Answer:
D
Explanation:
When molecules absorb energy they speed up and have a more forceful collision with solute molecules.
Classify the following as either an element, compound, homogeneous mixture or
heterogeneous mixture:
sodium chloride
Sodium chloride is the chemical name for salt and is composed of sodium and chlorine, so it is a compound.
An element's atomic number refers to - (TEKS 8.5A)
Answer:
An element's atomic number refers to the number of protons found in the nucleus of each atom of the element.
Answer:
ur mom
Explanation:
ur mom lol
What observations and reasoning led to the development of Hubble's Law?
Answer:
Hubble's law says that the universe is expanding outward.
Explanation:
Actually Hubble's law was discovered before the Big Bang theory was formulated. The Big Bang Theory is an attempt to explain the observations that led to Hubble's Law.Before the 1900s the theory was that the universe was eternal and self existent. The idea was that the universe was in a steady state having always existed and would always continue to exist. Albert Einstein even changed the equations in his general theory of relativity to reflect the idea of a steady state. Later he called putting in a fudge factor to result in a steady state the worse mistake of his life.
Hubble observed that most of the universe has a red shift indicating that the universe is expanding and moving away from itself. The further out that the universe is observed the faster it is moving apart.
These observations were inconsistent with a steady state universe.
The Big Bang theory extrapolated backwards. If the universe is expanding and spreading out from itself then further back in time the universe was closer together. The Theory explained Hubble's observations by the idea that at the beginning of time ( for our universe) all the matter and energy were together in one place.
This super dense ball of matter and energy then exploded outwards creating space and time as it is presently observed. The question was would the forces of gravity and black holes bring the matter and energy back together again. The answer found in 1998 was no. The rate of the expansion of the universe is increasing not slowing down and the universe will not collapse back into the super dense ball of matter that it began as.
The Big Bang Theory postulated based on the empirical evidence that our universe had a beginning and it will eventually cease to exist. The conclusion based on Hubble's observations is that matter and energy are not eternal and self existent.
i What
What is ment by
ment by covalency?
What is a hot spot?
Own words
Answer: Hotspot: A hotspot is a physical location where people can access the Internet, typically using Wi-Fi, via a wireless local area network (WLAN) with a router connected to an Internet service provider. ... While many public hotspots offer free wireless access on an open network, others require payment.
A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.
Explanation: MY own word's.
can u identify a chemical equation for the saponification of olive oil as per your experiment?
I
What is the standard temperature? Express your answer in kelvins to two decimal places.
Answer:
The standart temperature is 273.15 degrees Kelvin
Explanation:
Answer:
i would say its 0 degrees celcius
Explanation:
In Which State of matter are molecules moving the slowest
A. Solid
B. Liquid
C. Gas
Answer:
Solid
Explanation:
Molecules in solids only vibrate in place, while the other two have moving molecules
If 6.70 g of zinc is reacted with 27.5 g of silver nitrate, the products will be zinc nitrate and silver metal. What is the theoretical mass of silver that will be produced?
a. Write a balanced equation
b. Interpret the equation by
particles and by moles
c. What is the limiting reactant?
Given:
Molar mass AgNO3 =
Needed:
unknown:
available:
d. What is the theoretical mass of silver that will be produced?
e. If the actual yield of silver was 14.1 g, what is the percent yield of the
reaction?
Explanation:
a. Write a balanced equation
The balanced equation for the reaction is given as;
Zn + AgNO3 → Ag + ZnNO3
b. Interpret the equation by particles and by moles
In this equation, 1mol of Zn reacts with 1 mol of AgNO3 to from 1 mol of Ag and 1 mol of ZnNO3
1 mol = 6.022 * 10^23 particles
c. What is the limiting reactant?
The mol ratio between both reactants is 1 : 1 from the equation.
Converting the masses given to ml;
Number of mol = Mass / Molar mass
Zn;
Number of mol = 6.70 / 65.38 = 0.1025 mol
AgNO3;
Number of mol = 27.5 / 169.87 = 0.1619 mol
The limiting reactant in this reaction is Zn. This is because Zn would get used up before AgNO3 according to the number of moles calculated.
d. What is the theoretical mass of silver that will be produced?
1 mol of Zn produces 1 mol of Ag
0.1025 mol of Zn would also produce 0.1025 mol mol of Ag
Mass = Molar mass * Number of Moles = 107.87 * 0.1025
Mass = 11.05 g
e. If the actual yield of silver was 14.1 g, what is the percent yield of the
reaction?
Percent yield = Actual Yield / Theoretical yield * 100%
Percent yield = 11.05 / 14.1 * 100 = 78.36%
Predict the products of the electrolysis of molten nickel(II) iodide. Write an ionic half-equation for the formation of one of these products. products:
ionic half-equation:
Answer:
See explanation
Explanation:
The electrolysis of nickel(II) iodide yields nickel solid and iodine gas.
In the oxidation half equation;
2I^-(aq)-------> I2(g) + 2e
In the reduction half equation;
Ni^2+(aq) + 2e -----> Ni(s)
These are the half equations of the process;
The overall equation is;
Ni^2+(aq) + 2I^-(aq)-------> NiI2
3. How many joules are required to raise the temperature of a 29.352g sample of water by 52.0°C? (the specific heat of water is 4.184 J/g °C)
Answer:
6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
Q= ?c= 4.184 [tex]\frac{J}{g*C}[/tex]m= 29.352 gΔT= 52 CReplacing:
Q= 4.184 [tex]\frac{J}{g*C}[/tex] *29.352 g* 52 C
Solving you get:
Q= 6,386.05 J
6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.
is the sun the only star in our solar system
Answer:
Hey mate......
Explanation:
This is ur answer.......
The largest star, and indeed the only star in our solar system, is the sun. The sun is a bit under a million miles across. About 110 Earths put side by side would equal the size of the sun. The sun has 99.8 percent of the mass of our solar system.
Hope it helps!
Mark me brainliest pls......
Follow me! :)
yes hahahahahahah......
What is the mass of 4.50mol Ca
It is often possible to change a hydrate into an anhydrous compound by heating it to drive off the water (dehydration). A 45.91 gram sample of a hydrate of MnSO4 was heated thoroughly in a porcelain crucible, until its weight remained constant. After heating, 37.07 grams of the anhydrous compound remained. What is the formula of the hydrate
Answer: The formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
Explanation:
Decomposition of hydrated manganese sulphate is given by:
[tex]MnSO_4.xH_2O\rightarrow MnSO_4+xH_2O[/tex]
Molar mass of [tex]MnSO_4[/tex] = 151.0 g/mol
According to stoichiometry:
(151.0+18x) g of [tex]MnSO_4.xH_2O[/tex] decomposes to give 151.0 g of [tex]MnSO_4[/tex]
Thus 45.91 g of [tex]MnSO_4.xH_2O[/tex] decomposes to give= [tex]\frac{ 151.0}{151.0+18x}\times 45.91g[/tex] of [tex]MnSO_4[/tex]
Also we are given : 37.07 g of [tex]MnSO_4[/tex] is produced
Thus we can equate the two equations:
[tex]\frac{ 151.0}{151.0+18x}\times 45.91=37.07[/tex]
[tex]x=2[/tex]
Thus the formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
What is a similarity between a fish embryo and a human embryo in the late stages of development?
They both have tails
They both have gills.
They both have spines.
They both have arms.
Answer:In the LATER stages of development they would have a spine
Explanation:
write acid formula where the non-metal element is has a valency of 6
Answer:
Hello ur answer is
Pyrosulphuric acid formula
Explanation:
thanks
Answer:
Hello There!!
Explanation:
The answer is=>Pyrosulphuric acid formula.
hope this helps,have a great day!!
~Pinky~
Sonni added 23.79 mL of KOH to 20.00 mL of 0.393 M HF until the equivalence point was reached. What is the concentration of conjugate base at the equivalence point after the initial neutralization?
Answer:
0.1795 M
Explanation:
From the given information:
The equation is:
[tex]\mathbf{HF_{(aq)}+ KOH_{(aq)} \to KF _{(aq)} + H_2O}[/tex]
From the above equation, the reaction will go to completion due to the strong base:
At the equivalence point, moles of acid (HF) will be equal to moles of base (KOH)
[tex]\text{Number of moles = Volume} \times Molarity[/tex]
Thus. since moles of HF = moles of KOH
Then; 0.020 × 0.393 M = 0.02379 × (x) M
(x) M = [tex]\dfrac{0.02 \times 0.393 \ M}{0.02379}[/tex]
(x) = 0.3304 M
Thus, the molarity of KOH = 0.3304 M
Using the balanced neutralization reaction;
moles of HF = moles of KOH = moles of conjugate base = 0.00786 mol
∴
Volume = 0.020 L + 0.02379 L
Volume = 0.04379 L
Volume of the solution = 0.04379 L
Therefore; Molarity = [tex]\dfrac{moles}{volume}[/tex]
Molarity = [tex]\dfrac{0.00786 \ mol}{0.04379 \ L}[/tex]
Molarity = 0.17949 mol/L
= 0.1795 M
After the initial neutralization, the molarity at the equivalence point will be:
"0.17949 mol/L"
Concentration of solutionAccording to the question,
→ HF (aq) + KOH (aq) [tex]\rightarrow[/tex] KF (aq) + H₂O
Since, moles of HF = moles of KOH
We know that,
Number of moles = Volume × Molarity
→ 0.020 × 0.393 = 0.02379 × M
By applying cross-multiplication,
The molarity of KOH be:
M = [tex]\frac{0.02\times 0.393}{0.02379}[/tex]
= [tex]\frac{0.00786}{0.02379}[/tex]
= 0.3304 M
By using balanced neutralization reaction,
Volume = 0.020 + 0.02379
= 0.04379 L
hence,
The molarity will be:
= [tex]\frac{Moles}{Volume}[/tex]
By substituting the values,
= [tex]\frac{0.00786}{0.04379}[/tex]
= 0.17949 mol/L
Thus the response above is correct.
Find out more information about concentration here:
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4.50 g of Nacl react with 10.00 g of Agno3 to produce 7.93 g of Agcl.if the theroretical amount of agcl that can be formed is 8.43 g what is the percent yield
Give an example of an electrolyte
Answer: sodium chloride water solution
Explanation: Eelctrolyte contains cations and anions which can
Transfer charge
Answer:
some energy drinks like powerade or Gatorade, and some juice drinks to.
________ exercise strengthens skeletal muscle, and ________ exercise strengthens skeletal and cardiac muscle.
a.resistance, aerobic
c.
aerobic, resistance
b.
aerobic, aerobic
d.
resistance, resistance
Answer:
... :-!...................nose...........Aspirin synthesis involves the addition of an acetyl group to salicylic acid in a condensation reaction with an alcohol. The acetyl group could be added with a carboxylic acid but the preferred procedure is to use the acid anhydride. Why is preferable to use an acid anhydride for ester formation with an alcohol rather than a carboxylic acid
Answer:
See explanation
Explanation:
The synthesis of asprin involves the;
i) Hydrolysis of Methyl salicylate
ii) Reaction of salicylic acid with acid anhydride
The chemical name of asprin is acetylsalicylic acid.
It is preferable to use an acid anhydride for ester formation with an alcohol rather than a carboxylic acid because we will not produce water which can then cause the hydrolysis of the newly formed ester.
If 5.00 g of O2 gas has a volume of 7.20 L at a certain temperature and pressure, what volume does 15.0 g of O2 have under the same conditions?
The volume 15.0 g of O₂ has at a certain temperature and pressure is 2.16 L.
What is volume?Volume is the space occupied by a three-dimensional object.
By the law of dilution
M₁/V₁ = M₂/V₂
Mass 1 is 5.00
Volume 1 is 7.20 L
Mass 2 15.0 g
Volume 2 is to find
Putting the value in the equation
5.00/ 7.20 = 15.0 / V₂
V₂ = 7.20 × 15.00/ 5.00 = 21.6
Thus, the volume will be 21.6 L.
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Which of the following is NOT part of STP?
O O Fahrenheit
O 1 Atmosphere
O 273 Kelvin
O 101.3 kiloPascals
Answer:
Farenheit
Explanation:
STP is used to measure standard temperature and pressure -- it uses Kelvin for temperature, not Farenheit.
How many grams of ( S ) - 1 - chloro - 4 - ethyl - 2 - methylhexane and triphenylphosphine would you need to create 4 . 1 5g of ( S ) - 1 - chloro - 4 - ethyl - 2 - methyl triphenylphosphonium assuming an 8 1 % yield for the reaction?
Answer:
Explanation:
The standard molar mass is:
For (S )-1-chloro-4-ethyl-2-methylhexane = 162.5 g/mol
For triphenylphosphine = 262 g/mol
For ( S )-1-chloro-4-ethyl-2-methyl triphenylphosphonium = 424.5 g/mol
The mass required for 81% yield = [tex]\dfrac{81}{100} \times Theoretical \ yield = 4.15 g[/tex]
Theoretical yield = [tex]\dfrac{4.15}{0.81}[/tex]
= 5.1235 g
thus, since 424.5 g yield produce from 162.5 g
∴
5.1235 g yield will produce = [tex]\dfrac{162.5}{424.5}\times 5.1235 \ g[/tex]
= 1.9613 g of alkyl halide (-chloro) required.
Also, since 424.5 g yield produce from 262 g phosphine
∴
5.1235 g yield will produce = [tex]\dfrac{262}{424.5}\times 5.1235 \ g[/tex]
= 3.1622 g of triphenylphosphine required.
What is the hydrogen ion concentration ([H']) of a substance with a pH of 4.91?
Answer:
The pH of a solution is a measure of the concentration of hydrogen ions in the solution. A solution with a high number of hydrogen ions is acidic and has a low pH value. A solution with a high number of hydroxide ions is basic and has a high pH value. The pH scale ranges from 0 to 14, with a pH of 7 being neutral.
g An oxidized silicon (111) wafer has an initial field oxide thickness of d0. Wet oxidation at 950 °C is then used to grow a thin film gate of 500 nm in 50 minutes. What is the original field oxide thickness d0 (in nm)?
Answer:
Explanation:
From the information given:
oxidation of oxidized solution takes place at 950° C
For wet oxidation:
The linear and parabolic coefficient can be computed as:
[tex]\dfrac{B}{B/A} = D_o \ exp \Big [\dfrac{-\varepsilon a}{k_BT} \Big][/tex]
Using [tex]D_o[/tex] and [tex]E_a[/tex] values obtained from the graph:
Thus;
[tex]\dfrac{B}{A} = 1.63 \times 10^8 exp \Big [ \dfrac{-2.05}{8.617 \times 10^{_-5}\times 1173}\Big] \\ \\ = 0.2535 \ \ \mu m/hr[/tex]
[tex]B= 386 \ exp \Big [-\dfrac{0.78}{8.617 \times 10^{-3} \times 1173} \Big] \\ \\ = 0.1719 \ \mu m^2/hr[/tex]
So, the initial time required to grow oxidation is expressed as:
[tex]t_{ox} = \dfrac{x}{B/A}+ \dfrac{x^2}{B} - t_o (initial)[/tex]
[tex]where; \\ \\ t_{ox} = 2 \ hrs;\\ \\ x = 0.5 \\ \\ B/A = 0.2535 \\ \\ B = 0.1719[/tex]
∴
[tex]2= \dfrac{0.5}{0.2535}+ \dfrac{0.5^2}{0.1719} - t_o (initial)[/tex]
[tex]2 = 3.4267 - t_o (initial) \\ \\ t_o(initial) = 3.4267 - 2 \\ \\ t_o(initial) = 1.4267 \ hr[/tex]
NOW;
[tex]1.4267 = \dfrac{d_o}{0.2535} + \dfrac{d_o^2}{0.1719} \\ \\ 1.4267 = 3.9448 \ d_o + 5.8173 \ d_o^2 \\ \\ d_o^2 + 0.6781 \ d_o = 0.2453[/tex]
[tex]d_o = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]
[tex]d_o = \dfrac{-(0.6781) \pm \sqrt{(0.6781)^2-4(1)(-0.245)}}{2(10)}[/tex]
[tex]d_o = \dfrac{-(0.6781) \pm \sqrt{0.45981961+0.98}}{20}[/tex]
[tex]d_o = \dfrac{-(0.6781) \pm \sqrt{1.43981961}}{20}[/tex]
[tex]d_o = \dfrac{-(0.6781) + \sqrt{1.43981961}}{20} \ OR \ \dfrac{-(0.6781) - \sqrt{1.43981961}}{20}[/tex]
[tex]d_o =0.02609 \ OR \ -0.0939[/tex]
Thus; since we will consider the positive sign, the initial thickness [tex]d_o[/tex] is ;
≅ 0.261 μm
what climate is Colorado in?
A.Most Subtropical Mid-Latitude
B.Polar
C.Moist ContinentaMid-Latitiude
D.Dry
Answer:
b
Explanation:
Answer:
D. Dry
Explanation:
Colorado's combination of high elevation, midlatitude, and continental interior geography results in a cool, dry climate.
There are eight diastereomers of 1,2,3,4,5,6-hexachlorocyclohexane. One of them is drawn. Draw the other seven in the cyclohexane framework below (5 points). One isomer loses HCl in an E2 reaction nearly 1000 times more slowly than the others. Circle the isomer that reacts so slowly, draw its corresponding chair conformers and explain the reason for the slow rate. (5 points).
Answer:
Attached below diagram of the eight diastereomers
The Isomer that reacts so slowly is DIASTEREOMER 8
Explanation:
The Isomer that reacts so slowly is DIASTEREOMER 8 in an E2 reaction and this is because no pair of chlorine and hydrogen atoms can assume the anti-periplanar orientation that is preferred in an E2 elimination
attached below is Diagram of the eight diastereomers ( screen shot from my drawing tool )
ould it make any difference if the methylene chloride solutioncontaining both thebasicand neutral components waswashed with 1Msodium hydroxiderather than 1Mhydrochloric acid? If so,what would that difference be? Would any layer separation bepossible in the new solution? Would it be possible to isolate the two components from oneanother using 1Msodium hydroxiderather than 1Mhydrochloric acid?Why or why not?Provide a balanced equation to justify your answ
Answer:
Explanation:
No, it is ludicrous and not possible to separate and detach a basic and neutral compound by 1M NaOH in DCM. This is due to the fact that neutral compounds don't respond and react with NaOH, and NaOH itself occurs to be a base. As a result, it can't respond and react with another base to produce salt. Consequently, we simply need a corrosive component i.e an acid
So; In DCM, we can't use 1M NaOH instead of 1M HCI for isolation and separation of neutral and basic compound mixtures.
Given that C = n/V. And you have n=2 and C=4 what does V= ??
1...0.5
2...2
3...4
4...8
or5...Dont know