Chemistry Middle School

Choose any electromagnetic wave we have discussed and write ONE PARAGRAPH telling me about the uses/benefits of that electromagnetic wave.

Answers

Answer 1

Answer:

UV Rays

Here are some points you can add

•used to sterilise equipment from microbacterial organisms

•used to create fluorescence mechanism

•used to purify air

•used to tenderize meat

•can be implemented in medical and dental practices

•water purification

•stimulates vitamin d production

Related Questions

WILL MARK THE BRAINLEST

Answers

Answer:

a. Hh, hh

b. hh

c. 50%

d. 50%

C I think but if I’m wrong I’m really sorry

Students in a chemistry class added 5 g of Zinc (Zn) to 50 g of hydrochloric acid (HCl). A chemical reaction occurred that produced zinc chloride (ZnCl2) and 6 g of hydrogen gas (H2).

Zn+ 2HCl → ZnCl2+H2

What is the mass of the zinc chloride?

Answers

Answer: 11 g

Explanation:

Zn + 2HCl → ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = 5 g / 65.38 g/mol

Number of moles = 0.08 mol

Number of moles of HCl :

Number of moles = 50 g / 36.5 g/mol

Number of moles = 1.4 mol

Compare the moles of both reactant with zinc chloride:

Zn : ZnCl₂

1 : 1

0.08 : 0.08

HCl : ZnCl₂

2 : 1

1.4 : 1/2×1.4 =0.7 mol

The number of moles of zinc chloride produced by Zn are less so it will limit reactants.

Mass of zinc chloride:

Mass = 0.08 mol × 136.3 g/mol

Mass = 11 g

The answer is 11
First you need to find the limiting reactant
n (Zn) = m/MM = 5/65.38 = 0.076 ≈ 0.08
ratio = moles/coefficient = 0.08/1 = 0.08

n(HCl) = m/MM = 50/36.45 = 1.37
ratio = moles/coefficient = 1.37/2 = 0.685

So the limiting reaction is Zn

0.08/1 = x/1
x= 0.08 moles of ZnCl2

Then u need to find the mass
m= n(MM) = 0.08 (136.28) = 10.9 ≈11

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