g A 12,000 m3/day treatment plant has a rectangular sedimentation basin with dimensions 12 meters wide, 3 meters deep, and 25 meters long. Will particles with a settling velocity of 6 x 10-3 m/s be removed in this basin

Answers

Answer 1

Answer:

The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.

Explanation:

Given;

volumetric flow rate of the treatment, Q₀ = 12,000 m³/day

length of the rectangular tank, L = 25 m

width of the tank, W = 12 m

height of the tank, H = 3 m

settling velocity of the particles, [tex]V_s[/tex] = 6 x 10⁻³ m/s

The overflow rate of the sediments are calculated as follows;

[tex]V_o = \frac{Q_o}{A_s}[/tex]

where;

As is the surface area of the tank, m²

Q₀ is the flow rate, m³/s

As = 2LW + 2LH + 2WH

As = (2 x 25 x 12) + (2 x 25 x 3) + (2 x 12 x 3)

As = 822 m²

[tex]Q_0 (m^3/s)= \frac{12,000 \ m^3}{day} \times \frac{1 \ day}{24 \ hr} \times \frac{1 \ hour}{60 \ \min} \times \frac{1 \ \min}{60 \ s} = \frac{12,000}{24 \times 60 \times 60} (m^3/s)= \frac{12,000}{86,400} \ m^3/s\\\\Q_o = 0.139 \ m^3/s[/tex]

The overflow rate;

[tex]V_o = \frac{Q_0}{A_s} = \frac{0.139}{822} = 1.69 \times 10^{-4} \ m/s[/tex]

The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.


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Answers

Answer:

take

play

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sits

crouches

direct

indirect

direct

direct

indirect

Explanation:

i had just taken the test

Expression for calories burned during workout

Answers

Women: Calories -((Age x 0.074) - (Weight x 0.05741) + (Heart Rate x 0.4472) – 20.4022) Time / 4.184 Men: Calories = ((Age x 0.2017) + (Weight 0.09036) + (Heart Rate x 0.6309) - 55,0969) x Time / 4.184

Explain the importance of wearing appropriate protective clothing and equipment (PPE), and keeping the work area safe and tidy

Answers

Answer:

The wearing of appropriate protective clothing and equipment (PPE) and the keeping of the work area safe and tidy achieve the following for the employees and employers: safety from physical and biological harm that may occur as a result of their contact with the work environment; reduces the cost of insurance and other risk management activities.

Explanation:

The personal protective equipment (PPE) is a safety equipment that protects workers from health or safety risks at their various workplaces. The main purpose is to reduce the workers' exposure to environmental hazards. PPE reduces accidents, improves the health of workers, and reduces the spread of contagious diseases.  Above all, it creates safe, secure, and healthy work environments for all.

Estimate the maximum expected thermal conductivity for a Cermet that contains 58 vol% titanium carbide (TiC) particles in a cobalt matrix. Assume thermal conductivities of 27 and 69 W/m-K for TiC and Co respectively.

Answers

Answer:

The right answer is "36.32 W/mk".

Explanation:

According to the question,

TiC = 76%

or,

      = 0.76

CO = 24%

or,

     = 0.24

Thermal conductivity of TiC,

= 26 W/mk

Thermal conductivity of CO,

= 69 W/mk

On applying the rule, we get

⇒  [tex]"K" \ of \ Cermet=(K)_{TiC} (V_f)_{TiC}+(K)_{CO} (V_m)_{CO}[/tex]

On putting the given values, we get

⇒                            [tex]=(26)(0.76)+(69)(0.24)[/tex]

⇒                            [tex]=19.76+16.56[/tex]

⇒                            [tex]=36.32 \ W/mk[/tex]

This String method removes beginning and ending spaces of the given string.
Solactone​

Answers

Answer:

The trim() method will remove both leading and trailing whitespace from a string and return the result. The original string will remain unchanged. If there is no leading or trailing whitespace to be removed, the original string is returned. Both spaces and tab characters will be removed.

This is very useful when comparing user input with existing data. A programmer often racks his brain for hours trying to figure out why what he enters is not the same as a stored string, only to find out that the difference is only a trailing space. Trimming data prior to comparison will eliminate this problem.

Answer:

String result = str. trim(); The trim() method will remove both leading and trailing whitespace from a string and return the result.

Explanation:

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