Help! I am stuck and can’t find this anywhere!

Answer:

1250 Meters

Step-by-step explanation:

75 kilometers divided by 60 minutes is 1.25 kilometers per minute.

1 kilometer = 1000 meters

Answer:

75km/hr =75000

60 sec =1min,60 min=1hr

75000÷60=1250m

Answer: 88 gallons

Step-by-step explanation:

Every 2 vanillas = 11 chocolates

so 16 vanillas = 88 chocolates

i did this by multiplying both numbers by 8

sorry if this is wrong

Step-by-step explanation:

(I) A number which can be expressed in the form m/n, where m and n are integers and n is not equal to zero, is called a Rational Number .

(ii) If the integers m and n have no common divisor other than 1 and n is positive, then the rational number m/n is said to be in the Simplest form .

(iii) Two rational numbers are said to be equal, if they have the same Simplest form .

(iv) If m is a common divisor of x and y, then x/y = (x ÷ k)/( y ÷ k) .

(v) The standard form of -1 is -1/1

(vi) If m/n is a rational number, then n cannot be 0

(vii) Two rational numbers with different numerators are equal, if their numerators are in the same ratio as their denominators.

Answer: D trust me it is 100

Step-by-step explanation:

The maximum area the goat can graze is 100Tt ft2​, the correct option is D.

Given

A goat is tethered to a rope that is 10 ft. long.

The area of the circle is equal to the pie times of the square of the radius of the circle.

The maximum area that the goat can graze in the area of the circle that can be formed due to its circular movement.

The length of the rope represents the radius of the circle, so that;

[tex]\rm Area \ the \ goat \ can \ graze =r^2 \times Tt\\\\ Area \ the \ goat \ can \ graze =(10)2 \times Tt\\\\Area \ the \ goat \ can \ graze =100 \ Tt\\[/tex]

Hence, the maximum area the goat can graze is 100Tt ft2​.

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Consider that,

x^2+4x+4 = (x+2)(x+2)

x^2+7x+10 = (x+2)(x+5)

Dividing those expressions leads to

(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)

The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.

Step-by-step explanation:

Hoping this will help you on your journey through brainly!

Answer:

[tex]\cot 330^{\circ} = -\sqrt{3}[/tex]

Step-by-step explanation:

The cotangent function can be rewritten by trigonometric relations, that is:

[tex]\cot 330^{\circ} = \frac{1}{\tan 330^{\circ}} = \frac{\cos 330^{\circ}}{\sin 330^{\circ}}[/tex] (1)

By taking approach the periodicity properties of the cosine and sine function (both functions have a period of 360°), we use the following equivalencies:

[tex]\sin 330^{\circ} = \sin (-30^{\circ}) = -\sin 30^{\circ}[/tex] (2)

[tex]\cos 330^{\circ} = \cos (-30^{\circ}) = \cos 30^{\circ}[/tex] (3)

By (2) and (3) in (1), we have following expression:

[tex]\cot 330^{\circ} = -\frac{\cos 30^{\circ}}{\sin 30^{\circ}}[/tex]

If we know that [tex]\sin 30^{\circ} = \frac{1}{2}[/tex] and [tex]\cos 30^{\circ} = \frac{\sqrt{3}}{2}[/tex], then the result of the trigonometric expression is:

[tex]\cot 330^{\circ} = -\frac{\frac{\sqrt{3}}{2} }{\frac{1}{2} }[/tex]

[tex]\cot 330^{\circ} = -\sqrt{3}[/tex]

The exact value of cot 330° with a rational denominator is √3.

To find the exact value of cot 330°, we can first determine the reference angle. The reference angle for 330° is 30°, as it is the angle between the terminal side of 330° and the x-axis.

Cotangent (cot) is the reciprocal of the tangent function, so we need to find the tangent of the reference angle, which is tan 30°. The tangent of 30° is √3/3.

Since cot is the reciprocal of tan, the cotangent of 330° is the reciprocal of √3/3, which is 3/√3.

To rationalize the denominator, we multiply the numerator and denominator by the conjugate of the denominator, which is √3.

(3/√3) x (√3/√3) = 3√3/3

Simplifying further, we can cancel out the common factor of 3:

(3√3/3) = √3

Therefore, the exact value of cot 330° with a rational denominator is √3.

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Given:

The figure of an algebraic tiles model of an inequality.

To find:

The inequality for the given model.

Solution:

On the left hand side of the inequality sign in the model we have 8 tiles of x and 12 tiles of 1. So,

[tex]LHS=8(x)+12(1)[/tex]

[tex]LHS=8x+12[/tex]

On the right hand side of the inequality sign in the model we have 12 tiles of -1. So,

[tex]RHS=12(-1)[/tex]

[tex]RHS=-12[/tex]

Now, the inequality for the given model is:

[tex]8x+12\geq -12[/tex]

Therefore, the required inequality for the given model is [tex]8x+12\geq -12[/tex].

Answer:

A

Step-by-step explanation:

Answer:

6761/320

Step-by-step explanation:

[(51/2)÷32/3]+14/5

=6761/320

Answer:

A- Quadrant one.

B- Quadrant three.

Step-by-step explanation:

So, the quadrants go counter-clockwise, starting at the top right which is Quadrant one. Therefore, A is in one. Using that information, we can assume that B is in Quadrant three.

Answer:

Step-by-step explanation:

[tex]y^2 = 100 + 196 = 296\\\\y = \sqrt{296} \\\\y = 17.20[/tex]

Answer: 37

8(4)+11-3(2)

32+11-6

43-6

37

Answer:

16

Step-by-step explanation:

The area of a triangle is

A =1/2 bh  where b is the base length  and h is the height

Substitute the values in

69.6 = 1/2 ( 8.7) * p

69.6 = 4.35p

Divide each side by 4.35

69.6/4.35 = p

16 = p

The formula for the area of a triangle is: A = 1/2 * base * height.

Using this formula, let's plug in what we know.

69.6 = 1/2 * 8.7 * height

Next, we'll go ahead and get rid of that 1/2 by multiplying everything by its reciprocal, 2.

139.2 = 8.7 * height

Then, all that's left is to divide both sides by 8.7.

Height = 16 yards

Hope this helps!! :)

Answer:

use Pythagorean theorem:

[tex]a^2+b^2=c^2\\9^2+12^2=18^2\\81+144=324\\225\neq 324[/tex]

it's not a right triangle

Answer:3

Step-by-step explanation:

Answer:

Step-by-step explanation:

log(3) = 0.477

log(8.2) = 0.913

log(0.04) = -1.397

Answer:

(x + 4)(5x - 4)

Step-by-step explanation:

[tex]5x^2 + 16x – 16 \\ = 5x^2 + 20x - 4x– 16 \\ = 5x(x + 4) - 4(x + 4) \\ = (x + 4)(5x - 4)[/tex]

Answer:

 (5x - 4) • (x + 4)

Step-by-step explanation:

Multiply the coefficient of the first term by the constant   5 • -16 = -80

Find two factors of  -80  whose sum equals the coefficient of the middle term, which is   16 .

Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -4  and  20  

                    5x2 - 4x + 20x - 16

Add up the first 2 terms, pulling out like factors :

                   x • (5x-4)

             Add up the last 2 terms, pulling out common factors :

                   4 • (5x-4)

Add up the four terms of step 4 :

                   (x+4)  •  (5x-4)

            Which is the desired factorization

Answer:

In order of increasing angle measure, the fourth roots of -3 + 3√3·i are presented as follows;

[tex]\sqrt[4]{6} \cdot \left[cos\left({-\dfrac{\pi}{12} } \right) + i \cdot sin\left(-\dfrac{\pi}{12} } \right) \right][/tex]

[tex]\sqrt[4]{6} \cdot \left[cos\left({\dfrac{5 \cdot \pi}{12} } \right) + i \cdot sin\left(\dfrac{5 \cdot\pi}{12} } \right) \right][/tex]

[tex]\sqrt[4]{6} \cdot \left[cos\left({\dfrac{11 \cdot \pi}{12} } \right) + i \cdot sin\left(\dfrac{11 \cdot\pi}{12} } \right) \right][/tex]

[tex]\sqrt[4]{6} \cdot \left[cos\left({\dfrac{17 \cdot \pi}{12} } \right) + i \cdot sin\left(\dfrac{17 \cdot\pi}{12} } \right) \right][/tex]

Step-by-step explanation:

The root of a complex number a + b·i is given as follows;

r = √(a² + b²)

θ = arctan(b/a)

The roots are;

[tex]\sqrt[n]{r}[/tex]·[cos((θ + 2·k·π)/n) + i·sin((θ + 2·k·π)/n)]

Where;

k = 0, 1, 2,..., n -2, n - 1

For z = -3 + 3√3·i, we have;

r = √((-3)² + (3·√3)²) = 6

θ = arctan((3·√3)/(-3)) = -π/3 (-60°)

Therefore, we have;

[tex]\sqrt[4]{-3 + 3 \cdot \sqrt{3} \cdot i \right)} = \sqrt[4]{6} \cdot \left[cos\left(\dfrac{-60 + 2\cdot k \cdot \pi}{4} \right) + i \cdot sin\left(\dfrac{-60 + 2\cdot k \cdot \pi}{4} \right) \right][/tex]

When k = 0, the fourth root is presented as follows;

[tex]\sqrt[4]{6} \cdot \left[cos\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 0 \cdot \pi}{4} \right) + i \cdot sin\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 0 \cdot \pi}{4} \right) \right] \\= \sqrt[4]{6} \cdot \left[cos\left({-\dfrac{\pi}{12} } \right) + i \cdot sin\left(-\dfrac{\pi}{12} } \right) \right][/tex]

When k = 1 the fourth root is presented as follows;

[tex]\sqrt[4]{6} \cdot \left[cos\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 1 \cdot \pi}{4} \right) + i \cdot sin\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 1 \cdot \pi}{4} \right) \right] \\= \sqrt[4]{6} \cdot \left[cos\left({\dfrac{5 \cdot \pi}{12} } \right) + i \cdot sin\left(\dfrac{5 \cdot\pi}{12} } \right) \right][/tex]

When k = 2, the fourth root is presented as follows;

[tex]\sqrt[4]{6} \cdot \left[cos\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 2 \cdot \pi}{4} \right) + i \cdot sin\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 2 \cdot \pi}{4} \right) \right] \\= \sqrt[4]{6} \cdot \left[cos\left({\dfrac{11 \cdot \pi}{12} } \right) + i \cdot sin\left(\dfrac{11 \cdot\pi}{12} } \right) \right][/tex]

When k = 3, the fourth root is presented as follows;

[tex]\sqrt[4]{6} \cdot \left[cos\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 3 \cdot \pi}{4} \right) + i \cdot sin\left(\dfrac{-\dfrac{\pi}{3} + 2\cdot 3 \cdot \pi}{4} \right) \right] \\= \sqrt[4]{6} \cdot \left[cos\left({\dfrac{17 \cdot \pi}{12} } \right) + i \cdot sin\left(\dfrac{17 \cdot\pi}{12} } \right) \right][/tex]

Answer:

Step-by-step explanation:

Just took the test.

1) 4sqrt6 cis(pie/6)

2) 4sqrt6 cis (2pie/3)

3) 4sqrt6 cis(7pie/6)

4) 4sqrt6 cis (5pie/3)

Answer:

Median: 10

Mean: 9

Range: 15

Step-by-step explanation:

Have a good day :)

Here Is your answer!!!!

Answer:

1/3

Step-by-step explanation:

3x3= 9

Make 3/9 a fraction and simplify it and it would give you 1/3

Step-by-step explanation:

Rewrite the expression 1/x^2/3 in the form x^nRewrite the expression 1/x^2/3 in the form x^n

An expression is defined as a set of numbers, variables, and mathematical operations. The given expression can be written in the form of xⁿ as x⁻⁰°⁶⁶.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The given expression  [tex]\dfrac{1}{x^{\frac23}}[/tex] can be written in the form of xⁿ using the exponential property 1/x=x⁻¹. Therefore, the expression can be rewritten as,

[tex]\dfrac{1}{x^{\frac23}}\\\\= x^{-\frac23}[/tex]

= x⁻⁰°⁶⁶

Hence, the given expression can be written in the form of xⁿ as x⁻⁰°⁶⁶.

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