Answer:
Positively charged objects have electrons; they simply possess more protons than electrons.
Explanation:
2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.
Information:If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.
Tips:If it loses an electron, it becomes positively charged and is known as a cation.
I hope this answers help you! :>Answer:
The contain both protons and electrons, but they have more protons than electrons making it a positively charged object.
A Piatma is a very hot gas comprised of freely moving positive and negative suale particles that are in random motion. Which of the following microscopic properties, together alwama held to have an observable macroscopic effect on the plasma when the plan is placed in the region that contains the magnetic field?
A. The particles have subatomically mal dimensions
B. The particles are charged
C. The particles are not all classified as fundamental particles
D. The particles are in random motion
Answer:
B. The particles are charged
Explanation:
We know that a moving charge particle in magnetic field experiences a magnetic force given by :
[tex]$\vec F = q (\vec v \times \vec B)$[/tex]
In the context, a very hot gas of piatma consists of freely moving positive particles as well as negative particles. Now when the plasma is placed in the region of a magnetic field, then it experiences a force and thus it shows that the particles are charged particles.
Hence , option (B) is correct.
A child with a mass of 20 kg slides down a slide at an angle of 40º from the horizontal. She accelerates at 1.3 m/s2. Calculate the magnitude of the frictional force on the child
Answer:
OK
The component of gravity that aids his sliding down.. is
Mgsin∆
Friction will oppose the motion
Therefore... The net force acting will be
MgSin∆ - Fr=Ma
Where Fr= Frictional Force
Fr = MgSin∆ - Ma
= 20x9.8Sin40 - 20x1.3
=125.99 - 26
=99.99N ~ 100N.
PLEASE HELP I WILL MARK BRAINLYIST!!!!!!!!!
All of the matter in the universe formed after the big bang. Scientists
predicted that hydrogen and helium would be the most abundant elements.
What did scientists discover?
A. The universe has 73% hydrogen and 25% helium, which does not
support the big bang theory
B. Planets are made mostly of other elements, which does not
support the big bang theory
C. Stars are made mostly of other elements, which supports the big
bang theory
D. The universe has 74% hydrogen and 24% helium, which supports
the big bang theory.
Answer:
The answer is D. Here is proof . Plz mark brainliest
Explanation:
state Newton's first law of motion in words
Answer:
An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.
ANSWER PLEASE ASAP science
1) cuscuta - parasitic
2) pitcher plant - insectivorous
3) Green plants -Autotrophs
4) Food store in - starch
plants
5) Rhizobium -Bacteria
please help, im having trouble can you please explain how to do it
Answer:
independent and the second one with the (-8, 1, -3)
If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardless of the order in which each object was plotted. True False
Answer:
True
Explanation:
It Depends on the order in which each object was plotted, if two connected points objects pass through the same set of three points, the shapes created by each point may be different
what is the value of 3 in
24.635
Answer:
3 tens
Explanation:
The value
of 3 in 24.635 is at 3 tens place as the place is two to the left.
The correct answer to the given is question is "0.03".
What is Place Value?The value of each digit in a number is known as place value.For example the 2 in 125 represent 2 tens or 20, however the 2 in 2103 represent 2 thousands or 2000.Frequently, they will only include the letters like Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, Ones, tenths, hundredths, and so on to denote each place. How to solve this question?Let's display the number 24.635 using a place value chart.
Tens -> 2 Ones -> 4 Tenth -> 6 Hundredths -> 3 Thousandths -> 5
The 3 is in Hundredths Place or the value of 3 in 24.635 is 0.03.
Thus, we can conclude that the value of 3 in 24.635 is 0.03 after solving the question.
Learn more about Place Value here:
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A current of 5 a flows in a copper wire for 20 s. how many coulombs of charge passed through the wire in this time?
Answer:
I think so too
Explanation:
:*
A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the lens strength (a.k.a, lens power) of her eyes. What is the closest object she can see clearly
Answer:
20.0 cm
Explanation:
Here is the complete question
The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?
Solution
Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.
Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.
Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m
Now, P' = 1/u + 1/v
1/u = P'- 1/v
1/u = 55.0 D - 1/0.02 m
1/u = 55.0 m⁻¹ - 1/0.02 m
1/u = 55.0 m⁻¹ - 50.0 m⁻¹
1/u = 5.0 m⁻¹
u = 1/5.0 m⁻¹
u = 0.2 m
u = 20 cm
So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.
Which of the following statements about asexual reproduction is NOT true? A Only one parent sex cell is needed. B The offspring are copies of the parent. C Most single-celled organisms reproduce this way. Dit results in more variation in species than does sexual reproduction
Answer:
D
Explanation:
D is false because asexual reproduction produces offspring much more similar to the parent than that produced in sexual reproduction.
If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen distance to be 4030 nm away what is the distance from the zero order fringe to the first order fringe
Answer:
Y = 3.39 x 10⁶ m
Explanation:
We will use Young's Double Slit formula here:
[tex]Y = \frac{\lambda L}{d}[/tex]
where,
Y = Fringe spacing = ?
λ = wavelength = [tex]\frac{speed\ of\ light}{frequency} = \frac{3\ x\ 10^8\ m/s}{375\ Hz}[/tex] = 8 x 10⁵ m
L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m
d = slit separation = 950 nm = 9.5 x 10⁻⁷ m
Therefore,
[tex]Y = \frac{(8\ x\ 10^5\ m)(4.03\ x\ 10^{-6}\ m)}{9.5\ x\ 10^{-7}\ m}[/tex]
Y = 3.39 x 10⁶ m
Select the correct answer. A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds of its travel. What is its average speed during the time from t = 5 seconds to t = 10 seconds? A. 2 meters/second B. 3 meters/second C. 4 meters/second D. 5 meters/second E. 6 meters/second
Answer:
2 m/s
Explanation:
...........................
Answer:
A:2 m/s
Explanation:
Plato
What is the component in a car engine that would detect the need for air?
Answer:
Control of air–fuel ratio
Oxygen sensors tell the ECU whether the engine is running rich (too much fuel or too little oxygen) or running lean (too much oxygen or too little fuel) as compared to ideal conditions (known as stoichiometric).
Explanation:
The power output of a car engine running at 2500 rpm is 500 kW . You may want to review (Pages 574 - 577) . Part A How much work is done per cycle if the engine's thermal efficiency is 20.0 %
Answer:
Explanation:
2500 rpm = 2500 / 60 rps ( revolution per second )
= 41.67 rps .
power output = 500 kW
thermal efficiency = 20 %
power input = (100 /20) x 500 kW
= 2500 kW .
work done per second = 2500 kJ
work done per cycle = 2500 / 41.67
= 60 kJ .
We have that the workdone per cycle is mathematically given as
Wc=12.00KJ
Workdone per cycle of engineQuestion Parameters:
The power output of a car engine running at 2500 rpm is 500 kW
Generally the work done per cycle is mathematically given as
Wc=500*1/41.666
Where
=2500rev/60sec
=41.666
Meaning one cycle takes 1/41.666
Hence
Wc=500*1/41.666
Wc=12.00KJ
For more information on work
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A graduated cylinder with which of the following gradations would lead to the most precise measurements of volume?
O marked every 10 ml
O marked every mL
O marked every 5 ml
g PRACTICE ANOTHER Two trains approach each other on separate but adjacent tracks. Train 1 is traveling at a speed of 30.3 m/s and train 2 at a speed of 22.5 m/s. If the engineer of train 1 sounds his horn which has a frequency of 520 Hz, determine the frequency of the sound heard by the engineer of train 2. (Use 343 m/s as the speed of sound. Enter your answer to the nearest Hz.)
Answer:
f'= 607.8 Hz
Explanation:
This is a Doppler effect exercise due to the relative velocity of the sound source and the observer.
By the time the source and the observer are getting closer the expression is
f ’=[tex]f_o \ \frac{ v+ v_o}{v - v_s}[/tex]
where vs is the speed of the source, vo is the speed of the observer, if the bodies move away the signs are exchanged
in this case, train 1 emits sound, so its speed is v_s = 30.3 m / s and train 2 is the receiver of the sound v₀ = 22.5 m / s
let's calculate
f ’= [tex]520 \ ( \frac{343 + 22.5}{343 - 30.3} )[/tex]520 (343+ 22.5 / 343 - 30.3)
f'= 607.8 Hz
paano mag drawing ng bilog
Answer: how to draw a circle
Explanation:
A boy stands between two vertical walls and fires a rifle. Under what condition will he hear a single echo from both walls? Calculate the distance between the walls if the single echo is heard six seconds later.
Answer:
d = 1,029 m
Explanation:
When the young man shoots the rifle the sound travels in all directions, if the young man is at the same distance from the two walls, as the speed of the wave is constant, he takes the same time to go to the wall and return for which he hears a single echo.
To calculate the distance let's use the uniform motion relationships
v = d / t
d = v t
As the speed is constant, the time to reach the wall is the same as it takes to go from the wall to the young man,
t = to / 2
t = 6/2
t = 3 s
d = 343 3
d = 1,029 m
state is newton third law of motion
Answer:
Hey mate.....
Explanation:
This is ur answer.....
Newton's third law of motion states that whenever a first object exerts a force on a second object, the first object experiences a force equal in magnitude but opposite in direction to the force that it exerts.
Hope it helps!
Brainliest pls!
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to increase the frequency by 2 octave (s), to 4 f , by what factor would you have to increase the tension
Answer:
16
Explanation:
Since frequency in a stretched string f = (n/2L)√T/μ and n, L and μ are constant, f ∝ √T where T = tension in string
Now f₂/f₁ = √T₂/√T₁
Since f₁ = f (frequency at tension T₁) and f₂ = 4f (since its frequency increases by 2 octaves to 4f at tension T₂).
So,
f₂/f₁ = √T₂/√T₁
4f/f = √T₂/√T₁
√T₂/√T₁ = 4
squaring both sides, we have
(√T₂/√T₁)² = 4²
T₂/T₁ = 16
T₂ = 16T₁
So, the tension would have to increase by a factor of 16
In a double-slit experiment, the third-order maximum for light of wavelength 510 nm is located 17 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 670 nm is then projected through the same slits. Part A How far from the central bright spot will the second-order maximum of this light be located
Answer:
14.9 mm
Explanation:
We know dsinθ = mλ where d = separating of slit, m = order of maximum = 3 and λ = wavelength = 510nm = 510 × 10⁻⁹ m
Also tanθ = L/D where L = distance of m order fringe from central bright spot = 17 mm = 0.017 m and D = distance of screen from slit = 1.6 m
So, sinθ = mλ/d
Since θ is small, sinθ ≅ tanθ
So,
mλ/d = L/D
d = mλD/L
Substituting the values of the variables into the equation, we have
d = 3 × 510 × 10⁻⁹ m × 1.6 m/0.017 m
d = 2448 × 10⁻⁹ m²/0.017 m
d = 144000 × 10⁻⁹ m
d = 1.44 × 10⁻⁴ m
d = 0.144 × 10⁻³ m
d = 0.144 mm
Now, for the second-order maximum, m' of the 670 nm wavelength of light,
m'λ'/d = L'/D where m' = order of maximum = 2, λ' = wavelength of light = 670 nm = 670 × 10⁻⁹ m, d = slit separation = 0.144 mm = 0.144 × 10⁻³ m, L' = distance of second order maximum from central bright spot and D = distance of screen from slit = 1.6m
So, L' = m'λ'D/d
So, substituting the values of the variables into the equation, we have
L' = 2 × 670 × 10⁻⁹ m × 1.6 m/0.144 × 10⁻³ m
L' = 2144 × 10⁻⁹ m²/0.144 × 10⁻³ m
L' = 14888.89 × 10⁻⁶ m
L' = 0.01488 m
L' ≅ 0.0149 m
L' = 14.9 mm
using the image provided, which moon phase is next?
Answer:
Waning Crescent
Answer: waxing crescent
Explanation:
how is intera in baseball
Answer:
Ok I guess
Explanation:
Answer:
what is intera basketball?
The diagram shows a man using a lever to move a rock.
Which change can he make to the fulcrum to decrease the force he has to apply?
A- Remove the fulcrum
B- Put the fulcrum on top of the lever.
C- move the fulcrum closer to himself
D-
move the fulcrum closer to the rock
Which of the following phase changes occurs at point B on the phase diagram shown below? (choose all that apply)
solid
liquid
gas
T
melting
sublimating
boiling
condensing
Answer:
Condensation and Melting
Explanation:
Gas to liquid = Condensation
Solid to liquid = Melting
Solve the following problem. A force of 5N is being applied to the right, and a force of
3N is being applied to the left. What is the net force?
A- 15 N
B- 8 N
C- 7N
D- 2N
Answer:
D 2N
Explanation:
these are opposite forces so one becomes negative and the other positive that is
-3+5=2 or 5-3=2
a spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?
a. 0.0014 meters
b. 0.45 meters
c. 2.2 meters
d. 5.0 meters
show your work
Answer:
I think its B
Explanation:
A charged particle of mass 0.0050 kg is subjected to a 5.0 T magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius 0.20 m at a speed of 2.0 m/s. what is the magnitude of the charge on the particle
Answer:
0.01 C
Explanation:
Applying,
F = qvBsinФ................ Equation 1
Where F = Force on the charged particle, q = charge on the particle, v = velocity, B = magnetic field, Ф = angle
Since the charged particle noves in a circle,
F = mv²/r................. Equation 2
Where m = mass of the particle, v = velocity of the particle, r = radius of the circle
Substitute equation 2 into equation 1
mv²/r = qvBsinФ
make q the subject of the equation
q = mv/(rBsinФ)............. Equation 3
Given: m = 0.005 kg, v = 2 m/s, r = 0.2 m, B = 5 T, Ф = 90° (Act at right angle)
Substitute these values into equation 3
q = (0.005×2)/(0.2×5×sin90°)
q = 0.01/(1)
q = 0.01 C
30 POINTS PLS ANSWER QUICK
Many objects within our solar system remain in constant motion and maintain predictable orbital patterns. What force
governs the motion and patterns of objects in our solar system?
A) The force of gravity keeps the Sun, asteroids, and comets orbiting in an elliptical pattern around the Earth.
B) The force of gravity keeps the Earth, asteroids, and comets orbiting in an elliptical pattern around the Sun.
C) The equal and opposite force between the Sun and the Earth keeps the comets and asteroids orbiting in an elliptical
pattern.
D) The Sun moves in an elliptical pattern and the planets, comets, and asteroids follow the gravity of the Sun in an
elliptical pattern.
Answer:
c
Explanation: