HELP ASAP-what has an atomic number of 1

The element that would behave most likely magnesium is calcium. The correct option is b.

An element is a material whose atoms all contain the same number of protons: that is, all atoms of each element have the same amount of protons.

Elements are the most basic chemical forms and thus cannot be broken down chemically.

A chemical element is something that cannot be broken down further through any chemical reaction. Every element's atom encompasses a distinct number of protons.

A pure element is defined in chemistry as a substance whose atoms all (or almost all) have the same atomic number, or number of protons.

Beryllium and Calcium exhibit chemical reactions similar to Magnesium.

Thus, the correct option is b.

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Answer : The theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.

Explanation : Given,

Mass of [tex]H_2[/tex] = 1.46 g

Mass of [tex]N_2[/tex] = 10.5 g

Molar mass of [tex]H_2[/tex] = 2 g/mol

Molar mass of [tex]N_2[/tex] = 28 g/mol

First we have to calculate the moles of [tex]H_2[/tex] and [tex]N_2[/tex].

[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]

[tex]\text{Moles of }H_2=\frac{1.46g}{2g/mol}=0.73mol[/tex]

and,

[tex]\text{Moles of }N_2=\frac{\text{Given mass }N_2}{\text{Molar mass }N_2}[/tex]

[tex]\text{Moles of }N_2=\frac{10.5g}{28g/mol}=0.375mol[/tex]

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

[tex]3H_2+N_2\rightarrow 2NH_3[/tex]

From the balanced reaction we conclude that

As, 3 mole of [tex]H_2[/tex] react with 1 mole of [tex]N_2[/tex]

So, 0.73 moles of [tex]H_2[/tex] react with [tex]\frac{0.73}{3}=0.243[/tex] moles of [tex]N_2[/tex]

From this we conclude that, [tex]N_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]H_2[/tex] is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of [tex]NH_3[/tex]

From the reaction, we conclude that

As, 3 mole of [tex]H_2[/tex] react to give 2 mole of [tex]NH_3[/tex]

So, 0.73 mole of [tex]H_2[/tex] react to give [tex]\frac{2}{3}\times 0.73=0.487[/tex] mole of [tex]NH_3[/tex]

Now we have to calculate the mass of [tex]NH_3[/tex]

[tex]\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3[/tex]

Molar mass of [tex]NH_3[/tex] = 17 g/mole

[tex]\text{ Mass of }NH_3=(0.487moles)\times (17g/mole)=8.28g[/tex]

Therefore, the theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.

Answer:

113.4g of N2

Explanation:

Step 1:

The balanced equation for the reaction.

N2 + 3H2 —> 2NH3

Step 2:

Determination of the mass of N2 and H2 that reacted from the balanced equation. This is illustrated below:

Molar mass of N2 = 2x14 = 28g/mol

Mass of N2 from the balanced equation = 1 x 28 = 28g

Molar mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

From the balanced equation above, 28g of N2 reacted with 6g of H2.

Step 3:

Determination of the mass N2 required to react with 24.3g of H2.

The mass of N2 required to react with 24.3g of H2 can be obtained as follow:

From the balanced equation above, 28g of N2 reacted with 6g of H2.

Therefore, Xg of N2 will react 24.3g of H2 i.e

Xg of N2 = (28 x 24.3)/6

Xg of N2 = 113.4g

Therefore, 113.4g of N2 is required to react completely with 24.3g of H2.

24.3g H2 × 1 mol H2/2.016g H2 × 1 mol N2/3 mol H2 × 28.014 g N2/1 mol N2 = 113g N2

Answer:

The probability of finding the particle somewhere in the universe must be equal to 1.

Answer:

Rises, sinks

the correct answer is B

Answer:

rises, sinks

Explanation:

Hot magma rises because as the temperature increases, it expands and becomes less dense. As it reaches the top, it cools down and becomes more dense, which means it will sink. Therefore, hot magma rises and cool magma sinks in convection mantle mechanism.