Draw a flowchart or write pseudocode to represent the logic of a program that allows the user to enter a value. The program multiplies the value by 10 and outputs the result

Answer:

Key escrow.

Explanation:

If a full disk encryption (FDE) password is forgotten, a key escrow can be incorporated to securely store the encryption key to unlock the disk.

A key escrow can be defined as a data security method of storing very essential cryptographic keys.

Simply stated, key escrow involves a user entrusting his or her cryptographic key to a third party for storage.

As a standard, each cryptographic key stored or kept in an escrow system are directly linked to the respective users and are encrypted in order to prevent breach, theft or unauthorized access.

Hence, the cryptographic keys kept in an escrow system are protected and would not be released to anyone other than the original user (owner).

Therefore, when a full disk encryption (FDE) password is forgotten, a key escrow if incorporated can be used to retrieve the password. Subsequently, the password would then be used to unlock or decrypt the disk.

Answer:

True is the correct answer to the given question .

Explanation:

In the longitudinal analysis of designing we are collecting the information from the similar sample frequently over an enlarged time where as in the cross-sectional analysis designing Gathering the information from the population at the given time interval .

The main objective longitudinal designed is used to monitor the variations in the similar sample as a result of frequent analysis of the similar variables that are not possible in the cross-sectional design analysis .

Therefore the given statement is true .

Willy Shakespeare has 17 characters. It's higher than 12,so the output will be Too long. Enter a name with fewer than 12 characters.

Letter a.

Answer:

Every noticeable event, transaction, interaction, request and reply, and so on are being expectantly captured and saved in storage appliances and arrays for real-time as well as posterior investigations create something we call it Big Data.

Another way to look at is that it comprises massive amounts of data that keeps on growing exponentially over time so much so that it cannot be processed or analyzed using usual data processing techniques.

Cheers!

Answer:

public class IntegerToBinary

{

public static void main(String[] args) {

 integerToBinary(6);

}

public static void integerToBinary(int num){

    while(num > 0){

       System.out.print(num%2);

       num = Math.floorDiv(num, 2);

    }

}

}

Explanation:

*The code is in Java.

Create a function called integerToBinary that takes one parameter, num

Inside the function, create a while loop that iterates while the num is greater than 0. Inside the loop, print the num%2. Then, get the floor division of the num by to and assign it to the num.

Inside the main, call the function with parameter 6.

Answer:

Bare metal DB systems

Explanation:

Oracle Call Interface OCI is comprehensive system which is native C language interface to Oracle Database for custom applications. The bare metal database system requires more compute node processing power. Customers are not given OS logons or SYSDBA in Oracle autonomous applications which prevents phishing attacks.

Answer:

Number of + operation done by this algorithm is 60

Explanation:

i = 4

j = 3

k = 6

Now, let "n" be number of '+' operations

n = i × j + i × 2k

substituting the figures

n = 4 × 3 + 4 × (2 × 6)

n = 12 + 4 × 12

n = 12 + 48

n = 60

Answer:

i can't see some of the numbers

Explanation:

Answer:

True

Explanation:

It is always possible and feasible for a programmer to come up with test cases that run through every possible path in a program is a "true statement" or the first option. It is very natural for a programmer/developer to come up with test that will run through every possible outcome in a program. Doing so will help the developer find things that might cause problems with the program in later time.

Hope this helps.

The answer to the question about the feasibility of a programmer to always come up with test cases that run through every possible path in a program is:

This refers to the set of actions which a programmer performs to find out if his software or program passes the system requirements in order to work properly.

With this in mind, we can see that while in some cases, it is possible for the programmer to come up with test cases, but it is not feasible in all cases as there can be hardware error which a virtual machine cannot solve.

Read more about test cases here:
https://brainly.com/question/26108146

Answer:

Following are the code to this question:

def data(a):#defining method data that accepts parameter

   print (a)#print parameter value

def data(b):#defining method data that accepts parameter

   print (b)#print parameter value

x=input("enter value: ")#defining variable x that5 input value from user

print(data(x))#call method data

Output:

enter value: hello..

hello..

None

Explanation:

Answer:

C. The main method proceeds to the next statement following the t3.join(); statement

Explanation:

join() method allows the thread to wait for another thread and completes its execution. If the thread object is executing, then t3.join() will make that t is terminated before the program executes the instruction. Thread provides the method which allows one thread to another complete its execution. If t is a thread object then t.join() will make that t is terminated before the next instruction. There are three overloaded functions.

join()

join(long mills)

join(long millis, int Nanos)

If multiple threads call the join() methods, then overloading allows the programmer to specify the period. Join is dependent on the OS and will wait .

Answer:

This program is written using Python Programming language,

The program doesn't make use of comments (See explanation section for line by line explanation)

Program starts here

print("Enter elements into the list. Enter 0 to stop")

newlist = []

b = float(input("User Input: "))

while not b==0:

    newlist.append(b)

    b = float(input("User Input: "))

newlist.sort()

print("Largest element is:", newlist[-1])

Explanation:

This line gives the user instruction on how to populate the list and how to stop

print("Enter elements into the list. Enter 0 to stop")

This line creates an empty list

newlist = []

This line enables the user to input numbers; float datatype was used to accommodate decimal numbers

b = float(input("User Input: "))

The italicized gets input from the user until s/he enters 0

while not b==0:

    newlist.append(b)

    b = int(input("User Input: "))

This line sorts the list in ascending order

newlist.sort()

The last element of the sorted list which is the largest element is printed using the next line

print("Largest element is:", newlist[-1])

Answer:

Last

Explanation:

Routing is a term in engineering which involves the process of selecting a path for traffic in a network or across multiple networks. It is applicable in circuit-switched networks, such as the public switched telephone network (PSTN), and computer networks, such as the Internet. It is mostly used as a term for IP Routing.

Hence, in IP Routing, the first step is comparing the packet's destination IP address to all rows, followed by selecting the nest-match row. However, If no other row matches, the router will select the LAST row as its best match.

Answer:

deployment phase

Explanation:

This specific scenario belongs to the deployment phase of the hardware lifecycle. This phase is described as when the purchased hardware and software devices are deployed to the end-user, and systems implemented to define asset relationships. Meaning that everything is installed and set up for the end-user to be able to use it correctly.

Answer:

Hello your question lacks the required options here are the options

A)This response means the port he is scanning is open.

B)The RST/ACK response means the port Fred is scanning is disabled.

C)This means the port he is scanning is half open.

D) This means that the port he is scanning on the host is closed

answer : This means that the port he is scanning on the host is closed ( D )

Explanation:

When you scan a network to ensure it is secure enough by sending a TCP probe to a host with a FIN flag and you receive a RST/ACK response it means that The port that is been scanned on the host is closed

A TCP scanning/probe involves sending a number of packets to each port that is scanned. when you Compare TCP scanning methods to other methods of scans, a TCP Connect scan is typically slow and methodical.

Answer:

akbar

Explanation:

Tilak friends had less time to visit him because they no longer next week so They brought Tilak a book about Snow White Cheetah

Hello,

This is in HTML language:

dl for Description List

dd for Description Description

   This tag is used in a description list (<dl>) and it describes a term in this list.

dt for Description Term

   This tag is used to define a term.

For instance,

<dl>

   <dt>Brainly</dt>

   <dd>Best website ever</dd>

</dl>

Hope this helps.

Answer:

C

Explanation:

Option A is used for line spacing.

Option B is used for right indent.

Option C is used for right paragraph alignment.

Option D is used for bullet points.

The button used for paragraph alignment would be option C.

Answer and Explanation:

The result of providing the which utility the command name i.e not covered under the search path is as follows

The device that shows a notification that the command you are searching for is not in your query path's directory list. The utility in which no information is shown. Because the search path has always been about which utility therefore it would not be work.

Answer:

Following are the code to this question:

#include<iostream>//declaring header file

using namespace std;  

void decode(string* arr, int n)//defining a method decode

{

for(int i = 0; i < n; i++)//defining a loop for print value

{

cout << arr[i][i] << " "; // using print method to print ith letter of the string

}

cout << endl;//line break

}

int main()//defining main method

{

string secret1[] = {"platypus","plethora","trend","croak","almost","toaster"};//defining string arry and assign value

string secret2[] = {"fire","seen","trend","produce"};//defining string arry and assign value

string secret3[] = {"tiretread","chains","stern","bed bug"};//defining string arry and assign value

string secret4[] = {"oracle","stetson","mother","stie","twigrot"};//defining string arry and assign value

decode(secret1, 6);//calling method decode and pass string array and integer number

decode(secret2, 4);//calling method decode and pass string array and integer number

decode(secret3, 4);//calling method decode and pass string array and integer number

decode(secret4, 5);//calling method decode and pass string array and integer number

return 0;

}

output:

Please find the attachment.

Explanation:

In the above C++ language code, a method "decode" is declared that accepts a string array and an integer variable in its parameter, inside the method a for loop is declared, which is used "n" variable to print its [tex]i^{th}[/tex] letter value in the given string value.  

In the main method,  4 string array "secret1, secret2, secret3, and secret4" is declared which assigns some value, and then we call the method "decode" and pass string array value and an integer value in its parameter.

141.95|212.95|312.95|10.95|

Reformatting the code snippet and giving it line numbers;

1.       var totals = [141.95, 212.95, 411, 10.95];

2.      totals[2] = 312.95;

3.      var totalsString = "";

4.      for (var i = 0; i < totals.length; i++) {

5.          totalsString += totals[i] + "|";

6.      }

Line 1 creates an array called totals with four elements.

     First element = totals[0] =141.95

     Second element = totals[1] = 212.95

     Third element = totals[2] = 411

     Fourth element = totals[3] = 10.95

Line 2 replaces the value of the third element totals[2] = 411 with 312.95.

     Therefore the array totals = [141.95, 212.95, 312.95, 10.95]

Line 3 creates an empty string called totalsString

Lines 4 - 6 create a for loop that cycles from i=0 to i<totals.length

       totals.length = 4 (which is the number of items in the array totals)

       This means that the loop cycles from i=0 to i<4

       During cycle 1 when i = 0, the expression inside the for loop executes as follows;

            totalsString = totalsString + totals[0] + "|"   //substitute the values

            totalsString = "" + 141.95 + "|"

            totalsString = 141.95|

       During cycle 2 when i = 1, the expression inside the for loop executes as follows;

            totalsString = totalsString + totals[1] + "|"   //substitute the values

            totalsString = "141.95|" + 212.95 + "|"

            totalsString = 141.95|212.95|

       During cycle 3 when i = 2, the expression inside the for loop executes as follows;

            totalsString = totalsString + totals[2] + "|"   //substitute the values

            totalsString = "141.95|212.95|" + 312.95 + "|"

            totalsString = 141.95|212.95|312.95|

       During cycle 4 when i = 3, the expression inside the for loop executes as follows;

            totalsString = totalsString + totals[3] + "|"   //substitute the values

            totalsString = "141.95|212.95|312.95|" + 10.95 + "|"

            totalsString = 141.95|212.95|312.95|10.95|

At the end of the execution, totalsString = 141.95|212.95|312.95|10.95|

Answer:

import java.util.Scanner; // Scanner class is to use input output functions

public class TwoDistinctLargest //class to find two distinct largest nos

{

public static void main(String[] args) { //start of main() function

Scanner input = new Scanner(System.in); // creates Scanner type object

       int integers = 0, largest1 = 0, largest2 = 0; // declare variables

/* integers holds the input integer values, largest1 has 1st largest number and largest 2 contains second distinct largest number, i is used as the count variable to move through the input integers */

       int i = 0;  

//prompts user to enter integers and enter 0 to stop

       System.out.println("Enter the integers (press 0 to stop): ");

       integers = input.nextInt(); //reads and scans input integers

       while(integers != 0) {

/* the loop keeps taking integer values from user until the value of integers is equal to 0, this means until the user enters 0 */

//checks if the value of integer is greater than first largest computed number

           if(integers > largest1) {

//if the value in largest1 is greater than that of largest2

               if(largest1 > largest2) {

                   largest2 = largest1; } // then value of largest1 is set to largest2                

               largest1 = integers; // largest1 now holds the value of integers //which means largest1 holds the first distinct largest integer

           } else { //checks if the value of integers is greater than largest2

               if(integers > largest2) {

//if the value of integers is not equal to that of largest1

                   if(integers!=largest1)  {

// set the value of second distinct largest number to largest2

                   largest2 = integers;}              }            }

                     i++; //keeps moving to the next input integer

           integers = input.nextInt();     //keeps taking input integers    }      

//prints the two distinct largest integers

       System.out.println("\n The 1st largest distinct integer is " + largest1);

       System.out.println("\n The 2nd largest distinct integer is " + largest2); } }

Explanation:

Lets suppose the user inputs the following integers

1, 6, 5, 6, 0

Initial values are:

integers = 0

largest1 = 0

largest2 = 0

i = 0

When the user enters 1, then value of integers = 1

while loop checks if integers!=0. As integers =1 so the program enters the body of while loop. The first IF condition is checked if(integers > largest1)

As largest1 = 0 and integers =1 so this condition evaluates to true as 1 > 0

So the statements in the body of this IF condition are executed. This if conditions contains another if statement if(largest1 > largest2) which checks if the value largest1 is greater than that of largest2. Its false because largest1 =0 and largest2 =0 so largest1 = largest2, so the statement of this if condition body will not execute and program moves to this                 largest1 = integers; statement which sets the value of integers i.e. 1 to largest1. So the value of largest1 = 1

Now the i is incremented by 1 and it points at second value of integers= 6.

while loop checks if integers!=0. As integers =6 so the program enters the body of while loop. The first IF condition is checked if(integers > largest1)

As largest1 = 1 and integers =6 so this condition evaluates to true as 6>1

So the statements in the body of this IF condition are executed. This if conditions contains another if statement if(largest1 > largest2) which checks if the value largest1 is greater than that of largest2.

Its true because largest1 =1 and largest2 =0 so largest1 > largest2, so the next statement is executed largest2 = largest1; So now the value of largest2=1.

Now program moves to this largest1 = integers; statement which sets the value of integers i.e. 6 to largest1. So the value of largest1 = 6

Now the i is incremented by 1 and it points at second value of integers= 5.

while loop condition is again true. IF condition is checked if(integers > largest1)

As largest1 = 6 and integers =5 so this condition evaluates to false as 5<6. So this IF part will not execute and program control moves to the else part.

Else part has an if condition if(integers > largest2) which evaluates to true because integers = 5 and largest2 = 1 so the program moves to next if statement inside the previous if statement of else part i.e. if(integers!=largest1). This if statement is the main statement which will help in finding two distinct largest numbers in case the same largest value is input more than once. It checks If the value of integers is not equal to largest1 value. As integers = 5 and  largest1 = 6 so this if condition is true. If this condition is not used in this program then largest2 will not be assigned distinct largest values but assigned 6 for both largest1 and largest2 as 6 is input twice. Next this if statement  largest2 = integers assigns value of integers to largest2 which is the second largest distinct integer.

Now the i is incremented by 1 integers value become 0.

while loop checks if integers!=0. As integers =0 so the while loop breaks. The last two print statements which produce following output.

The 1st largest distinct integer is: 6

The 2nd largest distinct integer is: 5

Answer:

Explanation:

In data communications, a protocol is connectionless if it describes communication between two devices in a network without first establishing or verifying establishment of some link (connection) between the two devices. In a connectionless protocol, data are exchanged between processes or devices without a prior check of whether the processes are ready to transmit data or not. In this type of protocol, there's no verification put in place to remember if these processes were or are in communication. Connectionless protocols are also called stateless protocols. Because connectionless protocol cannot be relied upon due to its lack of delivery-assurance policy, it is sometimes referred to as unreliable protocol. In other words, delivery of data packets is not guaranteed. An example of a connectionless protocol is the UDP (User Datagram Protocol).

However, if the protocol defines some checks to ascertain that there is first a connection between two communicating processes before beginning transmission, then, the protocol is connection-oriented. An example of this is the TCP (Transmission Control Protocol). Connection-oriented protocols are reliable since they ensure connection be made between processes before transmitting data packets.

A typical application of a connectionless/unreliable protocol is in the streaming of real time videos or voice communication where packets of data could be dropped and not resent.

An example of the connection-oriented/reliable protocol is analogous to making a telephone call where data packets (voice messages) are not sent until the receiver on the other end makes a connection.

Answer: Computer engineering refers to the study that integrates digital engineering with computer sciences to design and develop computer structures and different technological gadgets.

Explanation:

Answer:

Computer engineering is the branch of engineering that integrates electronic engineering with computer sciences. Computer engineers design and develop computer systems and other technological devices.

Answer:

Here is the Python code.

import csv  

inputfile = input("Enter name of the file: ")

count = {}

with open(inputfile, 'r') as csvfile:

 csvfile = csv.reader(csvfile)

 for line in csvfile:

   for words in line:

     if words not in count.keys():

       count[words] = 1

     else:

         count[words] + 1

   print(count)

Explanation:

I will explain the code line by line.

import csv   here the css is imported in order to read the file using csv.reader() method

inputfile = input("Enter name of the file: ")  This statement takes the name of the input file from the user

count = {}  this is basically a dictionary which will store the words in the file and the number of times each word appears in the file.

with open(inputfile, 'r') as csvfile:  This statement opens the inputfile using open() method in read mode. This basically opens the input file as csv type

 csvfile = csv.reader(csvfile)  This statement uses csv.reader() method to read the csv file contents.

for line in csvfile:  This outer for loop iterates through each line of the file

for words in line:  This inner loop iterates through each word in the line

if words not in count.keys():  This if condition checks if the word is not in the dictionary already. The dictionary holds key value pair and keys() method returns a list of all the keys of dictionary

count[words] = 1  if the word is not present already then assign 1 to the count dictionary

co unt[words] + 1 if the word is already present in dictionary increment count of the words by 1. Suppose the input file contains the following words:

hello,cat,man,hey,dog,boy,Hello,man,cat,woman,dog,Cat,hey,boy

Then because of co unt[words] + 1 statement if the word appears more than once in the file, then it will not be counted. So the output will be:

{' cat': 1, ' man': 1, ' dog': 1, ' woman': 1, ' Hello': 1, ' hey': 1, ' boy': 1, 'hello': 1, ' Cat': 1}

But if you want the program to count those words also in the file that appear more than once, then change this co unt[words] + 1 statement to:  

count[words] = count[words] + 1

So if the word is already present in the file its frequency is increased by 1 by incrementing 1 to the count[words]. This will produce the following output:

{' Cat': 1, ' cat': 2, ' boy': 2, ' woman': 1, ' dog': 2, ' hey': 2, ' man': 2, ' Hello': 1, 'hello': 1}  

You can see that cat, boy, dog and hey appear twice in the file.                    

print(count) This statement prints the dictionary contents with words and their frequencies.

The program with its output is attached.

The program is an illustration of file manipulations.

File manipulations involve reading from and writing into files.

The program in Python, where comments are used to explain each line is as follows:

#This imports csv module

import csv  

#This initializes a dictionary

kounter = {}

#This gets input for the file name

fname = input("Filename: ")

#This opens and iterates through the file

with open(fname, 'r') as cfile:

   #This reads the csv file

   cfile = csv.reader(cfile)

   #This iterates through each line

   for line in cfile:

       #This iterates through each word on each line

       for words in line:

           #This counts the occurrence of each word

           if words not in kounter.keys():

               kounter[words] = 1

           else:

               kounter[words] + 1

#This prints the occurrence of each word

print(kounter)

Read more about similar programs at:

https://brainly.com/question/14468239

Question:

The technology environment would include studies of:

A) family changes

B) social engineering

C) information technology

D) minimum wage laws

E) customer service

Answer:

The correct answer is Information Technology (C)

Explanation:

Information and communications technology (ICT) or Information Technology. Whenever the technology environment is under discourse, these are usually the predominant subject matter.

It doesn't come as a surprise given that we live in an information age. An era of the internet of things. If we are tending towards an era where every equipment and even most biological species will give off and receive data, then a technology environment is really predominantly IT.

Cheers!

Answer:

Goals

Explanation:

Interestingly, the term goals refers to a perceived future a certain individual or group of individuals are hopeful for, or better still it could be an expectation of improved quality of worth or merit, excellence and importance; custom or ideals that people desire as an end, often shared within a group.

Remember, goals are desired end, achieved as a result of deliberate action or actions towards attaining it.

Answer:

Using Python:

def displaySubMenu():

   print("[S]top – Press ‘S’ to stop.")

Using C++ programming language:

void displaySubMenu(){

cout<<"[S]top – Press ‘S’ to stop.";}

Explanation:

The function displaySubMenu() has a print statement that prints the following message when this function is called:

[S]top – Press 'S' to stop.

You can invoke this function simply by calling this function as:

displaySubMenu()

The function doesn't take any input from the user and just displays this message on output screen whenever this function is called.

In C++ you can simply call the function using following statement:

void main(){

displaySubMenu(); }

Answer:

Parameters of primitive type are considered by Java methods to be local variables.

Explanation:

The parameters in JAVA are passed by value only. This means a parameter is considered to be local and a copy of the value is created used locally.

So if you change parameters of the primitive type so the value you change is local to the method. This implies that a copy of the parameter is made and the changes made on this copy will not affect the argument's value. In a nut shell, the parameters of primitive type are considered by Java methods to be local variables.

Answer:

c. The date as of which all progress on a project is reported

Explanation:

In construction scheduling, data date (DD), also known in MS Project as Status Date is used to update the periodic schedule. The data date is usually set at month-end or towards the month-end. It is required that all activities prior to the data date are completed and no work is reported as not completed or in-progress.

Appropriate information on the details of the project and accomplishments should be updated before the data date. After the data date, what follows should be the implementation of the remaining part of the project. The data date is also called the as-of date and time-now date.

I wrote it in Python because it was quick so i hope this is helpful

Answer:

date = input('Enter Date: ')

split_date = date.split('/')

month = split_date[0]

day = split_date[1]

if month == '1':

   english_month = 'January'

   spanish_month = 'Enero'

elif month == '2':

   english_month = 'February'

   spanish_month = 'Febrero'

elif month == '3':

   english_month = 'March'

   spanish_month = 'Marzo'

elif month == '4':

   english_month = 'April'

   spanish_month = 'Abril'

elif month == '5':

   english_month = 'May'

   spanish_month = 'Mayo'

elif month == '6':

   english_month = 'June'

   spanish_month = 'Junio'

elif month == '7':

   english_month = 'July'

   spanish_month = 'Julio'

elif month == '8':

   english_month = 'August'

   spanish_month = 'Agosto'

elif month == '9':

   english_month = 'September'

   spanish_month = 'Septiembre'

elif month == '10':

   english_month = 'October'

   spanish_month = 'Octubre'

elif month == '11':

   english_month = 'November'

   spanish_month = 'Noviembre'

elif month == '12':

   english_month = 'December'

   spanish_month = 'Diciembre'

US_English = f'{english_month} {day}'

International_Spanish = f'{day} {spanish_month}'

print(f'US English Form: {US_English}')

print(f'International Spanish Form: {International_Spanish}')

Input:

3/5

Output:

US English Form: March 5

International Spanish Form: 5 Marzo

Explanation:

You start by taking input from the user then splitting that at the '/' so that we have the date and the month in separate variables. Then we have an if statement checking to see what month is given and when the month is detected it sets a Spanish variable and an English variable then prints it to the screen.

Hope this helps.