Answer:
49π m² or 153.94 m²
Step-by-step explanation:
Area of a circle: A = πr²
We are given r as 7, so simply plug it in
A = π(7)^2
A = 49π m²
AC =
Round your answer to the nearest hundredth.
A
5
35
B
C
Answer:
2.87 = AC
Step-by-step explanation:
Since this is a right triangle we can use trig functions
sin theta = opp / hyp
sin 35 = AC /5
5 sin 35 = AC
2.867882182= AC
To the nearest hundredth
2.87 = AC
) Let an denote number of n-digit ternary sequences (sequences of 0,1 and 2) which have no consecutive 0’s in them. Find a recurrence relation for an. (Do not solve the recurrence. However, depending on the order of the recurrence, provide a sufficient number of initial conditions. )
Answer:
The recurrence relation for aₙ is aₙ = 2aₙ - 1 + 2aₙ -2 ; is n≥ 3 with the initial conditions as a₁ =3; a₂ = 8
Step-by-step explanation:
Solution
Recurrence relation for n - digit ternary sequence with no occurrence of consecutive 0's in them.
Ternary sequence is sequence with each of digits either 0, 1 or 2.
Now
Let aₙ = denote the number of n - digit ternary sequence with no occurrence of consecutive 0's in them.
Let us first find few initial values of aₙ
For n = 1
a₁ represent the number of 1- digit ternary sequence with no occurrence of consecutive 0's in them.
This 1-digit sequence can be either 0 or 1 or 2.
Thus,
a₁ = 3
For n =2
a₂ represent the number of 2- digit ternary sequence with no occurrence of consecutive 0's in them.
This 2-digit sequence can have either 0 or 1 or 2 as each of its two digit, but making sure that there are no two consecutive 0 in the sequence.
here are " 9 " 2-digit ternary sequence ........... (three choices for 1st digit and three choices for 2nd digit)
But one of these 9 sequence there are consecutive 0's .... (00)
So we eliminate this one sequence.
So, a₂ = 8
Now
let us find the recurrence relation
Fir n ≥ 3
aₙ s the number of n - digit ternary sequence with no occurrence of the consecutive 0's in them.
For the first case: if 1st digit of this n - digit ternary sequence is 1 or 2
Let assume the 1st digit of this n - digit ternary sequence is 1.
Then for remaining n - 1 digits of this n - digit ternary sequence we have to make sure that there is no consecutive 0's in them.
For example, we have to form a n-1-digit ternary sequence with no occurrence of consecutive 0's in them which is by definition aₙ -1
So,
The number of n - digit ternary sequence with no occurrence of consecutive 0's in them if 1st digit of this sequence is 1 is aₙ -1.
Likewise, the number of n - digit ternary sequence with no occurrence of consecutive 0's in them if 1st digit of this sequence is 2 is aₙ -1.
So
If 1st digit of this n - digit ternary sequence is 1 or 2, then the number of n - digit ternary sequence with no occurrence of consecutive 0's in them is shown as:
aₙ-1 + aₙ -1 = 2aₙ -1
For the second case: if 1st digit of this n - digit ternary sequence is 0
If 1st digit of this n - digit ternary sequence is 0, then the next digit cannot be 0 as well because that would make two consecutive 0's in the sequence Thus,
If 1st digit of this n - digit ternary sequence is 0, the next term can be either 1 or 2.
So there are 2 choices for 2nd digit.
After this there are more n-2 digits.
Then
For remaining n - 2 digits of this n - digit ternary sequence we have to make sure that there is no consecutive 0's in them
For example, we have to form a n-2-digit ternary sequence with no occurrence of consecutive 0's in them. which is by definition aₙ - 2.
Now,
The total number of sequence in this case is given as:
2aₙ -2........... (2 choices for 2nd digit and aₙ - 2 choices for remaining n-2 digit)
Hence
The number of n - digit ternary sequence with no occurrence of consecutive 0's in them if 1st digit of this sequence is 0 is aₙ = 2aₙ - 1 + 2aₙ -2 which is n≥ 3
Now,
The recurrence relation for aₙ is shown below:
aₙ = 2aₙ - 1 + 2aₙ -2; is n≥ 3
With the initial conditions as a₁ =3; a₂ = 8
Jiangsu divided 751.6 by 10 by the power of 2 and got a quotient of 0.7516. yesseinafhinks that the quotient should be7.516. Who is correct?
Answer:
yesseinafhinks
Step-by-step explanation:
Dividing by 10² is also the same thing as multiplying by 10^-2. In that case, we simply move the decimal places only 2 places back. That would give us 7.516, not 0.7516 (which is 3 times, not 2).
I would really appreciate it if you could help me please
Answer:
Yes, triangle GYK is similar to triangle BAK.
Step-by-step explanation:
The sides of each triangle are proportional to each other.
Take the longest side of each triangle. You are comparing line AK with line KY.
The proportion is 15/25.
Now, take the shortest side of each triangle. You are comparing line KB with GK.
The proportion is 6/10.
To determine if the triangles are proportional, we can see if the two proportions are equal to each other:
15/20=6/10
3/5=6/10
Correct! 3/5 equals to 6/10. Therefore, the two triangles are similar because their sides are proportional.
Hope this helps :)
Answer:
O Yes!
Step-by-step explanation:
We would check whether the proportionality of their sides is equal
Taking proportionality
= [tex]\frac{6}{10} = \frac{15}{25}[/tex]
Cross Multiplying
6 × 25 = 15 × 10
150 = 150
So, ΔABK is similar to ΔGKY
What is the area of the triangle below?
18
Answer:
D. 32 sq. unit s
Step-by-step explanation:
4×18/2=32
Do all systems of linear inequalities have solutions? If not, write a system of inequalities that has no solution. What would the graph of a system of linear inequalities with no solution look like?
Answer: There are systems with no solutions, and the graphs may show two regions with no intersections (as you know, the solution set is in the intersection of the sets of solutions for each inequality)
Step-by-step explanation:
Ok, suppose that our system is:
y > x
and
y < x.
This system obviously does not have any solution, because y can not be larger and smaller than x at the same time.
The graph of y > x is where we shade all the region above the line y = x (the line is not included)
and the graph of y < x is where we sade all the region under the line y = x (the line is not included)
So we will look at a graph where we never have a region with the two shades overlapping (so we do not have a intersection in the sets of solutions), meaning that we have no solutions.
Phil has $20,000, part of which he invests at 8% interest and the rest at 6%. If the total income from the two investments was $1460, how much did he invest at 6%?
Answer: 7000
Step-by-step explanation:
Let the amount invested in 8% account be P1 and the amount invested in 6% account be P2
. If the total amount invested is $20,000 then:
P1+P2=20,000. (Eq. 1)
The interest earned in one year from the 8% account is:
I1=0.08P1
and the interest earned in one year from the 6% account is:
I2=0.06P2
If the total interest earned is $1460, then:
I1+I2=1460
0.08P1+0.06P2=1460
(Eq. 2) From Eq. 1 :
P1=20000−P2
Substituting this into Eq. 2:
0.08 (20000−P2) + 0.06P2 = 1460
1600 − 0.08P2 + 0.06P2 = 1460
0.02P2 = 140
P2 = 140 / 0.02
P2 = 7000
Hence, he invested $7000 at the rate of 6%.
Deanna's Quiz Scores
Use the dot plots to answer the question
has quiz scores that are less variable and
typically higher
80 82 84 86 88 90 92 94 96 98 100
Amy's Quiz Scores
.
.
.
..
80 82 84 86 88 90 92 94 96 98 100
Answer:
1.90.93
2.90.27
Step-by-step explanation:
Answer:
one above correct
Step-by-step explanation:
1st - 90.93
2nd-90.27
Levi would like to use a credit card to make a $3000 purchase. He is considering two credit options. The first requires
a down payment of $1000 followed by monthly payments of $125. The second requires a down payment of $1300
followed by monthly payments of $110. The two options accumulate the same amount of interest and require the
same number of monthly payments.
What is the amount of interest for this loan?
Answer:
The amount of interest for this loan is 16.6%.
Step-by-step explanation:
Since Levi will make a purchase for $ 3000 with your credit card, you should explore the two options you have:
-On the one hand, a down payment of $ 1000, with fees of $ 125.
-on the other, a down payment of $ 1,300, with fees of $ 110.
In both cases, the fees are the same, and the interest too. Therefore, to determine the amount of installments and interest, the difference between the down payment of one option and the other must be taken and divided by the difference between the value of the installments of either option.
Thus, the difference of the down payment of 300 (1300 - 1000) must be divided by 15 (125 - 110). This yields a result of 20 (300/15), with which that will be the total of quotas until both have paid the same amount of money.
Thus, given that 1300 + 110 x 20 = 3,500, and that 1000 + 125 x 20 = 3,500, in both cases the total value to be paid is $ 3,500. Since 500 is 16.6% of 3000, the total purchase interest will be 16.6%.
A lottery is conducted using three urns. Each urn contains chips numbered from 0 to 9. One chip is selected at random from each urn. The total number of sample points in the sample space is:_______ a) 30 b) 100 c) 729 d) 1,000"
Answer: Option d.
Step-by-step explanation:
Ok, we have 3 urns.
Each urn can give a number between 0 and 9, so each urn has 10 options.
And as the urns are different, the outcome in the first urn does not affect the outcomes in the others, and the same happens for the outcome in the second urn, so the events are independent.
The total number of combinations is equal to the product of the number of options for each event (here each urn is one event)
then the number of combinations is:
C = 10*10*10 = 10^3 = 1000
Then the correct option is d.
A product is introduced to the market. The weekly profit (in dollars) of that product decays exponentially as function of the price that is charged (in dollars) and is given by P ( x ) = 95000 ⋅ e − 0.05 ⋅ x Suppose the price in dollars of that product, x ( t ) , changes over time t (in weeks) as given by x ( t ) = 53 + 0.95 ⋅ t 2 Find the rate that profit changes as a function of time, P ' ( t ) dollars/week How fast is profit changing with respect to time 7 weeks after the introduction. dollars/week
Answer:
1). [tex]P'(t) = (-9025t).e^{-0.05(53+0.95t^2)}[/tex]
2). (-435.36) dollars per week
Step-by-step explanation:
Weekly price decay of the product is represented by the function,
P(x) = [tex]95000.e^{-0.05x}[/tex]
And the price of the product changes over the period of 't' weeks is represented by,
x(t) = [tex]53+0.95t^2[/tex]
Function representing the rate of change in the profit with respect to the time will be represented by,
1). P'(t) = [tex]\frac{dP}{dx}.\frac{dx}{dt}[/tex]
Since, P(x) = [tex]95000.e^{-0.05x}[/tex]
P'(x) = [tex]95000\times (-0.05).e^{-0.05x}[/tex]
= [tex](-4750).e^{-0.05x}[/tex]
Since, x(t) = 53 + 0.95t²
x'(t) = 1.9t
[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05x}\times (1.9t)[/tex]
By substituting x = 53 + 0.95t²
[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05(53+0.95t^2)}\times (1.9t)[/tex]
P'(t) = [tex](-9025t).e^{-0.05(53+0.95t^2)}[/tex]
2). For t = 7 weeks,
P'(7) = [tex](-9025\times 7).e^{-0.05(53+0.95(7)^2)}[/tex]
= [tex](-63175).e^{-4.9775}[/tex]
= (-63175)(0.006891)
= (-435.356) dollars per week
≈ (-435.36) dollars per week
Solve the linear equality 4x-7 <5
Answer:
X<3
Step-by-step explanation:
4x-7 <5
4x < 5+7
4x < 12
X < 12/4
X < 3
Hope this helps..
Good Luck!
Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. Find the 95th percentile of the hip breadth of adult men. Round your answer to one decimal place; add a trailing zero as needed. The 95th percentile of the hip breadth of adult men is [HipBreadth] inches.
Answer:
[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]
And if we solve for a we got
[tex]a=14.4 +1.64*1.1=16.204[/tex]
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(14.4,1.1)[/tex]
Where [tex]\mu=14.4[/tex] and [tex]\sigma=1.1[/tex]
For this part we want to find a value a, such that we satisfy this condition:
[tex]P(X>a)=0.05[/tex] (a)
[tex]P(X<a)=0.95[/tex] (b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
[tex]P(X<a)=P(\frac{X-\mu}{\sigma}<\frac{a-\mu}{\sigma})=0.95[/tex]
[tex]P(z<\frac{a-\mu}{\sigma})=0.95[/tex]
And we have:
[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]
And if we solve for a we got
[tex]a=14.4 +1.64*1.1=16.204[/tex]
The 95th percentile of the hip breadth of adult men is 16.2 inches.
The management of a chain of frozen yogurt stores believes that t days after the end of an advertising campaign, the rate at which the volume V (in dollars) of sales is changing is approximated by V ' ( t ) = − 26400 e − 0.49 t . On the day the advertising campaign ends ( t = 0 ), the sales volume is $ 170 , 000 . Find both V ' ( 6 ) and its integral V ( 6 ) . Round your answers to the nearest cent.
Answer:
Step-by-step explanation:
Given the rate at which the volume V (in dollars) of sales is changing is approximated by the equation
V ' ( t ) = − 26400 e^− 0.49 t .
t = time (in days)
.v'(6) can be derived by simply substituting t = 6 into the modelled equation as shown:
V'(6) = − 26400 e− 0.49 (6)
V'(6) = -26400e-2.94
V'(6) = -26400×-0.2217
V'(6) = $5852.88
V'(6) = $5,853 to nearest dollars
V'(6) = 585300cents to nearest cent
To get v(6), we need to get v(t) first by integrating the given function as shown:
V(t) = ∫−26400 e− 0.49 t dt
V(t) = -26,400e-0.49t/-0.49
V(t) = 53,877.55e-0.49t + C.
When t = 0, V(t) = $170,000
170,000 = 53,877.55e-0 +C
170000 = 53,877.55(2.7183)+C
170,000 = 146,454.37+C
C = 170,000-146,454.37
C = 23545.64
V(6) = 53,877.55e-0.49(6)+ 23545.64
V(6) = -11,945.63+23545.64
V(6) = $11,600 (to the nearest dollars)
Since $1 = 100cents
$11,600 = 1,160,000cents
Help needed ASAP please !!!!
Answer:I believe that it is A but i am not fully sure
Step-by-step explanation:
Please answer this correctly
Answer:
I want to say 9 but im preety sure it's 6
Step-by-step explanation:
you have 54 times to pick it
you have 9 marbles,
54 divided by 9= 6
answer is 6
hope this helped:))))
have a grate dayy
Answer:
1
this is because I see only one marble present which is orange
Any help would be appreciated
6• 2hen+3pens-5anchors
Answer:
[tex]180[/tex]
Step-by-step explanation:
[tex]6 \times 2 \times 3 \times 5[/tex]
[tex]12 \times 15[/tex]
[tex]=180[/tex]
Steps to solve:
6 * 2 + 3 - 5
~Multiply
12 + 3 - 5
~Add
15 - 5
~Subtract
10
Best of Luck!
Which leader was a member of the Kikuyu tribe?
A. Kwame Nkrumah
B. Marcus Garvey
C. Mohandas Gandhi
D. Jomo Kenyatta
Answer:
Jomo Kenyatta
Step-by-step explanation:
Jomo Kenyatta was a Kenyan politician, who was one of the first African anti-colonial figures. He became the prime minister of Kenya from 1963 to 1964, and after Kenyan independence in 1964, he became president of Kenya. Jomo Kenyatta was born into a family of Kikuyu farmers in Kiambu, present day Kenya which was then, British East Africa. He had his basic schooling in a missionary school before proceeding to study at Moscow's Communist University of the Toilers of the East, University College London, and the London School of Economics.
Answer:
Jomo Kenyatta
Step-by-step explanation:
took the test
26
Ping lives at the corner of 3rd Street and 6th Avenue. Ari
lives at the corner of 21st Street and 18th Avenue. There is
a gym į the distance from Ping's home to Ari's home.
24
22
20
n
Ari (21.18)
7
x =
18
(x2 – x) + x3
mi+n
16
Avenue
14
-- ( , Jive - y) +
12
10
Where is the gym?
00
6
Ping (36)
4
2
9th Street and 10th Avenue
12th Street and 12th Avenue
0 14th Street and 12th Avenue
15th Street and 14th Avenue
2
x
4 6 8 10 12 14 16 18 20 22 24 26
Street
Corrected Question
Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym 2/3 the distance from Ping's home to Ari's home. Where is the gym?
9th Street and 10th Avenue 12th Street and 12th Avenue 14th Street and 12th Avenue 15th Street and 14th AvenueAnswer:
(D)15th Street and 14th Avenue
Step-by-step explanation:
Ping's Location: (3rd Street, 6th Avenue)
Ari's Location: (21st Street, 18th Avenue)
The gym is at point P which is [tex]\dfrac{2}{3}[/tex] the distance from Ping's home to Ari's home.
That is, Point P divides the line segment in the ratio 2:1.
We use the section formula:
[tex](x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)[/tex]
m:n=2:1, [tex](x_1,y_1)=(3,6), (x_2,y_2)=(21,18)[/tex]
[tex]=\left(\dfrac{2*21+1*2}{2+1}, \dfrac{2*18+1*6}{2+1}\right)\\=\left(\dfrac{45}{3}, \dfrac{42}{3}\right)\\=(15,14)[/tex]
The gym is located at 15th Street and 14th Avenue.
Please answer this correctly
Answer:
9 bags
Step-by-step explanation:
130, 134, 136, 145, 145, 147, 147, 151, 154
9 bags had at least 130 peanuts.
Write the expression 3*3*3*3*3 in exponential notation
Answer:
3^5
Step-by-step explanation:
becuase 3*3*3*3*3
Answer: 3^5 (3 to the power of 5)
Step-by-step explanation:
3 is multiplied by itself 5 times
To shorten the expression, exponential notation is used and it becomes 3^5, which essentially means three multiplied by itself 5 times
ex. 4^3 equals 4x4x4
The population of a city has increased by 35% since it was last measured. If the current population is 29,700 , what was the previous population?
Answer:
19305
Step-by-step explanation:
We simply take the percentage of 29700 to find how many people were added.
29700(0.35) = 10395 <== so 10395 people have been added
Subtract it from the current:
28700 - 10395 = 19305 people before.
A group of campers is going to occupy 4 campsites at a campground. There are 14 campsites from which to choose. In how many ways can the campsites be chosen?
There are
possible ways to choose the campsites.
Check
Enter your answer in the answer box and then click Check Answer.
Clear All
All parts showing
Answer:
24024 are the total number of ways of choosing 4 campsites out of 14.
Step-by-step explanation:
We are given that there are a total of 14 campsite out of which 4 campsites are to be chosen.
It is a simple example of selection problem.
Number of ways to choose the first campsite = 14
Now, one campsite is chosen, 13 campsites are left.
Therefore,
Number of ways to choose the second campsite = 13
Now, one more campsite is chosen, 12 campsites are left.
Therefore,
Number of ways to choose the third campsite = 12
Now, one more campsite is chosen, 11 campsites are left.
Therefore,
Number of ways to choose the fourth campsite = 11
So, total number of ways for choosing 4 campsites out of 14:
14 [tex]\times[/tex] 13 [tex]\times[/tex] 12 [tex]\times[/tex] 11 = 24024
Hence, answer is 24024.
Which is the cosine ratio of
Answer:The answer is B
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Cos A = [tex]\frac{Adjacent}{Hypotenuse}[/tex]
Where Adjacent = 28, Hypotenuse = 197
Cos A = [tex]\frac{28}{197}[/tex]
Not sure how to answer question 4
Answer:
Option D is correct
Step-by-step explanation:
Applying the cosine theorem for triangle ABC, you would have:
cos (angle BAC) = (BA^2 + CA^2 - BC^2)/(2*BA*CA)
= (10^2 + 18^2 - 20^2)/(2*10*18)
= 24/360
=> angle BAC = ~86 deg
Hope this helps!
A group of 8 students paid $48.24 for food at a picnic whats each persons share
Answer:
Each persons share is 6.03
Step-by-step explanation:
Divide the total cost by the number of students
48.24 / 8
6.03
Each persons share is 6.03
Answer:
$6.03
Step-by-step explanation:
A group of 8 students paid $48.24 for food.
Each of their shares would be divided among the 8 students.
48.24/8=6.03
Each student paid a share of $6.03.
match the term with the definition
Answer:
1 - c
2 - a
3 - e
4 - d
5 - b
Answer: c, a, e, d, b
Step-by-step explanation:
1. Angle: (c) A figure consisting of two rays with the same endpoint.
2. Circle: (a) The set of all points in a plane that are a given distance from a point. That distance is called the radius.
3. Point: (e) A location, has no size.
4. Ray: (d) The portion of a line that starts at one point and goes off to infinity.
5. Vertex: (b) A point where two or more rays or "arms" of an angle meet.
What are the like terms in the algebraic expression? Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b Negative a squared b and negative 6 a Negative a squared b and 5 a squared b 6 a b and 5 a squared b 6 a b and negative 6 a
Answer:
The like terms are: [tex]a^{2}b,\ ab,\ \teaxt{and}\ a[/tex]
Step-by-step explanation:
The expression is:
[tex]-a^{2}b+6ab-8+5a^{2}b-6a-b-a^{2}b-6a-a^{2}b+5a^{2}b+6ab+5a^{2}b+6ab-6a[/tex]
Collect the like terms as follows:
[tex]-a^{2}b+6ab-8+5a^{2}b-6a-b-a^{2}b-6a-a^{2}b+5a^{2}b+6ab+5a^{2}b+6ab-6a[/tex]
[tex]=(-a^{2}b+5a^{2}b-a^{2}b-a^{2}b+5a^{2}b+5a^{2}b)+(6ab+6ab+6ab)-(6a-6a-6a)-b-8[/tex]
[tex]=12a^{2}b+18ab+18a-b-8[/tex]
Thus, the final expression is [tex]12a^{2}b+18ab+18a-b-8[/tex]
The like terms are: [tex]a^{2}b,\ ab,\ \teaxt{and}\ a[/tex].
Answer:
The CORRECT answer is B
Step-by-step explanation:
Express the number using scientific notation: 0.000000067
Select one:
O a. 67 x 10-7
O b. 6.7 x 10-7
O c. can not be written in scientific form
O d. 6.7 x 10 -8
Answer: D
Step-by-step explanation:
To express this number in scientific notation, we want to move the decimal so that it goes past the first nonzero integer. In this case, we would move it to the right 8 times.
6.7×10⁻⁸
The only reason why the 8 is negative is because when you write the scientific notation in standard form, you will need to move the decimal to the left in order to get 0.000000067. Negative means moving to the left. Therefore, 6.7×10⁻⁸ is our correct answer.