Answer:
The fact that it reveals is that:
Epinephrine binds to the receptor tyrosine kinase on the cell membrane and does not act on glycogen phosphorylase.
Explanation:
In cellular respiration, epinephrine is a neurotransmitter and a plasma membrane hormone receptor. It is not a lipid-derived hormone, but rather an amino acid-derived hormone. As a result, they are unable to pass through the plasma membrane of cells. They bind to receptors on the outer surface of the plasma membrane through plasma membrane hormone receptors (receptor's tyrosine kinase of the cell membrane) because they are lipid insoluble hormones.
Unlike steroid hormones, lipid insoluble hormones (epinephrine) do not directly influence glycogen phosphorylase or the target cell because they cannot enter the cell and operate directly on DNA. The activation of a signaling pathway occurs when these hormones attach to a cell surface receptor; this activates intracellular activity and performs the hormone's specific effects. Nothing crosses through the cell membrane in this fashion; the hormone that binds at the cell's surface stays at the cell's surface, while the intracellular component stays within the cell.
Imagine you are protesting against global warming. What would you protest sign say?
Answer:
My sign would prob say "Pretect the earth and the earth will pretect you"
Explanation:
This is not copy wright so pls don't copy mine
definition of human rights
What is happening in these images?
Prequipo, resuelvan los siguientes problemas. Pueden
uladora
Encuentren los términos faltantes de las siguientes si
a) 1, 4, 16, ____, 256, 1024, 4096,
b) 4. 28, 196, 1372,
3294172,..
2. ¿Cómo encontraron los términos faltantes en cadas
Answer:
a.) (4×2)² = 8² = 64
b.) =9604, 67228,470596
solo dividi el segundo termino con el tercero y me dio 7 y fui multiplicando el resultado por 7
The probability of a white chicken and a black chicken having a checkered chicken is ________
and is an example of ________
A- 50% incomplete dominance
B- 100% co-dominance
C- 100% incomplete dominance
D- 50% co- dominance
proteins are made where in the cell
Answer:
Ribosomes
Explanation:
HELP PLSSS, IM SO CONFUSED
Can some help me please ..
Answer: 2 dominant.
Explanation: The t's are capital so they are both dominant :)
In mutualism, both organisms participating benefit from the relationship.
True or False?
Answer:
true
Explanation:
Based on your knowledge of roots and affixes which is most likely definition of the word microscopic?
Explanation:
Microscopy is the science of investigating small objects and structures using a microscope. ... Microscopic means being invisible to the eye unless aided by a microscope.
When one glucose molecule travels through the glycolysis processes, four molecules of ATP are generated. Is it accurate to suggest that glycolysis produces two ATP molecules?
Answer:
No
Explanation:
Technically, this is inaccurate. To say that glycolysis produces two ATP molecules strays from the input of ATP needed. Overall, 4 ATP molecules are produced during glycolysis. However, there is an input of 2 ATP molecules at the beginning. Therefore, the correct statement would be that glycolysis produces 2 net ATP molecules, not that glycolysis produces 2 ATP molecules. (The word net makes a big difference!!).
its also nice to keep a _______ in my purse
Answer:
its also nice to keep a __phone_____ in my purse
Explanation:
Select the correct answer.
Which of the following is correct for the effect of linkage on recombination?
A. It increases the percentage of recombinants.
B. It results in 50% recombinants.
C. It reduces the percentage of recombinants.
Answer:
C. It reduces the percentage of recombinats
Explanation:
When linkage between two genes increases, the chance of these two crossing over is reduced, because linkage keeps these particular genes together, unlike crossing voer which will mix them up.
What will i do to meet my goals?
Answer:
Study and believe in yourself,don't give up!
Answer:
whatever your goals are you are going to try and try everyday and make sure you have people around you to help build you up
hope this helps
have a good day :)
Explanation:
Please answer only if you know this is a final 
Answer:
ecosystem
Explanation:
_______ are large geographical areas that have similar climate and weather patterns.
a.Symbioses
b. Zones of tolerance
c. Biomes
d. Communitie
Answer:
i think its c.............
Answer:
The answer is C. Biomes
Explanation:
Large areas with similar climate and weather are called biomes.
How many offspring would result from a
single bacterium in 8 hours if they
reproduce every 20 minutes? (hint: the
population doubles three times every
hour)
Answer:
16777216
Explanation:
(8*60)/20 = 24 time
2 ^ 24 = 16777216
Receptor binding motifs such as RGD have highly selective recognition for cell adhesion. Outline a strategy for incorporating a cell adhesive recognition domain to a biomaterial. Address the problems surrounding domain quantity, type, and affinity in your discussion.
Answer:
Explanation:
RGD stands for Arginine Glycine Aspartate and is a three-amino-acid peptide. It is the most extensively utilized adhesive peptide for adhering diverse cell types to a variety of biomaterials. Integrins, fibrinogen, osteopontin, fibronectin, and bone sialoprotein, as well as collagens and laminins, all include an RGD primary binding domain. As a result, the synthetic (artificial) peptide RGD may bind to a wide range of integrin types. The artificial RGD retains its functioning through the sterilizing and processing processes of biomaterial creation because of its recognition advantage. This feature denotes the immune reactivity and pathogen transmission during xenograft.
Affinity can be modulated by the conformation of artificial RGD. The efficacy of RGD is also determined by the in vitro deposition of cells on the surface of the material sample.
The molecular processes unravel its effectiveness throughout its use as a scaffold foundation in in-vivo models. The fact that artificial RGD cannot work well in isolation is now a major aspect that defines its activity.
It has been discovered that cells release a variety of integrin-binding proteins that are more effective in activating integrin signalling than pure RGD. As a result, most biomaterials will bind and adsorb these proteins rather than RGD. As a result, a serum-free medium is employed in the majority of in vitro research.
As a result, biomaterials are supplied with RGD as well as quasi polymers such as polyethylene glycol to reduce the variance produced by native proteins. The addition of additional amino acids to RGD based on natural sequences can increase its biological activity, which can aid in the development of new tissues and the stimulation of cellular responses and signalling.
The amino terminal endpoint of the peptide, as well as the carboxyl group of the material surface, establish a covalent connection, which binds the peptide to just the surface of its biomaterial. Cell adhesion biomaterials are made from a variety of cell adhesion materials, including poly-L-lysine, mussels adhesive protein (MAP), and outer membrane (extracellular matrix) proteins.
Because MAPS are high in Dihydroxyphenylalanine and lysine, RGD is coupled with either of these to boost its cell adhesion capability. As a result, they can also aid in the attachment to damp or moist surfaces. It may also firmly adhere to glass, metals, and plastics. The addition of thiol groups to a peptide can also aid in its orientation and boost its stability.
The gap and density of this peptide sequence and structure on the biomaterial surface may be adjusted using a micro and nanotechnology (nanoscale patterning) method, which also improves ligand binding accuracy. Cellular reactions and cell activity are also under its control. Integrin receptors have been shown to be between 9 - 12 nm in size, therefore nanoscale surface patterning is crucial.
As a result, the above methods serve as a strategy for incorporating a cell adhesion recognition domain into a biomaterial while taking into account all of the technical intervention affecting its quantity, type, and affinity to the top layer for cell adhesion as a functioning tissue rather than a monolayer.
What percent of the organisms genetic information is the same as the genetic information of the parent PLEASE HELP FASSTTTTT
Answer:
Every person has two copies of each gene, one inherited from each parent. Most genes are the same in all people, but a small number of genes, which is less than one percent of the total are slightly different between people.
Explanation:
16. Which process has most likely occurred when new traits appear in a species?
Mutations in these genes can produce new or altered traits, resulting in heritable differences (genetic variation) between organisms. ... Evolution occurs when these heritable differences become more common or rare in a population, either non-randomly through natural selection or randomly through genetic drift.
Mutations in genes produce new or altered traits, that leads to heritable differences (genetic variation) between organisms.
What is heredity?Heredity is defined as the sum of all biological processes through which particular characteristics are transmitted from parents to their offspring.
Evolution occurs when these heritable differences become more common in a population, either non randomly through natural selection or randomly through genetic drift.
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The mononuclear phagocyte system is an intricate passageway within and between tissues and organs and is an area full of lymphocytes, which are phagocytic cells used to attack foreign invaders.
a. True
b. False
Answer:
False.
Explanation:
Mononuclear phagocyte comprises of cells defined from the bone marrow progenitors, cells that descend blood monocytes and tissue macrophages. This undergo phagocytosis and they phagocytes foreign Invaders and bacteria. That is they ingest or engulf any foreign substances in the liver cells.
Gametes contain how many copies of each chromosome?
Answer:
Explanation:
each gamate carries 22 ordinary chromosome and one sex chromosome,altogether they carry 23 chromosome each.
What would be the correct complimentary base pair be for a DNA strand with the following sequence...
ACGTGA
A. TGCACT
B. GGCTA
C. OTGAACT
Answer:
Explanation:
A TGCACT
The correct complementary base pair for the DNA sequence ACGTGA is TGCACT (Option A).
Deoxyribonucleic acid (DNA) is a double helix molecule composed of two long chains of nucleotides linked by hydrogen bonds.In DNA, there are four types of nucleotides, each one containing one different nitrogenous base (i.e., Cytosine, Guanine, Adenine and Thymine).According to the base pair rules, Adenine always pairs with Thymine, while Cytosine always pairs with Guanine.In conclusion, the correct complementary base pair for the DNA sequence ACGTGA is TGCACT (Option A).
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Our hair and nail contain
Α. Protein
B Calcium
C Chlorine
D Phosphorus.
Answer:
protein
Explanation:
our hair and nail contain option ( D) protein.nails and hairs of one body's made up of follicles and matris.
PLS HELP FAST NO LINKS!
If you live in a region that has hot, dry summers, and cool, wet winters, what climate might you live in?
A. arid
B.temperate
C.tropical
D.Mediterranean
Answer:
Mediterranean climate
How is editing the genetic code different from artificial selection?
A It enables humans to influence the inheritance of DNA
B It enables humans to directly change DNA
C It can only be used on animal DNA
D It is not yet possible to edit the genetic code
Answer:
Option B
Explanation:
Artificial selection is influencing of inheritance of any trait . in this limited options are given to allow a species to mate and produce offspring
In genetic code editing directly genes are edited.
Hence, option B is correct
In guinea pigs, the color of the fur is determined by a single gene with two alleles control. The brown allele (B) is dominant over the white allele (b). Two heterozygous guinea pigs are crossed. Draw a genetic diagram with the genotypic, phenotypic and ratio information of the P₁ and F ₁ generations of this cross.
Answer:
B b
B BB Bb
b Bb bb
Genotype:
ratio - 1:2:1
1 BB = 25%
2 Bb = 50%
1 bb = 25%
Phenotype:
ratio - 3:1
3 Brown: 75%
1 White:25%
HOpe this helps
Which statement is true? (1 point)
O Fossils cannot provide information about relatedness of life forms.
O Fossils can provide information about when life forms existed.
O Fossils cannot provide information about life cycles and behaviors.
O Fossils can provide information about the entire evolutionary process of life forms.
Please help! I will give you Brainly !
Answer:
1. fossils can provide information about when life forms existed
2.3
3.they can show false relationships between organisms that are not reflected in the DNA
4.Living things have adapted and changed over time for specific, discoverable reasons
5.This suggests that all of these species share a common ancestor
Explanation:
Fossils give us information about how animals and plants lived in the past.
Fossils can provide information about when life forms existed.
Fossils can provide information about the entire evolutionary process of life forms.
What are Fossils?Fossil of an animal or plant has been preserved in Earth’s crust. It is the primary source of information about the history of life on Earth.Fossils are the undecayed remains of the living organisms. These remain preserved inside the lining of sediments.Thus, we can conclude that the correct options are A and D.
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Dr. Nachman and his colleagues collected rock pocket mice across 35 kilometers of the Arizona Sonoran Desert, which included both dark, rocky lava outcrops and light, rocky, granite areas. They recorded substrate color, and coat-color frequencies for each location. Each site was separated from any of the others by at least eight kilometers. The researchers trapped a total of 275 mice. Their data are summarized below:
Collecting Site Substrate Color Number of Mice Phenotype
Light Dark
1 Dark 22 3 19
2 Light 80 74 6
3 Light 22 19 3
4 Dark 28 3 25
5 Light 58 25 33
6 Dark 65 9 56
Required:
a. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on light-colored substrates.
b. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on dark-colored substrates.
c. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the light, rocky, granite substrate. For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.
Complete question
Dr. Nachman and his colleagues collected rock pocket mice across 35 kilometers of the Arizona Sonoran Desert, which included both dark, rocky lava outcrops and light, rocky, granite areas. They recorded substrate color, and coat-color frequencies for each location. Each site was separated from any of the others by at least eight kilometers. The researchers trapped a total of 275 mice. Their data are summarized below (numbers have been slightly modified for the purposes of this worksheet).
Field Data Summary
Collecting Site Substrate Color Number of Mice Phenotype Light Dark
1 Dark 22 3 19
2 Light 80 74 6
3 Light 22 19 3
4 Dark 28 3 25
5 Light 58 25 33
6 Dark 65 9 56
1. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on light-colored substrates. [to 3 decimal places]
2. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on dark-colored substrates. (to 3 decimal places)
3. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the light, rocky, granite substrate. For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.
4. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the dark, rocky lava substrate. (to 3 decimals). For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.
5. Which fur color seems to have the greatest overall selective advantage? Use data collected from both dark-colored and light- colored substrates to support your answer.
6.What environmental change gave a selective advantage for one coat color over another?
7. In a separate study, 76 rock pocket mice were collected from four different, widely separated areas of dark lava rock. One collecting site was in Arizona. The other three were in New Mexico. Dr. Nachman and colleagues observed no significant differences in the color of the rocks in the four locations sampled. However, the dark-colored mice from the three New Mexico locations were slightly darker than the dark-colored mice from the Arizona population. The entire Mc1r gene was sequenced in all 76 of the mice collected. The mutations responsible for the dark fur color in the Arizona mice were absent from the three different populations of New Mexico mice. No Mc1r mutations were associated with dark fur color in the New Mexico populations. These findings suggest that adaptive dark coloration has occurred at least twice in the rock pocket mouse and that these similar phenotypic changes have different genetic bases. How does this study support the concept that natural selection is not random?
8. To determine if the rock pocket mouse population is evolving, explain why it is necessary to collect fur color frequency data over a period of many years.
Answer:
1)
frequencies of light-colored mice ≅ 0.74 frequencies of dark-colored mice ≅ 0.262)
frequencies of light-colored mice ≅ 0.13 frequencies of dark-colored mice ≅ 0.873)
p² ≅ 0.02 q² ≅ 0.74 2pq ≅ 0.244)
q² = 0.13 p² = 0.4 2pq = 0.465) The dark-colored fur seems to have the greatest overall selective advantage
6) Dark lava changed the color of the substrate, from light to dark.
7) Because to produce dark color, animals from the different regions suffered different mutations that drove them to have almost the same dark fur color.
8) To see if the mice population is evolving. If it is, there will be a change in the allelic and genotypic frequencies over the years. If it is not evolving, the frequencies will keep equal through the years.
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
In a grassland ecosystem, what advantages does a burrower have over an animal that does not burrow?