Empirical formula of C6H10O6

Answer:

tanaka..........................

Answer: The wavelength of yellow light with the energy of [tex]3.45 \times 10^{-19} J[/tex] is [tex]5.76 \times 10^{-7} m[/tex].

Explanation:

Given: Energy = [tex]3.45 \times 10^{-19} J[/tex]

Formula used to calculate the wavelength is as follows.

[tex]E = \frac{hc}{\lambda}[/tex]

where,

E = energy

h = Planck's constant = [tex]6.63 \times 10^{-34} Js[/tex]

c = speed of light = [tex]3 \times 10^{8} m/s[/tex]

[tex]\lambda[/tex] = wavelength

Substitute the values into above formula as follows.

[tex]E = \frac{hc}{\lambda}\\3.45 \times 10^{-19} J = \frac{6.63 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 5.76 \times 10^{-7} m[/tex]

Thus, we can conclude that the wavelength of yellow light with the energy of [tex]3.45 \times 10^{-19} J[/tex] is [tex]5.76 \times 10^{-7} m[/tex].

Explanation:

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[tex]\small\mathfrak\purple{Double \: displacement \: reaction} \\ \\ \small\mathfrak\orange{hope \: it \: helps...}[/tex]

Answer:

A "chaser," a high-boiling compound whose vapors will displace the vapors of the desired low-boiling compound, can be used to distill a small amount of compound.

A smaller fractionation apparatus or a Vigreux column could be used instead.

Explanation:

Answer:

A. The heat needed to raise the temperature of 1 g of a substance 1°C.

Explanation:

how this has helped you

Answer:

110.92 g

Explanation:

Amount of Ni2O3 consumed= 55.3/59 =0.94 moles

From the reaction equation;

2 moles of Ni2O3 yields 4 moles of Ni

0.94 moles yields 0.94 moles * 4/2

= 1.88 moles of Ni2O3

Mass of 1.88 moles of Ni2O3 = 1.88 moles of Ni2O3  *  59 gmol-1 = 110.92 g

Answer:

1083.6 g

Explanation:

At STP, 1 mol of any given mass will occupy 22.4 L.

With the information above in mind we can calculate how many moles of nitrogen gas (N₂) are there in 867 L:

Finally we convert 38.7 moles of N₂ into grams, using its molar mass:

Answer:

Your correct.

Explanation:

Answer:

The answer is C.

Explanation:

I just know.

Answer:

3.93 × 10²¹ molecules

Explanation:

Convert 1.98 grams of PbSO₄ to molecules.

Step 1: Given data

Mass of PbSO₄: 1.98 g

Step 2: Calculate the number of moles corresponding to 1.98 g of PbSO₄

The molar mass of PbSO₄ is 303.26 g/mol.

1.98 g × 1 mol/303.26 g = 6.53 × 10⁻³ mol

Step 3: Calculate the number of molecules in 6.53 × 10⁻³ moles of PbSO₄

To convert moles to molecules, we need a conversion factor: Avogadro's number. There are 6.02 × 10²³ molecules of PbSO₄ in 1 mole of molecules of PbSO₄.

6.53 × 10⁻³ mol × 6.02 × 10²³ molecules/1 mol = 3.93 × 10²¹ molecules

Answer:

0.0395 mol NaCl

Explanation:

¡Hola!

En este caso, es necesario para nosotros considerar que las relaciones masa-mol se desarrollan teniendo en cuenta las masas molares de los compuestos involucrados en el sistema. Ahora, dado que este sistema se compone de NaCl, cloruro de sodio como sal de mesa, es posible saber que la masa molar de este es alrededor de 58.44 g/mol.

De esta manera, las moles en 2.31 g se calculan como sigue:

[tex]=2.31gNaCl*\frac{1molNaCl}{58.44gNaCl}\\\\=0.0395molNaCl[/tex]

¡Saludos!

The formation of soap can be done with the process of saponification in which triglyceraldehyde reacts with 3 molecules of Sodium Hydroxide (NaOH) and produces Glycerol and 3 molecules of Sodium palmitate (Soap).

(Reaction is attached as image)

Saponification is a process that involves the conversion of fat, oil, or lipid, into soap and alcohol by the action of aqueous alkali.

Soaps are salts of fatty acids, which in turn are carboxylic acids with long carbon chains.

Hence, The formation of soap can be done with the process of saponification in which triglyceraldehyde reacts with 3 molecules of Sodium Hydroxide (NaOH) and produces Glycerol and 3 molecules of Sodium palmitate (Soap).

Learn more about Saponification here ;

https://brainly.com/question/2263502

#SPJ1

Answer:

Graphite, because it has atoms of same atomic and electrovalent electrons

Answer:

Tri.

Explanation:

''Tri'' is the Greek prefix used to represent the CH3 because there are three hydrogen atoms to form the covalent compound so in Greek method ''Tri'' is used for three. In Greek system, there are certain names for prefixes such as ''di'' is used for two, ''tri'' is used for three, ''tetra'' is used for four etc. This method only provides information about the number of atoms that form the covalent compound.

Answer:

Evaporation of ocean water and the formation of sea ice both increase the salinity of the ocean.

Explanation:

Answer:

5Fe⁺² + MnO₄⁻ + 8H⁺ => 5Fe⁺³ + Mn⁺² + 4H₂O

Explanation:

Fe⁺² + MnO₄⁻ +  H⁺ => Mn⁺² + Fe⁺³ +  H₂O

5(Fe⁺² => Fe⁺³ + 1e⁻)      =>                        5Fe⁺² => 5Fe⁺³ + 5e⁻

MnO₄⁻ + 5e⁻ => Mn⁺²    =>   MnO₄⁻ + 8H⁺ + 5e⁻ => Mn⁺² + 4H₂O

                                      =>  5Fe⁺² + MnO₄⁻ + 8H⁺ => 5Fe⁺³ + Mn⁺² + 4H₂O

Answer:

Diffusion means that particles travel from a higher concentration to a lower concentration region before balance is achieved. The semi-permeable membrane is present in osmosis, so that only solvent molecules can travel freely to equalize the levels.

Answer:

305.15

Explanation:

32 celsius converted to kelvin is 305.15 kelvin

Formula

32°C + 273.15 = 305.15K

I think its phosphorus and nitrogen

Answer:

A) 2-pentene

Explanation:

We count from side where we encounter double bond closest so that's going to be from left to the 2nd carbon. Total carbons are 5.

Thus pent- for prefix of 5 carbons and -ene as suffix for double bond.

2- for locant of double bond.

Thus, 2-pentene

Answer:

True

Explanation:

In a cell reaction, half cell reaction is oxidation. Oxidation means addition of electrons. This addition of electrons takes place at cathode. Therefore, cathode is site of oxidation. However, the other half cell reaction is reduction. In reduction reaction removal of electrons takes place. Reduction takes place at anode of the cell.

Therefore, the given statement is true.

Answer:

I think its false

Explanation:

Answer:

K = 6.25x10⁻⁴

Explanation:

Based on the reaction:

SO₂ + 1/2 O₂ ⇄ SO₃ Kp = 2.5x10⁻²

We can find the Kp of a similar reaction using Hess's law where the sum of 2 reactions a and b produce a K that is:

K = Ka*Kb

The sum of twice the reaction of the problem:

SO₂ + 1/2 O₂ ⇄ SO₃

+ SO₂ + 1/2 O₂ ⇄ SO₃

2SO₂ + O₂ ⇄ 2SO₃

Where K must be:

K = Kp*Kp = Kp²

K = (2.5x10⁻²)²

Answer:

See Explanation

Explanation:

Let us recall that;

[H^+] [OH^-] = 1 * 10^-14

Where;

[OH^-] = 1 x 10^-11

Then;

[H^+] = 1 * 10^-14/1 x 10^-11

[H^+] = 1 * 10^-3

pH = -log [H^+]

pH = -log(1 * 10^-3)

pH = 3

Also;

pH + pOH = 14

pOH = 14 - pH

pOH = 14 -3

pOH = 11

Answer:

Lowest ionization energy: Cs

Most favorable electron affinity: Cl

Most energy required to remove an electron: Cu2+

Explanation:

Ionization energy decreases down the group. That means that as we move down the group, the ionization energy of elements decreases due to greater distance of the outermost electron from the nucleus and greater screening effect of inner electrons on this outermost electron. Hence Cs has the lowest ionization energy.

Electron affinity of halogens decreases down the group. Hence, Cl possess the most favorable electron affinity.

When an electron has been removed from an atom, the removal of the next electron is usually harder. Thus, the second ionization energy is always greater than the first ionization energy and so on. Thus, it is most difficult to remove an electron from Cu^2+ from which two electrons have already been removed.

Answer:

yes because it has a fixed shape and volume

hope this helps

have a good day :)

Explanation:

Answer:

Lyric

Explanation:

My best guess

Answer:

(a) oxygen

(b) 154g (to 3sf)

(c) 79.9% (to 3sf)

Explanation:

mass (g) = moles × Mr/Ar

note: eqn means chemical equation

(a)

moles of P = 84.1 ÷ 30.973 = 2.7152 moles

moles of O2 = 85÷2(16) = 2.65625 moles

Assuming all the moles of P is used up,

moles of O2 / moles of phosphorus = 5/4 (according to balanced chemical eqn)

moles of O2 required = 5/4 × 2.7152moles = 3.394 moles (more than supplied which is 2.65625moles)

therefore there is insufficient moles of O2 and the limiting reactant is oxygen.

(b)

moles of P2O5 produced

= 2/5 (according to eqn) × 2.7152

= 1.08608moles

mass of P2O5 produced

= 1.08608 × [ 2(30.973) + 5(16) ]

= 154.164g

= approx. 154g to 3 sig. fig.

(c)

% yield = actual/theoretical yield × 100%

= 123/154 × 100%

= 79.870%

= approx. 79.9% (to 3sf)

Answer:

a

Explanation:

Answer:

1.3 moles

Explanation:

pv = nrt

n = pv/rt

n = (125 * 25) / (8.3144598 * 289)

n = 1.3 moles