Help please this is due very SOOON!!​

We know these triangles are congruent with the missing side, N would be equal to 15.

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We know these triangles are congruent.

To find the missing side, N

ΔABC ≅ΔQRS

AC/QS = BC/RS

2/5 = 6/n

n = 6 x 5/2

n = 30/2

n = 15

Thus, the value of N is 15.

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Answer:

14 × (19 + 6)

hope it helps

The expression represents the total number of cans of beans Mr. Jenkins is, (19+6)×14, So Option B is correct.

An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.

For example, 2x+3

Given that,

Mr. Jenkins has 19 cases of beans

He also has 6 cases of beans in the stock room

There are 14 cans of beans in each case

Expression for total number of beans = ?

Total number of beans  = Total number of cases ×beans in each case

Total number of beans = (beans in grocery store+beans in stock room)×14

Total number of beans = (19 +6) × 14

Hence, the expression is  (19 +6) × 14

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Answer:

option is B)

Step-by-step explanation:

2x is a perfect square. but x is not a perfect square, this brings us to the conclusion tht prob x is 2.

2x = 4

hence correct option is B) 4x is a perfect square, as 4x4=16, which is a perfect square...

Answer:

P(white ball)=0.29

Step-by-step explanation:

12 yellow balls

5 red balls

7 white balls

12+5+7=24

so 24 balls in the bag

[tex]\frac{7}{24}[/tex]=0.2916

rounded to the nearest is 0.29

Answer:

Intersection

Step-by-step explanation:

The intersection of two set A and B is defined as the elements which can be found in both set A and set B.

For instance :

A = {1, 3, 5, 7, 9, 11}

B = {2, 4, 6, 7, 8, 9, 10}

The intersection of the two sets A and B denoted as ;

AnB = {7, 9}

Answer:

27.95 and 34.05 are compatible because when you add up the decimals, the equal 0, which makes it easier to add. 27. 95 + 34.05 = 61.00.

Same with 19.37 and 21.63, it adds up to 40.00

The answer to all of this would be 101.00

Answer:

  [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]   = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Step-by-step explanation:

Given expression

            [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]

we know that the algebra formula

[tex]\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }[/tex]

[tex]\sqrt{\frac{2x^{5} }{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{9} \sqrt{2} }[/tex]

          = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}}[/tex] :

[tex] \underline{ \underline{ \text{To \: prove}}} : [/tex]

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd} = \sqrt{(a - b - c)(b - c - d)} } [/tex]

[tex] \underline{ \underline{ \text{Solution}}} : [/tex]

Left hand side ( L.H.S ) :

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd}} [/tex]

⟶ [tex] \tt{ \sqrt{d {k}^{3} \cdot \: d {k}^{2} } - \sqrt{d {k}^{2} \cdot \: dk } - \sqrt{dk \cdot \: d} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} {k}^{5} } - \sqrt{ {d}^{2} {k}^{3} } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: {k}^{2} \cdot \: k } - \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: k \: } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} } \cdot \sqrt{ {k}^{2} } \cdot \: \sqrt{ {k}^{2} } \cdot \: \sqrt{k} } - \sqrt{ {d}^{2} }\cdot \: \sqrt{ {k}^{2}} \cdot \: \sqrt{k} \: - \sqrt{ {d}^{2} } \cdot \: \sqrt{k} [/tex]

⟶ [tex] \tt{d {k}^{2} \sqrt{k} - dk \sqrt{k} - d \sqrt{k} }[/tex]

⟶ [tex] \tt{ d\sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

Right Hand Side ( R.H.S) :

[tex] \tt{ \sqrt{(a - b - c)(b - c - d)}} [/tex]

⟶ [tex] \tt{ \sqrt{(d {k}^{3} - d {k}^{2} - dk)( d{k}^{2} - dk - d)} }[/tex]

⟶ [tex] \tt{ \sqrt{ \{dk( {k}^{2} - k - 1) \} \: \{d( {k}^{2} - k - 1) \}} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k( {k}^{2} - k - 1) ^{2} } } [/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k } \cdot \: \sqrt{ {( {k}^{2} - k - 1)}^{2} } } [/tex]

⟶[tex] \tt{ \sqrt{ {d}^{2} } \cdot \: \sqrt{k} \cdot \: \sqrt{( {k}^{2} - k - 1) ^{2} } }[/tex]

⟶ [tex] \tt{d \sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

L.H.S = R.H.S

Hence , Proved !

Hope I helped ! ♡

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Answer:

x= 8 and y= 8 square root of 2

Step-by-step explanation:

Answer:

wht

!?

............

..............

..

.

Step-by-step explanation:

AB = 72 so, then FB would be half of that

so 72 divided by 2 would be 36

5x+1=36 then do substitution

-1 from both sides (from +1 you gotta do the inverse)

5x = 35

divide 5 from both sides because in between 5 and x is a times so the inverse of that is divide

x = 7

Answer:

He made a profit of 40-32 = Rs 8 per copy.

He got a 25% profit in the business of copies

Step-by-step explanation:

Newton buys and sells copies in his business. He bought 12 dozen = 12*12=144 copies in Rs 4320.

He also has Rs 288 in expenses to bring the copies to his shop, thus the total cost is 4320+288=4608.

Each copy finally cost 4608/144 = Rs 32.

He sold all copies for Rs 5760, at 5760/144= Rs 40 each.

Therefore, he made a profit of 40-32 = Rs 8 per copy.

The total profit in his business of copies was 5760 - 4608= 1152

This is a percentage of:

[tex]\frac{1152}{4608}*100 = 25\%[/tex]

Answer:

3/2

Step-by-step explanation:

Answer:5/9

Step-by-step explanation:

4/9+1/9

add 1 to 4

5/9

Answer: X = 1

Y= 5

Step-by-step explanation:

Plug in y = 3x + 2 in the Y coordinate to find X

-4x + 4(3x + 2) = 16

Now you can solve for X

X = 1

Then plug in 1 in the X coordinate to find Y

-4(1)+ 4y= 16

Now you can solve for Y

Y= 5

YOUR WELCOME

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

Answer: D-reduced by a factor 1/3

Step-by-step explanation:

got it correct on edge 2021

Answer:

B - The values of both x and y will be real numbers greater than or equal to 0.

The answer choice that best describes the values of x and y is B - The values of both x and y will be real numbers greater than or equal to 0.

Given that peaches are being sold for $2 per lb.

If we define x as the number of pounds that you buy, and y as the cost of these peaches, we can write the function:

y = $2*x

Therefore, the best description of the values of x and y is found in option B. The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.

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Answer:

4, 6/9    sry if wrong

Step-by-step explanation:

Answer:5.25

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given costs:

Sum of the costs:

Average cost is sum divided by number:

Answer:

[tex]\frac{1}{2\sqrt{5} }[/tex]

Step-by-step explanation:

Let, [tex]\text{sin}^{-1}(\frac{x}{6})[/tex] = y

sin(y) = [tex]\frac{x}{6}[/tex]

[tex]\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})[/tex]

[tex]\frac{d}{dx}\text{sin(y)}=\frac{1}{6}[/tex]

[tex]\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}[/tex] ---------(1)

[tex]\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}[/tex]

[tex]\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}[/tex]

cos(y) = [tex]\sqrt{1-\text{sin}^{2}(y) }[/tex]

          = [tex]\sqrt{1-(\frac{x}{6})^2}[/tex]

          = [tex]\sqrt{1-(\frac{x^2}{36})}[/tex]

Therefore, from equation (1),

[tex]\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}[/tex]

Or [tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}[/tex]

At x = 4,

[tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}[/tex]

[tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}[/tex]

                   [tex]=\frac{1}{6\sqrt{\frac{36-16}{36}}}[/tex]

                   [tex]=\frac{1}{6\sqrt{\frac{20}{36} }}[/tex]

                   [tex]=\frac{1}{\sqrt{20}}[/tex]

                   [tex]=\frac{1}{2\sqrt{5}}[/tex]

Step-by-step explanation:

-70x^4 + 30x

= 10x(-7x^3 + 3)

ANSWER: 10x(-7x^3 + 3)

Answer:

The two points are (0,1) and (0.75, 0)

Step-by-step explanation:

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Answer:

24

Step-by-step explanation:

x = 8, y = 3, z = 2

(1/4) x {8[2(3)+3(2)]}

(1/4) x {8(6 + 6)}

(1/4) x {48 + 48} (by distributing)

1/4 x 96

= 24

Answer:

k = i√ 5 , -i√ 5

Step-by-step explanation:

3 + kx^2 + 2 = ?

3 + k(1)^2 + 2 = ?

5 + k(1)^2 = ?

5 + k^2 = ?

k^2 = -5

k = i√ 5 , -i√ 5

Answer:

A = 2167.73 cm²

Step-by-step explanation:

Given that,

A trailer ramp is in the shape of a triangular prism.

the height of the ramp, h = 14 inches

The volume of the ramp, V = 4704 inches²

We need to find the area of the base of the trailer ramp.

The volume of the triangular prism is given by :

[tex]V=A\times h[/tex]

A is area of base and h is height

[tex]A=\dfrac{V}{h}\\\\A=\dfrac{4704}{14}\\\\A=336\ \text{inches}^2[/tex]

or

A = 2167.73 cm²

So, the area of the base of the ramp is 2167.73 cm².

Answer:

8(x-y);use x=5,and y=2

8(5 - 2) = 8(3) = 24

answer

24

Step-by-step explanation:

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