HELP!! :))
I’ll give Brainliest to whoever balances the equation and says what the theoretical and percent yields are of the equation :)

Answer:

k

Explanation:

that is shide rong and shide right

Answer

Rise: The kingdom of D'mt populated the majority of the Northern horn which had developed much agriculture and expansion of trade with other empires like Egypt. After the fall of the D'mt kingdom many small kingdoms took its place and slowly came together as one large kingdom called, Aksum. Aksum rose to power in the first century after the son of a Solomon queen had expanded to the land near the red sea.

Fall: The empire had become isolated from civilizations when it came to trade after battling Arabian armies. Their religion segregated them and caused the downfall of their power over the trading ports on the Red Sea.

For more information, go here: https://storymaps.arcgis.com/stories/9b7b377398724be99a0d94dfa9f55550

Answer:

[tex]fro \: the \: equation : \\ 6 \: moles \: of \: nitric \: acid \: produce \: 2 \: moles \: of \: water \\ 1.1 \: moles \: of \: nitric \: acid \: react \: with \: ( \frac{1.1}{6} \times 2) \: moles \\ = 0.367 \: moles \: of \: water \\ 1 \: mole \: of \: water \: weighe \: 18 \: g \\ 0.367 \: moles \: will \: weigh \: ( 0.367 \times 18) \: g \\ = 6.6 \: g \: of \: water[/tex]

Answer:

computers

Explanation:

Answer:D). C3H6N

Explanation:applesause

Answer:

2 experimental

Explanation:

Answer:

Your answer I think would be 3,764,000 .If Im wrong please correct me and comment below.

I got my answer by converting 3,764 liters to millileters using a converter calculator

then I rounded it to the nearest whole number using the rounding calculator from calculator soup. This has worked for me in the past.

Hope this helps, good luck!

Answer:

2.7 g/cm³

Explanation:

Step 1: Calculate the mass of kerosene

The mass of the full beaker (mFB) is equal to the sum of the masses of the empty beaker (mEB) and the mass of the kerosene (mK).

mFB = mEB + mK

mK = mFB - mEB

mK = 60 g - 20 g = 40 g

Step 2: Calculate the density of kerosene

Density (ρ) is an intrinsic property of matter. It can be calculated as the quotient between the mass of kerosene and its volume.

ρ = m/V

ρ = 40 g/15 cm³ = 2.7 g/cm³

Answer:

83.33 m/s^2

Explanation:

Acceleration is defined as the rate of change of velocity.

So if we know that at the beginning an object has a velocity V1.

And after a time T, the object has a velocity V2, then the average acceleration in that time interval can be calculated as:

A = (V2 - V1)/T

In this case, we know that the initial speed was 5,000 m/s

And after a time of 60 s, the velocity is 10,000 m/s

Then we have:

V1 = 5,000 m/s

T = 60s

V2 = 10,000 m/s

Then the average acceleration is:

A = (10,000 m/s - 5,000 m/s)/60s = 83.33 m/s^2

Answer:

The molecular formula of sodium choride is NaCl

Answer: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.

Explanation:

edge

Answer:

Your answer is A.

Explanation:

Answer:

The empirical formula of the compound is [tex]Mg_3N_2[/tex].

Explanation:

Mass of magnesium in compound = 0.273 g

Mass of nitrogen in the compound = 0.105 g

Moles of magnesium =[tex]\frac{0.273 g}{24.305 g/mol}=0.0112 mol[/tex]

Moles of nitrogen = [tex]\frac{0.105 g}{14.0067 g/mol}=0.00750 mol[/tex]

Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.

Magnesium [tex]=\frac{0.0112 mol}{0.00750 mol}=1.5[/tex]

Nitrogen [tex]=\frac{0.00750mol}{0.00750 mol}=1[/tex]

The empirical formula of a compound:

[tex]Mg_{1.5}N_1=Mg_{\frac{15}{10}}N_1=Mg_{15}N_{10}=Mg_3N_2[/tex]

The empirical formula of the compound is [tex]Mg_3N_2[/tex].

Answer:

The reaction is endothermic

Explanation:

we know that the reactants had to get energy from its surroundings which means that the reaction is endothermic

Answer:

Physical property

Explanation:

As the piece of paper is being colored, no change has really occurred, in the end it's still a paper, unless a substance was mixed with it or etc then it would be considered to be a chemical property but not in this case.

Answer:

B: turns litmus red

Explanation:

Looking at the given options;

An acid tastes sour and not bitter and so option A is not correct.

Acid turns blue litmus paper red and not any litmus paper. Thus option B is correct.

Acid has a PH < 7. Thus option C is not correct.

An acid feels just wet while it is a base that feels slippery to touch. Option D is not correct.

Answer:0.94

Explanation:

Answer:

[tex]x_{SO_3}=0.82\\\\x_{SO_2} =0.18\\[/tex]

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to solve this problem by using the Dalton's law which allows us to calculate the mole fractions by dividing the partial pressures over the total pressure. In such a way, we plug in the given pressures of sulfur trioxide (SO3) and sulfur dioxide (SO2) to obtain:

[tex]x_{SO_3}=\frac{1.45atm}{1.45atm+0.32atm} =0.82\\\\x_{SO_2}=\frac{0.32atm}{1.45atm+0.32atm} =0.18\\[/tex]

Best regards!

Answer:

You depend on each other and need the nonliving things in your home, like food, water, air, and furniture. Living things need nonliving things to survive. Without food, water, and air, living things die. Sunlight, shelter, and soil are also important for living things.

Explanation: i dunno if this is right or not ;-; but i tried UnU

Answer:

first, find the density of sand grains by using a small weighing scale. put at least 10 measuring spoons of sand on the scale. calculate the density by its formula d = m/v. this result can count the volume whole sand grains based on its weights

You can count the grains of sand ( estimated value ) by ;  determining an estimate of the density and mass of the sand grains in the aquarium.

Since the volume of the tank = volume of the sand therefore the volume of the sand grains in the aquarium will be 100 liters, next is to determine the mass of the sand grains by using a weighing scale to take the mass of at least 20 measuring spoons of sand.

Find the density of the sand grains using the formula for determining, Density = mass / volume . with this result, We can determine an estimate of the number of sand grains with results gotten from the density and mass of the sand grains

To determine the number of atoms in a sample matter we also determine the mass and density of the matter just as with the counting of sand grains in the tank. which we can then use to determine an estimate of the number of atoms contained in the matter.

Hence we can conclude that you can count the grains of sand ( estimated value ) by; determining the density and mass of the sand grains in the aquarium.

Learn more : https://brainly.in/question/32356304

Given

P1 = 1 Atm ( at stp)

V1 = 3.00 L

V2 = 3.20 L

P2 = ?

We know that,

at constant temperature

P1V1 = P2V2

1 × 3 = 3.2 × P2

P2 = 3/3.2

P2 = 0.9375 Atm

pressure at 3.2 L is 0.9375 Atm.

Answer:

40.72g of sulfuric acid are needed

Explanation:

When sulfuric acid, H₂SO₄, is neutralized by lead (IV) hydroxide, Pb(OH)₄, Lead (IV) sulfate, Pb(SO₄)₂ and water as follows:

2 H₂SO₄ + Pb(OH)₄ → Pb(SO₄)₂ + 4H₂O

To solve this question we must find the moles of 57.18g of Pb(SO₄)₂. As 2 moles of H₂SO₄ produce 1mol Pb(SO₄)₂ we can find the moles of H₂SO₄ and its mass as follows:

Moles Pb(SO₄)₂ -Molar mass: 275.23 g/mol-

57.18g * (1mol / 275.23g) = 0.2078 moles Pb(SO₄)₂

Moles H₂SO₄:

0.2078 moles Pb(SO₄)₂ * (2mol H₂SO₄ / 1mol Pb(SO₄)₂) = 0.4155 moles H₂SO₄

Mass H₂SO₄ -Molar mass: 98g/mol-

0.4155 moles H₂SO₄ * (98g / mol) =

Answer:

C7H16 + 11 O2 → 7 CO2 + 8 H2O

This is an oxidation-reduction (redox) reaction:

7 C-16/7 - 44 e- → 7 CIV (oxidation)

22 O0 + 44 e- → 22 O-II (reduction)

C7H16 is a reducing agent, O2 is an oxidizing agent.

Reactants:

C7H16

O2

Names: Dioxygen source: wikidata, accessed: 2019-09-07, Oxygen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, Oxygen (liquefied) source: ICSC, accessed: 2019-09-04

Appearance: Odourless compressed gas source: ICSC, accessed: 2019-09-04; Liquefied gas. colourless-to-blue extremely cold liquid source: ICSC, accessed: 2019-09-04

Products:

CO2

Names: Carbon dioxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, {{plainlist| source: wikipedia, accessed: 2019-09-27, CO2 source: wikidata, accessed: 2019-09-02

Appearance: Colorless gas source: wikipedia, accessed: 2019-09-27; Odourless colourless compressed liquefied gas source: ICSC, accessed: 2019-09-04; Colorless, odorless gas. [Note: Shipped as a liquefied compressed gas. Solid form is utilized as dry ice.] source: NIOSH NPG, accessed: 2019-09-02

H2O – Water, oxidane source: wikipedia, accessed: 2019-09-27

Other names: Water (H2O) source: wikipedia, accessed: 2019-09-27, Hydrogen hydroxide (HH or HOH) source: wikipedia, accessed: 2019-09-27, Hydrogen oxide source: wikipedia, accessed: 2019-09-27

Appearance: White crystalline solid, almost colorless liquid with a hint of blue, colorless gas source: wikipedia, accessed: 2019-09-27

Search by reactants (C7H16, O2)

1 O2 + C7H16 → H2O + CO2

2 O2 + C7H16 → H2O + CO

3 O2 + C7H16 → H2O + CO2 + CO

4 O2 + C7H16 → H2 + CO2

Search by products (CO2, H2O)

12345678910...

1 HCl + CaCO3 → H2O + CO2 + CaCl2

2 HCl + NaHCO3 → H2O + CO2 + NaCl

3 O2 + CH4 → H2O + CO2

4 NaHCO3 → H2O + CO2 + Na2CO3

5 H2SO4 + KMnO4 + (COOH)2 → H2O + CO2 + K2SO4 + MnSO4

6 O2 + C3H8 → H2O + CO2

7 H2SO4 + K2CO3 → H2O + CO2 + K2SO4

8 O2 + C2H6 → H2O + CO2

9 CH3COOH + NaHCO3 → H2O + CO2 + CH3COONa

10 HCl + Na2CO3 → H2O + CO2 + NaCl

12345678910...

Search by reactants (C7H16, O2) and by products (CO2, H2O)

1 O2 + C7H16 → H2O + CO2

2 O2 + C7H16 → H2O + CO2 + CO

Explanation:

Answer:

Explanation:

Atoms are neutral; they contain the same number of protons as electrons. A neutral sodium atom, for example, contains 11 protons and 11 electrons. Atoms that gain extra electrons become negatively charged.

Answer:

22.2 g of MgF₂

Explanation:

We star from the reaction:

NaF → sodium fluoride

Mg → Magnesium

2NaF  +  Mg →  MgF₂  +  2Na

2 moles of sodium fluoride react to 1 mol of Mg in order to produce 1 mol of magnesium fluoride and 2 moles of sodium.

We convert mass of the reactant to moles:

30 g . 1mol / 41.98 g = 0.715 mol

We assume that Mg is in excess

As ratio is 2:1, if we have 0.715 moles of NaF we may produce the half of moles, of MgF₂

0.715 mol /2 = 0.357 moles of MgF₂

We convert moles to mass: 0.357 mol . 62.30g /mol = 22.2 g

I think it's 80 . 12

pls tell me if correct