Answer:
D) Since the stars would move from East to West just as the Sun and Moon do.
An electromagnetic wave moves through electric and magnetic fields. How might the movement of the wave be described?
A.
The vibrations of the fields are perpendicular to the direction in which the wave moves.
B.
The wave moves back and forth through the fields.
C.
The vibrations of the fields are parallel to the direction in which the wave moves.
close
D.
The wave moves through the fields in a random motion.
A. The vibrations of the fields are perpendicular to the direction in which the wave moves.
An electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.
What is the significance of an electromagnetic wave?Electromagnetic waves have many applications, including the transmission of information and energy, and they are also used in other technologies such as radio, television, hospitals, wireless communications, and so on. Other different rays, such as microwaves, infrared radiation, visible light, ultraviolet radiation, etc., are used in different fields, such as X-rays for imaging, etc.
Hence, an electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.
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A voltage is applied to a resistor,
which creates a 1.50 A current. If
you double the resistance, keeping
the voltage the same, what will the
new current be?
(Unit = A)
Answer:
Explanation:
By Ohms Law, Voltage = Current * Resistance
Keeping the voltage the same and doubling the resistance, the current will be halved.
So the new current = 1.5/2 = 0.75A
By using Ohms law, the current will be 0.75A.
What is Ohm's law?Ohm's law states that the current flowing through a resistance is proportional to potential difference across the resistance under constant temperature and pressure conditions. Ohm's law can be expressed as:
V =IR
Here, I = 1.50 AR = R Ωso, V = 1.50 R Now Voltage is same but resistance is doubled so new resistance is
Now, put the values of given data in ohms law formula:
2RI = 1.50 R/ 2R = 0.75A
Hence current is 0.75A
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A wave travels at 1,500 m/s with a frequency of 5 hertz. What is its wavelength?
Answer:
λ = 300 m
Explanation:
We are given;
Speed; v = 1500 m/s
Frequency; f = 5 Hz.
Formula for wavelength is given by;
λ = v/f
Plugging in the relevant values;
λ = 1500/5
λ = 300 m
The wavelength of the wave will be 300m. The space between two consecutive troughs or crests is understood as the wavelength.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The given data in the problem is;
v is the speed = 1500 m/s
f is the frequency= 5 Hz.
λ is the wavelength of the wave=?
The relationship between the wave's wavelength, frequency, and speed is given as
wavelength = speed of wave / frequency
The wavelength of the wave is found as;
[tex]\rm \lambda= \frac{v}{f} \\\\ \rm \lambda= \frac{1500}{5} \\\\ \rm \lambda=300 \ m[/tex]
Hence the wavelength of the wave will be 300m.
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Studying children's interactions by watching them play on the school playground is
an example of
a survey.
naturalistic observation.
a case study.
a single-blind study.
Answer:
a survey
Explanation:
how kids like the playground or they do not like it at all
Martin has hypothesized that the size and types of trees differ between valleys and higher elevations. He sets up a transect line in a wooded valley and randomly creates three 10 x 10 meter plots along the transect line, recording GPS coordinates for the northwest corner of each plot. He identifies and measures (diameter at breast height) every tree within the plots. He repeats this procedure in a wooded area on the ridge above the valley.
Using the scenario above, state the independent and dependent variables.
Answer: The dependent Variables include: Size and Types of trees.
The independent Variables include:
geographic elevations that is, valleys and the higher elevations.
Explanation:
The dependent variable simply refers to the variable a researcher tests or measures during an experiment. On the other hand, the independent variable simply refers to the variable that's controlled during an experiment.
Based on the definition above, the dependent variables include the size and the types of trees while the independent variables include the
geographic elevations that is, the valleys and the higher elevations.
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling with a force of 60 Newtons. The third child, Eric, is pulling with enough force to exactly balance Abe and Barry (no child is winning the tug-o-war for the toy). We can label our forces A, B, and E (from each child's name). These three forces are in equilibrium.
If Abe is pulling toward the North and Barry is pulling toward the East, we want to find the total force R due to Abe and Barry (the Resultant of their forces). Note: in THIS case the two forces and R form a right-triangle (with R as the hypotenuse) - as seen using graphical vector addition. As a convention let's have NORTH upward and EAST rightward on this page.
a. Sketch an ACCURATE free-body diagram (three arrows outward from a point showing LABELED forces A, B, and E - each arrow a reasonable length and correct direction):
b. Sketch a labeled diagram for graphical addition of A and B to get R:
c. Show the calculation of the magnitude of R from the magnitudes of A and B:
d. Give the magnitude of force E (in units of Newtons):
e. Describe the direction of force E in terms of the "cardinal" directions (north, east, south, and/or west):
Solution :
c). [tex]$\vec{F}_A = $[/tex] force applied by Abe
[tex]$\vec{F}_B = $[/tex] force applied by Barry
[tex]$\vec{F}_E = $[/tex] force applied by Eric
[tex]$\vec{F}_R = $[/tex] Resultant force
[tex]$\vec{F}_A $[/tex] in the vector form can be written as :
[tex]$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$[/tex]
[tex]$\vec{F}_B $[/tex] in the vector form can be written as :
[tex]$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$[/tex]
The resultant,
[tex]$\vec{F}_R= \vec{F}_A+\vec{F}_B $[/tex]
[tex]$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$[/tex]
[tex]$=60 \hat i + 60 \hat j$[/tex]
[tex]$|\vec{F}_R| = \sqrt{60^2+60^2}$[/tex]
= 84.853 N
d). As the three forces are in equilibrium, therefore,
[tex]$|\vec F_E| = |\vec F_R|$[/tex]
[tex]$|\vec F_E| =84.853 \ N$[/tex]
e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.
The direction of the resultant force is :
[tex]$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$[/tex]
[tex]$ = \tan ^{-1}\left(\frac{60}{60}\right)$[/tex]
= 45° north east
The direction of the force E is 45° west or 45° south west.
On top labeled A 2 waves 1 above the other, with crests and troughs that line up. On bottom labeled B 2 waves, 1 above the other, so that the crests of the top wave line up with the troughs of the bottom wave.
Will there be noise cancellation in example A or example B?
Answer:
b
Explanation:
Answer:
B B*
Explanation:
B BBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity
of Uranus is pulling 3.00 x 1025 N on Oberon, what is the mass of Uranus? (6 points)
Answer:
acc to formula= F= G m1m2/rsq
mass of Uranus= F×r sq/G×m
M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21
=3×10^25-8×7614×7614/667×301×10^-2-11+21-2
=173918988×10^11/200767
=866×10^11(approx)
write any three utilities of plastics
Explanation:
container, bottles, boxes, cups
define prism and itz colo plz tell me fast
Answer:
A prism is a clear crystal that refracts light
Explanation:
Which are uses of convex mirrors? Check all that apply.
magnifying mirrors for putting on makeup
side-view mirrors on vehicles
hallway safety mirrors
focusing automobile headlights
lenses in sunglasses
Answer:
B. Side-view mirrors on vehicles
C. Hallway safety mirrors
E. Lenses in sunglasses
Explanation:
Trust Me, Look At Attachment.
Answer:
2, 3, and 5 on Edge, 2022.
Explanation:
I had this question on Edge.
(See the attachment below.)
The rest of the answers are:
O Slide 8 - Sample Response: The image seems to be behind the mirror, but nothing is really there.
O Slide 9 - Concave
O Slide 10 - Same size
A student lifts their 75 N backpack 0.50 m onto their chair. How much work is done?
Answer:
37.5 J
Explanation:
With work done equation: W=Fs
W=75*0.50=37.5 J
or use mgh=(75)(0.5) which is the same
Which of the following planets were the ancient Greeks able to see and make careful observations of?
Saturn and Neptune
Neptune and Uranus
Mars and Venus
Mercury and Uranus
Answer:
Neptune and Uranus
Explanation:
Did a quiz on this not to long ago
a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?
Answer:
L = 2 J.s
Explanation:
The angular momentum of an object travelling in a horizontal circle is given by the following formula:
[tex]L = mvr[/tex]
where,
L = Angular momentum = ?
m = mass = 0.8 kg
v = linear speed = rω
r = radius of circular path = length of rope = 0.5 m
ω = Angular Speed = 10 rad/s
therefore,
[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]
L = 2 J.s
explain the role of good marketing in the success of business
Answer:
I am joker if you are mad x_________-..............,,,,,,........ €£
PLEASE HELP!!!!
ITS URGENT!
Answer:
the answer is D
Explanation:
A Body OF Volume 36cc Floats With 3/4 of its volume submerged in water . The density Of Body is
1. 0.25g/cc 2. 0.75g/cc
3. 0.9g/cc 4. 0.1g/cc
Answer:
Density of body = 0.25g/cc
Explanation:
Given:
Volume submerged in water = 3/4
Find:
Density Of Body
Computation:
Density of body = fraction of body in liquid x density of water
Density of body = [1-3/4]1
Density of body = 0.25g/cc
The velocity of an object with mass = 2kg is given as a function of time:
V = 2ti + 4[tex]t^{2}[/tex]j
Find the force acting on the object at t = 2 seconds.
Answer:
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
Explanation:
Given that object has a constant mass in time, the force acting on the object ([tex]\vec F[/tex]), in newtons, is defined by following expression:
[tex]\vec F = m\cdot \vec a[/tex] (1)
Where:
[tex]m[/tex] - Mass, in kilograms.
[tex]\vec a[/tex] - Acceleration, in meters per square second.
By definition of acceleration, we know that:
[tex]\vec a = \frac{d}{dt} \vec v[/tex] (2)
Let suppose that given vector velocity is expressed in meters per second. If we know that [tex]m = 2\,kg[/tex], [tex]\vec v = (2\cdot t, 4\cdot t^{2})\,\left[\frac{m}{s} \right][/tex] and [tex]t = 2\,s[/tex], then the force acting on the object is:
[tex]\vec a = (2, 8\cdot t)\,\left[\frac{m}{s^{2}} \right][/tex]
[tex]\vec F = (4, 16\cdot t)\,[N][/tex]
[tex]\vec F = (4, 32)\,[N][/tex]
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
How many resistors are found in this circuit?
A) 0
B) 1
C) 2
D) 3
If 11,550 J heat is absorbed by a copper object when it is heated from 20.0°C to 30.0°C,
what is the mass of the copper?
The specific heat of copper is 385 J/kgK.
Answer:
The mass of the copper is 3.00kg
Explanation:
The person kicks the ball in the image below 20 meters. Suppose the soccer ball in the image is replaced by one that is twice the mass of a regular soccer ball. How could the person kick the ball the same distance as the first soccer ball?
( will give brainliest if you help! )
( no trolling or I’ll report you)
Answer:
D
Explanation:
What problem did Katherine face in checking other people’s calculations in the movie ¨Hidden figures¨
Answer:
Information from the leading mathematicians was considered "classified".
A piece of paper floats though the air towards the ground. At one point, the air resistance (Fair) on the
paper pushes up with 0.01 N of force. Force due to gravity (Fg) pulls the ball down with a force of 0.02 N.
Show your work
Answer:
-0.01N
Explanation:
I'm assuming you're asking for the net force of the paper.
0.01N - 0.02N = -0.01N
8) A force of 10 N stretches a spring 0.50 m from equilibrium. What is the value of the spring constant?
Explanation:
We use Hooke's Law, which states that,
F=kx
F- is the force in newtons
k- is the spring constant
x- is the extension of the spring in meters
Solving for k we get k=F/x
k= 10N/0.50m
=100 N/m
A person drives a car around a circular road with a constant speed of 20 m/s. The
radius of the circular road is twenty-five meters. What is the acceleration of the car?
o 20 m/s2
O 16 m/s2
O 10 m/s2
O 8 m/s2
Answer:
16 m/s^2
Explanation:
acceleration tangential = (v^2)/r
a=400/25
a=16 m/s^2
Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:
angular acceleration=acceleration tangential/r
angular acc.=16/25
angular acc.=0.64 rad/s^2
In a 1953 experiment a rocket sled went from 284 m/s to rest within 178 m. If the test subject, John Stapp, had a mass of 84.0 kg: a) what is the amount of Work done to stop the John Stapp? b) how much Force was applied to John Stapp?
A ball is thrown up at a 60 degree angle and lands in 18.5 seconds. what is the initial velocity of the ball?
[tex] \sf \bullet \: \theta = {60}^{ \circ} [/tex]
[tex] \sf \bullet \:Time \: of \: flight , \: t = 18.5 \: s[/tex]
To Find :-[tex] \bullet \sf \: Initial \: velocity , \: u[/tex]
Solution :-[tex] \bf \star\boxed{ \bf t = \dfrac{2u \: sin \theta}{g} }[/tex]
[tex] : \implies \sf 18.5 = \dfrac{2u \: sin60}{10} [/tex]
[tex] : \implies \sf \: 2u \: sin60 = 185[/tex]
[tex]: \implies \sf u = \dfrac{185 \times 2}{ \sqrt{3} \times 2 } [/tex]
[tex]: \implies \sf u = \dfrac{185}{1.73} [/tex]
[tex] \bf: \implies u = 107 \: m {s}^{ - 1} [/tex]
[O.04H]The table below shows the use of some energy production methods over time.
Type of energy Average energy used annually in the past (in million tons) Average energy used annually at present (in million tons) Average energy most likely to be used annually in the future (in million tons)
Oil 200 4000 300
Gas 100 2500 700
Coal 1000 2500 1500
Wind 0.1 50 2000
Hydropower 0.7 60 150
Tidal power 0.02 50 500
Based on the table, which of these statements best describes the impact of different methods of energy production on the environment in the past?
There was a rise in the height of tides.
There was a rise in greenhouse gases.
The coastal ecosystem was harmed.
The coastal areas were highly polluted.
I think The coastal areas were highly polluted
Answer:
i think its greenhouse gases may increase
Explanation:
Light passing through a double slit
with separation d = 2.42x10-5 m
creates its second maximum (m = 2)
at an angle of 2.74 deg. What is the
wavelength of the light, IN
NANOMETERS?
(Hint: The answer will be between 400 and
700.) (Unit = nm)
Answer:
573
Explanation:
totally not stealing previous answer cause I know it's right
The wavelength of the light is 578.45 nm.
Light passing through a double slit with separation is given as
d = 2.42 × 10⁻⁵ m.
Line number m = 2
Angle θ = 2.74°
How wavelength is calculated and what is the wavelength of the light?The distance between two sound waves i.e., crest and trough is called the wavelength.
To find the wavelength, here we use the formula as,
sin θ = Line number × λ ÷ ( distance )
By substituting all the given values,
Sin ( 2.74° ) = 2 × λ ÷ ( 2.42 × 10⁻⁵ )
Rearranging the equation,
λ= (Sin ( 2.74° ) × ( 2.42 × 10⁻⁵ ) ) ÷ (2)
λ = 578.45 nm.
Thus, wavelength λ of the light is 578.45 nm.
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Calculate the acceleration of a school bus that was stopped at a bus stop and then traveled down the road at a speed of 15 meters per second in 13 seconds