please see the attached picture...
Hope it helps...
Good luck on your assignment.....
Answer:
The answers are
Step-by-step explanation:
7 X -3 = -21
24/ -12= -2
we nendndhdhebdbdbdd
Step-by-step explanation:
Joe mama
Halfway through the season, a soccer player has made 15 penalty kicks in 19 attempts. Based on her performance to date, what is the relative frequency probability that she will make her next penalty kick?
Answer:
[tex]\dfrac{15}{19}[/tex]
Step-by-step explanation:
The soccer player so far has made 15 penalty kicks in 19 attempts.
Therefore:
Total Number of trials =19
Number of Successes =15
Therefore, the relative frequency probability that she will make her next penalty kick is:
[tex]=\dfrac{\text{Number of Successes}}{\text{Total Number of Trials}} \\=\dfrac{15}{19}[/tex]
In a study of the effectiveness of airbags in cars, 11,541 occupants were observed in car crashes with airbags available, and 41 of them were fatalities. Among 9,853 occupants in crashes with airbags not available, 52 were fatalities. (a) Construct a 95% confidence interval for the difference of the two population fatality rates. (please keep 4 decimal places throughout for accuracy) (b) Based on the confidence interval
Answer:
Please the read the answer below
Step-by-step explanation:
In order to find the 95% confidence interval for the difference of the two populations, you use the following formula (which is available when the population size is greater than 30):
CI = [tex](p_1-p_2)\pm Z_{\alpha/2}(\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2}})[/tex] (1)
where:
p1: proportion of one population = 52/9853 = 0.0052
p2: proportion of the other population = 41/11541 = 0.0035
α: tail area = 1 - 0.95 = 0.05
Z_α/2: Z factor of normal distribution = Z_0.025 = 1.96
n1: sample of the first population = 52
n2: sample of the second population = 41
You replace the values of all parameters in the equation (1) :
[tex]CI =(0.0052-0.0035)\pm (1.96)(\sqrt{\frac{0.0052(1-0.0052)}{52}+\frac{0.0035(1-0.0035)}{41}})\\\\CI=0.0017\pm0.026[/tex]
By the result obtained in the solution, you can conclude that the sample is not enough, because the margin error is greater that the difference of proportion of each sample population.
If the rectangular menu is 3 feet long by 2 feet wide, what is the area of the menu?
Answer:
Step-by-step explanation:
Area of rectangular menu
Length × breadth
3×2=6sq feet
Answer:
6 ft^2
Step-by-step explanation:
area of rectangle = length * width
area = 3 ft * 2 ft
area = 6 ft^2
A researcher is conducting a study on eating disorders. Using a list of recent participants in the online Weight Watchers program, she randomly selects a name from the alphabetized list. She then chooses every tenth person from that point on to include in her study. What is this sampling plan and example of?A. Judgmental SamplingB. Random SamplingC. Systematic SamplingD. Stratified SamplingE. Cluster Sampling
Answer:
Option c
Step-by-step explanation:
Systematic sampling is a probability type of samplng method in which elements are picked from a large population at a random start point and then the others are picked by constant periodic intervals which is usually done by dividing the population size by the chosen sample size. Then do a random start between 1 and the sampling interval, then repeatedly add the sampling interval to select subsequent elements.
Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and n=1000 . Round your answers to three decimal places.
Given Information:
Population proportion = p = 0.55
Sample size 1 = n₁ = 30
Sample size 2 = n₂ = 100
Sample size 3 = n₃ = 1000
Required Information:
Standard error = σ = ?
Answer:
[tex]$ \sigma_1 = 0.091 $[/tex]
[tex]$ \sigma_2 = 0.050 $[/tex]
[tex]$ \sigma_3 = 0.016 $[/tex]
Step-by-step explanation:
The standard error for sample proportions from a population is given by
[tex]$ \sigma = \sqrt{\frac{p(1-p)}{n} } $[/tex]
Where p is the population proportion and n is the sample size.
For sample size n₁ = 30
[tex]$ \sigma_1 = \sqrt{\frac{p(1-p)}{n_1} } $[/tex]
[tex]$ \sigma_1 = \sqrt{\frac{0.55(1-0.55)}{30} } $[/tex]
[tex]$ \sigma_1 = 0.091 $[/tex]
For sample size n₂ = 100
[tex]$ \sigma_2 = \sqrt{\frac{p(1-p)}{n_2} } $[/tex]
[tex]$ \sigma_2 = \sqrt{\frac{0.55(1-0.55)}{100} } $[/tex]
[tex]$ \sigma_2 = 0.050 $[/tex]
For sample size n₃ = 1000
[tex]$ \sigma_3 = \sqrt{\frac{p(1-p)}{n_3} } $[/tex]
[tex]$ \sigma_3 = \sqrt{\frac{0.55(1-0.55)}{1000} } $[/tex]
[tex]$ \sigma_3 = 0.016 $[/tex]
As you can notice, the standard error decreases as the sample size increases.
Therefore, the greater the sample size lesser will be the standard error.
What is the area of the trapezoid below? Select one: a. 88 cm2 b. 44√3 cm2 c. 65 cm2 d. 36√3 cm2
Answer: D
Step-by-step explanation:
Since we are not given the height of the trapezoid, we can split this into a triangle and a rectangle. We find the area of each and then add them together. In order to do so, we must use Pythagorean Theorem to find the missing length so that we can find the area.
a²+b²=c²
a²+4²=8²
a²+16=64
a²=48
a=√48
a=4√3
Now that we know the missing length of the triangle, we can find the area of the triangle and the rectangle.
Triangle
A=1/2bh
A=1/2(4)(4√3)
A=8√3
-----------------------------------------------------------------------------------------
Rectangle
A=lw
A=7(4√3)
A=28√3
With our areas, we can add them together.
4√3+28√3=36√3 cm²
Calculate the interest produced by a principal of $ 4,500 at 5% annual simple interest in 8 months.
Answer:
4,500 x 5 = 22,500
4,500 divided by 5 = 900
4,500 plus 5 = 4,505
4,500 minus 5 = 4,495
Step-by-step explanation:
it is either one of those that u have to choose from good luck
Use the given probability value to determine whether the sample results could easily occur by chance, then form a conclusion. A study of the effect of seatbelt use in head-on passenger car collisions found that drivers using a seatbelt had a 64.1% survival rate, while drivers not using a seatbelt had a 41.5% survival rate. If seatbelts have no effect on survival rate, there is less than a 0.0001 chance of getting these results. What do you conclude?
Answer:
As the P-value is very low, we can conclude that there is enough evidence to support the claim that the survival rate is significantly higher when the seatbelt is used.
Step-by-step explanation:
We have a hypothesis test that compares the survival rate using the seatbelt versus the survival rate not using it.
The claim is that the survival rate (proportion) is significantly higher when the seatbelt is used.
Then, the null hypothesis is that the seatbelts have no effect (both survival rates are not significantly different).
The P-value is the probabilty of the sample we have, given that the null hypothesis is true. In this case, this value is 0.0001.
This is very low, what gives enough evidence to claim that the survival rate is significantly higher when the seatbelt is used.
Use the multiplication rule for independent event probabilities. Two friends are both pregnant, and find out they are each expecting twins! Let A be the event that one friend is pregnant with identical twins, and note that P(A) = 0.0045. Let B be the event that the other friend is pregnant with fraternal twins, and note that P(B)= 0.01. A and B are independent events. What is the probability that one friend is pregnant with identical twins, and one friend is pregnant with fraternal twins? Give your answer as a percent, rounded to four decimal places if necessary.
Answer:
We have to multiply P(A) and P(B) which is 0.0045 * 0.01 * 100 (to make it a percentage) = 0.0045%.
The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United States. For 15 top-ranking restaurants located in Boston, the average price of a dinner, including one drink and tip, was $48.60. You are leaving on a business trip to Boston and will eat dinner at three of these restaurants. Your company will reimburse you for a maximum of $50 per dinner. Business associates familiar with the restaurants have told you that the meal cost at 5 of the restaurants will exceed $50. Suppose that you randomly select three of these restaurants for dinner.
Required:
a. What is the probability that none of the meals will exceed the cost covered by your company?
b. What is the probability that one of the meals will exceed the cost covered by your company?
c. What is the probability that two of the meals will exceed the cost covered by your company?
d. What is the probability that all three of the meals will exceed the cost covered by your company?
Answer:
a. P(x=0)=0.2967
b. P(x=1)=0.4444
c. P(x=2)=0.2219
d. P(x=3)=0.0369
Step-by-step explanation:
The variable X: "number of meals that exceed $50" can be modeled as a binomial random variable, with n=3 (the total number of meals) and p=0.333 (the probability that the chosen restaurant charges mor thena $50).
The probabilty p can be calculated dividing the amount of restaurants that are expected to charge more than $50 (5 restaurants) by the total amount of restaurants from where we can pick (15 restaurants):
[tex]p=\dfrac{5}{15}=0.333[/tex]
Then, we can model the probability that k meals cost more than $50 as:
[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{3}{k} 0.333^{k} 0.667^{3-k}\\\\\\[/tex]
a. We have to calculate P(x=0)
[tex]P(x=0) = \dbinom{3}{0} p^{0}(1-p)^{3}=1*1*0.2967=0.2967\\\\\\[/tex]
b. We have to calculate P(x=1)
[tex]P(x=1) = \dbinom{3}{1} p^{1}(1-p)^{2}=3*0.333*0.4449=0.4444\\\\\\[/tex]
c. We have to calcualte P(x=2)
[tex]P(x=2) = \dbinom{3}{2} p^{2}(1-p)^{1}=3*0.1109*0.667=0.2219\\\\\\[/tex]
d. We have to calculate P(x=3)
[tex]P(x=3) = \dbinom{3}{3} p^{3}(1-p)^{0}=1*0.0369*1=0.0369\\\\\\[/tex]
Find the volume of the rectangular prism.
8 ft
8 ft
8 ft
Answer:
V = 512 ft^3
Step-by-step explanation:
The volume of a prism is length * width * height
V = 8*8*8
V = 512 ft^3
The volume of a rectangular prism is lwh.
V=lwh
V=8*8*8
V=8^3
V=512
The probability that a person in the United States has type B+ blood is 12%. Three unrelated people in the United States are selected at random. Complete parts (a) through (d). (a) Find the probability that all three have type B+ blood. The probability that all three have type B+ blood is nothing. (Round to six decimal places as needed.)
Answer:
The probability that all three have type B+ blood is 0.001728
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The probability that a person in the United States has type B+ blood is 12%.
This means that [tex]p = 0.12[/tex]
Three unrelated people in the United States are selected at random.
This means that [tex]n = 3[/tex]
Find the probability that all three have type B+ blood.
This is P(X = 3).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728[/tex]
The probability that all three have type B+ blood is 0.001728
Graph g(x)=-2|x-5|-4
Answer:
Step-by-step explanation:
The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 255.4 and a standard deviation of 63.9. (All units are 1000 cells/muL.) Using the empirical rule, find each approximate percentage below. a. What is the approximate percentage of women with platelet counts within 3 standard deviations of the mean, or between 63.7 and 447.1? b. What is the approximate percentage of women with platelet counts between 191.5 and 319.3?
Answer:
a) From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data
b) [tex] P(191.5<X<319.5)[/tex]
We can find the number of deviations from the mean for the limits using the z score formula given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
And replacing we got:
[tex] z=\frac{191.5-255.4}{63.9}= -1[/tex]
[tex] z=\frac{319.3-255.4}{63.9}= 1[/tex]
So we have values within 1 deviation from the mean and using the empirical rule we know that we have 68% of the values for this case
Step-by-step explanation:
For this case we have the following properties for the random variable of interest "blood platelet counts"
[tex]\mu = 255.4[/tex] represent the mean
[tex]\sigma = 63.9[/tex] represent the population deviation
Part a
From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data
Part b
We want this probability:
[tex] P(191.5<X<319.5)[/tex]
We can find the number of deviations from the mean for the limits using the z score formula given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
And replacing we got:
[tex] z=\frac{191.5-255.4}{63.9}= -1[/tex]
[tex] z=\frac{319.3-255.4}{63.9}= 1[/tex]
So we have values within 1 deviation from the mean and using the empirical rule we know that we have 68% of the values for this case
Which equation represents the line that passes through and left-parenthesis 4, StartFraction 7 Over 2 right-parenthesis.?
Answer:
We want a line that passes through the point (4, 7/2)
and we have no other information of this line, so we can not fully find it, but we can find a general line.
We know that a line can be written as:
y = a*x + b.
Now we want that, when x = 4, we must have y = 7/2.
7/2 = a*4 + b
b = -a*4 + 7/2
Then we can write this line as:
y = a*x - a*4 + 7/2.
Where a can take any value, and it is the slope of our line.
Answer:
A
Step-by-step explanation:
Seven new employees, two of whom are married to each other, are to be assigned seven desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have adjacent desks
Answer:
2/7
Step-by-step explanation:
Seven employees can be arranged in 7! ways. n(S) = 7!
Two adjacent desks for married couple can be selected in 6 ways viz.,(1, 2), (2, 3), (3,4), (4, 5), (5,6),(6,7).
This couple can be arranged in the two desks in 2! ways. Other five persons can be arranged in 5! ways.
So, number of ways in which married couple occupy adjacent desks
= 6×2! x 5! =2×6!
so, the probability that the married couple will have adjacent desks
[tex]\frac{n(A)}{n(s)} =\frac{2\times6!}{7!} \\=\frac{2}{7}[/tex]
The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin(πt) + 5 cos(πt), where t is measured in seconds.
A) Find the average velocity during each time period.
1) [1, 2]
2) [1, 1.1]
3) [1, 1.01]
4) [1, 1.001]
B) Estimate the instantaneous velocity of the particle when t = 1. cm/s
Answer:
A) 10, -3.73, -6.035, -6.259 . . . cm/s
B) -6.2832 cm/s
Step-by-step explanation:
A) For problems like this, where repeated evaluation of a function is required, I find a graphing calculator or spreadsheet to be an appropriate tool. The attached shows that we defined the position function ...
p(t) = 2sin(πt) +5cos(πt)
and a function for computing the average velocity from t=1. For some time interval ending at t2, the average velocity is ...
Va(t2) = Δp/Δt = (p(t2) -p(1))/(t2 -1)
Then, for example, for t2 = 2, the average velocity on the interval [1, 2] is ...
Va(2) = (p(2) -p(1))/(2 -1) = ((2sin(2π) +5cos(2π)) -(2sin(π) +5cos(π)))/(1)
= (2·0+5·1 -(2·0 +5·(-1)) = 10 . . . . matches the table value for x1 = 2.
Then the average velocity values for the intervals of interest are ...
1) [1, 2] Va = 10
2) [1, 1.1] Va = -3.73
3) [1, 1.01] Va = -6.035
4) [1, 1.001] Va = -6.259
__
B) Sometimes a better estimate is obtained when the interval is centered on the point of interest. Here, we can compute the average velocity on the interval [0.999, 1.001] as a better approximation of the instantaneous velocity at t=1. That value is ...
[0.999, 1.001] Va = -6.283175*
Our estimate of V(1) is -6.2832 cm/s.
The exact value is -2π ≈ -6.2831853... cm/s
__
* This is the average of the Va(0.999) and Va(1.001) values in the table.
The measurement of the circumference of a circle is found to be 64 centimeters, with a possible error of 0.9 centimeter. (a) Approximate the percent error in computing the area of the circle. (Round your answer to two decimal places.) 2.81 Correct: Your answer is correct. % (b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 1%. (Round your answer to one decimal place.)
Answer:
(a) 2.81%
(b) 0.5%
Step-by-step explanation:
We have the following information from the statement:
P = 64 + - 0.9
(a) We know that the perimeter is:
P = 2 * pi * r
if we solve for r, we have to:
r = P / 2 * pi
We have that the formula of the area is:
A = pi * r ^ 2
we replace r and we are left with:
A = pi * (P / 2 * pi) ^ 2
A = (P ^ 2) / (4 * pi)
We derive with respect to P, and we are left with:
dA = 2 * P / 4 * pi * dP
We know that P = 64 and dP = 0.9, we replace:
dA = 2 * 64/4 * 3.14 * 0.9
dA = 9.17
The error would come being:
dA / A = 9.17 / (64 ^ 2/4 * 3.14) = 0.02811
In other words, the error would be 2.81%
(b) tell us that dA / A <= 0.01
we replace:
[P * dP / 2 * pi] / [P ^ 2/4 * pi] <= 0.01
solving we have:
2 * dP / P <= 0.01
dP / P <= 0.01 / 2
dP / P <= 0.005
Which means that the answer is 0.5%
Bradley and Kelly are flying out kites at a park one afternoon. And model of Bradley and Kelly skates are shown Below on the coordinate plane as the kites BRAD and KELY, respectively:
Answer: b) they ARE similar because BRAD:KELY is 1:2
Step-by-step explanation:
In order for the shapes to be similar they must have congruent angles and proportional sides.
With the options a through d given, we can assume that their sides are proportional. Since BRAD is smaller than KELY, BRAD would have the smaller number in the ratio.
Answer:
They are similar because Brad and Kelly are 1:2
Step-by-step explanation:
Help me with this problem pleaseeeeee
Answer:
122 in2
Step-by-step explanation:
area = (2*tri area) + (3*rec area)
area = (2*0.5*4*3.5) + (3*4*9)
area = 14 + 108 = 122 Squared in
a painter paints the side of a house at a rate of 3 square feet per minute. if the dimensions of the side of the house are 15 feet by 18, how many minutes does it take the painter to finish the job?
Answer: 90 minutes
Step-by-step explanation:
Area of the side = 15 x 18 = 270 sq. ft.
3 sq. ft take a minute to paint
270 sq. ft. will take 270 / 3
= 90 minutes
Please answer this correctly
Answer:
Pillows:
Blankets:
Pet Beds:
Step-by-step explanation:
18 + 45 + 27 = 90 (there are 90 students)
18 out of 90 = 20%
45 out of 90 = 50%
27 out of 90 = 30%
Hope this helps!
Consider a binomial experiment with n = 20 and p = .70.
A. Compute f(12).
B. Compute f(16).
C. Compute P(x 16).
D. Compute P(x 15).
E. Compute E(x).
F. Compute Var(x).
Complete question:
Consider a binomial experiment with n = 20 and p = .70.
A. Compute f(12).
B. Compute f(16).
C. Compute P(x≥ 16).
D. Compute P(x≤15).
E. Compute E(x).
F. Compute Var(x).
Answer:
a) 0.1144
b) 0.1304
c) 0.2375
d) 0.7625
e) 14
f) 4.2
Step-by-step explanation:
Given:
n = 20
p = 0.70
q = 1 - p ==> 1 - 0.70 = 0.30
a) Use the formula:
[tex] P(x) = CC\left(\begin{array}{ccc}n\\x\end{array}\right) p^x q^(^n^-^x^) [/tex]
Thus,
[tex]P(12) = C\left(\begin{array}{ccc}20\\12\end{array}\right) (0.7^1^2) (0.3^(^2^0^-^1^2^) )[/tex]
[tex] = 125970*0.0138*0.00006 [/tex]
[tex] = 0.1144 [/tex]
b) [tex]P(16) = C\left(\begin{array}{ccc}20\\16\end{array}\right) 0.7^1^6 (0.3^(^2^0^-^1^6^))[/tex]
[tex] = 4845 * 0.0033 * 0.0081 [/tex]
[tex] = 0.1304 [/tex]
c) Compute P(x≥16):
P(x ≥ 16) = P(16) + P(17) + P(18) + P(19) + P(20)
[tex]= C\left(\begin{array}{ccc}20\\16\end{array}\right) 0.7^1^6 (0.3^(^2^0^-^1^6^)) + C\left(\begin{array}{ccc}20\\17\end{array}\right) 0.7^1^7 (0.3^(^2^0^-^1^7^) ) + C\left(\begin{array}{ccc}20\\18\end{array}\right) 0.7^1^8 (0.3^(^2^0^-^1^8^)) + C\left(\begin{array}{ccc}20\\19\end{array}\right) 0.7^1^9 (0.3^(^2^0^-^1^9^)) + C\left(\begin{array}{ccc}20\\20\end{array}\right) 0.7^2^0 (0.3^(^2^0^-^2^0^))[/tex]
[tex] = 0.1304 + 0.0716 + 0.0278 + 0.0068 + 0.0008 = 0.2375 [/tex]
d) P(x ≤ 15):
= 1 - P(x ≥ 16)
= 1 - 0.2375
= 0.7625
e) E(x): use the formula, n * p.
= n*p
= 20 * 0.7
= 14
f) Var(x)
Use the formula: npq
npq = 20 * 0.7 * 0.3
= 4.2
σ
George earned e extra credit points. Kate earned 35 fewer extra credit points than George. Choose the expression that
shbws how many extra credit points Kate earned.
O A. 35
B.35e
C.35 + e
D. e - 35
Ronat Selection
Answer:
D. e - 35
Step-by-step explanation:
We have that:
George earned e extra points.
Kate earned k extra points.
Kate earned 35 fewer extra credit points than George.
This means that k is e subtracted by 35, that is:
k = e - 35
So the correct answer is:
D. e - 35
Plot the point (5, 5). Using a line tool, create AB with a length of 4 units from point A. Turn on the trace feature at point B, and move point B
around point A. keeping the length of AB fixed.
Answer:
Step-by-step explanation:
Plotting a point A and tracing a point B at 4 units from A results in a circle.
▪The locus of a point at equal distance from a fixed point is a circle.
▪Point A is (5,5) and length of AB is 4 units
This implies that the radius of circle is 4 units.
▪The point B can be swirled around A keeping the distance AB constant.
▪The resulting figure is a circle.
▪This circle is plotted and attached below.
I hope this helped. I am sorry if you get it wrong
Answer:
This is the right answer for Edementum and Plato users
Like and Rate!
PLEASE HELP!
A farmer wanted to paint a shed out in his field. Here is the breakdown of the dimensions: the building is sitting on a square slab of cement that is 10' x 10'. It is 8 feet from the bottom of the shed to the bottom of the roof on the edge, and 10 feet from the bottom of the shed to the top of the very tip top of the roof. So A = 10, B = 8 and C = 10. Using the formula for the area of a rectangle, A = l x w and the area of a triangle, 1/2(bh), b is base and h is height, then find the total area that needs to be painted. Total area =
Answer:
340 square feet
Step-by-step explanation:
If we "unwrap" the painted surface from the shed, it will have the shape shown in the attachment. It is essentially a 40' by 8' rectangle with two 10' wide by 2' high triangles added.
The rectangle area is ...
A = LW = (40 ft)(8 ft) = 320 ft²
The total area of the two triangles is ...
A = 2(1/2)bh = (10 ft)(2 ft) = 20 ft²
Then the painted area is ...
total area = 320 ft² +20 ft²
total area = 340 ft²
Jaden had 2 7/16 yards of ribbon. He used 1 3/8 yards of ribbon to make a prize ribbon. How much does he have now?
EASY!
Answer: 17/16 or 1 1/16
Step-by-step explanation:
BRO IT'S ELEMANTARY FRACTIONS!!!!
Please answer this correctly
Answer:
There are 10 teams.
Step-by-step explanation:
Given that the question wants at least 48 swimmers so any numbers above 47 are counted.
In this diagram, there are 10 teams consisting 48 swimmers and above, 48, 52, 53, 63, 76, 79, 82, 84, 85 and 86.
Answer:
10 teams have 48 or more swimmers.
Step-by-step explanation:
If we look at stem 4 there is one team with 48 members.
So counting from there we have:
1 + 2 + 1 + 2 + 4
= 10 teams.
A researcher predicts that listening to music while solving math problems will make a particular brain area more active. To test this, a research participant has her brain scanned while listening to music and solving math problems, and the brain area of interest has a percentage signal change of 58. From many previous studies with this same math problems procedure (but not listening to music), it is known that the signal change in this brain area is normally distributed with a mean of 35 and a standard deviation of 10. (a) Using the .01 level, what should the researcher conclude
Answer:
As the P-value (0.0107) is bigger than the significance level (0.01), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that listening to music while solving math problems will make a particular brain area more active.
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that listening to music while solving math problems will make a particular brain area more active.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=35\\\\H_a:\mu> 35[/tex]
The significance level is 0.01.
The sample has a size n=1.
The sample mean is M=58.
The standard deviation of the population is known and has a value of σ=10.
We can calculate the standard error as:
[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{1}}=10[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{58-35}{10}=\dfrac{23}{10}=2.3[/tex]
This test is a right-tailed test, so the P-value for this test is calculated as:
[tex]\text{P-value}=P(z>2.3)=0.0107[/tex]
As the P-value (0.0107) is bigger than the significance level (0.01), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that listening to music while solving math problems will make a particular brain area more active.