Explain the phenomenon and change in potential energy

Answer:

yes.

Explanation:

potential Energy is associated with position

Answer:

true

Explanation:

the energy possessed by a body by virtue of its position or configuration is called potential energy.Everything at a height from the earth surface posseses potential energy.

Answer:

121

Explanation:

Hey there!

The energy that is stored in food is called CHEMICAL ENERGY

So, when humans/people eat foods their bodies transfigure the energy that is stored which is known as the calories.

Whereas the chains (bonds) in the middle of the atoms in the food humans eat that break up the check mal reactions that has been taken into place and newer compounds will be created. Each food that you eat stores unlikeable amounts of energy

Answer: Chemical energy

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

Explanation:

a )

Time to reach the speed of 20 m/s with an acceleration of 2 m/s² can be calculated as follows .

v = u + a t

20 = 0 + 2 t

t = 20 /2 = 10 s .

Total time = 10 s + 20 s + 5 s = 35 s .

b) Average velocity = Total distance travelled / total time

Distance travelled in first 10 s

S₁ = ut + 1/2 a t²

= 0 + .5 x 2 x 10²

= 100 m

Distance travelled in next 20 s

S₂= 20s x 20 m/s  = 400 m

Distance travelled in last 5 s .

deceleration in last 5 s

v = u + at

0 = 20 m/s + a x 5

a = - 4 m/s²

v² = u² - 2 a s

0 = (20 m/s)² - 2 x 4 m/s² x s

s = 50 m

S₃ = 50 m

Total distance = S₁ + S₂ + S₃

= 100 m + 400 m + 50 m

= 550 m .

Average velocity = 550 m / 35 s

= 15.71 m /s .

Answer: Minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.

Explanation:

Velocity is only in horizontal direction at the top most point which is similar to the velocity in the horizontal direction at the time of launch.

Now, according to the law of conservation of energy the formula used is as follows.

[tex]mgh = \frac{1}{2} mv^{2}_{y}\\v_{y} = \sqrt{2gh}\\= \sqrt{2 \times 9.8 m/s^{2} \times 1.2}\\= 4.85 m/s[/tex]

As speed at which the person is travelling was 6.8 m/s. Hence, the initial velocity will be calculated as follows.

[tex]v = \sqrt{v^{2}_{x} + v^{2}_{y}}\\= \sqrt{(6.8)^{2} + (4.85 m/s)^{2}}\\= 11.65 m/s[/tex]

Thus, we can conclude that minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.

Answer:

45m/s

Explanation:

(here I'm taking gravity due to acceleration as 10 m/s^2 and not 9.8 m/s^2 to match the options)

We know that when an object is dropped from a certain height it has initial velocity 0 m/s

so;

u= 0m/s

s= 100m

a= 10m/s^2

Using 4th law of motion;

v^2 - u^2 = 2× a× s

v^2 - 0^2 = 2 × 10 × 100

v^2 = 2000

v = √2000

v = 44.72 m/ s

Final velocity = 45 m/ s (rounding off to 45)

Please feel free to tell me if you have any confusion.

Answer:

60MW wasted

Explanation:

600-540

=60MW

Solution :

We know, resistance is given by :

[tex]R = \dfrac{\rho l}{A}[/tex]

[tex]A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2[/tex]

Now, we know mass of wire is given by :

[tex]Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram[/tex]

Hence, this is the required solution.

Given:

The resistance will be:

→ [tex]R = \frac{\rho l}{A}[/tex]

or,

→ [tex]A = \frac{\rho l}{R}[/tex]

By substituting the values, we get

      [tex]= \frac{1.72\times 10^{-8}\times 3.5}{0.125}[/tex]

      [tex]= 4.816\times 10^{-7} \ m^2[/tex]

hence,

The mass will be:

→ [tex]Mass = Density\times Volume[/tex]

             [tex]= 8.9\times 10^3\times 4.816\times 10^{-7}\times 3.5[/tex]

             [tex]= 0.01500 \ kg[/tex]

             [tex]= 15.00 \ g[/tex]

Thus the above answer is right.  

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Answer:

the acceleration of the small bug is 12.83 m/s²

Explanation:

Given;

time of motion, t = 0.5 s

radius of the circular path created by his arm, r  = 1.3 m

if he rotates his arm from horizontal to vertical, the angular displacement = 90⁰

The centripetal acceleration of the ball is calculated as;

[tex]a_c = \omega^2 r\\\\a_c = (\frac{\theta}{t} )^2 r\\\\[/tex]

[tex]a_c = (\frac{90}{360} \times\frac{ 2\pi }{t} )^2r\\\\a_c = (\frac{\pi}{2t} )^2 r\\\\a_c = \frac{\pi^2r}{4t^2} = \frac{\pi^2 \times1.3 }{4\times 0.5^2} = 12.83 \ m/s^2[/tex]

Therefore, the acceleration of the small bug is 12.83 m/s²

Answer: A. The acceleration of an object is determined by its mass and the net force acting on it.

Explanation:

Newton's second law of motion explains that the acceleration of an object will depend on two vital variables which are the mass of the object and the net force that's acting on it.

It should be noted that the acceleration of the object directly depend on the net force while it depends inversely on the mass. Therefore, when the force that's acting on such object is increased, then the acceleration will increase as well. On the other hand, when there is an increase in mass, there'll be a reduction in the acceleration.

Answer:

(m1+m2)vo=m1v+m2×0

⟹vo=m1+m2m1v

The impulse imparted to second object is equal to change is momentum is -

J=m2vo=m1+m2m2m1v

Answer:

The required emf moved across the wire is zero

Explanation:

For a moving charge particle, the magnetic force can be determined by using the formula;

[tex]\varepsilon = Bvlsin \theta[/tex]

since the wire moves in parallel, the angle [tex]\theta[/tex] between magnetic field and velocity = 0°

B = 0.500 T

v = 1.50 m/s

l = 0.200 m

∴

[tex]\varepsilon = (0.500 \ T )(1.50 \ m/s) \times (0.200 \ m)\times sin (0)[/tex]

[tex]\varepsilon = 0.15\times sin (0)[/tex]

[tex]\varepsilon = 0[/tex]

Answer:

true ,the kinetic energy is associated with energy

Answer:

D) 0.008

Explanation:

I just did it on Edg22 and I got it correct :D (Picture above)

Option D) 0.008T is the correct answer.

Hence, if the current is increased to the given value, the strength of the magnetic field around the wire carrying the current increases to 0.008T

Given the data in the question;

First scenario

Second scenario

Magnetic field is a vector field or region around a magnet or electric charge upon which magnetic force is exerted.

To determine the strength of the magnetic field if the current is changed, we equate the two scenario.

[tex]\frac{B}{I} = \frac{B'}{I'}[/tex]

We substitute our given values into the expression

[tex]\frac{0.004T}{20A} = \frac{B'}{40A}\\ \\ B' * 20A = 0.004T * 40A\\\\B' = \frac{0.004T * 40A}{20A} \\\\B' = \frac{0.004T * 40}{20}\\ \\B' = \frac{0.16T}{20}\\ \\B' = 0.008T[/tex]

Option D) 0.008T is the correct answer.

Hence, if the current is increased to the given value, the strength of the magnetic field around the wire carrying the current increases to 0.008T

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A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant k is

43.8 N = k (0.155 m)   ==>   k = (43.8 N) / (0.155 m) ≈ 283 N/m

The total work done on the spring to stretch it to 15.5 cm from equilibrium is

1/2 (283 N/m) (0.155 m)² ≈ 3.39 J

The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be

1/2 (283 N/m) (0.259 m)² ≈ 9.48 J

Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.

Answer:

The full form of MBBS is Bachelor of Medicine, Bachelor of Surgery

pls mark me brainliest :))

The full form of MBBS in India is 'Bachelor of Medicine, Bachelor of Surgery'. However, MBBS is an abbreviation of Medicinae Baccalaureus Baccalaureus Chirurgiae, which is the term used for this course in Latin.

Answer:

the number of photons absorbed by the solar panel is 1.08 x 10²¹

Explanation:

Given;

frequency of each photon absorbed, f = 5045 x 10¹⁴ Hz

energy to be created by the solar panel, E = 360 kJ = 360,000 J

The energy of each photon absorbed is calculated as;

[tex]E_{photon} = hf\\\\where;\\\\h \ is \ Planck's \ constant = 6.626 \times 10^{-34} \ Js\\\\E_{photon} = (6.626 \times 10^{-34} )(5045 \times 10^{14})\\\\E_{photon} = 3.343 \times 10^{-16} \ J[/tex]

let the number of photons absorbed = n

[tex]n(E_{photon}) = 360,000 \ J\\\\n = \frac{360,000 \ J}{3.343 \times 10^{-16} \ J} \\\\n = 1.08 \times 10^{21} \ photons[/tex]

Therefore, the number of photons absorbed by the solar panel is 1.08 x 10²¹

Answer:

Option C

Explanation:

C. Radiation.....

Answer:

heat travel through vacuum by radiation

Answer:

98N

Explanation:

El peso se mide en kg y la fuerza no afecta

Answer:

75%

Explanation:

We'll begin by calculating the final volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Initial temperature (T₁) = T

Initial pressure (P₁) = P

Final pressure (P₂) = 2P

Final temperature (T₂) = ½T

Final volume (V₂) =?

P₁V₁/T₁ = P₂V₂/T₂

PV/T = 2P × V₂ / ½T

Cross multiply

T × 2P × V₂ = PV × ½T

T × 2P × V₂ = PV × ½T

Divide both side by T × 2P

V₂ = (PV × ½T) / T × 2P

V₂ = ¼V

Next, we shall determine the absolute change in the volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Final volume (V₂) = ¼V

Absolute change in volume |ΔV| =?

|ΔV| = |V₂ – V₁|

|ΔV| = |¼V – V|

|ΔV| = |0.25V – V|

|ΔV| = 0.75V

Finally, we shall determine percentage change in the volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Absolute change in volume |ΔV| = 0.75V

Percentage change =?

Percentage change = |ΔV| / V × 100

Percentage change = 0.75V / V × 100

Percentage change = 0.75 × 100

Percentage change = 75%

Thus, the percentage change in the volume of the gas is 75%

Answer:

Pluto revolves around sun with constant speed in a circular orbit, so it is an example of uniform circular motion.

Explanation:

The magnetic field strength is needed to generate a peak voltage is 0.287 T.

The given parameters;

The maximum voltage in the coil is calculated as follows;

[tex]E_{max} = NAB\omega \\\\[/tex]

where;

The magnetic field strength is needed to generate a peak voltage is calculated as;

[tex]B = \frac{E_{max} }{NA \omega } \\\\B = \frac{E_{max} }{N (\frac{\pi d^2}{4} ) \times 2\pi f}\\\\ B = \frac{330}{120 \times (\frac{\pi \times 0.18^2}{4} ) \times 2\pi \times 60} \\\\B = 0.287 \ T[/tex]

Thus, the magnetic field strength is needed to generate a peak voltage is 0.287 T.

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Answer:

the animals are 26.2 meters apart.

Explanation:

Let's define t = 0s as the moment when the cheetah starts accelerating.

The gazelle moves with constant velocity, thus, it is not accelerating, then the acceleration of the gazelle is:

a₁(t) = 0m/s^2

where I will use the subscript "1" to refer to the gazelle and "2" to refer to the cheetah.

for the velocity of the gazelle we just integrate over time to get:

v₁(t) = V0

where V0 is the initial speed of the gazelle, which we know is 19.3 m/s

v₁(t) = 19.3 m/s

To get the position of the gazelle we integrate again:

p₁(t) = ( 19.3 m/s)*t + P0

where P0 is the position of the gazelle at t = 0s, let's define P0 = 0m

p₁(t) = ( 19.3 m/s)*t

The equations that describe the motion of the gazelle are:

a₁(t) = 0m/s^2

v₁(t) = 19.3 m/s

p₁(t) = ( 19.3 m/s)*t

Now let's do the same for the cheetah.

We know that its acceleration is 7.1 m/s^2

then:

a₂(t) =  7.1 m/s^2

for the velocity of the cheetah we integrate:

v₂(t) = (7.1 m/s^2)*t + V0

where v0 is the initial velocity of the cheetah, which we know its zero.

v₂(t) = (7.1 m/s^2)*t

Finally, for the position equation we integrate again, and remember that we have defined the initial position for the gazelle as zero, then the same happens for the cheetah.

p₂(t) = (1/2)*(7.1 m/s^2)*t^2

The equations for the cheetah are:

a₂(t) =  7.1 m/s^2

v₂(t) = (7.1 m/s^2)*t

p₂(t) = (1/2)*(7.1 m/s^2)*t^2

Now, we want to find the distance between both animals when the speed of the cheetah is 19.3 m/s, then first we need to solve:

v₂(t) = (7.1 m/s^2)*t =  19.3 m/s

t = (19.3 m/s)/(7.1 m/s^2) = 2.72s

Now, to find the distance between the two animals, we just compute the difference between the position equations for t = 2.72s

Distance = p₁(2.72s)  -  p₂(2.72s)

               = ( 19.3 m/s)*2.72s -  (1/2)*(7.1 m/s^2)*(2.72s)^2

               = 26.2 m

So the animals are 26.2 meters apart.

Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.

Explanation:

The inductive reactance [tex]X_L[/tex] is given by

[tex]X_L = \omega L = 2 \pi fL[/tex]

Solving for f, we get

[tex]f = \dfrac{X_L}{2 \pi L} = \dfrac{12000\:\text{ ohms}}{2\pi (0.8\:H)}[/tex]

[tex]\:\:\:\:\:\:\:= 2387.3\:\text{Hz}[/tex]

Answer:

[tex]F=1152N[/tex]

Explanation:

From the question we are told that:

Mass/one sec [tex]m=36.0kg/s[/tex]

Incident water stream [tex]v=16.0m/s[/tex]

Exiting water stream [tex]v'=-16.0m/s[/tex]

Generally the equation for Force is mathematically given by

[tex]F=\frac{mv-mu}{t}[/tex]

[tex]F=\frac{36(-16-16)}{1}[/tex]

[tex]F=1152N[/tex]