Answer: Option A is your answer
Explanation:
2. An athlete runs up the stairs of a tall building in 10 s. If she has a mass of 55 KG and the total vertical distance she covers is 8.2 m, what is the average power (in W)developed by her legs?
Answer:
P = 37.0 W (watts)
Explanation:
Using the formula for power :
P = ( kg × m^2/s^2 ) W
given the mass 55kg, the time 10s, and the displacement 8.2m.
55 kg × 8.2^2 / 10^2
55kg × 67.24 / 100
3698.2/100
P = 36.982 ≈ 37.0 W (nearest tenth)
Are Stereotyping and prejudice are the same thing true or false
Answer:
Yes it's false for this finish touch
When are all the forces acting upon an object balanced?
Answer:
When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces.
Explanation:
List 20 examples vector quantities
Answer:
That's all I got.
Explanation:
acceleration
velocity
momentum
force
increase
and decrease in temperature
weight
1) Construct a graph showing the relationship between and independent variable and a dependent variable. 2) Demonstrate potential and kinetic energy. 3) Design a pendulum. 4) Investigate which variables influence the period of a pendulum. 5) Solve a problem using the scientific method. 6) Use graphs to characterize gow drop height responds to bounce height. (Next answer questions 1 - 6). 1) Write the goal of the lab or the question you tried to answer? 2) which observations, experiences, or lesson materials helped you form a hypothesis? 3) State your hypothesis? 4) Use the data from your experiment to complete these data tables? [Data Table 1: Period vs. Mass] Mass(g) / Time for 10 periods (s). [ Data Table 2: Period vs. String Length] String Length (cm) / Time for 10 periods (s). ( Question 5) Graph your data: A) Determine the values in seconds (s) for the y-axis based on your time data. B) Plot mass vs. time for 10 periods on the first graph. C) Plot string length vs. time for 10 periods on the second graph. ( question 6) Compare your data with your hypothesis. Explain how the data supports or does not support your hypothesis. If your data does not support your hypothesis, use the data you collected to answer the original question. { Truly Need Help and will mark brainlest} Please Please be very honest with your response.
all the elements are found on earth, where were they formed?
1. in the sun
2. in ancient stars
3. in earths core
4. in the gas cloud that formed earth
Answer:
in the Earths core
Explanation:
What is the formula for speed?
गतत का सूत्र क्या है?
A : Distance covered/Time | तय की गई
दरूी/समय
B : Change in velocity/Time | वेग में
पररवतषन/समय
C : Distance in definite direction /Time |
तनजचचत टदशा में दरूी/समय
D : Change in momentum/Time | संवेग में
पररवतषन/समय
Ans:
A : Distance covered/Time | तय की गई
दरूी/समय
Explanation:
Formula for speed = Distance covered/Time
Therefore,
Option A is correct.
Answer:
a.distance÷timetaken
Explanation:
The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).
A person has a mass of 1000 g and an acceleration of 20 M/S/S what is the force on the person
Answer:
The answer is 20 NExplanation:
The force acting on an object can be found by using the formula
force = mass × accelerationFrom the question
mass = 1000 g = 1 kg
acceleration = 20 m/s²
We have
force = 20 × 1
We have the final answer as
20 NHope this helps you
A car traveling east in a straight line on a highway decreases its speed from 30. meters per second to 23. meters per second in 2.0 seconds. What is the magnitude of the car's average acceleration to the nearest tenths place, during this time interval?
Answer:
Acceleration = -3.5 m/s²
Explanation:
Given:
Initial velocity u = 30 m/s
final velocity velocity v = 23 m/s
Time t = 2 second
Find:
Acceleration
Computation:
v = u + at
23 = 30 + (a)(2)
-7 = 2 a
a = -7 / 2
a = -3.5 m/s²
Acceleration = -3.5 m/s²
A 1500 kg car traveling at 35 m/s hits its brakes and comes to rest in 5 seconds. Calculate the force applied by the brakes. (hint: solve for a first) Show all steps!!
Answer:
We are given:
m = 1500 kg
initial velocity (u) = 35 m/s
final velocity (v) = 0 m/s
time (t) = 5 seconds
acceleration = a m/s/s
Force (f) = F newtons
Solving for acceleration:
Using the first equation of motion:
v = u + at
replacing the variables
0 = 35 + a(5)
a = -35/5
a = -7 m/s/s
Force applied by the brakes:
From newton's second law of motion:
F = ma
replacing the variables
F = (1500)(-7)
F = -10500 N
Therefore, the force applied by the brakes is -10500 N, we have a negative sign since the force is being applied opposite to the direction of motion
A mass of M-kg rests on a frictionless ramp inclined at 30°. A string with a linear mass density of μ=0.025" kg/m" is attached to the M-kg mass. The string passes over a frictionless pulley of negligible mass and is attached to a hanging mass (m). The system is in static equilibrium. A wave is induced on the string and travels up the ramp.
(a) Show that the mass of M is equal to twice the mass of the hanging mass: M = 2m.
(b) and at what wave speed does the wave travel up the string, if m = 5 kg?
Answer:
44.3 m/s
Explanation:
a) Draw a free body diagram of the mass M. There are three forces:
Weight force mg pulling down,
Normal force N pushing perpendicular to the ramp,
and tension force T pulling parallel up the ramp.
Sum of forces in the parallel direction:
∑F = ma
T − Mg sin 30° = 0
T = Mg sin 30°
T = Mg / 2
Draw a free body diagram of the hanging mass m. There are two forces:
Weight force mg pulling down,
and tension force T pulling up.
Sum of forces in the vertical direction:
∑F = ma
T − mg = 0
T = mg
Substitute:
mg = Mg / 2
m = M / 2
M = 2m
b) Velocity of a standing wave in a string is:
v = √(T / μ)
T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N. Therefore:
v = √(49 N / 0.025 kg/m)
v = 44.3 m/s
This is a whole quiz please answer ill make as many points as i can. Btw this is pickleball
Question 1 10 pts
The ___________________ rule says the ball must bounce one on each side before either team may start volleying the ball in the air.
Group of answer choices
Double Bounce
Volley Bounce
Bounce
Two Bounce
Flag this Question
Question 2 10 pts
The player standing in the _____________ service court is always the firsts server.
Group of answer choices
right
left
No answer text provided.
No answer text provided.
Flag this Question
Question 3 10 pts
Each game is played to ___________ points, won by _________.
Group of answer choices
11, 2
21,1
15,1
12,2
Flag this Question
Question 4 10 pts
According to one of the inventors, the game was officially named after a family dog, Pickles, who would chase the ball and run off with it.
Group of answer choices
True
False
Flag this Question
Question 5 10 pts
Pickleball is played on a court the size of a Badminton court with what looks like an oversized ping pong paddle and a __________ball.
Group of answer choices
whiffle
tennis
paddle
boccee
Flag this Question
Question 6 10 pts
In Pickleball, there are two non-volley lines, which create an area called the _______ .
Group of answer choices
Kitchen
Ally
Drop Zone
Dead Area
Flag this Question
Question 7 10 pts
Only the receiving team can score a point by winning a rally.
Group of answer choices
True
False
Flag this Question
Question 8 10 pts
Pickleball combines elements of Badminton, Tennis and ____________.
Group of answer choices
Ping Pong
volleyball
Bocce
Four Square
Flag this Question
Question 9 10 pts
Players may not hit the ball while standing in the kitchen unless the ball has already bounced on their side.
Group of answer choices
True
False
Flag this Question
Question 10 10 pts
Before serving, the server must call the score.
Group of answer choices
True
False
Answer:
1- bounce rule
2- left
3-11,2
4-true
5- whiffle ball
6- kitchen
7-false
8- ping pong
9- true
10- true
Explanation:
I'm pre5sure they are all right. brainliest please
Answer: I had the same quiz too I’m only doing so the other guy can get brainliest
Explanation:Kfkfkfjgjggj
The vehicle land-speed record has long been held by rocket cars. These vehicles resemble the high-speed rocket planes that were used in the early days of the space program, but they have heavy metal wheels. On September 5, 1997, the world land-speed record was set by the British-built Thrust SSC rocket car, which had a top recorded speed of 341 m/s. The kinetic energy of the car at this speed is 5.289 × 108 J. What is the car’s mass?
Answer:
9096.93 Kg
Explanation:
The following data were obtained from the question:
Velocity (v) = 341 m/s
Kinetic energy (KE) = 5.289×10⁸J.
Mass (m) =.?
The mass of the car can be obtained as follow:
KE = ½mv²
5.289×10⁸ = ½ × m × 341²
5.289×10⁸ = ½ × m × 116281
5.289×10⁸ = m × 58140.5
Divide both side by 58140.5
m = 5.289×10⁸ / 58140.5
m = 9096.93 Kg
Therefore, the mass of the car is 9096.93 Kg
Explain which planets have seasons and why some planets have none at all.
Discuss which planet has seasons most similar to earth and why.
Discuss additional factors that some planets have that affect their seasons.
What fact about other planet’s seasons most surprised you and what did you find the most interesting? Why?
Answer:
Some planets have seasons some don't bc of the distance from the sun some of them are too cold or too hot to have seasons
Atoms tend to be stable and nonreactive if they have six valence electrons.
Select one:
O True
O False
Answer:
True
Explanation:
A 1288.1 kg car is traveling at 24.1 m/s when the driver takes his foot off the gas pedal. It takes 4.4 s for the car to slow down to 20 m/s. How large is the net force slowing the car? Answer in units of N.
Answer:
A 1288.1 kg car is traveling at 24.1 m/s when the driver takes his foot off the gas pedal. It takes 4.4 s for the car to slow down to 20 m/s. How large is the net force slowing the car? Answer in units of N.
Explanation:
It takes 25.7 N to push a crate
at a constant speed across flat
ground where uk
= 0.238.
What is the normal force acting
on the crate?
(Unit = N)
Answer:
108 N
Explanation:
Divide the force by uk to get the normal force
(25.7)/(0.238) = 107.98 N = 108 N
Answer:
107
Explanation:
Glucose is a carbohydrate.
True
0r False
Answer: True
Explanation: Glucose is a carbohydrate.
A microwave oven operates at 2.00 GHz . What is the wavelength of the radiation produced by this appliance?
Answer:
Wavelength = 0.15 m
Explanation:
The frequency of a microwave oven is 2.00 GHz or [tex]2\times 10^9\ Hz[/tex].
We need to find the wavelength of the radiation produced by this appliance. We know that the relationship between the frequency and wavelength is given by :
[tex]c=f\lambda[/tex]
Where,
[tex]\lambda[/tex] is the wavelength
So,
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2\times 10^9}\\\\=0.15\ m[/tex]
So, the wavelength of the radiation produced by this appliance is 0.15 m.
A shot-putter exerts an unbalanced force of 128 N on a shot giving it an acceleration of 19
m/s2. What is the mass of the shot?
Answer:
128 is the ans cuz N is also lnown as mass
Explanation:
128
Waves do NOT carry.
A)Weight
B)Matter
C)Energy
D)Color
(Choose one)
A light ray, traveling parallel to the axis of a convex thin lens, strikes the lens near its midpoint. After traveling through the lens, this ray emerges traveling obliquely to the axis of the lens:
a. passing between the lens and its focal point.
b. passing through its focal point.
c. crossing the axis at a point equal to one-half the focal length.
d. such that it never crosses the axis.
Answer:
d. such that it never crosses the axis.
Explanation:
A convex lens is type of converging lens. When parallel rays of light pass through a convex lens, the rays which are refracted converge at the principal focus. Focal length is the distance between the principal focus and the centre of the lens.
A light ray, traveling parallel to the axis of a convex thin lens, strikes the lens near its midpoint. After traveling through the lens, this ray emerges traveling obliquely to the axis of the lens such that it never crosses the axis.
from readong these two paragraph only the best description of Austin is that he is a ___ character
Explanation:
may you send the paragraph pic please im curious as to the answer too
Answer:
can I get the passage please
In which scenario will the two objects have the greatest gravitational force
between them?
A. Mass of object 1 = 22 kg
Mass of object 2 = 14 kg
Distance between objects = 28 m
B. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 48 m
C. Mass of object 1 = 22 kg
Mass of object 2 = 14 kg
Distance between objects = 48 m
D. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 28 m
Answer: The answer is D
Explanation:
The greater the mass and the less the distance
The two objects that will have the greatest gravitational force between them is:
D. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 28 m
What is Gravitational force?It is an appealing power that exists between all items with mass; an article with mass draws in one more particle with mass; the size of the power is straightforwardly corresponding to the majority of the two articles and contrarily relative to the square of the distance between the two particles.
It is given by:
[tex]F=G*\frac{m_1*m_2}{r^2}[/tex]
So, for the highest value of gravitational force there must be greater mass and lesser distance. So the option that holds good is option D.
Find more information about Gravitational force here:
brainly.com/question/19050897
Help me out here please!!!
Answer:
I beleive the answer is d
Explanation:
This is beause theball starts going back down because the velocity slows down.
Answer:
d
Explanation:
the velocity changes as it goes down
A force vector has a magnitude of 42 N and is applied at an angle of 108°
above the eastern horizontal.. Determine they component of this force
vector
0 -15 N
O -13 N
39.9 N
35 N
a leaky faucet is dripping at a rate of 1 pint per hour how many hours to fill 10 gallons
Answer:
80 hours :)))))))))))))
I need helpppppppppppppppppppppppppppppppppppppppppppppp
Answer:u
Laa c
Explanation:
just add an answer and you get 50 points
Answer:
cswqwqqddqd
Explanation:
wdq
Answer:
tyyyyy ..
Explanation:
What is the takeoff distance for an airplane on a runway at
300km/hr with acceleration of 1 m/s 2
Answer:
x = 3472 [m]
Explanation:
To solve this problem we must use the following expression of kinematics:
[tex]v_{f}^{2}= v_{i}^{2}+(2*a*x)\\[/tex]
where:
Vi = initial velocity = 0
Vf = final velocity = 300 [km/h]
a = acceleration = 1 [m/s^2]
x = takeoff distance [m]
Note: The initial velocity is equal to zero as avion starts its movement from rest.
Now we have to convert units of kilometers per hour to meters per second, the final velocity.
[tex]300 [\frac{km}{h}]*[\frac{1h}{3600s} ]*\frac{1000m}{1km} \\= 83.33 [\frac{m}{s} ][/tex]
(83.33)^2 = 0 + (2*1*x)
2*x = 6943.88
x = 3472 [m]