When an object is located 32 cm to the left of the lens, the image is formed 17 cm to the right of the lens. What is the focal length of the lens?

Answers

Answer 1

Answer: 11.1cm

Explanation:

Object distance (u) = 32cm

Image distance(v) = 17cm

Focal length(f) =?

Lens formular:

1/f = 1/u + 1/v

1/f = 1/32 + 1/17

Taking the L. C. M of 17 and 32

1/f = (17 + 32) / 544

1/f = 49/544

Taking the reciprocal

f = 544/49

f = 11.1 cm

Therefore, Focal length of the lens is 11.1cm


Related Questions

AS WE CLIMB UP, THE PRESSURE INSIDE OUR BODY WILL BE.................. *
1 )low
2)high
3)very high
4)same

Answers

Less depth means less pressure,as we go up in elevation,or height,air pressure decreases.
Prob low since the higher we go, the pressure/ our heart starts to feel heavy (drop low)
Take riding a Roller Coaster for an example, When you go down or up fast, your heart starts dropping as if it’s heavier than it was.

If a truck if it is accelerating at a rate of 5m/s2 and hits a parked car with a force of 16,000 newtons what is its mass?

Answers

Answer:

3200kg

Explanation:

F=ma

16000=5m

m=3200kg

Hope this helps!

The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

What is mass?

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.

It is given that:

If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons

As we know,

Newton's second law:

F = ma

Here F is the force acting on an object.

m is the mass of the object

a is the acceleration of the object.

a = 5 m/s²

F = 16,000 N

m = 3200kg

16000 = 5m

3200 kg

Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

Learn more about the mass here:

https://brainly.com/question/15959704

#SPJ2

A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a position of 10 m south of the reference point. What is the car's average velocity?

Answers

Answer:

  v = -4 m / s

Explanation:

The average speed of a body is defined by the distance traveled in a given time interval

     v = (x₂ -x₁) / (t₂ -t₁)

in this case the end point is x₂ = -10 m and the start point is x₁ = 10 m, the negative sign is because the point is below the reference that can be considered as zero point

let's calculate

     v = (-10 - 10) / 5

     v = -20 / 5

      v = -4 m / s

Amina has a mass of 48.4kg, what is her weight.please show calculation

Answers

G=m×g

since g=10N,

G=48.4×10

G=484

I hope it's true .d

good luck

A high surface tension results from _____.

Answers

Answer:

Capillary Action.

Explanation:

Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.

factorise x^3 - 3x^2 - 9x - 5​

Answers

Answer:

(x +1), (x -5) and (x +1)

Explanation:

The computation of the factorization is shown below

Data provided in the question

[tex]X^3 - 3x^2 - 9x - 5[/tex]

Based on the above information, the factors are

Now we have to open these equations in order to get the factors which are as follows

[tex]= x^3 + x^2 - 4x^2 - 4x - 5x - 5[/tex]

[tex]= x^2( x + 1) - 4x ( x + 1) - 5(x + 1)[/tex]

[tex]= (x + 1) (x^2 - 4x - 5)[/tex]

[tex]= (x + 1)(x^2 -5x + x - 5)[/tex]

So,

= (x + 1) (x - 5) (x + 1)

Therefore the (x +1), (x -5) and (x +1) are the factors of the mention polynomial give in the question

A lamp hangs from the ceiling at a height of 2.6 m. The lamp has a mass of 3.8 kg. The screws holding the lamp break, and it falls to the ground. a. How much gravitational potential energy does the lamp have before it falls? b. How much kinetic energy does the lamp have when it reaches the ground? c. How fast is the lamp moving when it hits the ground?

Whoever answers will get the Brainliest.

Answers

Answer:

Explanation:

Given height of lamp from the ceiling = 2.6m

mass of the lamp = 3.8kg

acceleration due to gravity = 9.81m/s²

As the body falls to the ground, it falls under the influence of gravity.

Gravitational potential energy = mass*acc due to gravity * height

Gravitational potential energy  = 3.8*2.6*9.81

Gravitational potential energy  = 96.923 Joules

b) Kinetic energy = 1/2 mv²

m = mass of the body (in kg)

v = velocity of the body (in m/s²)

To get the velocity v, we will use the equation of motion [tex]v^{2} = u^{2}+2gh[/tex]

[tex]v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s[/tex]

Since mass = 3.8kg

[tex]K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules[/tex]

c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s

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