Forces act on a box that is initially at rest as shown. Coefficient of friction between the object and the surface is μ=0.1.

If the box' mass is 6kg box and if it is moving with acceleration of 0.4m/s2, what distance will the box travel if it was pushed for 4s?

Answer:

1306.66N

Explanation:

Given data

r=12.0 m

v=14 m/s

m= 80kg

From the formula

F= mv^2/r

substitute

F= 80*14^2/12

F= 80*196/ 12

F= 15680/12

F=1306.66N

Hence the force applied is 1306.66N

Answer:

1.6e20

Explanation:

Answer:

If the frequency of a wave is doubled, what happens to its wavelength? If the frequency is doubled, the wavelength is only half as long.

Hey,

✔ We have : λ = v/f

According to this relationship, the wavelength is inversely proportional to the frequency. So when the frequency doubles, the wavelength is halved.

Answer:

I think it's theoretical.

Answer:

it would be 83% in a fatal crash.

Answer:

a. i) The pressure drop per unit length is 52,151.89 Pa

ii) The atmospheric pressure ≈ 19.175 × The pressure drop along 10 cm length of aorta

b i) The power required for the heart to push blood along a 10 cm length of aorta, is 2.6075945 Watts

ii) The basal metabolic rate ≈ 38.35 × The power to push the blood along a 10 cm length of aorta

c. i) Please find attached the drawing for the velocity profile created with Microsoft Excel

ii) The velocity at the center is approximately 2.04 m/s

Explanation:

The given diameter of the aorta, D = 2.5 cm = 0.025 m

The maximum flow rate, Q = 500 cm³/s = 0.0005 m³/s

Assumptions;

The blood flow is laminar

The blood is a Newtonian fluid

The viscosity of water ≈ 0.01 poise = 1 cp

a. i) The pressure drop per unit length of pipe ΔP/L is given by the Hagen Poiseuille equation as follows;

[tex]Q = \dfrac{\pi \cdot R^4}{8 \cdot \mu} \cdot \left(\dfrac{\Delta p}{L} \right)[/tex]

Where;

Q = The flow rate = A·v

A = The cross sectional area

R = The radius = D/2

Δp/L = The pressure drop per unit length of the pipe

Therefore, we have;

[tex]\dfrac{\Delta p}{L} = \dfrac{Q\cdot 8 \cdot \mu }{\pi \cdot R^4} = \dfrac{0.0005 \times 8 \times 1}{\pi \times 0.0125^4 } = 52151.89[/tex]

The pressure drop per unit length ΔP/L = 52,151.89 Pa

ii) The pressure, ΔP, drop along 10 cm (0.1 m) length of aorta = ΔP/L × x;

∴ ΔP = 52,151.89 Pa × 0.1 m = 5,215.189 Pa

Given that the atmospheric pressure, [tex]P_{atm}[/tex] = 10⁵ Pa, we have;

[tex]P_{atm}[/tex]/ΔP = 10⁵/5,215.189 ≈ 19.175

Therefore, the atmospheric pressure is approximately 19.175 times the pressure drop along 10 cm length of aorta

b. i) The power, P = Q × ΔP

Therefore, the power required for the heart to push blood along a 10 cm length of aorta, is P₁₀ = 0.0005 m³/s × 5,215.189 Pa = 2.6075945 Watts

ii) Therefore compared to the basal metabolic rate of, 'P', 100 W, we have;

P/P₁₀ = 100 W/2.6075945 Watts = 38.349521 ≈ 38.35

The basal metabolic rate is approximately 38.35 times more powerful than the power to push the blood along a 10 cm length

c. i) The velocity profile across the aorta is given as follows;

[tex]v_m = \dfrac{1}{4 \cdot \mu} \cdot \dfrac{\Delta P}{L} \cdot R^2[/tex]

Where;

[tex]v_m[/tex] = The velocity at the center

We get;

[tex]v_m = \dfrac{1}{4 \times 1} \times 52,151.89 \times 0.0125^2 \approx 2 .04[/tex]

The velocity at the center, [tex]v_m[/tex] ≈ 2.04 m/s

ii) The velocity profile, v(r), is given by the following formula;

[tex]v(r) = v_m \cdot \left[1 - \dfrac{r^2}{R^2} \right][/tex]

Therefore, we have;

[tex]v(r) = 2.04 - \dfrac{2.04 \cdot r^2}{0.0125^2} \right] = 2.04 - 163\cdot r^2[/tex]

The velocity profile of the pipe is created with Microsoft Excel

Answer:

a)  v = 2.9 m / s, b) A = 0.350 m, c)    v = 2.9 m / s, d)   A = 1.00 m

Explanation:

The oscillatory motion is described by the expression

          x = A cos (wt + Ф)

the wavelength which is the distance for the wave to repeat and the frequency which is the number of times a wave oscillates per unit of time

a) In this part they ask us for the speed of the wave.

Let's use the relationship between speed, wavelength and frequency

          v = λ f

For the wavelength they indicate that the distance between two crest is 6.1 m

        λ / 2 = 6.10

        λ = 12.20 m

They give us the period of the wave is the time it takes to return to the same point, in this case they give half a period

       A / 2 = 2.10

       A = 4.20 me

        f = 1 / t

        f = ¼, 2

        f = 0.238 Hz

let's calculate

         v = 12.20 0.238

         v = 2.9 m / s

b) the amplitude of the wave, is the distance from zero to some maximum

                 2A = 0.700

                   A = 0.350 m

c) the speed of the wave is not function of the amplitude, so the speed is the same

           v = 2.9 m / s

d) the amplitude is

           2A = 0.50

             A = 1.00 m

Answer:

Advantages of mercury as a thermometric liquid.

-It is a good conductor of heat and therefore the whole liquid reaches the temperature of the surroundings quickly.

-It does not wet (cling to the sides of) the tube.

-It has a high boiling point

-It expands uniformly (linear expansion) and responds quickly to temperature changes, hence is sensitive.

-It has a visible meniscus.

Disadvantages

-Mercury is very poisonous.

-its expansively is fairly low

-it is expensive

-It has a high freezing point therefore it cannot be used in places where the temperature gets very low.

Alcohol has a thermometric fluid

-Alcohol expands uniformly.

-It has a low freezing point (-115 degreecentigrade) therefore it is very suitable for place where the temperature gets very low.

-It has a large expansively

-It is an easily available cheap liquid, which is safe to use

Disadvantages of alcohol

-it wets the tube

-it has a low boiling point (cannot be used in places with high temperatures)

-it does not react quickly to changes in temperature

-It needs to be dyed, since it's colourless.

Disadvantages of water

-Water has high specific heat capacity. So it cannot be used for measuring small temperature differences.

- Water will wet the surface of the glass tube. It is a sticky substance.

- Water is transparent

Explanation:

Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a tennis racket hits a ball A. The ball pushes back on the racket in the opposite direction.

When a tennis racket hits a ball, the ball exerts a force on the racket, and according to Newton's third law of motion, the racket exerts an equal and opposite force on the ball. This means that the ball pushes back on the racket in the opposite direction to which the racket struck the ball.

This principle is often referred to as "action-reaction" or "equal and opposite forces." When the racket collides with the ball, the force applied by the racket causes the ball to accelerate in the opposite direction, leading to its movement away from the racket.

Therefore, when a tennis racket hits a ball A. The ball pushes back on the racket in the opposite direction.

For more details regarding Newton's third law of motion, visit:

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Answer:

Once we place a positive test at a point close to the sphere, we find that an electrostatic force is applied to the outside of the sphere. Therefore, at any point around the sphere, the electric field vector is radially outward.

Answer:

[tex]0.005847\ \text{s}[/tex]

Explanation:

Radio waves travel at the speed of light

[tex]c[/tex] = Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]

[tex]d_r[/tex] = Distance between two radios = 46 km

[tex]v[/tex] = Speed of sound in air = 348 m/s

[tex]d_s[/tex] = Distance sound travels across the newsroom = 2.1 m

Time taken by the radio signal to reach the required location is

[tex]t_r=\dfrac{d_r}{c}\\\Rightarrow t_r=\dfrac{46\times 10^3}{3\times 10^8}\\\Rightarrow t_r=0.000153\ \text{s}[/tex]

Time taken by sound to reach the required location is

[tex]t_s=\dfrac{d_s}{v}\\\Rightarrow t_s=\dfrac{2.1}{348}\\\Rightarrow t_s=0.006\ \text{s}[/tex]

The time difference is

[tex]t_s-t_r=0.006-0.000153=0.005847\ \text{s}[/tex]

The difference in time that the message is received is [tex]0.005847\ \text{s}[/tex].

Answer:

1.11 m.

Explanation:

Why?

The speed for a wave is done by the equation:   v = f * w. Because the frecuency tells us about how many cycles the wave makes each time, but for each cycle the wave runs certain distance, given for the wavelenght. If you isolate the letter w you get the value just doing a ratio.

v = speed

f = frecuency

w = wavelenght

w = v / f

molecular weights are written in the picture.

CH4<NH3<H2O<Cl2

a. The period of the child's motion is 3.171 seconds.

b. The frequency of the vibration is 0.315 Hz.

Since A child swings with a small amplitude on a playground with a 2.5m long chain.

a. So here the time period should be

[tex]2\times \ pi(L/g)^{1/2}\\\\2\times 3.14(2.5/9.81)^{1/2}[/tex]

T=3.171s

b) Now the frequency is

[tex]T=1\div f\\\\f=1\div 3.171[/tex]

f=0.315Hz

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Answer:

Work= Fcos∆×S

W=60N×cos 30⁰×100

W=60×0.866×100=5196.1J

PLEASE GIVE BRAINLIEST

The spring constant of the given spring is= -533.33

The potential energy of the spring= 6 Joule

A push or pull that causes object to change its state of rest or motion.

For spring;

K is the spring constant.

         ⇒Force = -kx

         ⇒80N=0.15m ×-k

          ⇒K=-80/0.15

          ⇒K= -533.333

So the spring constant is 533.333

Potential Energy=1/2kx²

                            ⇒0.5×533.33 ×0.15×0.15

                            ⇒5.95.99 N

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Answer:

a) θ = 1.67 10⁻⁵ m,  b) Consequently we must affirm that the vehicle headlights cannot resolve.

Explanation:

a) To find the resolution of the camera we use the Rayleigh criterion for diffraction

            a sin θ = m λ

where m = 1 for the first zero of the slit

we must remember that the angles in the experiments are measured in radians and are very small

            sin θ = θ

we substitute

             θ = [tex]\frac{\lambda}{a}[/tex]

this expression is for a slit, in the case of circular openings the expression must be solved in polar coordinates giving

             θ = [tex]1.22 \ \frac{\lambda}{D}[/tex]

where D diameters of the opening

let's calculate

            θ = [tex]1.22 \ \frac{550 \ 10^{-9}}{ 40\ 10^{-3}}[/tex]

           θ = 1.67 10⁻⁵ m

b) let's use trigonometry to find the separation distance on earth

            tan θ = y / x

            y = x tan θ

let's calculate

remember that the angles must be in radians

                y = 250 10³ tan 1.67 10⁻0-5

                y = 4.18 m

as they indicate that the separation of the headlights is y = 1.6m,

we see that this separation is greater than the separation distance separation.

Consequently we must affirm that the vehicle headlights cannot resolve.

Answer:

The Cell Membrane is found in both plant and animal cells.

Explanation:

Chloroplast, Large Vacuole and Cell Wall are all found in plant cells.

Answer:

Your answer is wood that is what they used

The primary energy source used by power plants to generate electricity is coal.

Power plants are plants which use fuels to generate electricity for use by homes and industries.

Power plants have different energy sources for their fuel.

The primary energy source used by power plants to generate electricity is coal.

Therefore, coal is a primary source of fuel for power plants.

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Answer: Given the evidence in the explanation, I'm pretty sure it's C. It still exists, but in a different form.

Explanation: "Some part of the energy supplied is used to change the internal energy of the system. Some part is also released into the surroundings. Generally, frictional losses are more predominant for the machines being not 100% efficient. This friction leads to the loss of energy in the form of heat, into the surroundings."

Answer:

it is for sure B. Quantitative data !

Explanation:

As I learned from quizlet!. there your welcome

Answer:

B. Quantity

Explanation:

This is easy

Answer:

* E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]

*E_ disk= 2kQ  [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]

Explanation:

Let's start by finding the electric field of the charged ring

in the attachment we can see a diagram of the system. Due to circular symmetry, the electric field perpendicular to the axis is canceled and only the electric field remains parallel to the axis.

            Eₓ = E cos θ          (1)

            E = k ∫  [tex]\frac{dq}{r^2}[/tex]

            cos θ = x / r

using the Pythagorean theorem

            r = [tex]\sqrt{x^2 + y^2}[/tex]

we substitute

            Eₓ = k ∫ [tex]\frac{dq}{x^2+y^2} \ \frac{x}{\sqrt{ x^2+y^2} }[/tex]

            Eₓ =  [tex]k \frac{x}{(c^2+y^2)^{3/2} }[/tex]   ∫ dq

             Eₓ = k \frac{x}{(c^2+y^2)^{3/2} }  Q

the ring's electric field

             E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]

Now let's find the electric field of the disk

The charge is distributed over the entire disk, so let's use the concept of charge density

              σ = [tex]\frac{dq}{dA}[/tex]

Let's approximate the disk as a group of rings, the width of each ring is dr, the area is

              dA = 2πr dr

we substitute

             σ = [tex]\frac{1}{2\pi r} \ \frac{dq}{dr}[/tex]

             dq = 2π σ r dr

we substitute in equation 1, where the electrioc field is of each ring

             Eₓ = [tex]k \int\limits^R_0 \ { \frac{x}{(x^2+r^2)^{3/2} } \ 2\pi \sigma \ r } \, dr[/tex]

if we use a change of variable

               dv = 2rdr

               v = r²

              Eₓ =  [tex]k x \pi \sigma \int\limits^a_b { \frac{1}{(x^2+v)^{3/2} } } \, dv[/tex]

we integrate

              Eₓ = k x π σ   [tex][ \frac{ (x^2 + r^2)^{-1/2} }{-1/2} ][/tex]

we value in the limits from r = 0 to r = R

              Eₓ = k π σ x  (-2) [ [tex]\frac{1}{ \sqrt{x^2+R^2} } - \frac{1}{x}[/tex]]

              Eₓ = 2π k  σ ([tex]1 - \frac{x}{(x^2 + R^2 ) ^{1/2} }[/tex]  )

             σ = Q/πR²

substitute

             Eₓ = 2 k Q/R² (1 - \frac{x}{(x^2 + R^2 ) ^{1/2} } )

             E_ disk= 2kQ  [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]

The two electric fields are

* E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]

*E_ disk= 2kQ  [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]

we can see that the functional relationship of the two fields is different

they are formed when hot

it's dependent on the rate of cooling of the melt, slow cooling allows large crystals to form, fast cooling yields small crystals. They cool too quickly to form crystals.

Hope this helps! <3 :3

Answer:

T.K.E = 750 Joules.

Explanation:

Given the following data;

Initial velocity, u = 5m/s

Final velocity, v = 10m/s

Mass of bicyclist = 50kg

Mass of bicycle = 10kg

Total mass, Tm = 50 + 10 = 60kg

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}mv^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

m represents mass measured in kilograms.

v represents velocity measured in metres per seconds square.

To find the total kinetic energy before accelerating simply means the kinetic energy due to the initial velocity and total mass;

[tex] T.K.E = \frac{1}{2}T_{m}U^{2}[/tex]

Substituting into the equation, we have;

[tex] T.K.E = \frac{1}{2}*60*5^{2}[/tex]

[tex] T.K.E = 30*25 [/tex]

T.K.E = 750 Joules.

describe how electrons create electricity

Atoms are made up of even smaller elements, called protons, electrons and neutrons. When electrical and magnetic forces move electrons from one atom to another, an electrical current is formed

Electrons in atoms can act as our charge carrier, because every electron carries a negative charge. If we can free an electron from an atom and force it to move, we can create electricity. ... In its balanced state, copper has 29 protons in its nucleus and an equal number of electrons orbiting around it.

Hope It Helps!