Every exercise regimen should include both a warm-up and a cool down.


Please select the best answer from the choices provided.

Answer:

The index of refraction of the oil is 1.41.

Explanation:

We can find the index of refraction of the oil using Snell's law:

[tex] n_{1}sin(\theta) = n_{2}sin(\alpha) [/tex]

Where:

n₁: is the index of refraction of medium 1 (air) = 1.00

n₂: is the index of refraction of medium 2 (oil) =?

θ: is the angle between the light ray and the medium 1 = 61.0°

α: is the angle between the light ray and the medium 2 = 38.3°

Hence, the index of refraction of the oil is:

[tex] n_{2} = \frac{n_{1}sin(\theta)}{sin(\alpha)} = \frac{1.00*sin(61.0)}{sin(38.3)} = 1.41 [/tex]

Therefore, the index of refraction of the oil is 1.41.

I hope it helps you!                                      

Answer:

1.41

Explanation:

The question is incomplete. The complete question is :

In your job as a mechanical engineer you are designing a flywheel and clutch-plate system. Disk A is made of a lighter material than disk B, and the moment of inertia of disk A about the shaft is one-third that of disk B. The moment of inertia of the shaft is negligible. With the clutch disconnected, A is brought up to an angular speed ?0; B is initially at rest. The accelerating torque is then removed from A, and A is coupled to B. (Ignore bearing friction.) The design specifications allow for a maximum of 2300 J of thermal energy to be developed when the connection is made. What can be the maximum value of the original kinetic energy of disk A so as not to exceed the maximum allowed value of the thermal energy?

Solution :

Let M.I. of disk A = [tex]$I_0$[/tex]

So, M.I. of disk B =  [tex]$3I_0$[/tex]

Angular velocity of A = [tex]$\omega_0$[/tex]

So the kinetic energy of the disk A = [tex]$\frac{1}{2}I_0\omega^2$[/tex]

After coupling, the angular velocity of both the disks will be equal to ω.

Angular momentum will be conserved.

So,

[tex]$I_0\omega_0 = I_0 \omega + 3I_0 \omega$[/tex]

[tex]$I_0\omega_0 = 4I_0 \omega$[/tex]

[tex]$\omega = \frac{\omega_0}{4}$[/tex]

Now,

[tex]$K.E. = \frac{1}{2}I_0\omega^2+ \frac{1}{2}3I_0\omega^2$[/tex]

[tex]$K.E. = \frac{1}{2}I_0\frac{\omega_0^2}{16}+ \frac{1}{2}3I_0\frac{\omega_0^2}{16}$[/tex]

[tex]$K.E. = \frac{1}{2}I_0\omega_0^2 \left(\frac{1}{16}+\frac{3}{16}\right)$[/tex]

[tex]$K.E. = \frac{1}{2}I_0\omega_0^2\times \frac{1}{4}$[/tex]

[tex]$\Delta K = \frac{1}{2}I_0\omega_0^2 - \frac{1}{2}I_0\omega_0^2 \times \frac{1}{4} $[/tex]

[tex]$2300=\frac{3}{4}\left(\frac{1}{2}I_0\omega_0^2\right)$[/tex]

[tex]$\frac{1}{2}I_0\omega_0^2=2300 \times \frac{4}{3 } \ J $[/tex]

Therefore, the maximum initial K.E. = 3066.67 J

Answer:

= 1200m/s or 1.2 x [tex]10^{3}[/tex] m/s

Explanation:

Answer:

c

Explanation:

search it up

Answer:

Option A.

Explanation:

Because this is a lunar eclipse it normally happens 2 times a year.  This is a decently rare phenomenon due to the positions they have to be in to make a lunar eclipse.  Therefore, it is option A.

Answer:

s ಕಣಗಳು ಒಂದು ಮಧ್ಯಮ ಟ್ರೋಗ್ ಹಲೋ ನೀವು ಹೇಗಿದ್ದೀರಿ ಬಿಎನ್ ನಾನು ಹಾಡುಗಳಿಂದ ಸುಳ್ಳಲ್ಲ

Answer:

F = 668.9N

Explanation:

Using the formula;

m1d1 = m2d2

m1 and m2 are the masses

d1 and d2 are the distances

Substitute;

15 * 2.5 = x * (55/100) [55cm was converted to metres]

37.5 = 0.55x

Swap

0.55x = 37.5

x = 37.5/0.55

x = 68.18kg

Since F = mg

F = 68.18 * 9.81

F = 668.9N

This gives the required force

Answer:

static friction=0.126

Answer:

It is example of Closed system

Answer:

Properties of matter

Explanation:

All properties of matter are either extensive or intensive and either physical or chemical. Extensive properties, such as mass and volume, depend on the amount of matter that is being measured. Intensive properties, such as density and color, do not depend on the amount of matter.

Answer:

The pythagoream theorem

Explanation:

Answer:

[tex]175\ \text{N/C}[/tex]

Explanation:

[tex]E_1[/tex] = Initial electric field = 3.5 N/C

[tex]E_2[/tex] = Final electric field

[tex]r_1[/tex] = Initial distance = 10 m

[tex]r_2[/tex] = Final distance = 20 cm

Electric field is given by

[tex]E=\sqrt{\dfrac{2P}{\pi r^2c\varepsilon_0}}[/tex]

So,

[tex]E\propto \dfrac{1}{r}[/tex]

[tex]\dfrac{E_2}{E_1}=\dfrac{r_1}{r_2}\\\Rightarrow E_2=E_1\dfrac{r_1}{r_2}\\\Rightarrow E_2=3.5\dfrac{10}{0.2}\\\Rightarrow E_2=175\ \text{N/C}[/tex]

The electric field amplitude at the required point is [tex]175\ \text{N/C}[/tex].

The acceleration is 1.2 m/s^2. The distance travelled is 1197 m. The time taken is 44.7 seconds.

The rate at which the velocity changes is  called the acceleration of the body.

Given that;

v = u - at

v = 0 m/s because the car comes to stop

u = at

a = u/t

a = 53.6 m/s/ 45 seconds

a = 1.2 m/s^2

The distance travelled is;

v^2 = u^2 - 2as

v = 0 m/s

u^2 = 2as

s = u^2/2a

a = ( 53.6 )^2/2 * 1.2

s = 1197 m

Time taken to stop is obtained from;

v = u - at

when v = 0 m/s

u = at

t = u/a

t = 53.6/1.2

t = 44.7 seconds

Learn more about acceleration:https://brainly.com/question/12550364?

#SPJ1

Answer:

41.64 N

Explanation:

Applying,

v = √(T/m')................ Equation 1

Where v = velocity of the wave, T = Tension of the rope, m' = mass per unit length of the rope.

make T the subject of the equation,

T = v²m'................. Equation 2

But,

v = λf............... Equation 3

Where λ = wavelength, f = frequency

And

m' = m/L........... Equation 4

Where m = mass of the rope, L = length of the rope

Substitute equation 3 and equation 4 into equation 2

T = (λf)²(m/L).............. Equation 5

From the question,

Given: λ = 0.740 m, f = 42 Hz, m = 0.125 kg, L = 2.9 m

Substitute these values into equation 5

T = (42×0.74)²(0.125/2.9)

T = 41.64 N

Answer:

to meet at a single point

(causing rays of light that are initially parallel to meet at a single point)

hope this helps:)

Explanation:

Answer:

focus

Explanation:

see more here

https://youtu.be/CJ6aB5ULqa0

Answer:

Cold

Explanation:

Im pretty sure im sorry if I am wrong

Answer:

If we use the equation for the transformation of velocities for moving frames:

v' = (v - u) / (1 - u * v / c^2) where we measure the speed of v' approaching from the left where v is in a frame moving at -u towards v'

v' = (.6 c - (-.6 c)) / (1 - (-.6 c) * .6 c / c^2) = 1.2 c / (1 + .6 * .6)

or v' = 1.2 c / (1 + .36) = .88 c

v is approaching from the left at .6 c in the reference frame and the other frame approaches from the right at -.6 c with speed u  (-.6 c) and we measure the speed of v as seen in the frame moving to the left

Answer:

d = 1.19 x 10⁻⁴ m = 0.119 mm

Explanation:

This problem can be solved by using Young's double-slit experiment formula:

[tex]Y = \frac{\lambda L}{d}[/tex]

where,

Y = fringe spacing = 32 mm = 0.032 m

L = slit to screen distance = 6 m

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

d = slit width = ?

Therefore,

[tex]0.032\ m = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{d}\\\\d = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{0.032\ m}[/tex]

d = 1.19 x 10⁻⁴ m = 0.119 mm

Answer:

Y = 3.87 x 10⁻³ m = 3.87 mm

Explanation:

This problem can be solved by using Young's double-slit experiment formula:

[tex]Y = \frac{\lambda L}{d}[/tex]

where,

Y = fringe spacing = ?

L = slit to screen distance = 2 m

λ = wavelength of light = 580 nm = 5.8 x 10⁻⁷ m

d = slit width = 0.3 mm = 3 x 10⁻⁴ m

Therefore,

[tex]Y = \frac{(5.8\ x\ 10^{-7}\ m)(2\ m)}{3\ x\ 10^{-4}\ m}[/tex]

Y = 3.87 x 10⁻³ m = 3.87 mm

Answer:

speed = 0.8c

Explanation:

Given :

Distance from earth to the distant planet = 10 ly

Time taken by the astronauts for the entire journey = 25 years

The time taken to reach the planet is [tex]$t_1=\frac{25}{2}$[/tex]

                                                                  = 12.5 years

Therefore, speed of the starship can be calculated by :

[tex]$\text{Speed} = \frac{\text{distance}}{\text{time}}$[/tex]

[tex]$v=\frac{10 \times c \times 3.15 \times 10^7}{12.5 \times 3.15 \times 10^7}$[/tex]

  [tex]$=0.8c$[/tex]

Therefore the speed of the starship is 0.8c

Answer:

Orion Nebula & cone nebula

Explanation:

From the huge, youthful stars that are forming the nebula to the pillars of thick gas that could be the homes of burgeoning stars, the Orion Nebula is a picture book of star formation. The four heaviest stars in the nebula reside in the bright central field. Since the stars are arranged in a trapezoid shape, they are known as the Trapezium.

These stars' ultraviolet radiation is cutting a hole in the nebula and stars that are already young enough to have disks of material encircling them can be seen near the Trapezium stars. Protoplanetary disks, also known as (proplyds) are too small to be seen distinctly and the disks are the foundation of solar systems.

The Cone Nebula is a monstrous creation, which resembles a nightmare beast flaring up from a crimson sea, is simply a benevolent pillar of gas and ashes. The Cone Nebula is so identified because it has a conical appearance in ground-based photographs. This massive pillar is located in a tumultuous star-forming area with gnarled mountainpeak of cold gas and dust is visible.

Answer:

5*10^2

Explanation:

A p e x

Answer:

Q = 8368 Joules.

Explanation:

Given the following data;

Mass = 50 g

Initial temperature = 30°C

Final temperature = 70°C

Specific heat capacity = 4.184 J/g °C

To find the amount of heat absorbed by the water;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 70 - 30

dt = 40°C

Substituting the values into the equation, we have;

[tex] Q = 50*4.184*40[/tex]

Q = 8368 Joules.

Answer:

The name of law is mass engery law

So they give us this

V=IR

V= 1.8

I=0.4

R=?

So we insert the thing that we know.

1.8=0.4*R

We need to leave our unknown value alone. So if our value of 0.4 is multiplying the unknown value it passes to the other side dividing.

So we have this.

Lastly we solve.

R=4.5ohms

The formula to find R is V=IR

V/I=R

So the resistance will be the Voltage divided by the Current

Answer:

B - As one variable increases the other decreases. (-1 to +1)     coefficient