Answer:
Area of a circle is πr²
where r is the radius
r = 7.29m
Area = π × 7.29²
= 166.957
= 166.96m² to 2 decimal places
Hope this helps you
assume the graph of a function of the form y=asin(k(x+b)) is given below. which of the following are possible values for a, k, and b?
Answer:
C
Step-by-step explanation:
Okay, here we have the equation of the sine wave as;
y = asin(k(x + b))
By definition a represents the amplitude
k represents the frequency
b represents the horizontal shift or phase shift
Now let’s take a look at the graph.
By definition, the amplitude is the distance from crest to trough. It is the maximum displacement
From this particular graph, amplitude is 4
K is the frequency and this is 1/period
The period ;
Firstly we find the distance between two nodes here and that is 1/2 from the graph (3/4 to 1/4)
F = 1/T = 1/1/2 = 1/0.5 = 2
b is pi/4 ( phase is positive as it is increasing rightwards)
So the correct option here is C
Answer: it is
a=4, k=2, and b= pi/4
Step-by-step explanation:
got it right on A P E X
A walking path across a park is represented by the equation A walking path across a park is represented by the equation y= -3x-3. A New path will be built perpendicular to this path. The Paths will intersect at a point paths will intersect at a point (-3, 6). Identify The equation that represents the new path.
Answer:
The equation representing the new path is;
[tex]y = \dfrac{1}{3} \cdot x + 7[/tex]
Step-by-step explanation:
The equation of the first walking park across the park is y = -3·x - 3
By comparison to the equation of a straight line, y = m·x + c, where m = the slope of the line, the slope of the line y = -3·x - 3 is -3
The park's new walking path direction = Perpendicular to first walking path
A line perpendicular to a line of (as example) y = m₁·x + c has a slope of -1/m
∴ The park's new walking path slope = -1/(Slope of first path) = -1/(-3) = 1/3
The point the paths will intersect = (-3, 6)
The equation of the line is found by recalling that [tex]Slope, \, m_1 =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Where:
y₂ and x₂ are coordinates of a point on the new walking path
y₁ and x₁ are coordinates of a point on the new walking path intersecting the first walking path
Given that (-3, 6) is the intersection of the two walking paths, therefore, it is a point on the new walking path and we can say x₁ = -3, y₁ = 6
Therefore, we have;
[tex]Slope, \, m_1 =\dfrac{y_{2}-6}{x_{2}-(-3)} = \dfrac{y_{2}-6}{x_{2}+3} =\dfrac{1}{3}[/tex]
Which gives;
(y₂ - 6) × 3 = x₂ + 3
y₂ - 6 = (x₂ + 3)/3
y₂ = (x₂ + 3)/3 + 6 = 1/3·x₂ + 1 + 6 = 1/3·x₂ + 7
Which gives the equation representing the new path as [tex]y = \dfrac{1}{3} \cdot x + 7[/tex].
Work out
(8 x 1011) : (4 x 1017
Give your answer in standard form.
Can someone please help I really need help
1 pound = 16 ounces.
9 pounds of sand x 16 = 144 total ounces of sand.
144 ounces / 6 ounce bottle = 24
He made 24 bottles.
Answer:
24 bottles
Step-by-step explanation:
Trevor bought 9 pounds of sand
He fills 6-ounce bottles
First let's convert pounds to ounces:
9 pounds= 9*16 ounces= 144 ouncesNow, number of bottles required:
144 / 6 = 24 bottlesThe area of a rectangular garden is given by the quadratic function:A(x)=-6x^2+105x-294A . Knowing that the area, length, and width all must be a positive value puts restrictions on the value of x. What is the domain for the function? Explain how you determined the domain. For what value of x, produces the maximum area? What is the maximum area of the garden? What is the Range of the function? Explain how you determined the range? What value(s) of x produces an area of 100 square units?
Answer and Step-by-step explanation:
The domain of a function is the values the invariable can assume to result in a real value for the variable. In other words, it is all the values x can be.
Since it's related to area, the values of x has to be positive. The domain must be, then:
[tex]-6x^{2} + 105x - 294 = 0[/tex]
Solving the second degree equation:
[tex]\frac{-105+\sqrt{105^{2} - 4(-2)(-294)} }{2(-6)}[/tex]
x = 3.5 or x = 14
The domain of this function is 3.5 ≤ x ≤ 14
The maximum area is calculated by taking the first derivative of the function:
[tex]\frac{dA}{dx} = -6x^{2} + 105x - 294[/tex]
A'(x) = -12x + 105
-12x + 105 = 0
-12x = -105
x = 8.75
A(8.75) = [tex]-6.8.75^{2} + 105.8.75 - 294[/tex]
A(8.75) = 165.375
The maximum area of the garden is 165.375 square units.
The Range of a function is all the value the dependent variable can assume. So, the range of this function is: 0 ≤ y ≤ 165.375, since this value is the maximum it will reach.
A(x) = 100
[tex]100 = -6x^{2} + 105x-294[/tex]
[tex]-6x^{2} + 105x - 394 = 0[/tex]
Solving:
[tex]\frac{-105+\sqrt{105^{2}-4(-6)()-394} }{2(-6)}[/tex]
x = 5.45 or x = 12.05
The values of x that produces an area of 100 square units are 5.45 and 12.05
Acellus
Find the value of x that will make
L||M.
2+5
x-5
--
X -
- [?]
Answer:
x = 60
Step-by-step explanation:
L // M
Sum of co-interior angles = 180
2x + 5 + x - 5 = 180
Add the like terms
3x + 0 = 180
3x = 180
Divide both sides by 3
3x/3 = 180/3
x = 60
Can someone please explain to me where did he get that 13 from or how to get it?
Answer:
2/9 * (-4 - 3) + 3
= 2/9 * (-7) + 3
= -14/9 + 3
= -14/9 + 27/9
= 13/9
Fred is making two rectangular flower beds.
The dimensions of the larger rectangle will be three times the dimensions of the smaller
rectangle.
There is going to be the same depth of soil in each flower bed.
Fred needs 180 kg of soil for the smaller flower bed.
Work out how much soil Fred needs for the larger flower bed.
Answer:
1620 kgSolution,
Let the length and breadth of smaller rectangle be l and b.
Length and breadth of larger rectangle be 3L and 3 b.
Besides, depth is same in both beds.
As area of small rectangle=180
Area of larger rectangle:
[tex]3l \times 3b \\ = 9lb \\ = 9 \times 180 \\ = 1620 \: kg[/tex]
Hope this helps..
Good luck on your assignment..
I really neeed helllpppp
Step-by-step explanation:
It's given that <KPL and <JPL are linear pair so when we add both we will get 180° so
<KPL + <JPL = 180° [ Being linear pair ]
2x + 24 + 4x + 36 = 180
6x + 60 = 180
6x = 120
x = 120/ 6
Therefore x = 20
Now
x = 20
m<KPL = 2x + 24 = 2 * 20 + 24 = 64
m<JPL = 4x + 36 = 4 *20 + 36 = 116
The volume of a right circular cone with both
2507
diameter and height equal to his What is the
3
value of h?
A) 5
B) 10
C) 20
D) 40
Question:
The volume of a right circular cone with both diameter and height equal to h is 250/7 cm³.
What is the value of h?
Answer:
A. 5
Step-by-step explanation:
Given
Solid Shape: Cone
Volume = 250/7
Diameter = Height
Required
Find the height of the cone
Provided that the diameter (D) and the height (h) are equal; This implies that
D = h ------ (1)
Also, Diameter (D) = 2 * Radius (r)
D = 2r
Substitute 2r for D in (1)
2r = h
Multiply both sides by ½
½ * 2r = ½ * h
r = ½h
Volume of a cone is calculated by;
Volume = ⅓πr²h
⅓πr²h = 250/7
Substitute ½h for r
[tex]\frac{1}{3} * \pi * (\frac{1}{2}h)^2 * h = \frac{250}{7}[/tex]
Take π as 22/7, the expression becomes
[tex]\frac{1}{3} * \frac{22}{7} * (\frac{1}{2}h)^2 * h = \frac{250}{7}[/tex]
Open the bracket
[tex]\frac{1}{3} * \frac{22}{7} * \frac{1}{4}h^2 * h = \frac{250}{7}[/tex]
Multiply both sides by 7
[tex]7 * \frac{1}{3} * \frac{22}{7} * \frac{1}{4}h^2 * h = \frac{250}{7} * 7[/tex]
[tex]\frac{1}{3} * 22 * \frac{1}{4}h^2 * h = 250[/tex]
Multiply both sides by 3
[tex]3 * \frac{1}{3} * 22 * \frac{1}{4}h^2 * h = 250 * 3[/tex]
[tex]22 * \frac{1}{4}h^2 * h = 750[/tex]
Multiply both sides by 4
[tex]4 * 22 * \frac{1}{4}h^2 * h = 750 * 4[/tex]
[tex]22 * h^2 * h = 3000[/tex]
[tex]22 * h^3 = 3000[/tex]
Divide both sides by 22
[tex]h^3 = \frac{3000}{22}[/tex]
[tex]h^3 = 136.36[/tex]
Take cube root of both sides
[tex]h = \sqrt[3]{136.36}[/tex]
[tex]h = 5.15[/tex]
[tex]h = 5[/tex] (Approximated)
? of 72 = 45 (answer in fraction)
Answer:
5/8
Step-by-step explanation:
72 = 16/10 of 45
45 = 10/16 = 5/8 of 72
If f(x) = 3x - 5 and g(x) = 7x + 2, what is f(x) x g(x)
Answer:
21x + 1
Step-by-step explanation:
f[g(x)]
= f(7x + 2)
= 3(7x + 2) - 5
= 21x + 6 - 5
= 21x + 1
Hope you can answer this one!! Offering BRAINLIEST!! Just answer a comfortable amount if you want! :))
The perimeter of a rectangular garden is 168 feet. If the length of the garden is 6 feet more than twice the width, what is the length of the garden? Length = 52.5 feet Length = 54 feet Length = 58 feet Length = 48 feet
Answer:
Length= 58
width= 26
Step-by-step explanation:
Brandybuck Insurance Company (BIC) is deciding whether to insure the lives of those leading a quest to Moria. Based on past experience, the probability of surviving such a quest is 85.4%. If BIC charges a premium of 5,533 silver coins and would pay a death benefit of 59,086 silver coins if the insured were to die, what is the expected value of this insurance policy to BIC?
Round to the nearest silver coin as needed. If the expected value is a loss to BIC, enter your answer as a negative number.
Answer:
-3901 silver coins (a loss)
Step-by-step explanation:
Probability of surviving the quest = 85.4% (Gain of 5,533 silver coins.)
If the insured were to die, the insurance company would pay a death benefit(incur a loss) of 59,086 silver coins.
Therefore:
The probability of not surviving the quest = 100%-85.4% =14.6%
Therefore, the expected value of this insurance policy to the insurance company
[tex]=(5,533 X 85.4\%)+(-59,086 X 14.6\%)\\=(5,533 X 0.854)+(-59,086 X 0.146)\\=-3901.37\\\approx -3901$ silver coins[/tex]
The expected value of this insurance policy to BIC is -3901 silver coins
The expected value of this insurance policy to BIC is -3901 silver coins (a loss)
Calculation of the expected value:Since st to Moria. Based on past experience, the probability of surviving such a quest is 85.4%. If BIC charges a premium of 5,533 silver coins and would pay a death benefit of 59,086 silver coins
So here the expected value is
= 85.4% of 5,533 + (14.6% of -59,086)
= -3901
Hence, The expected value of this insurance policy to BIC is -3901 silver coins (a loss)
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Orion is working with a data set that compares the outside temperature, in degrees Celsius, to the number of gallons of ice cream sold per day at a local grocery store.
The data has a line of best fit modeled by the function f(x) = 3x + 4 . Orion determines that when the temperature is 25∘C, the store should sell about 79 gallons of ice cream. The correlation coefficient of the data is 0.39.
Explain how accurate Orion expects the prediction to be.
Answer: kindly check Explanation.
Step-by-step explanation:
The function f(x) = 3x + 4 is a linear regression model. Orion's prediction was obtained by Substituting 25 for x to obtain the predicted variable
f(25) = 3(25) + 4 = 75 + 4 = 79.
However, with a correlation Coefficient of 0.39, which is a numerical value of range - 1 to +1 and is used to measure the statistical relationship between the dependent variable (number of gallons of ice-cream sold per day) and the independent variable (temperature).
The closer the correlation Coefficient (r) value is to +1 or - 1, the stronger the degree of correlation. Positive r values depicts positive relationship while negative r values depicts negative relationship. The closer the r value is to 0. The weaker the relationship and a r value of means there is no Relationship exists between the two variables.
With a correlation Coefficient of 0.39, we can Infer that that only a moderate positive relationship exists between temperature and gallons of ice cream sold per day.
THIS IS A WHOLE PAGE ITS FOR 40 points MIDDLE SCHOOL PLEASE HELP
Answer:
the leanth of the track is 1/2 miles long.
Step-by-step explanation:
Im sorry that i couldn't complete all the questions, I had a family thing to go to so sorry.
Q3. Ishah spins a fair 5-sided spinner. She then throws a fair coin.
(i) List all the possible outcomes she could get. The first one has been done for you.
(1, H)
(ii) Ishah spins the spinner and tosses the coin.
Work out the probability that she will get a 2 and a head.
Answer:
see below
Step-by-step explanation:
1.
1, H - 2, H - 3, H - 4, H - 5, H
1, T - 2, T - 3, T - 4, T - 5, T
2.
2,H is one out of 10 possible outcomes, so the probability is 1/10
Trig work that i don’t understand. pls help
Answer:
B. 642.22 units squared
Step-by-step explanation:
Knowing that QP ║ MN and ∠QLP = ∠MLN, then ΔQLP ~ ΔMLN.
That means corresponding sides and heights have the same ratios.
We know that QP = 25, which corresponds to MN = 34. Also, the height of ΔQLP, LS, corresponds to the height of ΔMLN, LR = LS + SR = LS + 10. Let's say LS = x.
We can now write:
QP / MN = LS / LR
25 / 34 = x / (x + 10)
Cross-multiply:
34 * x = 25 * (x + 10)
34x = 25x + 250
34x - 25x = 250
9x = 250
x = 250/9 ≈ 27.78 units
So, LS = 27.78 units and LR = LS + SR = 27.78 + 10 = 37.78 units.
The area of a triangle is denoted by A = (1/2) * b * h, where b is the base and h is the height.
Here, the base of ΔLMN is MN = 34, and the height is LR = 37.78. Plug these in:
A = (1/2) * b * h
A = (1/2) * 34 * 37.78 ≈ 642.22 units squared
The answer is thus B.
~ an aesthetics lover
Please help! It is Geometry
Answer:
X=20; pqr = 130°
Step-by-step explanation:
They key here is to notice that the instructions say that qs bisects pqr, meaning that it evenly cuts it into 2 pieces. So, to find x, you just solve for x in the equation 3x+5=2x+25. Then, you plug it back into either side of the equation, at which point, you should get 65. Since it is half of pqr, just double it to get your final answer of 130°
Which expression gives the solutions to the equation 2x^2 + 5x – 10 = 0?
Answer:
D.
Step-by-step explanation:
The formula to find the solutions of a quadratic equation is -b plus or minus the square root of b^2 - 4ac divided by 2a. In this case, a = 2, b = 5, and c = -10.
[tex]\frac{-b +-\sqrt{b^2 - 4ac} }{2a}[/tex]
= [tex]\frac{-5 +-\sqrt{5^2 - 4*2*-10} }{2 * 2}[/tex]
So, the right answer should be the choice on the lower right corner.
Hope this helps!
PLEASE HELP IMMEDIATELY
Find x when[tex] - \frac{1}{2} + x = - \frac{21}{4} [/tex]
[tex] - \frac{23}{4} [/tex]
[tex] - \frac{19}{4} [/tex]
[tex] \frac{19}{4} [/tex]
[tex] \frac{23}{4} [/tex]
Answer:
[tex]x = - \frac{19}{4} [/tex]Option B is the correct option.
Step-by-step explanation:
[tex] - \frac{1}{2} + x = - \frac{21}{4} [/tex]
Move constant to R.H.S and change its sign:
[tex]x = - \frac{21}{4} + \frac{1}{2} [/tex]
Take the L.C.M
[tex]x = \frac{ - 21 + 1 \times 2}{4} [/tex]
[tex]x = \frac{ - 21 + 2}{4} [/tex]
Calculate
[tex]x = - \frac{19}{4} [/tex]
Hope this helps...
Good luck on your assignment..
Step-by-step explanation:
-19/4 is the correct answer for your question
31.7+42.8+26.4+x/4=39.1 100.9+x/4
31.7 + 42.8 + 26.4 + x/4 = 39.1
Add up all the plain numbers on the left side:
100.9 + x/4 = 39.1
Subtract 100.9 from each side:
x/4 = 39.1
Multiply each side by 4:
x = 156.4
Answer:
Step-by-step explanation:
To solve this, we have to first find the sum of each of the terms on the numerator of the fraction on the right:
31.7 + 42.8 + 26.4 + x = 100.9 + x
The sum of terms ind the numerator of the fraction on the right.
39.1 + 100.9 + x= 140 + x
Next step is to cancel out the denominators as they are equal.
Now we are left with
100.9+x = 140+x
Rearrange and solve
To get x = 156.4
Anya graphed the line (y−2)=3(x−1) on the coordinate grid. A coordinate plane with a line passing through the points, (negative 2, negative 7), (0, negative 1), and (1, 2). What is the slope of Anya’s line? −3 −1 1 3
Answer:
Slope of Anya's line is m = 3
Step-by-step explanation:
Explanation:-
Given Anya graphed the line
(y−2)=3(x−1)
we know that slope intercept form is
y = mx +c
now given Anya line
y−2=3(x−1)
⇒ y - 2 = 3x - 3
⇒ y = 3x - 3 + 2
⇒ y = 3 x - 1
Comparing slope -intercept form
y = mx +c
slope of Anya's line is m = 3 and y-intercept C = -1
Answer:
M=3
Step-by-step explanation:
Hope this helps!
Find the the perimeter of triangle JKL
Answer:
60
Step-by-step explanation:
Tangents to a circle from a common external point are congruent, thus
JA = JB = 6
AL = KC = 11
CK = KB = 13
Thus
perimeter = 2(6) + 2(11) + 2(13) = 12 + 22 + 26 = 60
The perimeter of a triangle JKL is 60 units. Therefore, option D is the correct answer.
What is tangent property of a circle?A Tangent of a Circle is a line that touches the circle’s boundary at exactly one point. The tangential point is the place where the line and the circle meet. The lengths of tangents drawn from an external point to a circle are equal.
Given that,
Given that, JK, KL and LJ are all tangent to O. JA=6, AL=11 and CK=13.
In the figure,
From the external point J, tangents JA=JB
JB=6
From the external point L, tangents AL=LC
LC=11
From the external point K, tangents KB=KC
BK=13
So, JL=JA+LA
JL=6+11=17
LK=LC+CK
= 11+13
= 24
JK=JB+KB
= 6+13
= 19
Now, the perimeter is JL+LK+JK
= 17+24+19
= 60 units
Therefore, option D is the correct answer.
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What are the roots of the function y = 4x2 + 2x - 30?
To find the roots of the function, set y = 0. The equation is 0 = 4x2 + 2x - 30.
Factor out the GCF of
Next, factor the trinomial completely. The equation becomes
Use the zero product property and set each factor equal to zero and solve.
The roots of the function are
Answer:
-3, 5/2
Step-by-step explanation:
What are the roots of the function y = 4x2 + 2x – 30?
To find the roots of the function, set y = 0. The equation is 0 = 4x2 + 2x – 30.
Factor out the GCF of : 2, so the equation becomes 0 = 2(2x2+x-15)
Next, factor the trinomial completely. The equation becomes: 0=2(x+3)(2x-5)
Use the zero product property and set each factor equal to zero and solve.
x+3=0 2x-5 = 0
x = -3, 5/2
The roots of the function are -3, 5/2.
Hope this helped!
The roots of the function y = 4x² + 2x - 30 are -3, 5/2 after using the zero product property.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have:
y = 4x² + 2x - 30
To find the roots of the quadratic equation plug y = 0
4x² + 2x - 30 = 0
4x² + 12x - 10x - 30 = 0
4x(x + 3) - 10(x + 3) = 0
(x + 3)(4x -10) = 0
x + 3 = 0 or 4x - 10 = 0
x = -3 or x = 10/4 = 5/2
Thus, the roots of the function y = 4x² + 2x - 30 are -3, 5/2 after using the zero product property.
Learn more about the function here:
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Your bank has two checking account options, one pays tax-free interest at a rate of 3% per annum and the other pays taxable interest at a rate of 4.5% per annum. You are currently in a 24% marginal tax bracket. If you converted the tax-free interest rate to the comparable taxable interest rate you would find that:
Answer:
The comparable tax rate is 3.95%, thus you should choose the 4.5% taxable account option.
Step-by-step explanation:
In order to convert the tax-free interest rate of 3% per year to the comparable taxable interest rate, one should consider that 3% is the interest rate after the marginal tax discount. If you are at the 24% marginal tax bracket, the comparable rate is:
[tex]r*(1-0.24)=0.03\\r=\frac{0.03}{0.76}\\r=0.0395\\r=3.95\%[/tex]
The comparable tax rate is 3.95%, thus you should choose the 4.5% taxable account option.
The comparable tax rate is 3.95%, so you should choose the 4.5% taxable account option.
calculation of the comparable tax rate:Since the rate is 3% per annum, the other rate should be 4.5% and there is tax rate of 24%
So,
rate (1 - 24%) = 3%
rate = 3.95%
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perpendicular to 2x-3y+12=0
Answer:
3x +2y = 0
Step-by-step explanation:
Swapping the x- and y-coefficients and negating one of them will get you a perpendicular line. Since you have not specified a point, we can make it go through the origin:
3x +2y = 0
el 2 porsiento del 2 porsiento del 2 porsiento de 100 es uno
Answer:
No... El 2 porsiento del 2 porsiento del 2 porsiento de 100 es 0.0008.
Step-by-step explanation:
100 * 2% = 100 * 0.02 = 2
2 * 2% = 2 * 0.02 = 0.04
0.04 * 2% = 0.04 * 0.02 = 0.0008
The probability distribution for the number of students in statistics classes at is given, but one value is missing. Fill in the missing value, then answer the questions that follow. Round solutions to three decimal places, if necessary. x P ( x ) 23 0.08 24 0.12 25 0.15 26 27 0.1 Find the mean number of students in a Statistics class at : μ = Find the standard deviation of the number of students in a Statistics class at : σ =
Answer:
The mean number of students in a Statistics class = 25.47
The standard deviation of the number of students in a Statistics class = 1.081.
Step-by-step explanation:
We are given the following probability distribution for the number of students in statistics classes below;
X P(X) [tex]X \times P(X)[/tex] [tex]X^{2} \times P(X)[/tex]
23 0.08 1.84 42.32
24 0.12 2.88 69.12
25 0.15 3.75 93.75
26 0.55 14.3 371.8
27 0.10 2.7 72.9
Total 1 25.47 649.89
The missing value against value 26 is calculated as;
= 1 - (0.08 + 0.12 + 0.15 + 0.10) = 0.55
The mean of the following data is given by;
Mean,[tex]\mu[/tex] = [tex]\sum X \times P(X)[/tex] = 25.47
The variance of the following data is given by;
Variance,[tex]\sigma^{2}[/tex] = [tex]\sum X^{2} \times P(X) - (\sum X \times P(X))^{2}[/tex]
= [tex]649.89 - (25.47)^{2}[/tex]
= 1.1691
Standard deviation = [tex]\sqrt{1.1691}[/tex] = 1.081