Consider a day in the physics lab room with room temperature of 20 0C and pressure of 1.0 atm. A container of 3.5 L is left open to the air for a long time. The container is then sealed and place on a Bunsen burner until its temperature reaches 95 0C. It is then open. How many moles of air escape?

Answers

Answer 1

Answer:

The number of moles of air that escape is approximately 0.027 moles

Explanation:

The room temperature, T₁ = 20 °C = 298.15 K

Atmospheric pressure, P₁ = 1.0 atm

The volume of the container, V₁ = 3.5 L

The final temperature of the air in the container after heating on the Bunsen burner, T₂ = 95 °C = 368.15 K

The container opened finally

The ideal gas equation is P·V = n·R·T

∴ n = P·V/(R·T)

Where;

R = The universal gas constant = 0.08205 L·atm/(mol·K)

Therefore, we get;

n₁ = 1.0 × 3.5/(0.08205 × 298.15) ≈ 0.143

The number of moles, n₁ ≈ 0.143 moles

When the gas is heated to 95 °C, the number of moles becomes

n₂ =  P₂·V₂/(R·T₂)

P₂ = 1.0 atm atmospheric pressure, V₂ = 3.5 L, the volume of the container, T₂ =

∴ n₂ = 1.0 × 3.5/(0.08205 × 368.15) ≈ 0.116

The number of moles of air remaining in the container, n₂ ≈ 0.116 moles

The number of moles of air that escape, n = n₁ - n₂

∴ n = 0.143 - 0.116 = 0.027

The number of moles of air that escape, n ≈ 0.027 moles


Related Questions

A student uses 80 joules of energy to lift a backpack in a time of 0.75 seconds. How much power
does the student have?

Answers

Answer:

P = 106.7 W

Explanation:

Given that,

Work done in lifting a backpack, W = 80 J

It is lifted in 0.75 seconds

We need to find the power of the student. The power of an object is defined as work done per unit time. So,

[tex]P=\dfrac{W}{t}[/tex]

Put all the values,

[tex]P=\dfrac{80}{0.75}\\\\P=106.7\ W[/tex]

So, the power of the student is 106.7 W.

a sample contains 110 g of a radioactive isotope. how much radioactive isotope will remain in the sample after 1 half-life?

a. 100g
b. 25 g
c. 75 g
d. 50 g

Answers

Answer:

The half-life of a radioactive isotope is the time such that the initial amount of the isotope is reduced to its half.

Thus, if we start with A grams of a given radioactive isotope, after a 1 half-life, we will have A/2 grams of the radioactive isotope.

In this case, we know that the sample has 110g of a radioactive isotope.

Then, after 1 half-life, we should have half of 110g, which is:

110g/2 = 55g

Then we should have 55 g of a radioactive isotope.

The answer that is closer to this result is option d (50 g), so that is the correct one.

The upper layer of soil consisting of rock particles, water, air, and organic matter is the​

Answers

Answer: Bedrock

Explanation:

Bedrock is the solid layer of rock beneath the soil. Soil is a mixture of rock particles, minerals, decayed organic material, air, and water. The decayed organic material in soil is humus, a dark-colored substance that forms as plant and animal remains decay.

A projectile is launched from the ground with an initial velocity of 12ms at an angle of 30° above the horizontal. The projectile lands on a hill 7.5m away. The height at which the projectile lands is most nearly

A- 1.78m
B- 3.10m
C- 5.34m
D- 6.68m
E- 12.0m

Answers

Answer:

A. 1.78 m

Explanation:

Given;

initial velocity of the, u = 12 m/s

angle of projection, θ =  30°

the range of the projectile, R = 7.5 m

To obtain the height through which the projectile lands, we must calculate the maximum height reached by the projectile.

[tex]H = \frac{u^2\ sin^2\theta}{2g} \\\\H = \frac{(12)^2\times (sin(30))^2}{2 \times 9.8} \\\\H = \frac{144 \times (0.5)^2}{19.6} \\\\H = 1.84 \ m[/tex]

Therefore, the height is most nearly 1.78 m


How many beats per second are heard when two vibrating tuning forks having
frequencies of 342 Hz and 345 Hz are held side by side?
5 Hz
3 H2
343.5 HZ
687 Hz

Answers

Answer: b.) 3 hertz

explanaition: you subtract 345 from 342

mechanical energy is two types ??​​​​​​​​​

Answers

Answer:

Yes Kinetic and Potential energy

Yup kenitkick and potatoes wnergy

A proton is released from rest in a uniform E – Field 8 x 104V/m directed alomg + ve x – axis, undergoes a displacement of 0. 5m in direction of field. Find: a) Change of potential for this displacement (A =» B)? B) Change of P.E for this displacement (A =» B)? C) The speed of proton after the displacement?

Answers

Answer:

a. -40 kV b. -6.408 fJ c. 2.77 × 10⁶ m/s

Explanation:

a) Change of potential for this displacement (A =» B)?

The potential energy change ΔV = -EΔx where E = electric field strength = 8 × 10⁴ V/m and Δx = displacement of charge = 0.5 m

So, ΔV = -EΔx

ΔV = -8 × 10⁴ V/m × 0.5 m

ΔV = -4 × 10⁴ V

ΔV = -40 × 10³ V

ΔV = -40 kV

B) Change of P.E for this displacement (A =» B)?

The change in potential energy ΔU = qΔV where q = proton charge = +1.602 × 10⁻¹⁹ C and ΔV = change in potential = -4 × 10⁴ V

So, ΔU = qΔV

ΔU = +1.602 × 10⁻¹⁹ C × -4 × 10⁴ V

ΔU = -6.408 × 10⁻¹⁵ J

ΔU = -6.408 fJ

C) The speed of proton after the displacement?

From the conservation of energy,

The electric potential energy change of the charge equals its kinetic energy change

ΔK + ΔU = 0

ΔK = -ΔU

ΔK = -(-6.408 × 10⁻¹⁵ J)

K₂ - K₁ = 6.408 × 10⁻¹⁵ J

where K₁ = initial kinetic energy of proton = 0 J (since it starts from rest)

K₂ = final kinetic energy of proton = 1/2mv² where m = mass of proton = 1.673 × 10⁻²⁷ kg and v = speed of proton

K₂ - K₁ = 6.408 × 10⁻¹⁵ J

1/2mv² - 0 = 6.408 × 10⁻¹⁵ J

1/2mv² = 6.408 × 10⁻¹⁵ J

v² = 2(6.408 × 10⁻¹⁵ J)/m

v = √[12.816 × 10⁻¹⁵ J)/1.673 × 10⁻²⁷ kg]

v = √[7.66 × 10¹² J/kg]

v = 2.77 × 10⁶ m/s

Object A and Object B have the same volume of 10 cm³. Object A has a mass of 20 grams. Object B has a mass of 50 grams. Which object will have the greater density and why?​

Answers

Answer:

Object B has greater density

desity A=20/10=2 g cm^-3 . density B=50/10=5 g cm^-3

the object that has greater mass has the greater density because the volume of the those two objects are same

If a person displaces a mass of
60kg through 300 metres in 1
Minute, what is the power?
?​

Answers

Answer:

Power = 2940 Watts

Explanation:

Given the following data;

Mass = 60 kg

Height = 300 meters

Time = 1 minutes = 60 seconds

To find the power;

First of all, we would determine the potential energy possessed by the person due to height.

We know that acceleration due to gravity is equal to 9.8 m/s².

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

[tex] P.E = mgh[/tex]

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

P.E = 60 * 9.8 * 300

P.E = 176400

Next, we find the power using the following formula;

Power = energy/time

Power = 176400/60

Power = 2940 Watts

Fossil's are the remains of ancient plants and animals which type of rock do you think is mostly likely to contain fossils?

Answers

Answer:

Sedimentary rocks.

Explanation:

A rock cycle can be defined as a concept used to describe the continuous process that leads to a rock's creation, formation, transformation from one form to another, destruction and reformation over a specific period of time. The natural phenomenons that influences the rock cycle are weathering, plate tectonic activity, erosion, etc.

A fossil can be defined as the mineral impression or remains of living organisms such as plants and animals that are prehistoric in nature.

Basically, the three (3) main types of rocks are; igneous rock, sedimentary rock and metamorphic rock.

Sediments come from living organisms such as plants to form organic sedimentary rocks and they are usually formed at pressure and temperature that doesn't destroy the fossils contained therein. Organic sedimentary rocks includes chalk, fossiliferous, coal, diatomite, etc. Also, some examples of inorganic land-derived sedimentary rocks are conglomerate, brescia and sandstone.

Hence, an organic sedimentary rock is a type of rock that contains or comprises of fossils.

Thom reads an article on the internet that that claims some lakes on Saturn are contain frozen methane. He reads that there is methane on Neptune, too. Which sentence best describes data that would suggest methane is frozen on Neptune?

a
Neptune's atmosphere has more methane than Saturn's.
b
Neptune's mass is less than Saturn's.
c
Neptune's surface temperature is colder than Saturn's.
d
Neptune's distance from the Sun is greater than Saturn's.

Answers

Answer: Neptune's distance from the Sun is greater than Saturn's.

Explanation:

The sentence that best describes data that would suggest methane is frozen on Neptune is that Neptune's distance from the Sun is greater than Saturn's.

Since Neptune is farther away from the Sun than Saturn, it implies that it has a colder temperature than Saturn and thus would suggest that methane is frozen on Neptune.

Which of these scenarios describes circular motion?
es )
A)
The moon orbiting the Earth
B)
A cannonball flying from a cannon
C)
A car moving along a straight track
D)
The pendulum of a grandfather clock

Answers

A)

The moon orbiting the Earth

See the picture and Anwser This

Answers

Answer:

20 m/s

Explanation:

Look at the time on the x-axis. Go up from 2 seconds until you reach a point. From that point go to the left and read from the y-axis.

In the eastern US, hurricanesusually form over the warm waters of the Caribbean Sea and travel north. When they are over the cold waters of the North Atlantic Ocean, would they become more powerful or less powerful than they were when they were over the warm Caribbean? Explain why.



please answer no files links answer ASAP please

Answers

Answer:

Less powerful

Explanation:

Hurricanes rely on warm water. It sucks heat energy from the water to use for fuel. Warmer water means more moisture, which also mean a bigger and/or stronger hurricane. The North Atlantic is definitely much colder than the Caribbean so the hurricane will not have much fuel.

Have a great day!

why stationary magnet inside a coil does not induce a electric current​

Answers

When the magnet moves closer to the coil the flux rapidly increases until the magnet is inside the coil. It can’t be induced because the flux through the coil is not changing.

What is the product of an oxidation reaction?
Ozone
Oxygen
Oxide

Answers

Answer:

Oxide

Explanation:

Ozone and oxygen are oxidising agents

[tex]O _{3} \: \: ozone \\ \\ O _{2} \: \: oxygen[/tex]

Answer:

Oxygen

Explanation:

The name oxidation actually originates from the word oxygen so the question answers it's self.

In case you don't know what oxidation is:

Oxidation occurs when an atom, molecule, or ion loses one or more electrons in a chemical reaction. When oxidation occurs, the oxidation state of the chemical species increases. Oxidation doesn't necessarily involve oxygen! Originally, the term was used when oxygen caused electron loss in a reaction.

Have a great day <3

Uniformly charged ring with 180 nC/m and radius R= 58 cm. Find the magnitude of the electric field in KN/C at a point P on the axis of the ring at distance 116 cm from its center.

Answers

Answer:

3.135 kN/C

Explanation:

The electric field on the axis of a charged ring with radius R and distance z from the axis is E = qz/{4πε₀[√(z² + R²)]³}

Given that R = 58 cm = 0.58 m, z = 116 cm = 1.16m, q = total charge on ring = λl where λ = charge density on ring = 180 nC/m = 180 × 10⁻⁹ C/m and l = length of ring = 2πR. So q = λl = λ2πR = 180 × 10⁻⁹ C/m × 2π(0.58 m) = 208.8π × 10⁻⁹ C and ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m

So, E = qz/{4πε₀[√(z² + R²)]³}

E = 208.8π × 10⁻⁹ C × 1.16 m/{4π8.854 × 10⁻¹² F/m[√((1.16 m)² + (0.58 m)²)]³}

E = 242.208 × 10⁻⁹ Cm/{35.416 × 10⁻¹² F/m[√(1.3456 m² + 0.3364 m²)]³}

E = 242.208 × 10⁻⁹ Cm/35.416 × 10⁻¹² F/m[√(1.682 m²)]³}

E = 6.839 × 10³ Cm²/[1.297 m]³F

E = 6.839 × 10³ Cm²/2.182 m³F

E = 3.135 × 10³ V/m

E = 3.135 × 10³ N/C

E = 3.135 kN/C

The power of crane is 30000 watt. What work will be done by it in 10 sec? ​

Answers

Explanation:

power =work done/time

work=power ×time

work =30000×10

work =300000j

stay safe healthy and happy.

How many tons of paper did Americans recycle in 2018? _______________. Show your work below:

Answers

Answer:

46 million tons

Explanation:

i dont know what im suppose to explain

The half‐life of Uranium‐237 is 5.83 x 10^5 seconds. What is the decay constant?

Answers

Answer:

λ = 1.19 x 10⁻⁶

Explanation:

The relationship between the half-life of an element and the decay constant of that element is given by the following formula:

[tex]T_{1/2} = \frac{0.693}{\lambda} \\\\\lambda = \frac{0.693}{T_{1/2}}[/tex]

where,

[tex]T_{1/2}[/tex] = half-life = 5.83 x 10⁵ s

λ = decay constant = ?

[tex]\lambda = \frac{0.693}{5.83\ x\ 10^5\ s}[/tex]

λ = 1.19 x 10⁻⁶

If Nitrogen gains three electrons, what will its charge be? *

Answers

Answer:

It's change will form the nitride ion

state and explain any effect on sensitivity of liquid in a glass thermometer (i) reducing the diameter of capillary tube​

Answers

Answer:

please give me brainlist and follow

Explanation:

The measuring sensitivity of liquid-in-glass thermometers increases with the amount of liquid in the thermometer. The more liquid there is, the more liquid will expand and rise in the glass tube. For this reason, liquid thermometers have a reservoir to increase the amount of liquid in the thermometer.

Help please!!


What are the three criteria that determine if a wave is a sound wave?

Answers

Answer:

Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed.

Explanation:

Sound wave can be described by five characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed. The minimum distance in which a sound wave repeats itself is called its wavelength. That is it is the length of one complete wave

Answer: Sound wave can be described by five characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed.

Explanation:

The minimum distance in which a sound wave repeats itself is called its wavelength. That is it is the length of one complete wave.

(c) Another spring has a spring constant of 250 N/m.
Calculate the work done in stretching the spring by 0.30 m.
State the unit.
Use the equation
E = 12 x K x x2

Answers

It is E=something which leases another something equaling another something

Can anyone answer this its a science question NO LINKS!!!

Answers

Answer:

The correct answer is C I took the mastery test

Explanation:

Answer:

d last one

Explanation:

For every 120 joules of energy input a car wastes 85 joules , find the useful energy output of the car ?

Answers

Answer:

35 Joules

Explanation:

Applying

Input Energy(Q) = Useful energy output(U)+Wasted Energy(W)

Q = U+W.............................. Equation 1

Make U the subject of the equation

U = Q-W................... Equation 2

From the question,

Given: Q = 120 Joules, W = 85 Joules

Substitute these values into equation 2

U = 120-85

U = 35 Joules

Conservation of Matter states that the reactants have to equal the _______.
A.products B.enablers

2. Products and reactants in a balanced chemical reaction have the same number of _______ of each element.
A.atoms B.molecules

3. If the equation on the board had shown 3 atoms of carbon on the reactants side, how many atoms of carbon would need to be represented on the products side?
A.2 B.3

Answers

Answer:

1. A. Products

2. A. Atoms

3. B. (3)

Explanation:

1. Conservation of Matter states that the reactants have to equal the products.

2. Products and reactants in a balanced chemical reaction have the same number of atoms of each element.

3. Three (3) atoms of carbon would need to be represented.

Number of atoms on the left and on the right side of the balanced chemical reaction is the same, for example: Mg + 2HCl → H₂ + MgCl₂. There are two hydrogen atoms, two chlorine atoms and one magnesium atom on both side of chemical reaction.

Which of the following items, when tested by litmus paper, would MOST LIKELY have a pH of 7?

A.
detergent

B.
distilled water

C.
ammonia

D.
lemon juice

Answers

Answer:

B- distilled water

Explanation:

What would Hubble's constant be if we found one galaxy moving away at 30,000 km/s at a distance of 600 Mpc?

Answers

Answer:

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

Explanation:

The Hubble's Constant can be found by the following formula:

[tex]v = H_o D\\\\H_o = \frac{v}{D}[/tex]

where,

H₀ = Hubble's Constant = ?

v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s

D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)

D = 18.52 x 10²⁴ m

Therefore,

[tex]H_o = \frac{3\ x\ 10^7\ m/s}{18.52\ x\ 10^{24}\ m}[/tex]

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

How would sound travel in outer space? Why would that make sense,
based on the chart below?

Answers

Explanation:

Sound does not travel at all in space. The vacuum of outer space has essentially zero air. Because sound is just vibrating air, space has no air to vibrate and therefore no sound. ... Radio is a form of electromagnetic radiation just like light and can therefore travel through the vacuum of space just fine

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