find the slope of the line y = 1/6x + 3/2

Answer: 1/6

Step-by-step explanation:

Slope is the m in y=mx+b

simplify the expression to a single numerical value ​

Need help with number 7 plzzz and just zoom in if u can’t see and I’ll love u forever

Question 1. If the perimeter of Rectangle ABCD is 34y+2. What is the width?

Question 2. What is the area of Rectangle ABCD in terms of y?

Question 3. If the perimeter of the rectangle is 70. What is it’s area?

Question 4. What are the length and width of the rectangle?

Which of the following is not a typical cost associated with renting?
a. last month's rent
b. pet deposit
c. property tax
d. security deposit

Steve prepreformed the chemistry experiment in which divided 5/8 of a box of baking soda evenly among the five bottles he then added vinegar and water teach volatile to make them bubble up like volcanoes how much baking soda do you put in each bottle

PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG.

Find the product and simplify.
(k+ 4)(-4k – 5)

A spherical balloon has a diameter of 4 feet.

Approximate how many cubic feet of air this balloon holds.



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NEED HELP!!! WILL GIVE BRANLIEST Which of the following options best describes the slope of line a?​

Work out the surface area of this cylinder.
Diameter = 7 cm

Height = 12 cm

NEED HELP NOW! 5 questions, 76 points!


1.
Given points B(−12,2), T(−8,10), A(−7,12), F(−6,10), and G(−2,2), which of the following proves that △BAG~△TAF?


2.
Given points A(2,1), B(1,4), C(−1,10), D(8,13), and E(4,5), which of the following proves that △ABE~△ACD?
Answers:

By the Distance Formula,AB=310‾‾‾√,AC=10‾‾‾√, AE=65‾√, and AD=25‾√. Since, ABAC=AEAD=13, and ∠A≅∠A by the Reflexive Property, △ABE∼△ACD by SAS ∼.


By the Distance Formula,AB=310‾‾‾√,AC=10‾‾‾√, AE=65‾√, and AD=25‾√. Since, ABAC=AEAD=13, and ∠A≅∠A by the Reflexive Property, △ABE∼△ACD by SSS ∼.

By the Distance Formula,AB=10‾‾‾√,AC=310‾‾‾√, AE=25‾√, and AD=65‾√. Since, ABAC=AEAD=13, and ∠A≅∠A by the Reflexive Property, △ABE∼△ACD by SSS ∼.

By the Distance Formula,AB=10‾‾‾√,AC=310‾‾‾√, AE=25‾√, and AD=65‾√. Since, ABAC=AEAD=13, and ∠A≅∠A by the Reflexive Property, △ABE∼△ACD by SAS ∼.



3.
Given points M(1,2), N(4,4), P(5,−1), J(−7,−1), K(−1,3), and L(1,−7), which of the following proves that △MNP≈△JKL?
Answers:

By the Distance Formula,MN=13‾‾‾√,NP=26‾‾‾√, and PM=5.Also, JK=213‾‾‾√,KL=226‾‾‾√, and LJ=10.Therefore, MNJK=NPKL=PMLJ=12, andtherefore, △MNP∼△JKL by SAS ∼.

By the Distance Formula,MN=13‾‾‾√,NP=26‾‾‾√, and PM=5.Also, JK=213‾‾‾√,KL=226‾‾‾√, and LJ=10.Therefore, MNJK=NPKL=PMLJ=12, andtherefore, △MNP∼△JKL by SSS ∼.

By the Distance Formula,MN=13,NP=26, and PM=25.Also, JK=52,KL=104, and LJ=100.Therefore, MNJK=NPKL=PMLJ=14, andtherefore, △MNP∼△JKL by SSS ∼.

By the Distance Formula,MN=13,NP=26, and PM=25.Also, JK=52,KL=104, and LJ=100.Therefore, MNJK=NPKL=PMLJ=14, andtherefore, △MNP∼△JKL by SAS ∼.



4.
Given points M(−5,5), R(−2,6), I(−2,4), B(2,−2), A(8,0), and G(8,−4), which of the following proves that △MRI~△BAG?
Answers:

By the Distance Formula,MR=10‾‾‾√,RI=2, and IM=10‾‾‾√.Also, BA=210‾‾‾√,AG=4, and GB=210‾‾‾√.Therefore, MRBA=RIAG=IMGB=10√210√=12,and therefore, △MRI~△BAG by SSS ~.

By the Distance Formula,MR=10,RI=2, and IM=10.Also, BA=40,AG=8, and GB=40.Therefore, MRBA=RIAG=IMGB=1040=14,and therefore, △MRI∼△BAG by SSS ∼.

By the Distance Formula,MR=2,RI=10, and IM=10.Also, BA=8,AG=40, and GB=40.Therefore, MRBA=RIAG=IMGB=1040=14,and therefore, △MRI∼△BAG by SAS ∼.

By the Distance Formula,MR=10‾‾‾√,RI=2, and IM=10‾‾‾√.Also, BA=210‾‾‾√,AG=4, and GB=210‾‾‾√.Therefore, MRBA=RIAG=IMGB=10√210√=12,and therefore, △MRI∼△BAG by SAS ∼.



5.
Given points L(−2,−2), A(−6,−3), U(−14,−5), X(4,−5), and P(0,−3), which of the following proves that △XUL~△PAL?

By the Distance Formula,LX=317‾‾‾√,PL=17‾‾‾√, LA=5‾√, and LU=35‾√. Since, LXPL=LULA=31=3, and ∠L≅∠L by the Reflexive Property, △XUL∼△PAL by SSS ∼.

By the Distance Formula,LX=35‾√,PL=5‾√, LA=17‾‾‾√, and LU=317‾‾‾√. Since, LXPL=LULA=31=3, and ∠L≅∠L by the Reflexive Property, △XUL∼△PAL by SAS ∼.

By the Distance Formula,LX=35‾√,PL=5‾√, LA=17‾‾‾√, and LU=317‾‾‾√. Since, LXPL=LULA=31=3, and ∠L≅∠L by the Reflexive Property, △XUL∼△PAL by SSS ∼.

By the Distance Formula,LX=317‾‾‾√,PL=17‾‾‾√, LA=5‾√, and LU=35‾√. Since, LXPL=LULA=31=3, and ∠L≅∠L by the Reflexive Property, △XUL∼△PAL by SAS ∼.

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Soon as possible !!!



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