Answer:
C. Remains the same
A. Is greater than Kc
B. Run in the reverse direction to restablish equilibrium.
C. Remain the same
Explanation:
As the reaction is exothermic (ΔH < 0), when occurs, produce heat.
Based on Le Chatelier's principle, if the temperature decreases, the system will produce more product trying to restore the equilibrium
* The value of Kc doesn't change because is the constant of the reaction, Kc. That is,
C. Remains the same* Qc is the ratio between products and reactants. As more product is produced, Qc will increase becomes:
A. Is greater than Kc*After the formation of product, the system must:
B. Run in the reverse direction to restablish equilibrium.Because product is produced
*Cl₂ as reactant is consumed producing more product, decreasing its concentration. But when the equilibrium is restored, its concentration would be the same
C. Remain the sameCarry out the following operations as if they were calculations of experimental results and express each answer in standard notation with the correct number of significant figures and wtih the correct units. Provide both the answer and the units.
1. 5.6792 m + .6 m + 4.33 m
2. 3.70 g - 2.9133 g
3. 4.51 cm x 3.6666 cm
Answer:
1. [tex]10.6\; \rm m[/tex] (one decimal place.)
2.[tex]0.79\; \rm g[/tex] (two decimal places.)
3. [tex]16.5\;\rm cm^2[/tex] (three significant figures.)
Explanation:
1.The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.
For example, in the first expression:
[tex]5.6792\;\rm m[/tex] has four decimal places.[tex]0.6\; \rm m[/tex] has only one decimal place.[tex]4.33\; \rm m[/tex] has two decimal places.Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: [tex]\rm m[/tex].)
Therefore:
[tex]\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m[/tex]. (Rounded to one decimal place.)
2.Similarly:
[tex]\rm 3.70\; \rm g[/tex] has two decimal places.[tex]2.9133\; \rm g[/tex] has four decimal places.Therefore, the result should be rounded to two decimal places. Its unit should be [tex]\rm g[/tex] (same as the unit of the two inputs.)
[tex]\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g[/tex]. (Rounded to two decimal places.)
3.When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:
[tex]4.51\; \rm cm[/tex] has three significant figures.[tex]3.6666\; \rm cm[/tex] has five significant figures.Therefore, the result should have only three significant figures.
The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be [tex]\rm cm \cdot cm[/tex], which is occasionally written as [tex]\rm cm^2[/tex].
[tex]\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2[/tex]. (Rounded to three significant figures.)
Arrange the ff substances in order of increasing tendency to donate electrons with reasons
Alpha- ketoglutarate, Oxaloacetate ,O2, NADP+, Malate
Answer:
Alpha- ketoglutarate --> NADP+ --> Oxaloacetate --> O2.
(O2 has the HIGHEST tendency to donate electrons).
Explanation:
Okay, we are to Arrange Alpha- ketoglutarate, Oxaloacetate ,O2, NADP+ and Malate in order of increasing tendency to donate electrons, therefore, the correct order is;
Alpha- ketoglutarate --> NADP+ --> Oxaloacetate --> O2.
And this result can be gotten if we consider these compounds in their oxidative mechanism and check their potential values.
(1). When Alpha- ketoglutarate react with CO2, it gives isocitrate and standard redox potential value of -0.38.
(2). NADP+ with react with two moles of electrons and one mole of hydrogen ion to produce NADPH and standard redox potential value of -0.32.
(3). Oxaloacetate will react with two moles of hydrogen ion and electrons respectively to produce standard redox potential value of -0.18 and Malate.
(4). O2 will react with 4 moles of hydrogen ion and electrons respectively to produce 2 moles of water and standard redox potential value of +0.82.
CONCLUSION: the higher the negative values of the potential, the lesser the electron affinity and vice versa.
There are 154,000 mg of sugar in a
container of orange juice at Mindy's
house. She only wants to have 11 g of
sugar from the orange juice per day.
How many days can she drink the
orange juice before it is gone?
Explanation:
1g = 1000mg
154000mg = 154g
No of days she can drink = 154÷ 11 = 14days
Choose the species that is incorrectly matched with its electronic geometry.
1. BeBr2 : linear
2. CF4 : tetrahedral
3. NH3 : tetrahedral
4. H2O : tetrahedral
5. PF3 : trigonal bipyramidal
Answer:
PF3 : trigonal bipyramidal
Explanation:
PF3 has 4 domains around the central phosphorus (3 shared pairs and one lone pair of electrons), thus the electron geometry that has 4 domains is tetrahedral not trigonal bipyramidal
From the options the specie that is incorrectly matched is ( 5 ) ; PF₃ : trigonal bipyramidal
The specie PF₃ is composed of 3 shared pairs and one unshared pair of electrons ( i.e. It has 4 domains ) as seen in the Lewis structure of PF₃. therefore when writing its electronic geometry, it should expressed/written as tetrahedral and not trigonal bipyramidal.
Hence we can conclude that The specie that is incorrectly matched is PF3 : trigonal bipyramidal
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How are atoms arranged in a network solid, such as a diamond? A) Covalent bonds join random sets of atoms into a loose, changeable structure. B) Intermolecular forces hold diatomic molecules in an array. C) Covalent bonds join all the atoms tightly together. D) Covalent bonds join groups of 6 to 10 atoms tightly together.
Covalent bonds join all the atoms tightly together
Calculate the percent composition of muscovite mica. Its chemical
formula is (KF)2(Al2O3)3(SiO2)6(H2O)
Answer:
Explanation:
(KF)2(Al2O3)3(SiO2)6(H2O)
molecular formula
K₂F₂Al₆Si₆O₂₂H₂
2 x 39 + 2 x 19 + 6 x 27 + 6 x 28 + 22 x 16 + 2 x 2
= 78 + 38 + 162+ 168+ 352+ 4
= 802
Percentage of K = 78 x 100 / 802
= 9.72 %
Percentage of F = 38 x 100 / 802
= 4.74 %
Percentage of Al = 162 x 100 / 802
= 20.2 %
Percentage of Si = 168 x 100 / 802
= 20.9 %
Percentage of O = 352 x 100 / 802
= 43.9 %
Percentage of H = 4 x 100 / 802
= .54 %
will give brainliest
Explain why someone would choose to use octane in a car engine rather than octene?
Energy is stored in glucose bonds.
A. True B. False
Answer:
This is true.
Explanation:
Which elements cannot have more than an octet of electrons? Select all that apply
C
S
O
N
Br
Answer:
{ Carbon, Oxygen, Nitrogen }
Explanation:
Elements can only have more than an octet of electrons if they demonstrate an expanded octet. This is if they belong to groups in or beyond the third group. Why? Well these elements have d - orbitals that they can rely on to expand the number of electrons that could otherwise be limited. * Here we are focusing on main group elements, P - block elements more specifically. *
Carbon belongs to the 2 group, and thus doesn't have an empty d - orbital. Thus, it can't have more than an octet of electrons. Sulfur belongs to group 3, hence has an empty d - orbital, and can have more than an octet of electrons. Oxygen belongs to the 2 group, and thus doesn't have an empty d - orbital, so it can't have more than an octet of electrons. Same goes for Nitrogen. Bromine belongs to group 4, thus has empty d - orbitals, and can expand further than Sulfur can - it can have more than an octet of electrons.
Solution = { Carbon, Oxygen, Nitrogen }
Total mass of products ?
Answer:
183.815
Explanation:
I added the first two, then I used the calculated masses on every third box, and added all of them up.
What solubility a measure of
Answer:
The amount of solute that will dissolve
Explanation:
A P E X
Use this information to determine the number of valence electrons in the atoms. Which of the following correctly compares the stability of the two atoms?
The question is incomplete. The complete question is :
The table compares the number of electrons in two unknown neutral atoms.
Comparison of Electrons
Atom Number of Electrons
A 9
D 11
Use this information to determine the number of valence electrons in the atoms. Which of the following correctly compares the stability of the two atoms?
A. Both are unreactive.
B. Both are highly reactive.
C. A is unreactive and D is reactive.
D. A is reactive and D is unreactive.
Answer:
B. Both are highly reactive.
Explanation:
Atomic number of electrons given is 9 and 11, it means that atom A is fluorine (F) and atom D is Sodium (Na).
In order to gain stability 8 electrons are required in outer shell. So atoms either gain or lose electrons in its outer shell to become more reactive.
Sodium has electronic configuration (2,8,1) and easily loses one electron and become (2, 8) which is highly reactive.
Fluorine has electronic configuration (2, 7) and can gain easily an electron and becomes reactive to form (2, 8).
So, both they both attain stability by losing and gaining only one electron.
Hence, they both are highly reactive and the correct option is B.
Both atoms are highly reactive because of incomplete outermost shell.
The first atom is fluorine that has atomic number 9 and the second atom is sodium having atomic number 11. Fluorine belongs to group 7a which is highly reactive due to incomplete outermost shell while on the other hand, sodium belongs to group 1a which is also very reactive due to incomplete outermost shell.
Sodium gets stability by losing of outermost electron whereas fluorine gets stability by gaining one electron so we can conclude that both atoms are highly reactive because of incomplete outermost shell.
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25 ml of 2.0 M silver acetate reacts with grams 35 ml of 1.0 M Calcium chloride
Answer:
[tex]m_{AgCl}=7.15gAgCl\\m_{Ca\ Acet}=3.15gCa\ Acet\\[/tex]
Explanation:
Hello,
In this case, with the given information, we can identify the limiting reactant and compute the theoretical yield for the undergoing chemical reaction:
[tex]2CH_3COOAg+CaCl_2\rightarrow (CH_3COO)_2Ca+2AgCl[/tex]
Thus, with the given concentrations and volumes we compute the available moles of silver acetate:
[tex]n_{Ag\ Acet}=2.0mol/L*0.025mL=0.05mol[/tex]
Then, the moles of silver acetate that are consumed by 35 mL of 1.0 M calcium chloride:
[tex]n=0.035mL*1.0molCaCl_2/L*\frac{2mol Ag\ Acet}{1molCaCl_2} =0.07mol Ag\ Acet[/tex]
Therefore, since there are less available moles, it is the limiting reactant, for that reason, the theoretical yields of both calcium acetate and silver acetate are:
[tex]m_{AgCl}=0.05mol Ag\ Acet*\frac{2molAgCl}{2mol Ag\ Acet} *\frac{143gAgCl}{1molAgCl} \\\\m_{AgCl}=7.15gAgCl\\\\m_{Ca\ Acet}=0.05mol Ag\ Acet*\frac{1molmol Ca\ Acet}{2molmol Ag\ Acet} *\frac{126gmol Ca\ Acet}{1mol Ca\ Acet} \\\\m_{Ca\ Acet}=3.15gCa\ Acet[/tex]
Best regards.
Question 1 of 10
How is each element represented in the periodic table?
A. Each element is in an order based on alphabetical order.
B. Each element is listed as an abbreviation of the first letters of its
DE ME
C. Each element is represented by a one or two-letter symbol.
D. Each element is listed in its own box based on when it was
discovered
Answer:
C
Explanation:
A- incorrect, not in alphabetical order
B- incorrect, symbol for salt in NA not SA
C- correct
D- incorrect, not based on discovery
Each element represented in the periodic table is represented by a one or two-letter symbol.Hence , Option (C) is Correct.
What is Periodic Table ?
The periodic table, also known as the periodic table of the elements, is a tabular display of the chemical elements.
It is widely used in chemistry, physics, and other sciences, and is generally seen as an icon of chemistry.
Each element represented in the periodic table is represented by a one or two-letter symbol.Hence , Option (C) is Correct.
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DATA AND CALCULATIONS: (you must show your calculations) Part I. Determination of accuracy of a graduated cylinder Calculations: Experimental Step Measurable Mass of empty graduated cylinder 47.229 g Mass of filled graduated cylinder 71.821 g Mass of water (filled – empty) g Volume of water, calculated (calculated from mass of water, using the equation “density = mass/volume”, given the fact that the density of water is exactly 1 g/mL) mL Volume of water, measured (from the reading of the scale on the graduated cylinder) 25.0 mL Percent difference between measured and calculated volumes of water [(measured-calculated)/calculated] ×100% %
Answer:
[tex]\large \boxed{2 \, \%}[/tex]
Explanation:
1. Data
Mass of graduated cylinder = 47.229 g
Mass of graduated cylinder + water = 71.821 g
Actual volume of water = 25.0 mL
2. Calculations
(a) Mass of water
Mass = 71.821 g -47.229 g = 24.592 g
(b) Volume of water
[tex]\text{Volume} = \dfrac{\text{mass}}{\text{volume }} = \dfrac{\text{24.592 g}}{\text{ 1 g/mL}} = \text{24.592 mL}[/tex]
(c) Percent Difference
[tex]\begin{array}{rcl}\text{Percent difference}&= &\dfrac{\lvert \text{Measured - Calculated}\lvert}{ \text{Calculated}} \times 100 \,\%\\\\& = & \dfrac{\lvert 25.0 - 24.492\lvert}{24.492} \times 100 \, \% \\\\& = & \dfrac{\lvert 0.5\lvert}{24.492} \times 100 \, \%\\ \\& = & 0.02 \times 100 \, \%\\& = & \mathbf{2 \, \%}\\\end{array}\\\text{The percent difference is $\large \boxed{\mathbf{2 \, \%} }$}[/tex]
A gaseous mixture of O2 and N2 contains 37.8% nitrogen by mass. What is the partial pressure of oxygen in the mixture if the total pressure is 525 mmHg?
PLEASE HELP, will mark brainliest!!!
Answer: The partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg
Explanation:
mass of nitrogen = 37.8 g
mass of oxygen = (100-37.8) g = 62.2 g
Using the equation given by Raoult's law, we get:
[tex]p_A=\chi_A\times P_T[/tex]
[tex]p_{O_2}[/tex] = partial pressure of [tex]O_2[/tex] = ?
[tex]\chi_{O_2} = mole fraction of O_2=\frac{\text{Moles of }O_2}{\text{Total moles}}[/tex]
[tex]P_{T}[/tex] = total pressure of mixture = 525 mmHg
[tex]{\text{Moles of }O_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{62.2g}{32g/mol}=1.94moles[/tex]
[tex]{\text{Moles of }N_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{37.8g}{28g/mol}=1.35moles[/tex]
Total moles = 1.94 + 1.35 = 3.29 moles
[tex]\chi_{O_2}=\frac{1.94}{3.29}=0.59[/tex]
[tex]p_{O_2}=\chi_{O_2}\times P_T=0.59\times 525=310mmHg[/tex]
Thus the partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg
A gaseous mixture of O₂ and N₂ that contains 37.8% nitrogen by mass, and whose total pressure is 525 mmHg, has a partial pressure of oxygen of 310 mmHg.
A gaseous mixture of O₂ and N₂ contains 37.8% nitrogen by mass, that is, in 100 g of the mixture, there are 37.8 g of N₂. The mass of O₂ in 100 g of the mixture is:
[tex]mO_2 = 100 g - 37.8 g = 62.2 g[/tex]
We will convert both masses to moles using their molar masses.
[tex]N_2: 37.8 g \times 1 mol/28.00 g = 1.35 mol\\\\O_2: 62.2 g \times 1 mol/32.00 g = 1.94 mol[/tex]
The mole fraction of O₂ is:
[tex]\chi(O_2) = \frac{nO_2}{nN_2+nO_2} = \frac{1.94mol}{1.35mol+1.94mol} = 0.590[/tex]
Given the total pressure (P) is 525 mmHg, we can calculate the partial pressure of oxygen using the following expression.
[tex]pO_2 = P \times \chi(O_2) = 525 mmHg \times 0.590 = 310 mmHg[/tex]
A gaseous mixture of O₂ and N₂ that contains 37.8% nitrogen by mass, and whose total pressure is 525 mmHg, has a partial pressure of oxygen of 310 mmHg.
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Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the equation H 2 S O 4 + 2 N a O H ⟶ 2 H 2 O + N a 2 S O 4 If you require 28.07 mL of 0.697 M NaOH solution to titrate 220.1 mL of H 2 SO 4 solution, what is the concentration of the H 2 SO 4 solution? Type answer:
Answer:
[tex]M_{acid}=0.0444M[/tex]
Explanation:
Hello,
In this case, for the given reaction:
[tex]H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4[/tex]
We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:
[tex]2*n_{acid}=n_{base}[/tex]
That in terms of concentrations and volumes we can compute the concentration of the acid solution:
[tex]2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M[/tex]
Best regards.
The concentration of the sulfuric acid solution (H₂SO₄) is 0.0444 M
From the question,
We are to determine the concentration of the H₂SO₄ solution
Using the titration formula
[tex]\frac{C_{A}V_{A} }{C_{B}V_{B}} = \frac{n_{A}}{n_{B}}[/tex]
Where
[tex]C_{A}[/tex] is the concentration of acid
[tex]C_{B}[/tex] is the concentration of base
[tex]V_{A}[/tex] is the volume of acid
[tex]V_{B}[/tex] is the volume of base
[tex]n_{A}[/tex] is the mole ratio of acid
and [tex]n_{B}[/tex] is the mole ratio of base
The given balanced chemical equation for the reaction is
H₂SO₄ + 2NaOH ⟶ 2H₂O + Na₂SO₄
∴ [tex]n_{A} = 1[/tex]
and [tex]n_{B} = 2[/tex]
From the given information
[tex]V_{A} = 220.1 \ mL[/tex]
[tex]C_{B} = 0.697 \ M[/tex]
[tex]V_{B} = 28.07 \ mL[/tex]
Putting the parameters into the equation, we get
[tex]\frac{C_{A} \times 220.1}{0.697 \times 28.07}= \frac{1}{2}[/tex]
∴ [tex]C_{A} = \frac{1 \times 0.697 \times28.07}{2\times 220.1}[/tex]
[tex]C_{A} = \frac{19.56479}{440.2}[/tex]
[tex]C_{A} = 0.0444 \ M[/tex]
Hence, the concentration of the sulfuric acid solution (H₂SO₄) is 0.0444 M
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Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kJ/g. How many grams of fat will you gain if you eat 10,000 kJ (about 2390 kcal) one day and do nothing but sit relaxed for 14.3 h and sleep for the other 9.70 h
Answer:
[tex]m=107.8g[/tex]
Explanation:
Hello,
In this case, for the given information, we can compute the gained grams by firstly compute the energy consumed by 14.3 h of being sit relaxed and 9.70 h of sleeping:
[tex]E_{sit}=120\frac{J}{s}*\frac{3600s}{1h} *14.3h*\frac{1kJ}{1000J} =6177.6kJ\\\\E_{sleep}=83\frac{J}{s}*\frac{3600s}{1h} *9.70h*\frac{1kJ}{1000J} =2898.36kJ[/tex]
Then, we compute the energy used that day:
[tex]E_T=10000kJ-2898.36kJ-6177.6kJ=4203.28kJ[/tex]
Finally, the mass by considering the consumed fat:
[tex]m=\frac{4203.28kJ}{39kJ/g} \\\\m=107.8g[/tex]
Regards.
Temperature on Reaction Rate Use the drop-down menus to answer the questions. Which form of the sodium bicarbonate tablet has the most surface area? As the surface area increases, what happens to the average time required for the reaction?
Answer:Crushed, decreased
Explanation:
Just got it right
How many milliliters of a 2.5 m lioh solution are needed to completely neutralize 50 ml if a 1.0 m h2so4 solution?
1) 10ml
2) 50ml
3) 29m
4) 8ml
Answer:
40 ml. is the right answer of this question
An atom or ion has 42 neutrons , 36 protons, and 36 electrons. Identify the element symbol, and determine the mass number and charge for this atom or ion.
Answer:
i hope this will help you :)
Explanation:
number of electrons=36
number of protons=36
number of neutrons=42
mass number=number of protons+number of neutrons
mass number=36+42
mass number=78
so the element will be krypton Kr
as elements are identified on their number of electrons so this atom is krypton
as the actual atomic mass of krypton is 86 here the calculated atomic mass is 78 so krypton has loss 8 electrons but this must require a great amount of energy so the charge on krypton is +8
The symbol for this element is Kr, because that element is Krypton.
It is possible to find this out by the atomic number of the element. This atomic number is equal to the number of protons in the element.
Therefore, you should look, in a periodic table, which element has the atomic number equal to 36. In this search, you will see that this element is Krypton.
To know the mass and electrical charge, follow these steps:
The element's mass is calculated as the sum of the number of protons and the number of neutrons.Thus, the mass of this element is calculated through 36+42 which results in 78u.The electric charge, refers to the amount of electrons in the valence layer of the atom.Atoms with more than 8 electrons in the valence layer have a positive electric charge and atoms with less than 8 electrons in the valence layer have a negative electric charge.Krypton has 8 electrons in the valence layer, which means this is a neutral element.Krypton is a noble gas, and electric stability is normal among these gases. With that, we can conclude that Krypton is an atom and not an ion.
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Arrange the compounds in order of increasing acid strength. Consult the references section for pKa values of each acid. Suppose the strongest acid is b, the acid of intermediate strength is c and the weakest acid is a Then this leads to the following input:
a. CH 3NH3
Methylammonium ion
b. CH3 COH
Acetic acid
c. H2S
Hydrogen sulfide
The strongest acid is b, the acid of intermediate strength is c and the weakest acid is a Then this leads to the H2S (Hydrogen sulfide). Therefore, option C is correct.
What do you mean by an acid ?A chemical that, when combined with certain metals, emits hydrogen ions in water and forms salts. Acids have a sour taste and cause certain dyes to turn red.
An acid is a substance that releases hydrogen ions into solution, whereas a base or alkali absorbs hydrogen ions.
In an aqueous solution or water, a weak acid is an acid that has been partially dissociated into its ions. A strong acid, on the other hand, completely dissociates into its ions in water. The pH of weak acids is higher than that of strong acids.
Thus, The strongest acid is b, the acid of intermediate strength is c and the weakest acid is a Then this leads to the H2S, option C is correct.
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Fuel cells are used in many areas, such as the aerospace industry, where energy efficiency is more important than high power output. One fuel cell uses methanol, CH3OH, as a fuel. Predict the ideal bond angle for each of the following:
a. H―C―H
b. H―C―O
c. C―O―H.
Answer:
Within a molecule, the bond angle refers to the angle found between the central atom and its bonded atoms. The total number of bonded atoms and the unshared pairs of electrons within a molecule is the number of electron domains.
By considering the Lewis formula for methanol it is witnessed that the central carbon atom comprises no unshared pair of electrons and four bonded atoms. Therefore, 4 is the number of electron domains present around the carbon atom, so the bond angle present in the given case will be 109.5 degrees. Thus, the bond angles of H-C-O and H-C-H will equivalent to 109.5 degrees.
There are two unshared pairs of electrons and two bonded atoms around the central oxygen atom. Therefore, 4 will be the number of electron domains around the atom of oxygen. Thus, a 109.5 degree will be the bond angle found on it, and therefore, the bond angle of C-O-H will also be equivalent to a 109.5 degree. Hence, in the methanol, CH3OH, the bond angles of H-C-H, C-O-H, and H-C-O will be 109.5 degrees.
Consider the following reversible reaction. Upper C upper O (g) plus 2 upper H subscript 2 (g) double-headed arrow upper C upper H subscript 3 upper O upper H (g). What is the equilibrium constant expression for the given system? K e q equals StartFraction StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 over StartBracket upper C upper H subscript 3 upper O upper H EndBracket EndFraction. K e q equals StartFraction StartBracket upper C upper H subscript 3 upper H upper O EndBracket over StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 EndFraction. K e q equals StartFraction StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket over StartBracket upper C upper H subscript 3 upper O upper H EndBracket EndFraction. K e q equals sart fraction StartBracket upper C upper H subscript 3 upper O StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket EndFraction.
Answer:
[tex]Keq=\frac{[CH_3OH]}{[CO][H_2]^2}[/tex]
Explanation:
Hello,
In this case, for the described reaction at equilibrium:
[tex]CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)[/tex]
The analysis of the law of mass action allows us to write the equilibrium expression as shown below:
[tex]Keq=\frac{[CH_3OH]}{[CO][H_2]^2}[/tex]
Which is written considering that carbon monoxide, hydrogen and methanol are all in gaseous phase, for that reason all of them are included in the expression due to homogeneous equilibrium. Moreover, since hydrogen has a stoichiometric coefficient of 2, it is squared in the law of mass action.
Best regards.
Answer:
the answer is B if your looking for the letter
Explanation:
K e q equals StartFraction StartBracket upper C upper H subscript 3 upper H upper O EndBracket over StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 EndFraction.
examplesfor gas in liquid sssloution
Answer:
Water vapor to dew
Explanation:
Water vapor turns from a gas into a liquid, such as dew on the morning grass.
Answer:
Coca cola, the beverage, is an example of gas - liquid solution, as it has carbon dioxide dissolved in water.
Summarize the feedback loop (transfer of energy) between the microbes and the mushrooms. (Video #1)
What is the Nitrogen Cycle? Discuss the 3 types of microbes required for the nitrogen cycle. What would happen to the soil if the microbes were not there?(Video #2)
Where and how does carbon move? How do plants help recycle CO2? Where do plants get their CO2 from? (Video #3)
Scientists are wondering how soil and soil microbes interact, how they will respond to global warming, specifically what will happen to the levels of CO2 and CH4 if the soil warms up.
Analyze the Results from this student’s data (Links to an external site.)
Based on these results, (1) would the warming of the climate cause an increase or a decrease in soil respiration? Use data to back up your claim. (2) How might this impact the environment?
Answer:
Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle.
Explanation:
Nitrogen Cycle is a type of cycle in which nitrogen moves from atmosphere to the earth surface and again return back to the atmosphere. Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle. If these microbes is vanished from the environment, the nitrogen cannot be converted into other forms. Carbon is present in the atmosphere in carbondioxide form. This CO2 is used by the plants from atmosphere and make food from it. When these plants are eaten by animals, this CO2 is again release in the atmosphere. Due to global warming, the microbes present in the soil die due to increase in temperature of the soil. Levels of CO2 and CH4 increases if the soil warms up. With the increase in temperature, soil respiration increases which leads to more emission of CO2 and as a result more global warming occurs.
You are given a sample of benzoin that has been contaminated with anthracene and you purify this sample by recrystallization. Which of the following is a possible melting point you may measure if you did not successfully purify benzoin and it is still contaminated with anthracene? (literature melting points: benzoin 134-138C; anthracene 210-215C).
A. 120-130B. 172-175C. 134-136D. 210-212
Answer:
The correct option is A
Explanation:
Now from the question we are told that the purification of benzoin was not successful and generally for every substance , it melting point at the pure state is higher that its melting point at its impure state, with this knowlege and the information given in the question that the melting point of benzoin at it pure state is (134-138 ) °C, we can deduce that the melting we may measure if we did not successfully purify benzoin and it is still contaminated with anthracene is (120-130) °C
A student is given 1.525 g of pure CuO. To recover the Cu present in the compound, the dark powdery solid was dissolved in 15.0 mL of 6 M HCl, the solution diluted with 50.0 mL of water, and 0.50 g of Mg was added. Was this enough Mg to displace all the ions from the solution
Answer:
The amount of Mg was enough
Explanation:
In this case, we have to start with the reaction between [tex]Mg[/tex] and [tex]CuO[/tex], so:
[tex]CuO~+~Mg~->~MgO~+~Cu[/tex]
If we check the reaction is already balanced. Now, we can do some stoichiometry to calculate the amount of Mg. The first step is the number of moles of [tex]CuO[/tex]. To this we have to calculate the molar mass of [tex]CuO[/tex] first, so:
Cu: 63.55 g/mol and O: 16 g/mol. So, (63.55+16)= 79.55 g/mol.
Now, we can calculate the moles:
[tex]1.525~g~CuO\frac{1~mol~CuO}{79.55~g~CuO}=0.0192~mol~CuO[/tex]
The molar ratio between [tex]Mg[/tex] and [tex]CuO[/tex] is 1:1, so:
[tex]0.0192~mol~CuO=0.0192~mol~Mg[/tex].
Now we can calculate the mass of Mg if we know the atomic mass of Mg (24.305 g/mol). So:
[tex]0.0192~mol~Mg\frac{24.305~g~Mg}{1~mol~Mg}=0.466~g~Mg[/tex]
With this in mind, the student added enough Mg to recover all the Cu.
Note: The HCl doesn't take a role in the reaction. The function of HCl is to dissolve the [tex]CuO[/tex].
I hope it helps!
How many liters of plasma are present in 8.5 pt?
Answer:
The question is missing what "pt" is. Btw 8.5 pints equal 4.02200002 liters
Explanation:
How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?
Answer:
700 mL of water
Explanation:
This is the perfect example of dilation calculations. Along with this concept we have a formula c = n ( solute ) / V ( solution ). Let us first solve for n by changing this equation to isolate the solute,
n ( KCL ) = 2.4 mol / L * 500 * 10 ^ - 3 L,
n ( KCL ) = 1.2 moles ( KCL )
Knowing the amount of moles of potassium chloride, we have to now identify how much is present in the target solution,
V = 1 .2 moles / ( 1.0 moles / L )
V = 1.2 L = 1200 mL
_______________________________________________________
Vadded = 1200 - 500 = 700 mL
Hope that helps!
Answer:
Use dilution equation:
M1V1 =
M2V2 1.0*V1 =
2.4*500 V1 =
1200mL
You already have 500mL KCl solution . You must add: 1200mL - 500mL = 700mL water.
Explanation:
Hope this helps!!! <3