Can you help me with this question please

Answer:

The magnitude of the impulse delivered to the baseball is 7.0 Ns

Explanation:

Given;

mass of the foul ball, m = 0.14 kg

initial velocity, u = 40 m/s

final velocity, v = 30 m/s in perpendicular direction

Impulse is given as change in momentum;

initial momentum in horizontal direction, Pi = mu

Pi = 0.14 x 40 = 5.6 Ns

final momentum in perpendicular direction, Pf = mv

Pf = 0.14 x 30

Pf = 4.2 Ns

The resultant impulse is given by;

J² = 5.6² + 4.2²

J² = 49

J = √49

J = 7.0 Ns

Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns

Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.

Answer:

Nine, Brazil, Venezuela

Explanation:

Answer:

movement generates energy=heat so 50c should be it

Explanation:

hope this answer was helpful

Answer:

F' = 100 F/r²

Explanation:

The gravitational force of attraction between two objects is given by the Newton's Gravitational Formula. The Newton's Gravitational Formula is as follows:

F = Gm₁m₂/r²

where,

F = Force between objects

G = Universal Gravitational Constant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects = 10 m

Therefore,

F = Gm₁m₂/10²

Gm₁m₂ = 100F   --------------------- equation (1)

Now, we consider these objects at any distance r apart. So, the force becomes:

F' = Gm₁m₂/r²

using equation (1), we get:

F' = 100 F/r²

So, if the force (F) between objects 10 m apart is known, we can find it at any distance from the above formula.

The force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]

According to the gravitational law, the force acting on an object is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Mathematically,

[tex]P=\frac{GMm}{r^2}[/tex]

M and m are the masses

r is the distance between the masses

If the force between objects that are 10 meters apart, hence;

[tex]P=\frac{GMm}{10^2}\\P=\frac{GMm}{100}\\GMm = 100P[/tex]

To find the force between objects that are any distance apart, we will use the same formula above to have;

[tex]P'=\frac{GMm}{r^2}\\[/tex]

Substitute the result above into the expression to have:

[tex]P'=\frac{100P}{r^2}[/tex]

Hence the force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]

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Answer: Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.

Explanation:

Answer:

f= ma

Explanation:

v-u/ t

30-0/10

3m/s

maas 1500

1500*3

4500

Answer:

the war of currents is

Explanation:

The war of currents was a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s.

Answer:

a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s

Explanation:

Answer:

Non-zero digits

Explanation:

umm (ꏿ﹏ꏿ;)

Answer:

There's three rules on determining how many important quantities are in a number: Non-zero digits are always predominant. Any zeros between two significant digits are always major. The final zero or dangling zeros in the decimal segment are really only important.

I hope this answered your question, have a nice day!

Answer:

A

Explanation:

The image formed by the concave mirror is always virtual. An enlarged image is caused when the concave mirror is positioned too near to the object.

When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.

A concave mirror is a name for this sort of mirror. An enlarged and fake image is caused when the concave mirror is positioned too near to the object.

When the distance between the item and the mirror is increased, however, the size of the image decreases, and a true picture is generated.

The picture created by the concave mirror may be manipulated. The image formed by the concave mirror is always virtual.

Hence, option A is correct.

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Answer:

Explanation:

v = u + at

v is final velocity , u is initial velocity , a is acceleration and t is time .

here v = 0 , u = 13 m /s , t = 14 s

putting the values

0 = 13 + 14 a

a = 13 / 14 m /s²

= - .9286

= -  0.929 m /s²

Answer:

2.4m

Explanation:

Given parameters:

Radius of circle  = 1.65m

Acceleration  = 3.5m/s²

Unknown:

Velocity of the object = ?

Solution:

To solve this problem, we have to apply the formula of centripetal acceleration;

   Centripetal acceleration  = [tex]\frac{v^{2} }{r}[/tex]  

v is the velocity

r is the radius

   v² = centripetal acceleration x radius

 Insert parameters and solve;

     v² = 3.5 x 1.65

     v  = √5.775  = 2.4m

The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.

Given the data in the question;

Velocity; [tex]v = \ ?[/tex]

From the centripetal force equation, we use the expression for centripetal acceleration:

[tex]a_c = \frac{v^2}{r}[/tex]

Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.

We substitute our given values into the equation

[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]

Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.

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Answer:

Im going to take an educated guess and say its B.

Explanation:

A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.

When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.

Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

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Answer:

The answer is the 4th one

Explanation:

Good luck man

Answer:

The combined force of the catapult and engines is 44545.455 newtons.

Explanation:

Let suppose that platform of the aircraft carrier is horizontal, such that changes in gravitational potential energy can be neglected. In addition, effects of non-conservative forces are neglected. By using Principle of Energy Conservation and Work-Energy Theorem we find that steam catapult-jet aircraft is represented by:

[tex]K_{1}+W_{1\rightarrow 2} = K_{2}[/tex] (1)

Where:

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final translational kinetic energies of the jet fighter, measured in joules.

[tex]W_{1\rightarrow 2}[/tex] - Work done on the jet fighter due to the combined force of the catapult and engines, measured in joules.

By applying definitions of translational kinetic energy and work, we expand and simplify the equation above as follows:

[tex]F\cdot \Delta s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex]

[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot \Delta s}[/tex] (2)

Where:

[tex]F[/tex] - Combined force of the catapult and engines, measured in newtons.

[tex]m[/tex] - Mass of the jet fighter, measured in kilograms.

[tex]\Delta s[/tex] - Length of the catapult, measured in meters.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the jet aircraft, measured in meters per second.

If we know that [tex]m = 4000\,kg[/tex], [tex]v_{1} = 0\,\frac{m}{s}[/tex], [tex]v_{2} = 70\,\frac{m}{s}[/tex] and [tex]\Delta s = 220\,m[/tex], then the combined force of the catapult and engines is:

[tex]F = \frac{(4000\,kg)\cdot \left[\left(70\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (220\,m)}[/tex]

[tex]F = 44545.455\,N[/tex]

The combined force of the catapult and engines is 44545.455 newtons.

The combined force of the catapult and engines is 44,545.5 N.

The given parameters;

The combined force of the catapult and engines is determined by applying work energy theorem as shown below;

[tex]W = \Delta E\\\\Fd = \frac{1}{2}m(v^2 -u^2) \\\\220F = \frac{1}{2}(4000)(70^2 - 0^2) \ \\\\220 F = 9,800,000\\\\F = \frac{9,800,000}{220} \\\\F = 44,545.5 \ N[/tex]

Thus, the combined force of the catapult and engines is 44,545.5 N.

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Answer:

B. Metallic bonds.

AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:

Explanation:

Answer:

there's no picture

Explanation:

and what would the question be anyways?

Answer:

what is the question

Explanation:

Answer:

c

Explanation:

because whatever elements are used like gas uses water evaporation so yeah

Answer:

(A) Space between particles!

Explanation:

Solids can hold their shape because their molecules are tightly packed together!

Voltage = (current) x (resistance) (Ohm's law)

Voltage = (15 A) x (0.10 ohm)

Voltage =  1.5 volts (B)

Answer:

A mixture is when two or more substances combine physically together.

However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone.

Explanation:

We are given:

Mass of the Paint bucket (with paint) = 7000 grams

Mass of the paint bucket (without paint) = 500 grams

Volume of Paint in the Bucket = 5000 cm³

Mass of Paint in the Bucket:

To get the mass of the paint in the bucket, we will subtract the mass of the bucket from the mass of the paint bucket (with paint)

Mass of Paint = Mass of Paint bucket (with paint) - Mass of the paint Bucket (without paint)

Mass of Paint = 7000 - 500

Mass of Paint = 6500 grams

Density of the Paint:

We know that density = Mass / Volume

Density of Paint  = Mass of Paint / Volume occupied by Paint

Density of Paint = 6500/5000

Density of Paint = 1.3 grams / cm³

Answer:

The correct solution will be "12.48 in/s²".

Explanation:

The given values are:

Angular speed

= 79.0 rev/min

Time

= 3.80 seconds

Now,

⇒  [tex]Angular \ acc.=\frac{(\frac{79\times 2\times \pi}{60})}{3.8}[/tex]

                          [tex]=\frac{8.2}{3.8}[/tex]

                          [tex]=2.1 \ rad/s^2[/tex]

Tangential acceleration will be:

= [tex]Angular acc.\times radius[/tex]

= [tex]2.1\times 6.5\times 0.0254[/tex]

= [tex]0.3467 \ m/s^2[/tex]

= [tex]12.48 \ in/s^2[/tex]

Answer:

I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.

Explanation:

pls vote brainliest

Complete question:

A 16-V battery powers a series circuit that contains two lightbulbs. The voltage across the first lightbulb is 12-V.

a. What fractional part of the circuit's total energy is transformed in the first lightbulb? Simply your answer.

b. What fractional part of the circuit's total energy is transformed in the second lightbulb? Simply your answer.

Answer:

(a) Fraction of energy of the first bulb in the total energy of circuit is 3/4

(b) Fraction of energy of the second bulb in the total energy of circuit is 1/4

Explanation:

Given;

total voltage across the series circuit, [tex]V_T[/tex] = 16 V

voltage across the first light bulb, V₁ = 12 V

The voltage across the second light bulb is given by;

V₂ = [tex]V_T[/tex] - V₁

V₂ = 16 V - 12 V

V₂ = 4 V

The total power across the circuit is given by;

P = I[tex]V_T[/tex]

P = 16I

Where;

I is the constant current in the circuit

(a)

power in the first light bulb is given by;

P₁ = 12I

Fraction of this power in the total energy of circuit is given by;

[tex]\frac{P_1}{P} = \frac{12I}{16I} = \frac{3}{4}[/tex]

(b)

power in the second light bulb is given by;

P₂ = 4I

Fraction of this power in the total energy of circuit is given by;

[tex]\frac{P_2}{P} = \frac{4I}{16I} = \frac{1}{4}[/tex]

Answer:

486,750 kg*m/s

Explanation:

Momentum is mass*velocity

M = m*v

M = 8850kg*55m/s

M = 486,750 kg*m/s

The momentum of an 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway is 486750 kg m / s.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.

According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.

Given:

The mass of the truck is, m = 8850 kg,

The velocity of the truck is, v = 55 m/s,

Calculate the momentum of the truck as shown below,

Momentum = m × v

Momentum = 8850 × 55

Momentum = 486750 kg m / s

Thus, the Momentum of the truck is 486750 kg m / s.

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Answer:

2.51 m/s

Explanation:

Given that,

Angular speed of a fan, [tex]\omega=0.5\ rev/s = 3.14\ rad/s[/tex]

Length of the fan arm, r = 0.8 m

We need to find the speed of a point on the end of the fan arm at this time. Let v is the speed. It is given in terms of angular speed is given by :

[tex]v=r\omega\\\\v=0.8\times 3.14\\\\v=2.51\ m/s[/tex]

So, the required speed is 2.51 m/s.