232[/tex]
The probability that the sample proportion is less than 0.77 is:
[tex]P(p<0.77)=P(z<-1.2232)=0.1106[/tex]
Construct a boxplot for the given data. Include values of the 5-number summary in all boxplots. The test scores of 40 students are listed below. Construct a boxplot for the data set.
25 35 43 44 47 48 54 55 56 57
59 62 63 65 66 68 69 69 71 72
72 73 74 76 77 77 78 79 80 81
81 82 83 85 89 92 93 94 97 98
Answer:
Minimum = 25
First quartile = 58
Second quartile = 72
Third quartile = 80
Maximum = 98
Step-by-step explanation:
Let y=tan(3x+4) Find the differential dy when x=5 and dx=0.3 Find the differential dy when x=5 and dx=0.6
Problem 1
y = tan(3x+4)
f(x) = tan(3x+4)
f ' (x) = 3sec^2(3x+4) .... apply derivative chain rule
dy/dx = f ' (x)
dy = f ' (x) * dx
dy = ( 3sec^2(3x+4) ) * dx
Now plug in x = 5 and dx = 0.3
dy = ( 3sec^2(3*5+4) ) * 0.3
dy = 0.920681 which is approximate
Make sure your calculator is in radian mode. Calculus textbooks will be in radian mode for the special sine limit definition [tex]\lim_{x\to0}\frac{\sin x}{x} = 1[/tex] to be true.
===========================================================
Problem 2
We'll have the same derivative function and same x value. The only difference is that dx = 0.6 this time.
dy = f ' (x) * dx
dy = ( 3sec^2(3*5+4) ) * 0.6
dy = 1.84136 approximately
Rewrite the expression using exponents .Then find the product
Answer:
[tex]m ^ {3/7}[/tex]
Step-by-step explanation:
=> [tex]\sqrt[7]{m^3}[/tex]
[tex]\sqrt[7]{}= ^\frac{1}{7}[/tex]
=> [tex]m^{3*1/7}[/tex]
=> [tex]m ^ {3/7}[/tex]
Butler Trucking Company has developed a regression equation to predict the delivery time for its drivers (y). The model is based on the miles traveled (x 1), the number of deliveries (x 2) and whether or not the travel will occur during rush hours (x 3 - 1 if during rush hour and 0 if not during rush hour). The regression equation that they use is y
Answer:
The answer is Y = 6.3973.
Note: Kindly find an attached document of the complete question to this solution
Sources: The complete question was researched from Quizlet site.
Step-by-step explanation:
Solution
Given that:
The regression equation is given below:
Y = - 0.3302 + 0.0672 x₁ + 0.6735 x₂ + 0.9980 x₃
Now,
When x₂ = 5, x₁ = 50, x₃ = 0
Y = - 0.3302 + 0.0672 * 50 +0.6735 * 5
Y= - 0.3302 + 3.36 + 3.3675
Y = 6.3973
Therefore the time (hour) it will take for the driver to make five deliveries on a 50 mile journey not during rush hour is 6.3973.