Answer:
[tex]\frac{1}{256}[/tex]
Step-by-step explanation:
Geometric sequence means there is a common ratio. All that means is term divided previous term is the same across your sequence.
ONE WAY:
So we are given here that:
[tex]\frac{f(2)}{f(1)}=\frac{1}{2}[/tex] and that the first term which is [tex]f(1)[/tex] is 2.
[tex]\frac{f(2)}{2}=\frac{1}{2}[/tex]
This implies [tex]f(2)=1[/tex] after multiplying both sides by 2 and getting that [tex]f(2)=\frac{1}{2}(2)=\frac{2}{2}=1[/tex].
So you have that
2,1,...
basically you can just multiply by 1/2 to keep generating more terms of the sequence.
Third term would be [tex]f(3)=1(\frac{1}{2})=\frac{1}{2}[/tex].
Fourth term would be [tex]f(4)=\frac{1}{2}(\frac{1}{2})=\frac{1}{4}[/tex].
...keep doing this til you get to the 10th term.
ANOTHER WAY:
Let's make a formula.
[tex]f(n)=ar^{n-1}[/tex]
[tex]a[/tex] is the first term.
[tex]r[/tex] is the common ratio.
And we want to figure out what happens at [tex]n=10[/tex].
Let's plug in our information we have
[tex]a=2[/tex]
[tex]r=\frac{1}{2}[/tex]:
[tex]f(10)=2(\frac{1}{2})^{10-1}[/tex]
Put into calculator or do by hand...
[tex]f(10)=2(\frac{1}{2})^9[/tex]
[tex]f(10)=2(\frac{1^9}{2^9})[/tex]
[tex]f(10)=2(\frac{1}{2^9})[/tex]
[tex]f(10)=\frac{2}{2^9}[/tex]
[tex]f(10)=\frac{2}{2(2^8)}[/tex]
[tex]f(10)=\frac{1}{2^8}[/tex]
Scratch work:
[tex]2^8=2^5 \cdot 2^3=32 \cdot 8=256[/tex].
End scratch work.
The answer is that the tenth term is [tex]\frac{1}{256}[/tex]
Answer:
For an nth term in a geometric sequence
[tex]U(n) = a ({r})^{n - 1} [/tex]
where n is the number of terms
r is the common ratio
a is the first term
From the question
a = 2
r = 1/2
n = 10
So the 10th term of the sequence is
[tex]U(10) = 2 ({ \frac{1}{2} })^{10 - 1} \\ \\ = 2 ({ \frac{1}{2} })^{9} \\ \\ \\ = \frac{1}{256} [/tex]
Hope this helps you
a) Reetu sold a watch to Reshmi at 20% profit. Reshmi again sold the same watch to
Nikita for Rs 1,350 at a loss of 10%. At what price did Reetu purchase the watch?
41
ique's Mathematics - 9
Answer:
1250,Rs
Step-by-step explanation:
Let Reetu paid for the watch x Rs. Then Reetu sold the watch to Reshmi having 20% profit => the selling price is 1.2*x
Then Teshmi sold the wathes with 10% loss (or 0.9 from purchase price 1.2x) to Nikita, i.e. selling price is
1.2*x*0.9=1350
1.08*x=1350
x=1350:1.08
x=1250, Rs
Question 4 of 10
Which polynomial represents the difference below?
5x2
+9x+3
(6x2-3x)
O A. -x + 12x+3
B. 5x2 + 3x + 3
O C. 5x2 + 6x + 3
O D. - x2 + 6x + 3
SUBMIT
PREVIOUS
Answer:
-x² + 12x + 3
Step-by-step explanation:
Step 1: Write expression
5x² + 9x + 3 - (6x² - 3x)
Step 2: Distribute
5x² + 9x + 3 - 6x² + 3x
Step 3: Combine like terms
-x² + 12x + 3
Find the fourth term in the expansion of the binomial
(4x + y)^4
a) 16xy^3
b) 256x^4
c) 64y^4
d) 4xy^3
Answer:
a) 16xy³
Step-by-step explanation:
For a binomial expansion (a + b)ⁿ, the r+1 term is:
nCr aⁿ⁻ʳ bʳ
Here, a = 4x, b = y, and n = 4.
For the fourth term, r = 3.
₄C₃ (4x)⁴⁻³ (y)³
4 (4x) (y)³
16xy³
Evaluate. Write your answer as a fraction or whole number without exponents. 6^–4 =
Answer:
The answer is 1/1296
Step-by-step explanation:
6^-4 can be written as 1/6⁴
And
1/6⁴ = 1/1296
Hope this helps you.
Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visit because of a coupon they'd received in the mail. Construct a 95% con dence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail.
Answer:
The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 603, \pi = \frac{142}{603} = 0.2355[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694[/tex]
The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)
Please answer this correctly
Step-by-step explanation:
pnotgrt8rthan4 = 3 ÷ 7 × 100
= 42.8571428571 / 43%
QUESTION 1 (ONLY ANSWER FOR ALL QUESTIONS) a) 2x/3 =8 (what is x=?) b)3x/2 =6 (what is x=?) QUESTION 2 a)x/3 -2 =6 (what is x=?) b )x/5 +1 = 5 (what is x=?) QUESTION 3 a) 5x/2 +1 =11 (what is x=?) b)2x/7 -3 = 2 (what is x=?)
Answer:
1 (a) x = 12
1 (b) x = 4
2 (a) x = 24
2 (b) x = 20
3 (a) x = 4
3 (b) x = 17.5
Step-by-step explanation:
1 (a)
2x/3 = 8
2x = 8 × 3
2x = 24
x = 24 ÷ 2
x = 12
1 (b)
3x/2 = 6
3x = 6 × 2
3x = 12
x = 12 ÷ 3
x = 4
2 (a)
x/3 - 2 = 6
x/3 = 6 + 2
x/3 = 8
x = 8 × 3
x = 24
2 (b)
x/5 + 1 = 5
x/5 = 5 - 1
x/5 = 4
x = 4 × 5
x = 20
3 (a)
5x/2 + 1 = 11
5x/2 = 11 - 1
5x/2 = 10
5x = 10 × 2
5x = 20
x = 20 ÷ 5
x = 4
3 (b)
2x/7 - 3 = 2
2x/7 = 2 + 3
2x/7 = 5
2x = 5 × 7
2x = 35
x = 35 ÷ 2
x = 17.5
What is the measure of PSQ?
Answer:
Do you have an image because I'm a bit confused with you just asking the measure of PSQ.
Step-by-step explanation:
What steps are used to solve the equation? g – 8 = 14 Complete the statements. First, both sides of the equation. The solution of the equation is . Check the solution by substituting for g and simplifying.
Answer:
g=22
Step-by-step explanation:
add 8 to both sides
g-8=14
g-8+8=14+8
g=14+8
g=22
The solution of expression g - 8 = 14 is,
⇒ g = 22
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
The equation is,
⇒ g - 8 = 14
Now, We can simplify as,
⇒ g - 8 = 14
Add 8 both side,
⇒ g - 8 + 8 = 14 + 8
⇒ g = 22
Thus, The solution of expression g - 8 = 14 is,
⇒ g = 22
Learn more about the mathematical expression visit:
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Josh and Lucy share some money in the ratio 3:7. What fraction of the money does Josh receive?
Answer:
3/10ths of the money
Step-by-step explanation:
Add together the two numbers to get the total.
Josh gets 30 percent and Lucy gets 70 percent.
3/10
Answer:
3/10
Step-by-step explanation:
3+7=10
Josh=3
Lucy=7
The graph shows the relationship between inches, x, and miles, y, on a map. Which equation represents the proportional relationship.
A y = x + 5
B y = 1/5x
C y = 5x
D y = 10x
I'll show you the graph
Find the value of x in the diagram below. A. B. C. D. Please select the best answer from the choices provided A B C D
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Trigonometry.
Since we have to use here, Sine ration.
Sine of an Angle = Perpendicular side/Hypotenuse Side.
So we get as,
X = 3 .
Answer:
the answer is c
Step-by-step explanation:
Please answer this correctly
Answer:
1/7
Step-by-step explanation:
There are 7 cards, 1 of which is less than 2. Therefore, P (less then 2) = 1/7
Answer:
1/7
Step-by-step explanation:
The number from the list that is less than 2 is 1.
1 number out of a total of 7 numbers.
= 1/7
The following situation can be modeled by a linear function. Write an equation for the linear function and use it to answer the given question. Be sure you clearly identify the independent and dependent variables. Then briefly discuss whether a linear model is reasonable for the situation described. The price of a particular model car is $19,000 today and rises with time at a constant rate of $960 per year. How much will a new car of this model cost in 3.7 years?
Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.)
A. The independent variable is the price (o) in dollars, and the dependent variable is time (1), in years. The linear function that models this situation is __________
B. The independent variable is time (), in years, and the dependent variable is the price (p), in dollars. The linear function that models this situation is________
The price of a car after 3.7 years will be $ (Simplify your answer.) Is a linear model reasonable for the situation?
A. The linear model is most likely not reasonable, because the price of a new car of the same model never changes, regardless of how much time passes.
B. The linear model is most likely not reasonable, because the price of a new car of the same model will always decrease at a constant rate.
C. The linear model is most likely not reasonable, because it is unlikely that the price of a new car of the same model will increase at a constant rate. always increases at a constant rate.
Answer: The answer is B)
B. The independent variable is time (t), in minutes, and the dependent variable is rental cost (r), in dollars. The linear function that models this situation is r equals to r=0.55x+8
Step-by-step explanation:
Flora paid her supplier $0.75 a stem for roses to sell at her flower shop. She added an 80% markup. What is the amount of markup?
Answer:
$0.60
Step-by-step explanation:
the question ask us to find the amount of the markup on Flora’s roses. The amount of markup is given by:
markup rate x original price = amount of markup
the markup rate is in decimal form
since the original price was $0.05 and the markup price is 80% = 0.80, we have
0.80 x .075 = 0.60
thus, the amount of the markup on Flora’s roses was $0.60
Stat 3309 - Statistical Analysis for Business Applications I
Consider the following data representing the starting salary (in $1,000) at some company and years of prior working experience in the same ï¬eld. The sample of 10 employees was taken and the following data is reported.
Years of experience
Starting Salary (in $1,000)
0
45
2 50
5 55
7 62
8 63
10 70
12 68
15 75
18 81
20 92
Part 1: Use the formulas provided on the 3rd formula sheet to compute the following quantities. Open an Excel spreadsheet and write the table with data given above. Add columns for x2, y2, and xy, as well as the last row for Σ. For each of the following quantities, write the formula for it in a cell and evaluate it.
(a) Find the sample correlation coeï¬cient r.
(b) Find the slope b1 of the sample regression line.
(c) Find the y-intercept b0 of the sample regression line.
(d) What is the equation of the sample regression line?
(e) Find the predicted starting salary for a person who spent 15 years working in the same ï¬eld.
(f) Find the observed starting salary for a person who spent 15 years working in the same ï¬eld.
(g) What is the diï¬erence between the observed and the predicted starting salary for a person who spent 15 years working in the same ï¬eld?
(h) Find the total sum of squares SST.
(i) Find the sum of squares error SSE.
(j) Find the sum of squares regression SSR.
(k) Use the answers from (h)-(j) to conï¬rm that SST = SSR + SSE. (l) Find the coeï¬cient of determination R2.
(m) Use your answers for (a), (b) and (l), to conï¬rm that r = ±âR2.
(n) What proportion of variation is explained using the regression model?
(o) Find the standard error of the estimate se.
(p) Find the standard error of the regression slope sb.
(q) Does the number of years of prior working experience in the same ï¬eld aï¬ect the starting salary at this company ? Use the sample provided above and the signiï¬cance level of 0.05.
(hint: perform the hypothesis test for H0 : β1 = 0 vs. H1 : β1 6= 0.)
Part 2: Find and use Excel built-in-functions to check your answers for r, b1, and b0. Next to each cell from Part 1, calculate these three quantities using Excel built-in-functions and conï¬rm your answers from Part 1.
(hint: for example, for r the Excel built-in function is "CORREL")
Part 3: Bellow your answers from Parts 1 and 2, perform the regression analysis using Excel built-in-module which can be found under "DATA" â "Data Analysis" â "Regression" and double check your answers from Part 1. Draw the scatter plot of the data and, by visually observing the graph, determine if there is a linear relationship between the number of years of prior working experience in the same ï¬eld and the starting salary at this company.
Answer:
Solved below.
Step-by-step explanation:
The data is provided for the starting salary (in $1,000) at some company and years of prior working experience in the same field for randomly selected 10 employees.
(a)
The formula to compute the correlation coefficient is:
[tex]r=~\frac{n\cdot\sum{XY} - \sum{X}\cdot\sum{Y}} {\sqrt{\left[n \sum{X^2}-\left(\sum{X}\right)^2\right] \cdot \left[n \sum{Y^2}-\left(\sum{Y}\right)^2\right]}} \\[/tex]
The required values are computed in the Excel sheet below.
[tex]\begin{aligned}r~&=~\frac{n\cdot\sum{XY} - \sum{X}\cdot\sum{Y}} {\sqrt{\left[n \sum{X^2}-\left(\sum{X}\right)^2\right] \cdot \left[n \sum{Y^2}-\left(\sum{Y}\right)^2\right]}} \\r~&=~\frac{ 10 \cdot 7252 - 97 \cdot 661 } {\sqrt{\left[ 10 \cdot 1335 - 97^2 \right] \cdot \left[ 10 \cdot 45537 - 661^2 \right] }} \approx 0.9855\end{aligned}[/tex]
Thus, the sample correlation coefficient r is 0.9855.
(b)
The slope of the regression line is:
[tex]b_{1} &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\\= \frac{ 10 \cdot 7252 - 97 \cdot 661 }{ 10 \cdot 1335 - \left( 97 \right)^2} \\\\\approx 2.132[/tex]
Thus, the slope of the regression line is 2.132.
(c)
The y-intercept of the line is:
[tex]b_{0} &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\\= \frac{ 661 \cdot 1335 - 97 \cdot 7252}{ 10 \cdot 1335 - 97^2} \\\\\approx 45.418[/tex]
Thus, the y-intercept of the line is 45.418.
(d)
The equation of the sample regression line is:
[tex]y=45.418+2.132x[/tex]
(e)
Compute the predicted starting salary for a person who spent 15 years working in the same field as follows:
[tex]y=45.418+2.132x\\\\=45.418+(2.132\times15)\\\\=45.418+31.98\\\\=77.398\\\\\approx 77.4[/tex]
Thus, the predicted starting salary for a person who spent 15 years working in the same field is $77.4 K.
Answer:
Yes correct
Step-by-step explanation:
I think this is correct becase: 2 50
5 55
7 62
etc
these are all correct
Solve the puzzle
Replace the question marks with numbers:
76533483
94529245
958??769
Answer:
95891769
Step-by-step explanation:
This is extract from a brain teaser exercise in which sequence is formed to identify the numbers. In this brain teaser we have made combinations of different numbers which lead to the correct answer. The two correct forms of number are given which are used as a base for determining the correct answer.
Question 4
If Madeline wanted to know whether or not her sample results could be generalized to the population, she would use
Answer:
Inferential statistical methods
Step-by-step explanation:
Remember, Madeline had obtained sample results, but she wants to decide whether to apply the sample results to the entire population. To do this, she can use the following:
- estimate her research parameters or
- or perform a hypothesis test which answers her research objectives.
Based on the results she gets, Madeline, can to thus infer from the sample results and apply them to the population.
A researcher looked at characteristics of elementary school students and,
in particular, observed whether students satisfied any of the following
criteria:
A = The student lived with at least one of their biological parents
B = The student lived with at least one grandparent
C = The student lived with two parents who were legally married
D = The student lived with only one parent
Which of the events above are mutually exclusive? Select all that apply.
1.) A,C
2.) A,D
3.) C,D
4.) B,C
(Side note: I put down options 3&4 but got it wrong, not sure what I’m missing?)
Answer:
1. A, C
2. A, D
Step-by-step explanation:
The mutually exclusive events are one which cannot happen together. The observation is made regarding with which students live. They live with either one of their biological parent or grandparent. The student have the option to live with two legally married couple this is mutually exclusive event. If the student is living with their one biological parent he cannot live with two legally married parents.
Below is the computer output for the appraised value (in thousands of dollars) and number of rooms for houses in East Meadow, New York. Predict the price of a 9 room house (in thousands of dollars) The regression equation is value 748+19.7 rooms Coef 9.718 R-sq 43.896 Stdev 19.04 2.631 t-ratio 3.93 7.49 Constant Rooms S 29.05 Analysis of Variance Source R-sq (adj) 43.0% MS 47398 844 DF 47398 60775 108173 Regression rror Total 72 73 a) 370.262 b) 257.262 c) 252.262 d) 362.262 e) 756.786 f) None of the above
Answer:
The predicted price of a 9 room house is $925.3 K.
Step-by-step explanation:
The regression equation for predicting the appraised value (in thousands of dollars) from the number of rooms for houses in East Meadow, New York is as follows:
[tex]\text{Value}=748+19.7\ \text{Rooms}[/tex]
Compute the price of a 9 room house as follows:
[tex]\text{Value}=748+19.7\ \text{Rooms}[/tex]
[tex]=748+(19.7\times 9)\\\\=748+177.3\\\\=925.3[/tex]
Thus, the predicted price of a 9 room house is $925.3 K.
The price of a 9-room house is (c) $252.262
The regression equation is given as:
[tex]\mathbf{y = 74.8 + 19.7 \times rooms}[/tex]
For a 9-room house, we have:
Rooms = 9
Substitute 9 for rooms in the above regression equation
[tex]\mathbf{y = 74.8 + 19.7 \times 9}[/tex]
Multiply
[tex]\mathbf{y = 74.8 + 177.3}[/tex]
Add
[tex]\mathbf{y = 252.1}[/tex]
The closest to this value is (c) $252.262
Hence, the price of a 9-room house is (c) $252.262
Read more about regression equations at:
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Circles c and c are similar state the translation rule and the scale factor of dilation
To obtain circle C', circle C was translated to the right 3 units and down 2 units, then dilated by a scale factor of 2
What is a transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, rotation, reflection and dilation.
Dilation is the increase or decrease in the size of a figure.
To obtain circle C', circle C was translated to the right 3 units and down 2 units, then dilated by a scale factor of 2
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Write the equation of each line in slope-intercept form.
(If possible please show work)
Answer:
y = -1/2x + 1/2
Step-by-step explanation:
Step 1: Write in known variables
y = -1/2x + b
Step 2: Find b
2 = -1/2(-3) + b
2 = 3/2 + b
b = 1/2
Step 3: Rewrite equation
y = -1/2x + 1/2
An engineer for an electric fencing company is interested in the mean length of wires being cut automatically by machine. The desired length of the wires is 12 feet. It is known that the standard deviation in the cutting length is 0.15 feet. Suppose the engineer decided to estimate the mean length to within 0.025 with 99% confidence. What sample size would be needed?
Answer:
[tex]n=(\frac{2.58(0.15)}{0.025})^2 =239.63 \approx 240[/tex]
So the answer for this case would be n=240 rounded up to the nearest integer
Step-by-step explanation:
We know the following info:
[tex]\sigma =0.15[/tex] represent the population deviation
[tex] ME= 0.025[/tex] the margin of error desired
The margin of error is given by this formula:
[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (a)
And on this case we have that ME =0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
[tex]n=(\frac{z_{\alpha/2} s}{ME})^2[/tex] (b)
The critical value for 99% of confidence interval now can be founded using the normal distribution. And we got [tex]z_{\alpha/2}=2.58[/tex], replacing into formula (b) we got:
[tex]n=(\frac{2.58(0.15)}{0.025})^2 =239.63 \approx 240[/tex]
So the answer for this case would be n=240 rounded up to the nearest integer
What is the area of the equilateral triangle with side length of 6?
Answer:
18
Step-by-step explanation:
area of a triangle is length x base
so 6 x 6 = 36
36 divided by 2 = 18
I hope it helps :)
Answer: The area is about 15.59 and is round to the nearest hundredth.
Step-by-step explanation:
An equilateral triangle has three equal sides is just like an isosceles triangle.
So in this case, we know that the base is 6 and since the base is 6 all the other two sides is also 6 .But we do not know the height to find the area so we need to find the height.
The height is the distance of from the base to the tip or top which helps form two right triangles.. And if you divide as an equilateral triangle into two parts you will form two right triangles. Imagine we have divide the isosceles triangle into two parts to form two right triangles. We will now have a base of 3 instead of 6 and and hypotenuse of 6 . but we still don't know the height so we need to find it.
Using the Pythagorean Theorem we could say that a^2 plus b^2 squared is equal to c^2 squared.
We know a as 3 and c the hypotenuse as 6.
so 3^2 + b^2 =6^2 solve for b
9 + b^2 = 36
-9 -9
b^2 = 27
b= [tex]\sqrt{27}[/tex]
b= 5.196
Now we know that b is about 5.196 which is the height.Now we could find the area by multiplying the base by the height.
5.196 * 6 = 31.176
31.176/2 = 15.588
Now you could round it to the nearest hundredth to be 15.59
The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.$lower bound of confidence interval ______________$ upper bound of confidence interval __________________Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.$ lower bound of confidence interval _______________$ upper bound of confidence interval. _______________
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.
Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.
xbar = $1,465,752
SD = $1,346,046.2
lower bound of confidence interval ________
upper bound of confidence interval _______
Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.
xbar = $1,371,191
SD = $1,130,666.5
lower bound of confidence interval _________
upper bound of confidence interval. ________
Answer:
Question 1:
lower bound of confidence interval = $1,124,027
upper bound of confidence interval = $1,807,477
Question 2:
lower bound of confidence interval = $1,081,512
upper bound of confidence interval = $1,660,870
Step-by-step explanation:
Question 1:
The sample mean salary of 62 couches is
[tex]\bar{x} = 1,465,752[/tex]
The standard deviation of mean salary is
[tex]s = 1,346,046.2[/tex]
The confidence interval for the mean salary of all basketball coaches is given by
[tex]$ CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $[/tex]
Where [tex]\bar{x}[/tex] is the sample mean, n is the sample size, s is the sample standard deviation and [tex]t_{\alpha/2}[/tex] is the t-score corresponding to a 95% confidence level.
The t-score corresponding to a 95% confidence level is
Significance level = α = 1 - 0.95 = 0.05/2 = 0.025
Degree of freedom = n - 1 = 62 - 1 = 61
From the t-table at α = 0.025 and DoF = 61
t-score = 1.999
So the required 95% confidence interval is
[tex]CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (\frac{1,346,046.2}{\sqrt{62} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (170948.04 ) \\\\CI = 1,465,752 \pm 341,725 \\\\LCI = 1,465,752 - 341,725 = 1,124,027 \\\\UCI = 1,465,752 + 341,725 = 1,807,477\\\\[/tex]
Question 2:
After removing the Coach Krzyzewski's salary from the data
The sample mean salary of 61 couches is
[tex]\bar{x} = 1,371,191[/tex]
The standard deviation of the mean salary is
[tex]s = 1,130,666.5[/tex]
The t-score corresponding to a 95% confidence level is
Significance level = α = 1 - 0.95 = 0.05/2 = 0.025
Degree of freedom = n - 1 = 61 - 1 = 60
From the t-table at α = 0.025 and DoF = 60
t-score = 2.001
So the required 95% confidence interval is
[tex]CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (\frac{1,130,666.5}{\sqrt{61} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (144767 ) \\\\CI = 1,371,191 \pm 289,678.8 \\\\LCI = 1,371,191 - 289,678.8 = 1,081,512 \\\\UCI = 1,371,191 + 289,678.8 = 1,660,870\\\\[/tex]
An athletics coach states that the distribution of player run times (in seconds) for a 100-meter dash is normally distributed with a mean equal to 13.00 and a standard deviation equal to 0.2 seconds. What percentage of players on the team run the 100-meter dash in 13.36 seconds or faster
Answer:
96.41% of players on the team run the 100-meter dash in 13.36 seconds or faster
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 13, \sigma = 0.2[/tex]
What percentage of players on the team run the 100-meter dash in 13.36 seconds or faster
We have to find the pvalue of Z when X = 13.36.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{13.36 - 13}{0.2}[/tex]
[tex]Z = 1.8[/tex]
[tex]Z = 1.8[/tex] has a pvalue of 0.9641
96.41% of players on the team run the 100-meter dash in 13.36 seconds or faster
Solve the equation: 1. 3y+(y−2)=2(2y−1) 2. 6(1+5x)=5(1+6x)
Answer:
Step-by-step explanation:
I'm not sure what are u asking exactly
Marty and Jean are married and have 4-year-old twins. Jean is going to school full-time for 11 months of the year, and Marty earns $59,200. The twins are in day care so Jean can go to school while Marty is at work. The cost of day care is $10,100. TABLE 6.1 CHILD AND DEPENDENT CARE CREDIT PERCENTAGES Adjusted Gross Income Applicable Percentage Over But Not Over $0 – $15,000 35% 15,000 – 17,000 34% 17,000 – 19,000 33% 19,000 – 21,000 32% 21,000 – 23,000 31% 23,000 – 25,000 30% 25,000 – 27,000 29% 27,000 – 29,000 28% 29,000 – 31,000 27% 31,000 – 33,000 26% 33,000 – 35,000 25% 35,000 – 37,000 24% 37,000 – 39,000 23% 39,000 – 41,000 22% 41,000 – 43,000 21% 43,000 – No limit 20% What is their child and dependent care credit?
Answer:
Answer: $2,000
Step-by-step explanation:
-Use form 2441 on the IRS website for 2019.
-Wages earned=$45,000, therefore, it would be between "over 43,000 but not over 'No Limit' " which is 20% (.20)
-$10,000(paid in daycare) × .20 = $2,000
Study the steps used to solve the equation. Given: StartFraction c Over 2 EndFraction minus 5 equals 7 Step 1: StartFraction c Over 2 EndFraction minus 5 plus 5 equals 7 plus 5 Step 2: StartFraction c Over 2 EndFraction plus 0 equals 12 Step 3: StartFraction c Over 2 EndFraction equals 12 Step 4: 2 (StartFraction c Over 2 EndFraction) equals 12 (2) Step 5: c equals 24 Choose the property that justifies each step of the solution. Step 1: Step 2: Step 3: Step 4:
Answer:
addition property of equalityintegers are closed to additionidentity elementmultiplication property of equalitycommutative property of multiplication; reals are closed to multiplication; identity elementStep-by-step explanation:
Given:
c/2 -5 = 7
Step 1: c/2 -5 +5 = 7 +5
Step 2: c/2 +0 = 12
Step 3: c/2 = 12
Step 4: 2(c/2) = 12(2)
Step 5: c = 24
Find:
The property that justifies each step of the solution.
Solution:
Step 1: addition property of equality (lets you add the same to both sides)
Step 2: integers are closed to addition
Step 3: identity property of addition (adding 0 changes nothing)
Step 4: multiplication property of equality
Step 5: closure of real numbers to multiplication; identity property of multiplication
_____
It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.
In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.
Apart from the arithmetic, the other properties used are properties of equality. Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.
Answer:
Step 1 ~ addition property of equality
Step 2 ~ additive inverses
Step 3 ~ additive identity
Step 4 ~ multiplication property of equality
Explanation:
Addition property of equality means that If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. In this problem, they added 5 to both sides to make the equation balanced.
Additive inverses means what you add to a number to get zero. The negative of a number. -5 + 5 = 0.
Additive identity means that the sum of a number and 0 is that number.
Multiplication property of equality states that when you multiply both sides of an equation by the same number, the two sides remain equal. In this problem, they multiplied 2 to both sides to get rid of the denominator in the fraction.
if 7 is added to a number then it becomes at least 15 what is the number?
Step-by-step explanation:
yeah,when 15-7=8
the number is 8