Answer:
Step-by-step explanation:
If, for example, we translate the graph of f(x) = |x| 3 spaces to the right, then the equation becomes g(x) = |x - 3|
The function fx =-x^2-4x+5 is shown on the graph which statement is true
Answer:
Option (3)
Step-by-step explanation:
Given question is incomplete; here is the complete question.
The function f(x) = –x2 – 4x + 5 is shown on the graph. Which statement about the function is true?
The domain of the function is all real numbers less than or equal to −2.
The domain of the function is all real numbers less than or equal to 9.
The range of the function is all real numbers less than or equal to −2.
The range of the function is all real numbers less than or equal to 9
By using a graph tool we get a parabola opening downwards.
Since domain of a function is represented by x-values and range by y-values.
Domain of the given function will be (-∞, ∞)
Range of the function will be (-∞, 9] Or a set of all real numbers less thn equal to 9.
Therefore, Option (3) will be the answer.
A recipe requires 31 cup of milk for each 41 cup of water. How
many cups of water are needed for each cup of milk?
Step-by-step explanation:
here,
31 cup of milk require 41 cup of water.
1 cup of milk require 41/31 cup of water.
so, 41/31 cup of water is required for 1 cup of milk.
hope u get it..
I travelled at 60km/hour and took 2hours for a certain journey.How long would it have taken me if I had travelled at 50km/hour?
Answer:
if you would travel 50km/h then the time will be 2.4hours
Step-by-step explanation:
speed=v1=60km/h
time=t1=2h
speed=v2=50km/h
time=t2=?
as we know that
v1×t1=v2×t2
evaluating the expression
(v1×t1)/v2=t2
putting values
[tex]\frac{60km/h*2h}{50km/h}=t2[/tex]
[tex]\frac{120km/h^2}{50km/h}=t2[/tex]
2.4hours=t2
i hope this will help you :)
What is the probability of getting a number less than 2 OR a prime number upon rolling a six-sided die?
Answer:
1/18Step-by-step explanation:
Probability is the likelihood or chance that an event will occur.
Probability = expected outcome/total outcome
Since a six-sided die is rolled, the total outcome will be the total number of possible siedes a die contain {1, 2, 3, 4, 5, 6} i.e 6 elements
If a number less than 2 is gotten, the expected outcome will be {1} i.e 1 element.
Probability of getting a number less than 2 = 1/6
If a prime number is gotten, the outcome will be the elements {2, 3, 5} i.e 3 elements.
The probability of getting a prime number = 3/6 = 1/2
The probability of getting a number less than 2 OR a prime number upon rolling a six-sided die will be 1/6*1/2 = 1/18
Answer:
Step-by-step explanation:
On a six-sided die, there is only one way to get a number less than 2, which is by rolling a 1. So the probability of getting a number less than 2 is:
P left parenthesis l e s s space t h a n space 2 right parenthesis equals 1 over 6
There are three primes numbers when rolling a six-sided die, which are {2, 3, 5}. So the probability of getting a prime number is:
P left parenthesis p r i m e right parenthesis equals 3 over 6
Since there is no overlap between these two events, the probability of getting a number less than 2 OR a prime number is:
P left parenthesis l e s s space t h a n space 2 space o r space p r i m e right parenthesis equals P left parenthesis l e s s space t h a n space 2 right parenthesis plus P left parenthesis p r i m e right parenthesis equals 1 over 6 plus 3 over 6 equals 4 over 6 equals 2 over 3
Answer is 2/3
Conscientiousness is a tendency to show self-discipline, act dutifully, and aim for achievement. The trait shows a preference for planned rather than spontaneous behavior. A random sample of 650 students is asked to fill out the Hogan Personality Inventory (HPI) to measure their level of conscientiousness. The 350 graduate students had a mean score of 153 with a standard deviation of 21. The 300 undergraduate students scored an average of 148 with a standard deviation of 16. We are interested in determining whether graduate students score higher, on average, on the HPI than undergraduate students. What is the value of the test statistic for testing these hypotheses using a pooled two sample t-test?
Answer:
a
The Null hypothesis represented as
[tex]H_0: \mu_1 - \mu_2 = 0[/tex]
The Alternative hypothesis represented as
[tex]H_a: \mu_1 - \mu_2 < 0[/tex]
b
p-value = P(Z < -3.37 ) = 0.000376
c
There is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students
Step-by-step explanation:
From the question we are told that
The population size is [tex]n= 650[/tex]
The sample size for graduates is [tex]n_1 = 300[/tex]
The sample mean for graduates is [tex]\= x _1 = 148[/tex]
The sample standard deviation for graduates is [tex]\sigma_1 = 16[/tex]
The sample size for under-graduates is [tex]n _2 = 350[/tex]
The sample mean for under-graduates is [tex]\= x _2 = 153[/tex]
The sample standard deviation for graduates is [tex]\sigma_2 = 21[/tex]
The Null hypothesis represented as
[tex]H_0: \mu_1 - \mu_2 = 0[/tex]
The Alternative hypothesis represented as
[tex]H_a: \mu_1 - \mu_2 < 0[/tex]
Where [tex]\mu_1 \ and \ \mu_2[/tex] are the population mean
Now the test statistic is mathematically represented as
[tex]t = \frac{(\= x_1 - \= x_2 ) }{ \sqrt{ \frac{ (n_1 - 1 )\sigma_1 ^2 + (n_2 - 1)\sigma_2^2}{n_1 +n_2 -2} } * \sqrt{ \frac{1}{n_1} + \frac{1}{n_2} } }[/tex]
substituting values
[tex]t = \frac{(148 - 153 ) }{ \sqrt{ \frac{ (300- 1 )16 ^2 + (350 - 1) 21^2}{300 +350 -2} } * \sqrt{ \frac{1}{300} + \frac{1}{350} } }[/tex]
[tex]t = -3.37[/tex]
The p-values is mathematically evaluated as
p-value = P(Z < -3.37 ) = 0.000376
The above answer is gotten using a p-value calculator at (0.05) level of significance
Looking the p-value we see that it is less than the level of significance (0.05) so Null hypothesis is rejected
Hence there is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students
Following are the two-Sample of the T-Test and CI:
[tex]\boxed{\boxed{\begin{matrix}Sample& N &Mean& StDev& SEMean\\ 1 &350 &153.0& 21.0 &1.1 \\ 2& 300& 148.0& 16.0& 0.92\end{matrix}}}[/tex]
Calculating the difference:
[tex]= \mu (1) - \mu (2)\\\\[/tex]
The estimated difference: [tex]5.00[/tex]
When the [tex]95\%[/tex] of CI so, the difference:[tex](2.09, 7.91)[/tex]
Therefore the T-Test difference value = 0
[tex]\to (vs \neq): T-Value = 3.37 \\\\\to P-Value = 0.001 \\\\\to DF = 648[/tex]
When the both use Pooled so, the StDev = 18.8583
Therefore, the final value of t is "3.37".
Learn more:
brainly.com/question/16380581
Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of time ttt (in years) can be modeled by a sinusoidal expression of the form a\cdot\sin(b\cdot t)+da⋅sin(b⋅t)+da, dot, sine, left parenthesis, b, dot, t, right parenthesis, plus, d. At year t=0t=0t, equals, 0, Pluto is at its average distance from the sun, which is 6.96.96, point, 9 billion kilometers. In 666666 years, it is at its closest point to the sun, which is 4.44.44, point, 4 billion kilometers away. Find P(t)P(t)P, left parenthesis, t, right parenthesis. \textit{t}tstart text, t, end text should be in radians.
Answer: P(t) = 1.25.sin([tex]\frac{\pi}{3}[/tex].t) + 5.65
Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:
y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D
where:
A is amplitude A=|A|
B is related to the period by: T = [tex]\frac{2.\pi}{B}[/tex]
C is the phase shift or horizontal shift: [tex]\frac{C}{B}[/tex]
D is the vertical shift
In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.
Amplitude:
a = [tex]\frac{largest - smallest}{2}[/tex]
At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:
a = [tex]\frac{6.9-4.4}{2}[/tex]
a = 1.25
b
A time period for Pluto is T=66 years:
66 = [tex]\frac{2.\pi}{b}[/tex]
b = [tex]\frac{\pi}{33}[/tex]
Vertical Shift
It can be calculated as:
d = [tex]\frac{largest+smallest}{2}[/tex]
d = [tex]\frac{6.9+4.4}{2}[/tex]
d = 5.65
Knowing a, b and d, substitute in the equivalent positions and find P(t).
P(t) = a.sin(b.t) + d
P(t) = 1.25.sin([tex]\frac{\pi}{3}[/tex].t) + 5.65
The Pluto's distance from the sun as a function of time is
P(t) = 1.25.sin([tex]\frac{\pi}{3}[/tex].t) + 5.65
Answer:
P(t) = 1.25.sin(.t) + 5.65
Step-by-step explanation:
Write the addition sentence below as a multiplication sentence.
2 + 2 + 2 + 2 + 2 + 2 = 12
Answer:
6*2 = 12
Step-by-step explanation:
2 + 2 + 2 + 2 + 2 + 2 = 12
There are six 2's being added together
6*2 = 12
Answer: 2*6
Step-by-step explanation:
There are 6 2's shown in the question. Thus, simply do 6*2.
Hope it helps <3
HELP! will give brainlest or whatever its called... Triangle ABC has vertices A(–2, 3), B(0, 3), and C(–1, –1). Find the coordinates of the image after a reflection over the x-axis. A’ B’ C’
Answers:
A ' = (-2, -3)
B ' = (0, -3)
C ' = (-1, 1)
=======================================================
Explanation:
To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.
Algebraically, the reflection rule used can be written as [tex](x,y) \to (x,-y)[/tex]
Applying this rule to the three given points will mean....
Point A = (-2, 3) becomes A ' = (-2, -3)Point B = (0, 3) becomes B ' = (0, -3)Point C = (-1, -1) becomes C ' = (-1, 1)The diagram is provided below.
Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.
Answer:
(-2,-3)...(0,-3)...(-1,1)
Step-by-step explanation:
In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arrested previously for a DUI offence. Suppose 41 people arrested for DUI in Illinois are selected at random. You may assume that this is a binomial distribution.
Required:
a. What is the probability that exactly 3 people are repeat offenders?
b. What is the probability that at least one person is a repeat offender?
c. What is the mean number of repeat offenders?
d. What is the standard deviation of the number of repeat offenders?
Answer:
a) 21.58% probability that exactly 3 people are repeat offenders
b) 97.91% probability that at least one person is a repeat offender
c) 3.69
d) 1.83
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders
This means that [tex]p = 0.09[/tex]
41 people arrested for DUI in Illinois are selected at random.
This means that [tex]n = 41[/tex]
a. What is the probability that exactly 3 people are repeat offenders?
This is P(X = 3).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158[/tex]
21.58% probability that exactly 3 people are repeat offenders
b. What is the probability that at least one person is a repeat offender?
Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So
[tex]P(X = 0) + P(X \geq 1) = 1[/tex]
We want [tex]P(X \geq 1)[/tex].
Then
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which
[tex]P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209[/tex]
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791[/tex]
97.91% probability that at least one person is a repeat offender
c. What is the mean number of repeat offenders?
[tex]E(X) = np = 41*0.09 = 3.69[/tex]
d. What is the standard deviation of the number of repeat offenders?
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83[/tex]
Bijan has agreed to run a half-marathon to raise money for charity. Each day before school, Bijan runs a 2.4-mile route around his neighborhood. Then, each day after school, he runs on a lakeside trail. After 4 days, Bijan has run a total of 14.8 miles. Suppose you want to find out the length of the lakeside trail, x. What expression would represent how far Bijan runs everyday? What is the equation that represents his total distance after 4 days?
Answer:
First one is (x+2.4)
Second one is 4(x+2.4)=14.8
Step-by-step explanation:
Answer:
What expression would represent how far Bijan runs everyday?
✔ (x + 2.4)
What is the equation that represents his total distance after 4 days?
✔ 4(x + 2.4) = 14.8
Step-by-step explanation: I TOOK THE TEST
Please answer this correctly
Answer:
1/7
Step-by-step explanation:
There are 7 cards, 1 of which is less than 2. Therefore, P (less then 2) = 1/7
Answer:
1/7
Step-by-step explanation:
The number from the list that is less than 2 is 1.
1 number out of a total of 7 numbers.
= 1/7
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is reasonable to assume that the population is approximately normal.
21.88 21.76 22.14 21.63 21.81 22.12 21.97 21.57 21.75 21.96 22.20 21.80
Required:
Construct a 90% confidence interval for the mean weight.
Answer:
A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].
Step-by-step explanation:
We are given the weights, in the ounces, of a sample of 12 boxes below;
Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean weight = [tex]\frac{\sum X}{n}[/tex] = 21.88 ounces
s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = 0.201 ounces
n = sample of boxes = 12
[tex]\mu[/tex] = population mean weight
Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.
So, 90% confidence interval for the population mean, [tex]\mu[/tex] is ;
P(-1.796 < [tex]t_1_1[/tex] < 1.796) = 0.90 {As the critical value of t at 11 degrees of
freedom are -1.796 & 1.796 with P = 5%}
P(-1.796 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 1.796) = 0.90
P( [tex]-1.796 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]1.796 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.90
P( [tex]\bar X-1.796 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+1.796 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.90
90% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-1.796 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+1.796 \times {\frac{s}{\sqrt{n} } }[/tex] ]
= [ [tex]21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }[/tex] , [tex]21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }[/tex] ]
= [21.78, 21.98]
Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].
A competition
took place in 1983
takes place every 6 years.
What is the first year after 2045 that it will also take place?
Answer:
2049.
Step-by-step explanation:
2045 - 1983 = 62 years.
So the competition will take place in 1983 + 60 = 2043.
After 2045 the competition takes place in 2049.
I need help please!!!!! Will give BRAINLIST !!
Answer:
0.65
Step-by-step explanation:
There are 65 student that do sports as 20+20+25=65. In total there are 100 student and you find this by adding up all the values. Now all you do is divide 65/100 and get 0.65 and that is the probability a random student plays sports.
Reflections over the X-Axis
Answer:
Domain : (-∞, ∞)
Range : (-∞, ∞)
Step-by-step explanation:
Parent function (y = [tex]\sqrt[3]{x}[/tex] ) of the given function y = -[tex]\sqrt[3]{x}[/tex] has been shown as the dotted line on the graph.
Solid curve represents the function,
y = [tex]-\sqrt[3]{x}[/tex]
Therefore, Domain of this function will be (-∞, ∞) Or x ∈ set of all real numbers.
And Range of the function will be (-∞, ∞) Or y ∈ set of all real numbers
Of 41 bank customers depositing a check, 22 received some cash back. Construct a 90 percent confidence interval for the proportion of all depositors who ask for cash back. (Round your answers to 4 decimal places.)
Answer:
CI: {0.4085; 0.6647}
Step-by-step explanation:
The confidence interval for a proportion (p) is given by:
[tex]p \pm z*\sqrt{\frac{(1-p)*p}{n} }[/tex]
Where n is the sample size, and z is the z-score for the desired confidence interval. The score for a 90% confidence interval is 1.645. The proportion of depositors who ask for cash back is:
[tex]p=\frac{22}{41}=0.536585[/tex]
Thus the confidence interval is:
[tex]0.536585 \pm 1.645*\sqrt{\frac{(1-0.536585)*0.536585}{41}}\\0.536585 \pm 0.128109\\L=0.4085\\U=0.6647[/tex]
The confidence interval for the proportion of all depositors who ask for cash back is CI: {0.4085; 0.6647}
HELP SNOG OR WHOEVER (x+3)(y-19)
Answer:
xy-19x+3y-57
Step-by-step explanation:
Once again, FOIL is the way to go!
First, Outside, Inside, Last
xy-19x+3y-57
Answer:
xy-19x+3y-57
Step-by-step explanation:
(x+3)(y-19)
FOIL
first: xy
outer: -19x
inner 3y
last -57
Add them together
xy-19x+3y-57
if X= 2, Y=-2 and Z=3 find the value of 3 X + Y - Z
Answer:
1Given,
X=2
y=-2
z=3
Now,
[tex]3x + y - z \\ = 3 \times 2 + ( - 2) - 3 \\ = 6 + ( - 2) - 3 \\ = 6 - 2 - 3 \\ = 4 - 3 \\ = 1[/tex]
Hope this helps...
Good luck on your assignment..
Answer:
1
Step-by-step explanation:
3X+Y-Z
Where X = 2, Y = -2 amd Z = 3
=> 3(2)+(-2)-(3)
=> 6-2-3
=> 4-3
=> 1
Write an equation in point-slope form for each line.
(If possible please show work)
Answer:
so
slope is calculated this way:
[tex] \frac{3 - 6}{2 - 1} = \frac{ - 3}{1} = - 3[/tex]
let's calculate y init by:
3 = -3×2 + b
b = 9
so equation is:
y=-3x+9
Identifying Additive Inverses
Try it
Match each polynomial expression to its additive inverse.
-6x²-x-2
6x²-x+2
6x2 + x-2
6x2 - X+2
622 - x + 2
622 + x + 2
1-6x²+x-2
6x²+x-2
Intro
Done
Answer:
he additive inverse of:
a) [tex]-6x^2-x-2[/tex] is : [tex]6x^2+x+2[/tex]
b) [tex]6x^2-x+2[/tex] is : [tex]-6x^2+x-2[/tex]
c) [tex]6x^2+x-2[/tex] is : [tex]-6x^2-x+2[/tex]
d) [tex]6x^2+x+2[/tex] is : [tex]-6x^2-x-2[/tex]
Step-by-step explanation:
You need to consider that the additive inverse of a polynomial is that polynomial that consists of the opposite of each term of the polynomial given.
Then, the additive inverse of:
a) [tex]-6x^2-x-2[/tex] is : [tex]6x^2+x+2[/tex]
b) [tex]6x^2-x+2[/tex] is : [tex]-6x^2+x-2[/tex]
c) [tex]6x^2+x-2[/tex] is : [tex]-6x^2-x+2[/tex]
d) [tex]6x^2+x+2[/tex] is : [tex]-6x^2-x-2[/tex]
find the third angle in a triangle when the other two angles are (2a-32)° and (3a+22)°
Answer:
(190-5a)°
Step-by-step explanation:
Sum of internal angles of a triangle equals to 180°
If the third angle is x, then we have:
(2a-32)°+(3a+22)° +x = 180°(5a- 10)° +x= 180°x= (180+10-5a)°x= (190-5a)°The third angle is: (190-5a)°
find the area of the Triangle
6 ft
12 ft
Answer:
area = 36 ft²
Step-by-step explanation:
no figure has been given ..
therefore, area of a triangle = 1/2 * b * h
assume b = 6 ft
assume h = 12 ft
area = 1/2 * 6 * 12
area = 36 ft²
PLEASE HELP!!!! Find the common difference
Answer:
The common difference is 1/2
Step-by-step explanation:
Data obtained from the question include:
3rd term (a3) = 0
Common difference (d) =.?
From the question given, we were told that the 7th term (a7) and the 4th term (a4) are related by the following equation:
a7 – 2a4 = 1
Recall:
a7 = a + 6d
a4 = a + 3d
a3 = a + 2d
Note: 'a' is the first term, 'd' is the common difference. a3, a4 and a7 are the 3rd, 4th and 7th term respectively.
But, a3 = 0
a3 = a + 2d
0 = a + 2d
Rearrange
a = – 2d
Now:
a7 – 2a4 = 1
Substituting the value of a7 and a4, we have
a + 6d – 2(a + 3d) = 1
Sustitute the value of 'a' i.e –2d into the above equation, we have:
–2d + 6d – 2(–2d + 3d) = 1
4d –2(d) = 1
4d –2d = 1
2d = 1
Divide both side by 2
d = 1/2
Therefore, the common difference is 1/2
***Check:
d = 1/2
a = –2d = –2 x 1/2 = –1
a3 = 0
a3 = a + 2d
0 = –1 + 2(1/2)
0 = –1 + 1
0 = 0
a7 = a + 6d = –1 + 6(1/2) = –1 + 3 = 2
a4 = a + 3d = –1 + 3(1/2) = –1 + 3/2
= (–2 + 3)/2 = 1/2
a7 – 2a4 = 1
2 – 2(1/2 = 1
2 – 1 = 1
1 = 1
Study the steps used to solve the equation. Given: StartFraction c Over 2 EndFraction minus 5 equals 7 Step 1: StartFraction c Over 2 EndFraction minus 5 plus 5 equals 7 plus 5 Step 2: StartFraction c Over 2 EndFraction plus 0 equals 12 Step 3: StartFraction c Over 2 EndFraction equals 12 Step 4: 2 (StartFraction c Over 2 EndFraction) equals 12 (2) Step 5: c equals 24 Choose the property that justifies each step of the solution. Step 1: Step 2: Step 3: Step 4:
Answer:
addition property of equalityintegers are closed to additionidentity elementmultiplication property of equalitycommutative property of multiplication; reals are closed to multiplication; identity elementStep-by-step explanation:
Given:
c/2 -5 = 7
Step 1: c/2 -5 +5 = 7 +5
Step 2: c/2 +0 = 12
Step 3: c/2 = 12
Step 4: 2(c/2) = 12(2)
Step 5: c = 24
Find:
The property that justifies each step of the solution.
Solution:
Step 1: addition property of equality (lets you add the same to both sides)
Step 2: integers are closed to addition
Step 3: identity property of addition (adding 0 changes nothing)
Step 4: multiplication property of equality
Step 5: closure of real numbers to multiplication; identity property of multiplication
_____
It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.
In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.
Apart from the arithmetic, the other properties used are properties of equality. Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.
Answer:
Step 1 ~ addition property of equality
Step 2 ~ additive inverses
Step 3 ~ additive identity
Step 4 ~ multiplication property of equality
Explanation:
Addition property of equality means that If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. In this problem, they added 5 to both sides to make the equation balanced.
Additive inverses means what you add to a number to get zero. The negative of a number. -5 + 5 = 0.
Additive identity means that the sum of a number and 0 is that number.
Multiplication property of equality states that when you multiply both sides of an equation by the same number, the two sides remain equal. In this problem, they multiplied 2 to both sides to get rid of the denominator in the fraction.
For what value of the constant c is the function f continuous on (−[infinity],[infinity]) ? f(x)={cx2+2xifx<3x3−cxifx≥3
Answer:
c = 6.25
Step-by-step explanation:
We are given the following piecewise function:
[tex]\left \{ {{cx^{2} + 2x, x < 3} \atop {3x^{3} - cx, x \geq 3}} \right[/tex]
Continuous function:
A function f(x) is continuous, at a point a, if:
[tex]\lim_{x \to a} f(x)[/tex] exists and [tex]\lim_{x \to a} f(x) = f(a)[/tex]
In this question:
Piece-wise function, so we have to verify if the limit exists.
The function changes at x = 3. So we verify at a = 3.
It will exist if:
[tex]\lim_{x \to 3^{-}} f(x) = \lim_{x \to 3^{+}} f(x)[/tex]
To the left:
Less than 3.
[tex]\lim_{x \to 3^{-}} f(x) = \lim_{x \to 3^{-}} cx^{2} + 2x = c*(3)^{2} + 2*3 = 9c + 6[/tex]
To the right:
Greater than 3.
[tex]\lim_{x \to 3^{+}} f(x) = \lim_{x \to 3^{+}} 3x^{3} - cx = 3*3^{3} - 3c = 81 - 3c[/tex]
f continuous:
They have to be equal:
[tex]\lim_{x \to 3^{-}} f(x) = \lim_{x \to 3^{+}} f(x)[/tex]
[tex]9c + 6 = 81 - 3c[/tex]
[tex]12c = 75[/tex]
[tex]c = \frac{75}{12}[/tex]
[tex]c = 6.25[/tex]
I have no idea what this is
Answer:
B. -1.
Step-by-step explanation:
[tex]i^1[/tex] = i
[tex]i^2 = -1[/tex]
[tex]i^3 = -i[/tex]
[tex]i^4 = 1[/tex]
...And it keeps going in a pattern, from i to -1 to -i to 1. And so, we have four values.
34 / 4 = 8 with a remainder of 2. That means that the value of [tex]i^{34}[/tex] is the same thing as [tex]i^2\\[/tex], so it is B. -1.
Hope this helps!
The route used by a certain motorist in commuting to workcontains two intersections with traffic signals. The probabilitythat he must stop at the first signal is 0.39, the analogousprobability for the second signal is 0.54, and the probability thathe must stop at least one of the two signals is 0.64. What is theprobability that he must stop.
a.) At both signals?
b.) At the first signal but not at the second one?
c.) At exactly on signal?
Answer:
a) P(A∩B) = 0.29
b) P1 = 0.1
c) P = 0.35
Step-by-step explanation:
Let's call A the event that the motorist stop at the first signal, and B the event that the motorist stop at the second signal.
From the question we know:
P(A) = 0.39
P(B) = 0.54
P(A∪B) = 0.64
Where P(A∪B) is the probability that he stop in the first, the second or both signals. Additionally, P(A∪B) can be calculated as:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where P(A∩B) is the probability that he stops at both signals.
So, replacing the values and solving for P(A∩B), we get:
0.64 = 0.39 + 0.54 - P(A∩B)
P(A∩B) = 0.29
Then, the probability P1 that he just stop at the first signal can be calculated as:
P1 = P(A) - P(A∩B) = 0.39 - 0.29 = 0.1
At the same way, the probability P2 that he just stop at the second signal can be calculated as:
P2 = P(B) - P(A∩B) = 0.54 - 0.29 = 0.25
Finally, the probability P that he stops at exactly one signal is:
P = P1 + P2 = 0.1 + 0.25 = 0.35
Can someone help me do this? Me and my son are stuck
Hey there! :)
Answer:
Last option. (-1, 0) and (0, 6).
Step-by-step explanation:
Solve this system by setting the two equations equal to each other:
6x + 6 = -x² + 5x + 6
Rearrange the equation:
x² + 6x + 6 - 5x - 6 = 0
Combine like terms:
x² + x = 0
Factor out x:
x(x + 1) = 0
Set each factor equal to 0:
x = 0
x + 1 = 0
x = -1
These are the x values of the solutions. Plug these into an equation to solve for y:
y = 6(0) + 6
y = 6
-------
y = 6(-1) + 6
y = -6 + 6
y = 0
Therefore, the solutions to the equation are (-1, 0) and (0, 6).
correct answer will get brainliest!
if 7 is added to a number then it becomes at least 15 what is the number?
Step-by-step explanation:
yeah,when 15-7=8
the number is 8