Decide which element probably forms a compound with oxygen that has a chemical formula most and least similar to the chemical formula of the compound formed by oxygen and barium.

High pressure and low temperature.

Answer:

Velocity

Explanation:

it is the rate of displacement over time in a SPECIFIED DIRECTION i.e it has both magnitude and direction

Answer:

In an equilibrium mixture of the three gases, PCO = PCl2 = 2.22 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is kp=(COCl2)/(CO)(Cl2) which is . So, the correct answer is 7.34.

Answer:

(a) [tex]BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)[/tex]

(b) The particles of the formed barium sulfate remain suspended in the aqueous media forming a colloid.

Explanation:

Hello,

In this case, when solutions of barium chloride and sodium sulfate are mixed, the following chemical reaction is carried out:

[tex]BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)[/tex]

Thus, we can notice that the product barium sulfate remains solid since its solubility in aqueous media is very low, for that reason at the beginning the solution becomes cloudy as its particles remain suspended in the water forming a colloid. Nevertheless, after some days, the suspended particles get precipitated by the effect of the gravity, therefore, we observe the solid on the bottom of the beaker.

Regards.

Answer:

Group 12

Explanation:

Group 12 transition metals include; zinc cadmium, mercury and copernicium. Because of their striking difference in property when compared to other transition elements, they are sometimes called post-transition elements.

These elements possess completely filled ns and nd orbitals hence they are diamagnetic. They have the lowest melting points and densities among all transition metals. Their densities in gcm^-3 are; Zn (7.14), Cd(8.65) and Hg (13.5). We can see that unlike other transition metal groups, their densities vary only within a narrow margin hence they have properties slightly different from other transition elements.

Answer:

Even all compounds are neutral.

Explanation:

Some of them exhibit polarity. Because of the difference in electron affinity of the constituent atoms, the shared electrons are pulled towards the atom with high affinity to electrons.

Answer:

C3H5NO2

Explanation:

C = 41.37%;

H = 5.75% ;

N= 16.09 %;

O= (100 - 41.37 - 5.75 - 16.09)% = 36.79 %.

In 100 g of substance we have

C = 41.37 g;

H = 5.75 g ;

N= 16.09 g;

O = 36.79 g.

Molar mass (C) = 12 g/mol;

Molar mass(H) =1 g/mol;

Molar mass(N)= 14 g/mol;

Molar mass(O) = 16 g/mol.

C = 41.37 g* 1 mol/12g = 3.4475 mol;

H = 5.75 g *1 mol/1g = 5.75 mol;

N= 16.09 g*1mol/14g = 1.1493 mol;

O = 36.79 g* 1mol/16g = 2.2994 mol.

The Empirical formula shows ratio of moles of elements in the substance , so

C : H : N : O = 3.4475 mol : 5.75 mol : 1.1493 mol : 2.2994 mol =

= (3.4475 mol /1.1493 mol) : (5.75 mol/1.1493 mol) : (1.1493 mol /1.1493 mol) :   :( 2.2994 mol/1.1493 mol) = 3 : 5 : 1 : 2

C : H : N : O = 3 : 5 : 1 : 2

C3H5NO2

Answer:

B) decay at a constant rate

Explanation:

Over their lifetime, the radioactive elements tend to have constant rate of decay. This is seen in chemistry in Kinetics, where we see that radioactive elements follow first order kinetics where the rate at which they decay is constant (no matter what concentration we have)

Answer:

B) decay at a constant rate

Explanation:

just took the test

Answer:

Sulfur dioxide + 2 ( water ) -----> sulfurous acid + water /

SO2 + 2 ( H2O ) -----> H2SO3 + H2O

Explanation:

This formula may not be right. Sulfur dioxide tends to react with water to produce sulfurous acid as per it's formula, but then again that chemical reaction need not be balanced. However, I will solve for either case here -

Sulfur dioxide + water -----> sulfurous acid,

Sulfur dioxide + water -----> sulfurous acid + water

_______________________________________________________

As I mentioned before, Sulfur dioxide + water -----> sulfurous acid is a chemical reaction that need not balancing as the number of each element present on the reactant and product side are the same. To help, let me rewrite this reaction -

SO2 + H2O -----> H2SO3,

Reactant                  |                Product

Sulfur = 1,                                  Sulfur = 1,

Oxygen = 3,                              Oxygen = 3,

Hydrogen = 2                           Hydrogen = 2

And hence the equation is already balanced. Now let us consider the case we supposedly have at hand - Sulfur dioxide + water -----> sulfurous acid + water. Take a look at the attachment below;

Answer:

The 2 different combinations are given in the attached figure. The 2nd combination has a higher yield due to less hindrance by the alkyl halide.

Explanation:

The first reaction is between an alkyl halide and metal alkoxide. In this case, the alkyl chloride would be a secondary component and thus will cause greater hindrance to the yield.  The reaction is as given in the attached figure

The second reaction is between a benzene ring containing halide and metal alkoxide. Now as the reaction is via alkyl chloride being the primary agent, there is less hindrance and thus greater yield in this case.

Answer:

the activation energy Ea = 179.176 kJ/mol

it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

[tex]T_1 = 100^0 C = 100+273 = 373 \ K \\ \\ T_2 = 113^0 C = 113 + 273 = 386 \ K[/tex]

[tex]R_1 = \dfrac{1}{7}[/tex]

[tex]R_2 = \dfrac{1}{49}[/tex]

Thus; [tex]\dfrac{R_2}{R_1} = 7[/tex]

Because at 113.0°C; the rate is 7 time higher than at 100°C

Hence:

[tex]In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})[/tex]

1.9459 = [tex]\dfrac{Ea}{8.314}* 9.0292 *10^{-5}[/tex]

[tex]1.9459*8.314 = Ea * 9.0292*10^{-5}[/tex]

[tex]16.1782126= Ea * 9.0292*10^{-5}[/tex]

[tex]Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}[/tex]

Ea = 179.176 kJ/mol

Thus; the activation energy Ea = 179.176 kJ/mol

b)

here;

[tex]T_2 = 386 \ K \\ \\T_1 = (89.8 + 273)K = 362.8 \ K[/tex]

[tex]In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})[/tex]

[tex]In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})[/tex]

[tex]In (\dfrac{R_2}{R_1}) = 0.00357[/tex]

[tex]\dfrac{R_2}{R_1}= e^{0.00357}[/tex]

[tex]\dfrac{R_2}{R_1}= 1.0035[/tex]

where ;

[tex]R_2 = \dfrac{1}7{}[/tex]

[tex]R_1 = \dfrac{1}{t}[/tex]

Now;

[tex]\dfrac{t}{7}= 1.0035[/tex]

t = 7.0245 mins

Therefore; it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

a). The activation energy given by the reactions related to the cooking of food in the pressure cooker would be:

[tex]Ea = 179.176 kJ/mol[/tex]

b). The time duration that is taken by the same food to cook in an open vessel would be:

[tex]7.0245 mins[/tex]

a). Given that,

Temperature [tex]1[/tex]  [tex]= 100[/tex]° C

Temperature [tex]2[/tex] [tex]= 113[/tex]° C

In Kelvin,

Temperature  [tex]1[/tex] [tex]= 100 + 273[/tex]

[tex]= 373 K[/tex]

Temperature  [tex]2[/tex] [tex]= 113 + 273[/tex]

[tex]= 386 K[/tex]

[tex]R_{1} = 1/7\\R_{2} = 1/49[/tex]

∵ [tex]R_{2}/R_{1} = 49/7 = 7[/tex]

It is given that at  [tex]113[/tex] rate [tex]=[/tex] [tex]7[/tex] × [tex]100[/tex]°C

Therefore,

[tex]Ea/8.314 (1/373 - 1/386) =[/tex] [tex]In(7)[/tex]

so,

[tex]Ea[/tex] [tex]= 16.1782126/(9.0292 * 10^{-5})[/tex]

∵ Activation energy [tex]= 179.176 kJ/mol[/tex]

b). As we know,

[tex]T_{2}[/tex] [tex]= 386 K[/tex]

[tex]T_{1}[/tex] [tex]= (89. 8 + 273)[/tex]

[tex]= 362.8 K[/tex]

by employing the formulae,

[tex]In(\frac{R_{2} }{R_{1} }) = \frac{Ea}{R} (1/T_{1} - 1/T_{2})[/tex]

[tex]In(\frac{R_{2} }{R_{1} }) = 179.176/8.314 (1/362.8 - 1/386)[/tex]

By solving this, we get

[tex]R_{2}/R_{1} = 1.0035[/tex]

Thus,

[tex]R_{2} = 1/7[/tex]

[tex]R_{1} = 1/t[/tex]

∵ t [tex]= 7.0245 min[/tex]

Thus, the time duration would be [tex]7.0245 minutes[/tex].

Learn more about "Boiling Point" here:

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Answer:

10.8 mm

Explanation:

Step 1: Calculate the volume (V) of the copper cylinder

The cylinder has a mass of 94.6754 g and a density of 8.96 g/cm³. The volume of the cylinder is:

[tex]94.6754 g \times \frac{1cm^{3} }{8.96g} = 10.6 cm^{3}[/tex]

Step 2: Calculate the length (h) of the copper cylinder

The diameter (d) of the copper cylinder is 3.52 cm. We can calculate the length using the following expression.

[tex]V = \pi \times (\frac{d}{2})^{2} \times h\\h = \frac{4V}{\pi \times d^{2} } = \frac{4(10.6cm^{3} )}{\pi \times (3.52cm)^{2} } = 1.08 cm[/tex]

Step 3: Convert the length to millimeters

We will use the relationship 1 cm = 10 mm.

[tex]1.08cm \times \frac{10mm}{1cm} = 10.8 mm[/tex]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: [tex]\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }[/tex]

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

[tex]56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm[/tex]

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

[tex]P_{2} =\frac{T_{2} P_{1} }{T_{1} }[/tex]

[tex]P_{2}=\frac{(337K)(0.55atm)}{418K}[/tex]

P₂=0.44 atm

Answer:

[tex][Ar] 3d^{2} 4s^{2}[/tex]

Explanation:

You can look at the periodic table and figure out the electron config.

Answer:

See below

Explanation:

* Burning fire wood is given to be our first option. Now burning tends to be a property of wood, and it does effect the chemical compositions of it. Wood, in the presence of fire / oxygen, turns into ash and carbon dioxide.

* Decomposition is recognized as a chemical change, and heating copper carbonate is a perfect example of decomposition. When energy is added to this chemical process, the copper carbonate decomposes into copper oxide.

* Mixing sodium chloride solution and silver nitrate solution. When this reaction takes place, a white precipitate of AgCl is formed. And of course, this is a chemical reaction.

* When acids or bases come in contact with citric acid, the pH degree changes much. Due to this, carbon dioxide bubbles are formed.

* When eggs are fried they absorb the heat in the pan. Doing so the egg starts to curl a bit, resulting in the formation of new particles.

_______________________________________________________

I hope this gave you a start!

Answer:

A. A + B + C --> D

Explanation:

Step 1: A + B --> X (fast)

Step 2: X + C --> Y (slow)

Step 3: Y --> D (fast)

To obtain the overall reaction, we have to sum up the reactants and products of all step and eliminate the intermediates.

Reactants:

A + B + X + C + Y

Products:

X + Y + D

So we have;

A + B + X + C + Y  --> X + Y + D

Upon elimination of intermediates, we have;

A + B + C --> D

The correct option is A.

Answer:

Yes, there is a limit to the size of atoms that scientists can make.

Explanation:

In the nucleus, atoms contain protons and neutrons. It is known that as the number of protons in the nucleus increases, the atom becomes unstable due to the repulsion of positively charged protons clumped together in the small space of the nucleus.

However, an attractive force exists between neutrons and protons which binds the nucleus together and minimizes repulsion between protons. Even neutrons have recently been found to slightly repel each other.

Several attempts made at synthesizing many very heavy elements lately have proved abortive because the elements only exist for a few fractions of a second owing to large repulsion between the particles in the nucleus.

This goes a long way to show that there is a limit to the number of protons and neutrons that can be assembled together to form a new nucleus. We cannot bring an unlimited number of nucleons together to form new atoms due to inter particle repulsive forces.

Answer:

Ba(+2)(aq) + SO4(-2)(aq) -----> BaSO4(s)

Explanation:

Take a look at the attachment below;

Answer:

B. s, p, d, f

Explanation:

These things are often referred to as suborbitals and you normally have s,p,d,f.

S has 1 two orbitals

P has 3 orbitals

D has 5 orbitals

F has 7 orbitals

and each orbital can house 2 electrons

Answer:

To limit pJ changes in solution

Answer:

The gas and liquid is in equilibrium.

Explanation:

liquids within a container undergoes state change, changing into gas. If this container is left open, these gases will escape into the external environment. In a situation in which the container is closed, the molecules that leave the liquid surface as gas will eventually condense on contact with the cover wall and change back into the liquid state. Some of these gases will reenter the liquid surface. At first, more of the liquid is transformed into gas and escape into the space above the liquid surface. Eventually, the available space becomes saturated with vapor, and then some of the gases start entering the liquid phase at the same rate as the liquid enters the gas phase. At this stage, the gas and liquid phase now exists in equilibrium.

Answer:

2H⁺(aq) + + 2OH⁻(aq) → 2H₂O(l)

Explanation:

A acid that has two acidic hydrogens requires to moles of NaOH per mole of acid producing the salt of the acid and water.

If the acid is tartaric acid, H₂C₄H₄O₆, the reaction with NaOH is:

H₂C₄H₄O₆(aq) + 2NaOH(aq) → 2H₂O(l) + 2NaC₄H₄O₆(aq)

Now, ions in solution in the reaction are:

2H⁺(aq) + C₄H₄O₆²⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → 2H₂O(l) + 2Na⁺(aq) +C₄H₄O₆²⁻(aq)

Thus, net ionic equation (Lisiting only the ions involved in the reaction) is:

Answer:

C18H24O3

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass of estriol = 13.42g

Mass of CO2 = 36.86g

Mass of H2O = 10.06g

Molar mass of estriol = 288.38g/mol

Step 2:

Determination of the mass of Carbon (C), Hydrogen (H) and Oxygen (O) present in the compound. This is illustrated below:

For Carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C in CO2 = 12/44 x 36.86 = 10.05g

For Hydrogen, H:

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H in H2O = 2/18 x 10.06 = 1.12g

For Oxygen, O:

Mass of O = 13.42 – (10.05 + 1.12) = 2.25g

Step 3:

Determination of the empirical formula for estriol. This is illustrated below:

C = 10.05g

H = 1.12g

O = 2.25g

Divide by their molar mass

C = 10.05/12 = 0.8375

H = 1.12/1 = 1.12

O = 2.25/16 = 0.1406

Divide by the smallest i.e 0.1406

C = 0.8375/0.1406 = 6

H = 1.12/0.1406 = 8

O = 0.1406/0.1406 = 1

Therefore, the empirical formula for estriol is C6H8O

Step 4:

Determination of the molecular formula for estriol. This is illustrated below:

Molecular formula is simply a multiple of the empirical formula i.e

Molecular formula => [C6H8O]n

[C6H8O]n = 288.38g/mol

[(12x6) + (8x1) + 16]n = 288.38

[72 + 8 + 16]n = 288.38

96n = 288.38

Divide both side by 96

n = 288.38/96 = 3

Molecular formula => [C6H8O]n

=> [C6H8O]n

=> [C6H8O]3

=> C18H24O3

Therefore, the molecular formula for estriol is C18H24O3

The compound is C18H24O3.

From the information in the question;

Mass of C = 36.86 g/44 g/mol × 12 g/mol = 10.1 g

Number of moles of carbon = 10.1 g/12 g/mol = 0.84 moles

Mass of hydrogen = 10.06 g/18 g/mol × 2 g/mol = 1.11 g

Number of moles of hydrogen = 1.11 g/1g/mol = 1.11 moles

Mass of oxygen = 13.42 - (10.1 g + 1.11 g) = 2.21 g

Number of moles of oxygen = 2.21g/16 g/mol = 0.14 moles

Dividing through by the lowest number of moles;

C - 0.84 moles/0.14 moles   H -  1.11 moles/0.14 moles   O - 0.14 moles/0.14 moles

C - 6   H - 8    O -1

The empirical formula is C6H8O

The molecular formula of the compound is;

[6(12) + 8(1) + 16]n = 288.38

n =  288.38/86 =3

The compound is C18H24O3

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Explanation:

8H+(aq) + MnO4-(aq) + 5Fe2+(aq) → Mn2+(aq) + 5Fe3+(aq) + 4H2O(l)

To determine if a substance was reduced or oxidized, the oxidation number at the reactant and product side is compared.

When oxidation occurs, an element loses electrons and its oxidation number increases (becomes more positive). When reduction occurs, an element gains electrons and its oxidation number decreases or is reduced (becomes more negative).

H+ (oxidized or reduced) Answer 1 Choose...

There is an increase in oxidation number from 0 to 1. This means H+ was oxidized.

MnO4- (oxidizing or reducing agent) Answer 2 Choose...

In chemistry, an oxidizing agent is a substance that has the ability to oxidize other substances — in other words to accept their electrons

MnO4- is a strong oxidizing agent.

Fe2+ (oxidizing or reducing agent) Answer 3 Choose...

A reducing agent means it will itself get oxidized. In  this reaction, Fe2+ is the reducing agent.

Fe2+ (oxidized or reduced) Answer 4 Choose...

Oxidized

O in MnO4- (oxidized or reduced) Answer 5 Choose...

There is no change in oxidation number of , so it was neither reduced nor was it oxidized.

Mn in MnO4- (oxidized or reduced) Answer 6 Choose...

There is a decreaase in oxidation number from +7 to +2. This means reduction.

Answer:

The play will be more  appealing to a younger audience.

Explanation:

A younger audience will more likely appreciate current pop hits rather than classical score.

Answer:

B. The play will be more appealing to a younger audience.

Explanation:

If the audience is younger, then this would be more appealing to them because pop has always been one of the fan-favorties of younger generations

Answer:

The final volume [tex]V2=1.3175L[/tex]

Explanation:

between work ( w), pressure ( P ) and volume ( V ) is the following:

w=−PΔV

where,

ΔV=V2−V1

It was stated that the gas is expanding, then the work is done by the system and it is of a negative value .

Note that work, should be expressed in 1L⋅atm=101.3J

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

Answer:

At 415.2nm and 519.6nm, the dyes observed by the instrument are violet and green respectively.

Explanation:

In the electromagentic spectrum, visible wavelengths cover a range from approximately 400 to 800 nm. The colours of the spectrum range from red to violet (Red, Orange, Yellow, Green, Blue, Indigo and violet: a.k.a ROGBIV), in order of decreasing wavelength.

I hope this explanation would suffice.

Answer: The change in internal energy of the gas is +408 J

Explanation:

According to first law of thermodynamics:

[tex]\Delta E=q+w[/tex]

[tex]\Delta E[/tex] =Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system= [tex]-P\Delta V[/tex]

As volume is constant , [tex]\Delta V[/tex] = 0 and w = 0.

q = +408J   {Heat absorbed by the system is positive}

[tex]\Delta E=+408J+(0J)=+408J[/tex]

Thus the change in internal energy of the gas is +408 J