Describe the relationship between the potential difference across the resistor and
the current through the resistor.

Answer:

Answer: question 2 is (a) (25+273)k=298k(b) (373+273)k=646k

question 5 is 25 degree Celsius

question 1 is

a = (293-273) =20 degree Celsius

b = (470-273)=197 degree Celsius

question 3 is

a = naphthalene ball undergo sublimation due to which it convert directly into vapour and disappear into air without leaving any solid

b = the participle of perfume diffuse rapidly into air and its smell can be felt while sitting serval metre away

question 4 isthe force of allraction between the particles increases as we go from liquid to gas so the required order is : Oxygen< water< sugar

I hope it is helpful to you

Answer:

3. Bacteria

Explanation:

If you don't trust me, search it up!

Answer:

a metal is an element that readily forms positive ions (cations) and has metallic bonds

coke is a strong stimulant made from coca leaves

Answer:

12 atoms of hydrogen will be present in the product

Explanation:

12 atoms of hydrogen will be present in the product because the law of conservation of mass states that mass is neither created nor destroyed in chemical reactions.

The law of conservation states that the mass of the element remains the same during the course of the reaction.

The law of reaction conformed by the following:-  

According to the question, the amount of hydrogen is 12 atoms in the reactant and the amount will remain the same at the end of the reaction, which is a product that is 12 atoms

Hence, the amount remains the same in the reaction that is 12 atoms

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Answer:

44.4%

Explanation:

The balanced chemical equation for the reaction is:

2 H₂(g) + O₂(g) → 2 H₂O(g)

According to the equation, 1 mol of O₂ produces 2 moles of water (H₂O). We convert the moles to grams by using the molecular weight (Mw) of each compound:

Mw(O₂) = 2 x 16 g/mol O = 32 g/mol

mass O₂ = 1 mol x 32 g/mol = 32 g O₂

Mw(H₂O) = (2 x 1 g/mol H) + 16 g/mol O = 18 g/mol

mass H₂O = 2 mol x 18 g/mol = 36 g H₂O

Thus, from 32 grams of O₂, 36 g of H₂O are produced (stoichiometric ratio= 36 g H₂O/32 g O₂). We calculate the amount of H₂O that would be produced from 20 grams of O₂ by multiplying the stoichiometric ratio by the mass of O₂, as follows:

36 g H₂O/32 g O₂ x 20 g O₂ = 22.5 g H₂O

The theoretical yield of H₂O is 22.5 g, and the actual amount produced is 10 g. So, we calculate the percent yield as follows:

Percent yield = actual yield/ theoretical yield x 100

                      = (10 g)/(22.5 g) x 100

                      = 44.4%

Answer:

pH = 7 ⇒ [H⁺] = 1.0x10⁻⁷ M

pH = 5.6 ⇒ [H⁺] = 2.5x10⁻⁶ M

pH = 3.7 ⇒ [H⁺] = 2.0x10⁻⁴ M

H⁺ concentration in the Hubbard Brook sample is 80 times higher than in unpolluted rainwater.

Explanation:

To answer this problem we need to keep in mind the definition of pH:

Meaning that after isolating [H⁺] we're left with:

Now we proceed to calculate [H⁺] for the given pHs:

Finally we calculate how many times higher is [H⁺] when pH = 3.7 than when pH = 5.6.

Answer:

1. 7 (a neutral solution)

Answer: 10-7= 0.0000001 moles per liter

2. 5.6 (unpolluted rainwater)

Answer: 10-5.6 = 0.0000025 moles per liter

3. 3.7 (first acid rain sample in North America)

Answer: 10-3.7 = 0.00020 moles per liter

The concentration of H+ in the Hubbard Brook sample is 0.00020/0.0000025, which is 80 times higher than the H+ concentration in unpolluted rainwater.

Explanation: -

Answer:

the reducing flame also called the carburizing flame.

Explanation:

because it gets the oxides of the unknown salts

✧ [tex] \underline{ \underline{ \large{ \tt{A \: N \:S \: W \: E \: R}}}} : [/tex]

[tex] \underline{ \underline{ \large{ \text{Molecular \: Formulaes}}}} : [/tex]

⇾ [tex] \large{ \text{Potassium \: Hydroxide : K \: OH}}[/tex]

⇾ [tex] \large{ \text{Sodium \: Chloride : NaCl}}[/tex]

⇾ [tex] \large{ \text{Sodium \: Hydroxide : NaOH}}[/tex]

⇾ [tex] \large{ \text{Calcium \: Chloride : CaCl}}[/tex]

⇾ [tex] \large{ \text{Sodium \: Bicarbonate} : \tt{Na ( HCO)_{ 3} }}[/tex]

---------------------------------------------------------

☥ [tex] \underline{ \underline{ \large{ \tt{ \: E \: X\: P \: L\: A\: N \: A \: T \: I \: O \: N}}} }: [/tex]

[tex] \underline{ \underline{ \text{Writing \: a \: molecular \: formula}}} : [/tex]

To write a molecular formula , the following steps are usually adopted only when we know the symbol and valencies of elements and radicals present in a molecule.

Step 1 : First , the name of the compound is written.

Step 2 : The symbols of basic and acidic radicals are written side by side.

Step 3 : The valency of each radical is written at the right upper corner of the symbol. The valency of one radical is transferred to another radical and it is written on the right hand side at the bottom corner. If necessary , L.C.M of the valencies us taken to get a simple whole number.

Step 4 : If a compound radical takes part in the molecular formula , the radical is enclosed in brackets and the valency number is written on the right side of the bracket at the bottom of the formula.

For instance :

[tex] \text{Calcium \: \: \: \: \: \: Sulphate}[/tex] [ compound ]

1. [tex] \sf{Ca \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: SO_{4} }[/tex] [ Symbol of basic and acidic radicals ]

2.We know : Valencies of calcium and sulphate are 2 and 2 respectively

3. [tex] \sf{Ca_{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (SO_{4} )_{2} }[/tex] [ Valencies are exchanged and compound radical is enclosed in bracket ]

4.[tex] \sf{CaSO_{4}}[/tex] [ L.C.M is taken to get molecular formula of calcium sulphate ]

Hope I helped ! ♡

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☥ [tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎

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Answer:

Prisms are sometimes used for the internal reflection at the surfaces rather than for dispersion. If light inside the prism hits one of the surfaces at a sufficiently steep angle, total internal reflection occurs and all of the light is reflected.

Explanation:

Prism, in optics, piece of glass or other transparent material cut with precise angles and plane faces, useful for analyzing and reflecting light. An ordinary triangular prism can separate white light into its constituent colours, called a spectrum.

CaO + 2H2O + Ca(OH)2 is a balance chemical equation. Therefore, option A is correct.

A balanced chemical equation is one that has the same number of atoms of each type in the reaction on both the reactant and product sides. In a balanced chemical equation, both the mass and the change are equal.

When a chemical reaction occurs, the mass of the products should be equal to the mass of the reactants, according to the law of conservation of mass. As a result, the number of atoms in each element remains constant during the chemical reaction. As a result, the chemical equation must be corrected.

The chemical equation is said to be balanced if there are no inequalities. Every element in this example now has an equal number of atoms on both the reactant and product sides.

Thus, option A is correct.

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Answer:

When dissolved in water, acids donate hydrogen ions (H+). Hydrogen ions are hydrogen atoms that have lost an electron and now have just a proton, giving them a positive electrical charge. Bases, on the other hand, mixed with water yield hydroxide ions (OH-). If a solution has a high concentration of H+ ions, then it is acidic.

Explanation:

So b

Answer:

1.634 molL-1

Explanation:

The mol ration between NH3 and HCl is 1 : 1

Using Ca Va / Cb Vb = Na / Nb   where a = acid and b = base

Na = 1

Nb = 1

Ca = 0.208 molL-1

Cb = ?

Va = 19.64 mL

Vb = 25.00mL

Solving for Cb

Cb = Ca Va / Vb

Cb = 0.208 * 19.64 / 25.0

Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)

Using the dilution equation;

C1V1 = C2V2

Initial Concentration, C1 = ?

Initial Volume, V1 = 25.00 mL

Final Volume, V2 =  250 mL

Final Concentration, C2 = 0.1634 molL-1

Solving for C1;

C1 = C2 * V2 / V1

C1 = 0.1634 * 250 / 25.00

C1 = 1.634 molL-1

Answer: the answer is a

Explanation:

I took the test and got it wrong because someone said the answer was divergent boundary and it’s wrong. I hate them I hate them I hate them. I hate it I hate school

Transform boundary is the type of tectonic plate boundary is a volcano least likely to occur.

Transform boundary is the type of tectonic plate boundary is a volcano least likely to occur.

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Answer:

t = d/v , 33.3 ns

Explanation:

Since distance, d = vt where v = speed and t = time taken to cover the distance.

Since the distance, d covered by the alpha particle is the length of Rutherford's lab which is 10 m long and the speed of the alpha particle is v = 3 × 10⁸ m/s, the time, t it takes the alpha particle to move from the alpha particle source to the gold foil target is thus

t = d/v

= 10 m/3 × 10⁸ m/s

= 10/3 × 10⁻⁸ s

= 3.33 × 10⁻⁸ s

= 33.3 × 10⁻⁹ s

= 33.3 ns

Answer:

1.09 mL

Explanation:

Density is a measure of a substance's mass over its volume.

d = m/v

We can rearrange the equation to solve for volume, using algebra.

v = d/m

Therefore v = 6.35/5.80 = 1.09 mL

Answer: The ratio of NaCN to HCN is, 1.26

Answer:

Running water makes rock edges very dull because of erosion.

Explanation:

hope this helps  ^_^

Answer:

1.3142 mol CoCl2

Explanation:

Well, to answer this we need to find out how many grams are in a single mole of CoCl2. Two find that we need to get the molar mass of CoCl2

Co = 28.0101 g Co per mole

Cl = 35.453 * g Cl per mole

28.0101 + 2 * 35.453 = 98.9161 g CoCl2 per mole

Now, we divide:

130/98.9161 = 1.3142 mol CoCl2

There are 1.31 moles in 130grams of cobalt chloride (CoCl2). Details about how to convert mass to moles can be found below.

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass.

According to this question, there are 130g of CoCl2.

molar mass of CoCl2 = 28 + 35.5(2) = 99g/mol

moles = 130g ÷ 99g/mol

moles = 1.31 moles

Therefore, there are 1.31 moles in 130grams of cobalt chloride (CoCl2).

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Answer:

[tex]Kp2=5.3967x10^{-5}[/tex]

Explanation:

Hello there!

In this case, since the Kp for the first reaction is given, according to the following equilibrium expression:

[tex]Kp=\frac{p_D^2p_E}{p_A^2p_Bp_C^3} =18530[/tex]

However, since the second reaction stands for the reverse of the initial one, the equilibrium expression would be:

[tex]Kp_2=Kp=\frac{p_A^2p_Bp_C^3}{p_D^2p_E}[/tex]

And therefore its Kp the inverse of the aforementioned one:

[tex]Kp2=1/18530\\\\Kp2=5.3967x10^{-5}[/tex]

Best regards!

Answer:

naturalistic

Explanation:

Answer:

C

Explanation:

When a line segment and a plane intersect, they intersect at a point. They both coincide on point C

Answer:

1. a body of air with horizontally uniform temperature, humidity, and pressure.

2. Boundaries between unlike air masses. Air masses have fairly uniform temperature and moisture content in horizontal direction (but not uniform in vertical). Air masses are characterized by their temperature and humidity properties.

3. Air masses have fairly uniform temperature and moisture content in horizontal direction (but not uniform in vertical). Air masses are characterized by their temperature and humidity properties.

4. Continental air masses are characterized by dry air near the surface while maritime air masses are moist. Polar air masses are characterized by cold air near the surface while tropical air masses are warm or hot.

5. Continental air masses form over land and are dry. Therefore, an air mass that develops over northern Canada is called a continental polar air mass and is cold and dry. One that forms over the Indian Ocean is called a maritime tropical air mass and is warm and humid.

6. an air mass that develops over northern Canada is called a continental polar air mass and is cold and dry.

7. Commonly, when the cold front is passing, winds become gusty; there is a sudden drop in temperature, and heavy rain, sometimes with hail, thunder, and lightning.

8. stormy

9. The symbol that is used to identify a cold front on a weather map is a blue line with triangles that point in the direction in which the cold front is moving. The line is represents the leading edge of the cooler air mass.

10. The symbol that is used to identify a cold front on a weather map is a blue line with triangles that point in the direction in which the cold front is moving. The line is represents the leading edge of the cooler air mass

11. Because a stationary front marks the boundary between two air masses, there are often differences in air temperature and wind on opposite sides of it. The weather is often cloudy along a stationary front, and rain or snow often falls, especially if the front is in an area of low atmospheric pressure.

12. At an occluded front, the cold air mass from the cold front meets the cool air that was ahead of the warm front. The warm air rises as these air masses come together. Occluded fronts usually form around areas of low atmospheric pressure.

13. The temperature drops as the warm air mass is occluded, or “cut off,” from the ground and pushed upward. Such fronts can bring strong winds and heavy precipitation. Occluded fronts usually form around mature low pressure areas.

14.An occluded front is a combination of those two signs. They are indicated on a weather map either by a purple line with alternating semicircles and triangles pointing in direction of travel, or by red semicircles and blue triangles pointing in the same direction.

Explanation:

:)

Answer:

Heya

Explanation:

1) air mass:- An air mass is a large volume of air in the atmosphere that is mostly uniform in temperature and moisture.

2) Air masses are characterized by their temperature and humidity properties.

3) ( same answer i.e. temperature and humidity properties).

4) Colder air masses are termed polar or arctic, while warmer air masses are deemed tropical. Continental and superior air masses are dry while maritime and monsoon air masses are moist. Weather fronts separate air masses with different density (temperature or moisture) characteristics.

5) Continental air masses are characterized by dry air near the surface while maritime air masses are moist. Polar air masses are characterized by cold air near the surface while tropical air masses are warm or hot. Arctic air masses are extremely cold.

6) Maritime air masses form over water and are humid. Continental air masses form over land and are dry. Therefore, an air mass that develops over northern Canada is called a continental polar air mass and is cold and dry.

7) Commonly, when the cold front is passing, winds become gusty; there is a sudden drop in temperature, and heavy rain, sometimes with hail, thunder, and lightning. Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds and thunderstorms.

8) Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface.

9) The symbol that is used to identify a warm front on a weather map is a red line with half circles that point in the direction in which the warm front is moving. The line represents the leading edge of the warmer air mass.

10) On weather maps, the surface position of the cold front is marked with the symbol of a blue line of triangles/spikes (pips) pointing in the direction of travel.

11) Because a stationary front marks the boundary between two air masses, there are often differences in air temperature and wind on opposite sides of it. The weather is often cloudy along a stationary front, and rain or snow often falls, especially if the front is in an area of low atmospheric pressure.

12)At an occluded front, the cold air mass from the cold front meets the cool air that was ahead of the warm front. The warm air rises as these air masses come together. Occluded fronts usually form around areas of low atmospheric pressure.

13) The warm air mass rises as the cool air masses push and meet in the middle. The temperature drops as the warm air mass is occluded, or “cut off,” from the ground and pushed upward. Such fronts can bring strong winds and heavy precipitation. Occluded fronts usually form around mature low pressure areas.

14)Occluded fronts are drawn as a solid purple line with half circles and triangles pointing in the direction that the front is moving. An occluded front usually brings dry air.

[tex] \underline \blue{ \fbox{check \: the \: attachment \: too \: :) }}[/tex]

Answer:

Water is unique because of our need to survive on something so simple. It is just 2 hydrogen atoms and an oxygen. so simple, but necessary for all of our lives. Just 3-4 minutes without it causes permanent damage

Answer:

b. d. f. h

Explanation:

Anions are negatively charged. They are usually non metals with few exceptions. They need to gain electrons in order to form and they are always listed after cation in a compound.