Find c. Round to the nearest tenth.

Answer:

300 sqft

Step-by-step explanation:

30 times ten is 300 and the measure is feet squared

Answer:

9000 ft 3

Step-by-step explanation:

Answer:

1,2 = 1,negative2

3,6 = 3,negative 6

-1,2 = negative 1, negative 2

-2,-2 = negative2, 2

Step-by-step explanation:

Sorry all i could do was reflect the coordinates across the x-axis.

The figure reflected along x-axis will have vertices A(1, -2), B (3, -6), C(-1, -2), and D(-2, 2).

When we reflect a figure along the x-axis the coordinate point of y changes its sign, (x, y) becomes (x, - y).

Think of holding the x-axis with two fingers and rotating it.

Given, we reflect a figure with vertices A(1,2) B (3,6), C(-1,2), and D(-2,-2)

across the x-axis.

∴ The rotated coordinate will be A(1, -2), B (3, -6), C(-1, -2), and D(-2, 2).

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Answer:

=32x−24

Step-by-step explanation:

12873t456473892220-209873

Answer:

=[tex](x-1)(x+6)[/tex]

Step-by-step explanation:

Answer:

[tex]x^{2} +5x-6=(x-1)(x+6)[/tex]

Step-by-step explanation:

Answer:

$3.25 for 1 pound of coleslaw

Step-by-step explanation:

i think,.

Answer:

∠U = 26°

∠V = 35°

∠W = 119°

Step-by-step explanation:

Given:

∠U = (x+9)°

∠V = (2x+1)°

∠W = (7x)°

Find:

Value of each angle

Computation:

Using angle sum property

∠U + ∠V + ∠W = 180°

(x+9)° + (2x+1)° + (7x)° = 180°

10x + 10 = 180

x = 17

So,

∠U = (x+9)° = 17 + 9 = 26°

∠V = (2x+1)° = 34 + 1 = 35°

∠W = (7x)° = 7 x 17 = 119°

Answer:

(f o h)(-5)=-33

Step-by-step explanation:

Let f(x) = 4x - 1, h(x) = - X-3.

(f o h)=4(-x-3)-1

(f o h)=-4x-12-1

(f o h)=-4x-13

(f o h)(-5)=-4(-(-5))-13

(f o h)(-5)=-20-13

(f o h)(-5)=-33

Given:

The statement is " a is the fourth root of 16".

To find:

The true statement for the given statement.

Solution:

The given statement is

a is the fourth root of 16.

Mathematically, it can be written as

[tex]a=\sqrt[4]{16}[/tex]

Taking power 4 on both sides.

[tex]a^4=(\sqrt[4]{16})^4[/tex]

[tex]a\times a\times a\times a=16[/tex]

Therefore, the correct option is A.

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

Important Information :

'a' is the fourth root of 16 can be written as

[tex]a=\sqrt[4]{16}[/tex]

To remove fourth root, we take exponent 4 on both sides

[tex]a=\sqrt[4]{16}\\(a)^4=(\sqrt[4]{16})^4[/tex]

Exponent 4  and fourth root will get cancelled

[tex]a^4=16\\a \cdot a\cdot a \cdot a=16[/tex]

a x a x a x a = 16

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

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Answer:

750 is the answer. Hope it helps!

Answer:

The last one

Step-by-step explanation:

Due to there being xy's in both terms

Answer:

9 beads are purple

Step-by-step explanation:

we know that

To find out how many  beads are purple, multiply the total beads by the fraction of the beads that are purple

so

therefore

9 beads are purple

Another way to solve the problem is convert the fraction in percentage

we have

so

If the total are 18 beads

50% is 9 beads

therefore

9 beads are purple

Answer:

The speed of the jet with no wind is 240 miles per hour.

Step-by-step explanation:

The speed of the jet with no wind is equivalent to the speed of the jet relative to wind. Physically speaking, we have the following system of linear equations under the assumption that both speeds of wind and jet are constant:

In favor of wind

[tex]\frac{s}{t_{F}} = v_{W}+v_{J/W}[/tex] (1)

Against wind

[tex]-\frac{s}{t_{A}} = v_{W} -v_{J/W}[/tex] (2)

Where:

[tex]s[/tex] - Travelled distance, measured in miles.

[tex]t_{F}[/tex], [tex]t_{A}[/tex] - Time, measured in hours.

[tex]v_{W}[/tex] - Wind speed, measured in miles per hour.

[tex]v_{J/W}[/tex] - Jet speed relative to wind, measured in miles per hour.

If we know that [tex]t_{F} = 5\,h[/tex], [tex]t_{A} = 7\,h[/tex], [tex]v_{W} = 40\,\frac{mi}{h}[/tex], then the speed of the jet with no wind is:

[tex]\frac{s}{5} = 40 + v_{J/W}[/tex] (3)

[tex]-\frac{s}{7} = 40-v_{J/W}[/tex] (4)

[tex]\frac{s}{5}-40 = 40 +\frac{s}{7}[/tex]

[tex]\frac{s}{5}-\frac{s}{7} = 80[/tex]

[tex]\frac{7\cdot s - 5\cdot s}{35} = 80[/tex]

[tex]2\cdot s = 2800[/tex]

[tex]s = 1400\,mi[/tex]

From (3), we find that speed of the jet with no wind is:

[tex]v_{J/W} = \frac{s}{5}-40[/tex]

[tex]v_{J/W} = \frac{1400}{5}-40[/tex]

[tex]v_{J/W} = 240\,\frac{mi}{h}[/tex]

The speed of the jet with no wind is 240 miles per hour.

Answer:

Sam will be 24 and his mom U can figure that out

Step-by-step explanation:

Math

Answer:

24

Step-by-step explanation:

`12

Answer:

He bought 2 cans of paint

Step-by-step explanation:

If he put ⅖ in each, and ⅘ total, he would have had 2 cans

Quantity of special paint additive Ernest bought = [tex] \tt \frac{4}{5} \: of \: a \: litre [/tex]

Quantity of additive he put in each can = [tex] \tt \frac{2}{5} \: of \: a \: litre [/tex]

Number of cans of paint he bought :

[tex] =\tt \frac{4}{5} \div \frac{2}{5} [/tex]

[tex] = \tt\frac{4}{5} \times \frac{5}{2} [/tex]

[tex] = \tt\frac{4 \times 5}{5 \times 2} [/tex]

[tex] =\tt \frac{20}{10} [/tex]

[tex]\color{plum} = \tt2 \: paint \: cans[/tex]

▪︎Therefore, Ernest bought 2 paint cans.

Answer:

i think 25.09 weighs more

Step-by-step explanation: well simply 25.018 has more decimal places down therefore making it a smaller number

sorry if you get it wrong :c

Answer:

4

Step-by-step explanation:keep change flip 4/5 x 5/1 = 20/5= 4

Answer:

[tex]P(X > 11) = 0.368[/tex]

[tex]P(X > 22) = 0.135[/tex]

[tex]P(X > 33) = 0.050[/tex]

[tex]x = 33[/tex]

Step-by-step explanation:

Given

[tex]E(x) = 11[/tex] --- Mean

Required (Missing from  the question)

[tex](a)\ P(X>11)[/tex]

[tex](b)\ P(X>22)[/tex]

[tex](c)\ P(X>33)[/tex]

(d) x such that [tex]P(X <x)=0.95[/tex]

In an exponential distribution:

[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf

[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf

[tex]P(X > x) = 1 - F(x)[/tex]

In the above equations:

[tex]\lambda = \frac{1}{E(x)}[/tex]

Substitute 11 for E(x)

[tex]\lambda = \frac{1}{11}[/tex]

Now, we solve (a) to (d) as follows:

Solving (a): P(X>11)

[tex]P(X > 11) = 1 - F(11)[/tex]

Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]

Remove bracket

[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]

[tex]P(X > 11) = e^{-1}[/tex]

[tex]P(X > 11) = 0.368[/tex]

Solving (b): P(X>22)

[tex]P(X > 22) = 1 - F(22)[/tex]

Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]

Remove bracket

[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]

[tex]P(X > 22) = e^{-2}[/tex]

[tex]P(X > 22) = 0.135[/tex]

Solving (c): P(X>33)

[tex]P(X > 33) = 1 - F(33)[/tex]

Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]

Remove bracket

[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]

[tex]P(X > 33) = e^{-3}[/tex]

[tex]P(X > 33) = 0.050[/tex]

Solving (d): x when [tex]P(X <x)=0.95[/tex]

Here, we make use of:

[tex]P(X<x) = F(x)[/tex]

Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]

So, we have:

[tex]0.95 = 1 - e^{-\lambda x}[/tex]

Subtract 1 from both sides

[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]

[tex]-0.05=- e^{-\lambda x}[/tex]

Reorder the equation

[tex]e^{-\lambda x} = 0.05[/tex]

Substitute 1/11 for [tex]\lambda[/tex]

[tex]e^{-\frac{1}{11} x} = 0.05[/tex]

Solve for x:

[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]

[tex]x = -11\ ln(0.05)[/tex]

[tex]x = 32.9530550091[/tex]

[tex]x = 33[/tex] --- approximated

Answer:

[tex]\displaystyle r = \sqrt{10}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Geometry

Algebra II

Step-by-step explanation:

Step 1: Define

Center (2, -3) → x₁ = 2, y₁ = -3

Circumference point (-1, -2) → x₂ = -1, y₂ = -2

In this case, the distance d from the center to the circumference point would be the radius r of the circle.

Step 2: Find Radius r

It would be B)no.

Hope This Helps!

After plotting the above equation on the coordinate plane, we can see the graph of the function.

A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.

We have two parametric equations:

x = 1 – t² and

y = 2t

t = y/2  and

0 ≤ t² ≤ 5

1 ≤ 1 - t²≤ 4

1 ≤ x≤ 4

Plug the above value in x = 1 – t²

x = 1- (y/2)²

x = 1 - y²/4

4x = 4 - y²

y² = 4(1 - x)

Thus, after plotting the above equation on the coordinate plane, we can see the graph of the function.

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Answer:

18.75

Step-by-step explanation:

18.75

Answer:

56

Step-by-step explanation: Use the values of a, b, and c to find the discriminant.

Answer:

[tex]\Delta =56[/tex]

Step-by-step explanation:

We are given:

[tex]y = x^2 - 8x + 2[/tex][tex]y=x^2-8x+2[/tex]

So, a = 1, b = -8, and c = 2.

The discriminant (symbolized by Δ) is given by:

[tex]\Delta =b^2-4ac[/tex]

So, our discriminant in this case will be:

[tex]\Delta=(-8)^2-4(1)(2)=64-8=56[/tex]

Since our discriminant is a positive value, our equation has two real roots.

0

1

2

3

4

5

take x 1 so 1-1

2-1..........

Answer:

He Had It Bronzed

Step-by-step explanation:

Hope this help pls mark as brainlest!!