Answer:
1.08 g of water
Explanation:
The balanced chemical equation for the reaction of combustion of methane (CH₄) is the following:
CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(g)
According to the equation, 1 mol of CH₄ reacts with 2 moles of O₂. We convert from mol to grams by using the molar masses:
1 mol CH₄ = (1 x 12 g/mol) + (4 x 1 g/mol) = 16 g
2 mol O₂ = 2 x (2 x 16 g/mol) = 64 g
2 mol H₂O = 2 x ((2 x 1 g/mol) + 16 g/mol)= 36 g
From the masses of reactants (CH₄ and O₂), we can see that the stoichiometric ratio is 64 g O₂/16 g CH₄ = 4.
First, we have to identify which reactant is the limiting reactant. We can compare the stoichiometric ratio with the actual reactants ratio (the masses of reactants we have):
1.92 g O₂/0.80 g CH₄ = 2.4
As 4>2.4, we can conclude that O₂ is the limiting reactant.
Now, we consider the stoichiometric ratio between the limiting reactant (64 g O₂) and the product we have to calculate (36 g H₂O), and we multiply the ratio by the actual mass of O₂:
1.92 g O₂ x 36 g H₂O/64 g O₂ = 1.08 g
Therefore, 1.08 g of H₂O will be produced by the chemical reaction of 0.80 g of methane with 1.92 g of oxygen.
A 9.70-g piece of solid CO 2 is allowed to sublime in a balloon. The final volume of the balloon is 1.00 L at 298 K. What is the pressure of the gas inside the balloon?
a. 5.39 atmb. 2.37 102 atmc. 2.52 atmd. 0.186 atme. none of these
Answer:
a. 5.39 atm
Explanation:
Pressure = ?
Volume = 1 L
Temperature = 298 K
Mass = 9.70g
The formular relating these variables is the ideal gas equation;
PV = nRT
where R = gas constant = 0.082057 L.atm.K-1.mol-1
n can be obtained from the formular below;
n = mass / molar mass = 9.70 / 44
n = 0.2205 mol
P = nRT / V
P = 0.2205 * 0.082057 * 298 / 1
P = 5.392 atm
The correct option is option A.
A container at STP contains 64.0O grams of oxygen. How many liters of O2(g) are in the container?
Answer:
44.80
Explanation:
How much heat is needed to increase the temperature of 15g of water from 10°C to 30°C? The specific heat of water is 4.18 (J/g °C).
Answer:
H=mc∆T
H=15×4.18×20
H=1254J
3. Gasoline, coal, batteries, and logs all have chemical energy. When they burn that chemical energy will be transformed into energy.
Answer:
Thermal energy
Explanation:
When gasoline, coal, batteries and logs are all burn they transform chemical energy to thermal energy.
The chemical energy is the energy held between chemical chains and bonds within an atom.
When they combust, they release thermal energyChemical energy is a potential energy. The thermal energy is a kinetic energyIt increase the average motion of the particles in the mediumThe breaking bond when produces heat which is a form of thermal energy.which of the following is the best definition for volume
a. solids are the only matter with volume
b. all energy has volume
c. volume is the three-dimensional size of an object
d. gases do not have volume
Answer:
C
Explanation:
I hope that helps!!! it kinda gave you the answer though
When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the _______________.
Answer: equivalence point
When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the equivalence point.
The equivalence point is called the moment when the equivalents of the titrated substance and those of the titrant substance are equal.
When a strong acid is neutralized with a strong base, the pH undergoes a sharp change just at the equivalence point.
At the time of neutralization, it is true that the number of equivalents of acid that have reacted is equal to the number of equivalents of the base.
This equivalence point is very easily detected since a sharp pH jump is observed in its vicinity, which can be detected in a pH meter or with an indicator.
Therefore, we can conclude that the equivalence point of a reaction is the point at which an equivalent amount of acid and base has been added.
Learn more here: https://brainly.com/question/9297714
Which gas law is represented by the following equation: P1/T1 = P2/T2
O none of these
Avogadro's law
Charles's law
Gay-Lussac's law
Boyle's law
Answer:
none of these
Explanation:
The expression:
P1/T1 = P2/T2 is a derivative of the combined gas law.
From the combination of the Boyle's and Charles's law, if the volume is taken to be constant, the pressure of the given mass of gas is directly proportional to the absolute temperature.
This is how the expression
P1/T1 = P2/T2 was obtained.
The thermite reaction ,
Fe2O3(s)+2Al(s)⟶2Fe(s)+Al2O3(s),ΔH∘=−851.5kJ/mol
is one of the most exothermic reactions known. Because the heat released is sufficient to melt the iron product, the reaction is used to weld metal under the ocean. How much heat is released per mole of Al2O3produced? How does this amount of thermal energy compare with the energy released when 2 mol of protons and 2 mol of neutrons combine to form 1 mol of alpha particles?
Answer:
Explanation:
1) The ΔH shows the heat of reaction of the reaction illustrated in the question and the negative sign shows the reaction is an exothermic reaction, meaning heat is released in this reaction. The amount of heat released in this reaction is 851.5 kilojoules per mole of Al₂O₃ produced.
2) The thermal energy of this reaction is however very low when compared to the energy released when 2 moles of protons and 2 moles of neutrons combine to form 1 mole of alpha particles. This is because, the reaction illustrated in the (1) above is a normal chemical reaction while the one that involves the protons and neutrons (as described in this section 2) is a nuclear reaction which involves large amount of energy. Nuclear reactions usually involve way larger amount of energy than ordinary chemical reactions.
Which of thes statements about heating up land and water is true
Answer:
b its radiant energy that heats up the earth.
Explanation:
Answer:
The answer is D
Explanation:
Heat from the Earth's core and radiation from the Sun is transferred to the surface of the Earth by conduction. The warm land and water radiates infrared, some of which is absorbed by the atmosphere, adding to its thermal energy.
Which statements are true of the electron cloud model? Check all that apply. It is also known as the planetary model. It is considered the modern atomic model. It describes the probable locations of the electrons. It describes the specific locations of the electrons.
Answer:
-It is considered the modern atomic model.
-It describes the probable locations of the electrons
Explanation:
edge 2020
The correct answer is:
It is considered the modern atomic model. It describes the probable locations of the electrons.The electron cloud model is another name used to describe the modern wave mechanical model of the atom.
It is the atomic model introduced by Erwin Schrodinger in 1927 based on the principles of quantum mechanics. It was an advancement over the Bohr model of the atom.
In this model, the atomic orbital is described as a region in space where there is a high probability of finding an electron. Hence, the electron is not found in specific orbits according to the Bohr model, rather, we describe the probability of finding the electron. This is the contemporary approach to the study of atomic structure.
https://brainly.com/question/1372327
Sodium carbonate reacts with silver nitrate according to the following balanced equation: Na2CO3 (s) + 2 AgNO3 (aq) → Ag2CO3 (s) + 2 NaNO3 (9) If 3.60 g of Na2CO3 is allowed to react with 5.14 g of AgNO3, what mass of Na2CO3 will remain at the end of the reaction?
a) 2.01 g
b) 1.54 g
c) 0.423 g
d) 0.0150 g
e) 0g
Answer:
a) 2.01 g
Explanation:
Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃First we convert 0.0302 mol AgNO₃ to Na₂CO₃ moles, in order to calculate how many Na₂CO₃ moles reacted:
0.0302 mol AgNO₃ * [tex]\frac{1molNa_2CO_3}{2molAgNO_3}[/tex] = 0.0151 mol Na₂CO₃So the remaining Na₂CO₃ moles are:
0.0340 - 0.0151 = 0.0189 moles Na₂CO₃Finally we convert Na₂CO₃ moles into grams, using its molar mass:
0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃The closest answer is option a).
454 grams of isomaltitol, C12H24O11, was combusted in a furnace completely in an excess oxygen. The products of this reaction are water and carbon dioxide. What is the theoretical yield (in kilograms) of water produced from this reaction?
The theoretical yield (in kilograms) of water produced from this reaction : 0.285 kg
Further explanationReaction
2C₁₂H₂₄O₁₁ + 25O₂ → 24CO₂ + 24H₂O
mass of C₁₂H₂₄O₁₁ - isomaltitol = 454 g
mol C₁₂H₂₄O₁₁(MW=344.31 g/mol) :
[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{454}{344.31 g/mol}\\\\mol=1.319[/tex]
mol H₂O based on C₁₂H₂₄O₁₁ as limiting reactant(O₂-oxygen as an excess)
From the equation above, mol ratio of C₁₂H₂₄O₁₁ : H₂O = 2 : 24, so mol H₂O:
[tex]\tt mol~H_2O=\dfrac{24}{2}\times 1.319=15.828[/tex]
then mass H₂O (MW=18 g/mol) :
[tex]\tt mass=mol\times MW\\\\mass=15.828\times 18=284.904~g=0.285~kg[/tex]
Calculate the percent composition of Carbon in the
compound shown below. Record your answer with two
decimal places.
C18H18010
Answer:54.82%
Explanation:
Percentage of carbon = mass of carbon in that compound/ mass of the compund *100
216/394*100 = 54.82%
How many dm in 14.5 mm?
The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol. How much energy is produced by burning 0.8210 g of naphthalene?
The energy produced by burning : -32.92 kJ
Further explanationDelta H reaction (ΔH) is the amount of heat change between the system and its environment
(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)
The enthalpy and heat(energy) can be formulated :
[tex]\tt \Delta H=\dfrac{Q}{n}\rightarrow n=mol[/tex]
The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol.
The energy released for 0.8210 g of naphthalene :
[tex]\tt Q=\Delta H\times n\\\\Q=-5139.6~kJ/mol\times \dfrac{0.8210~g}{128.17~g/mol}~\\\\Q=-32.92~kJ[/tex]
When 80.0 mL of a 0.812 M barium chloride solution is combined with 40 mL of a 1.52 M potassium sulfate solution, 10.8 g of barium sulfate precipitates. What is the % yield of this reaction
Answer:
76.1%
Explanation:
The reaction that takes place is:
BaCl₂ + K₂SO₄ → BaSO₄ + 2KClFirst we determine how many moles of each reactant were added:
BaCl₂ ⇒ 80 mL * 0.812 M = 64.96 mmol BaCl₂ K₂SO₄ ⇒ 40 mL * 1.52 M = 60.8 mmol K₂SO₄Thus K₂SO₄ is the limiting reactant.
Using the moles of the limiting reactant we calculate how many moles of BaSO₄ would have been produced if the % yield was 100%:
60.8 mmol K₂SO₄ * [tex]\frac{1mmolBaSO_4}{1mmolK_2SO_4}[/tex] = 60.8 mmol BaSO₄Then we convert that theoretical amount into grams, using the molar mass of BaSO₄:
60.8 mmol BaSO₄ * 233.38 mg/mmol = 14189.504 mg BaSO₄14189.504 mg BaSO₄ / 1000 = 14.2 g BaSO₄Finally we calculate the % yield:
% yield = 10.8 g / 14.2 g * 100 %% yield = 76.1%What is the cation in the chemical formula MnSe?
Answer:
Mn
Explanation:
The cation in the chemical formula MnSe is the Mn specie.
A cation is a positively charge ion or radical. Such an ion has lost electrons and this leaves a net positive charge on them. The Mn is the cationMost metals forms cations as they readily lose electrons due to their large atomic radius. Se is the anion as it will carry a negative chargeMost non-metals are anions1. A football player throws a football 30 meters/second2 using 600 Newtons of force What
was the mass of the football?
Answer:
20 kgExplanation:
The mass of the football can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{600}{30} = \frac{60}{3} \\ [/tex]
We have the final answer as
20 kgHope this helps you
Please help me I need these answers
Answer:
Q8) True
Q9) First ionization energy
Q10) Metal oxides
Explanation:
A common property of group one elements (alkali metals) is their combination with water to form basic solutions. E.g 2K(s)+2H2O(l)→2KOH(aq)+H2(g).
The distance of the outermost electron in the atom from the nucleus is inversely related to the first ionization energy. As the distance between the outermost electron and the nucleus in group 17 elements gets larger, the corresponding first ionization energies of elements in the group gets smaller.
Group 1 elements can combine with oxygen to give metal oxides. E.g 4K + O2 --> 2 K2O
Can someone help me with number 5:/
So to answer this question first let's decribe precision vs accuracy.
Precision in this case means exact and accurate; in this scenario all of the dots next to each other mean that it is highly precise.
Whereas Accuracy means aiming for the middle of the circle in this case. Thus the accuracy is low, but the precision is high.
TLDR: It is highly precise but not accurate.
Look up "Accuracy vs. Precision: What’s the Difference?" for a better detailed example and solution.
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Which of these elements has the highest first ionization energy?
a) As
b) Ga
c) Bi
d) Cs
e) K
Answer:
Cesium (Cs)
Explanation:
This eliment has an ionization energy of 3,8939
A voltaic cell is constructed that is based on the following reaction:
Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq).
If the concentration of Sn2+ in the cathode compartment is 1.00 M and the cell generates an emf of 0.16 V , what is the concentration of Pb2+ in the anode compartment?
Answer: The concentration of Pb2+ in the anode compartment is [tex]1.74\times 10^{-6}M[/tex]
Explanation:
[tex]Sn^{2+}(aq)+Pb(s)\rightarrow Sn(s)+Pb^{2+}(aq)[/tex]
Here Pb undergoes oxidation by loss of electrons, thus act as anode. Sn undergoes reduction by gain of electrons and thus act as cathode.
[tex]E^0=E^0_{cathode}- E^0_{anode}[/tex]
Where both [tex]E^0[/tex] are standard reduction potentials.
[tex]E^0_{[Sn^{2+}/Sn]}=-0.14V[/tex]
[tex]E^0_{[Pb^{2+}/Pb]}=-0.13V[/tex]
[tex]E^0=E^0_{[Sn^{2+}/Sn]}- E^0_{[Pb^{2+}/Pb]}[/tex]
[tex]E^0=(-0.14-(-0.13)V=-0.01V[/tex]
Now using Nernst Eqn :
[tex]E=E^0-\frac{0.059}{n}\log\frac{[Pb^{2+}]}{[Sn^{2+}]}[/tex]
[tex]0.16=(-0.01)-\frac{0.059}{2}\log\frac{[Pb^{2+}]}{[1.00]}[/tex]
[tex]0.17=-0.0295\log\frac{[Pb^{2+}]}{[1.00]}[/tex]
[tex]-5.76=\log\frac{[Pb^{2+}]}{[1.00]}[/tex]
[tex]1.74\times 10^{-6}=\frac{[Pb^{2+}]}{[1.00]}[/tex]
[tex][Pb^{2+}]=1.74\times 10^{-6}[/tex]
. KMnO4 oxidizes ethyl benzene to benzoic acid. If this reaction generally results in a 40 % experimental yield, how many grams of ethyl benzene are required to obtain 244 g of benzoic acid
Answer:
530.835 g
Explanation:
First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:
244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acidTheoretically, one mol of ethyl benzene would produce one mol of benzoic acid. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.
With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:
2.00 moles benzoic acid * [tex]\frac{1molEthylBenzene}{0.4molBenzoicAcid}[/tex] = 5.00 moles ethyl benzeneFinally we convert moles of ethyl benzene (C₈H₁₀) into grams, using its molar mass:
5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzeneWhich two factors often determine the type of rock that is formed by a process?
A.The type of material that is present at the beginning of the process
B.The amount of time the process of rock formation takes
C.The season in which the rock formation process ends
D.Whether the process takes place north or south of the equator
Answer:
A and B
Explanation:
Trust me I just did it on a p e x
Answer: he’s correct it’s d and b for me but it’s the same answers
Explanation:
Help please! I’ll give brainliest!
hurry plaese big points brainliest
Answer:
No because a straw is plastic look at it by this was, the energy used to create one metal straw is roughly equivalent to creating 90 plastic straws, and also produces carbon emissions equivalent to 150 plastic straws. This may not seem like a lot, but in order to offset the environmental impact of creating a metal straw, it must be used over 150 times
Explanation:
Using the van der waals equation, the pressure in a 22.4 L vessel containing 1.50 mol of chlorine gas at 0.00 c is____________atm. (a= 6.49L^2-atm/mol^2, b=0.0562 L/mol)
A. 1.50
b. 0.676
c. 0.993
d. 1.48
e. 1.91
Answer:
D. 1.48atm
Explanation:
Van der waals equation is given as:
(P +an²/v²) (v - nb) = nRT
Where;
P = pressure (atm)
V = volume (L)
R = gas constant (0.0821 Latm/molK)
a and b = gas constant specific to each gas
T = temperature (K)
n = number of moles
According to the given information; V = 22.4L, T = 0.00°C (273.15K), R = 0.0821 Latm/molK, a = 6.49L^2-atm/mol^2, b = 0.0562 L/mol, n = 1.5mol
Hence;
(P + 6.49 × 1.5²/22.4²) (22.4 - 1.5×0.0562) = 1.5 × 0.0821 × 273.15
(P + 6.49 × 2.25/501.76) (22.4 - 0.0843) = 33.638
(P + 0.0291) (22.316) = 33.638
22.316P + 0.649 = 33.638
22.316P = 33.638 - 0.649
22.316P = 32.989
P = 32.989/22.316
P = 1.478
P = 1.48atm
Xenon tetrafluoride has two sets of lone pairs of electrons. What should be the relative positions of the two sets of lone pairs?Why?
Answer: Two equatorial positions so as to minimize the repulsion.
Explanation:
Formula used for calculating number of electrons :
[tex]\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom = 8
N = number of monovalent atoms bonded to central atom = 4
C = charge of cation = 0
A = charge of anion = 0
Now we have to determine the hybridization of the [tex]XeF_4[/tex] molecule.
[tex]\frac{1}{2}[8+4-0+0]=6[/tex]
Bond pair electrons = 4
Lone pair electrons = 2
The number of electrons are 6 that means the hybridization will be [tex]sp^3d^2[/tex] and the electronic geometry of the molecule will be octahedral.
The molecular geometry will be square planar as two alternate positio ns will be occupied by lone pair of electrons so as to minimize the repulsion.
You are asked to write observations about a 100g sample of Nitrogen-16 before it decays , but you running late. In order to make observations, you require at least 5g of material Can make observations you are 57 seconds late to the lab?
Answer:
You can not make the observation in the lab
Explanation:
We must know the amount of Nitrogen-16 that remains after 57 seconds before we can make our conclusion.
Hence, from;
N/No = (1/2)^t/t1/2
Where;
N = amount of Nitrogen-16 present after 57 seconds
No = 100g of Nitrogen-16 originally present
t = 57 seconds
t1/2 = half life of Nitrogen-16 which is 7.13 seconds
Substituting values;
N/100 = (1/2)57/7.13
N/ 100 =(1/2)^8
N/100 = 1/256
256N = 100
N = 100/256
N = 0.39 g
You can not make the observation because you need at least 5g of Nitrogen-16 and only 0.39 g is left after 57 seconds.
The minimum amount of sample required has been 5 grams, while the remaining sample has been 0.39 grams. Thus, it has not been possible to make the observations.
The half life can be defined as the time required for the sample to reduce to half of its initial concentration. The half life can be given as:
Amount remained = Initial amount [tex]\rm \times\;\dfrac{1}{2}^\dfrac{time}{Half-life}[/tex]
The half life of nitrogen 16 has been 7.13 second.
The initial concentration of the sample has been 100 grams.
The concentration of sample remained after 57 seconds has been:
Amount remained = 100 [tex]\rm \times\;\dfrac{1}{2}^\dfrac{57\;sec}{7.13\;sec}[/tex]
Amount remained = 0.39 grams.
The amount of sample remained after 57 seconds has been 0.39 grams.
The amount of sample required for the analysis has been 5 grams, after 57 seconds only 0.39 grams of sample has been remaining. Thus, the student will not be able to made analysis of nitrogen-16.
For more information about the sample decay, refer to the link:
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