Can someone please help, ty!!
(Will mark brainliest)

Answer:

3 hours

Explanation:

180 divided by 60 (mph means miles per hours by the way)

Answer:

The height at point of release is 10.20 m

Explanation:

Given:

Spring constant : K= 5 x 10 to the 3rd power n/m

compression x = 0.10 m

Mass of block m= 0.250 kg

Here spring potential energy converted into potential energy,

mgh = 1/2 kx to the 2 power

For finding at what height it rise,

0.250 x 9.8 x h = 1/2 x 5 x 10 to the 3 power x (0.10)to the 2 power) - ( g= 9.8 m/8 to the 2 power

h= 10.20

Therefore, the height at point of release is 10.20 m

Answer:

I believe the answer is specific gravity

Explanation:Hope this helps :)

Answer:

F = Changing momentum / time

Explanation:

change in momentum = final momentum - initial momentum

Answer:

1.429*10^-5 m

Explanation:

From the question, we are given that

Diameter of the cable, d = 3 cm = 0.03 m

Force on the cable, F = 2 kN

Young Modulus, Y = 2*10^11 Pa

Area of the cable = πd²/4 = (3.142 * 0.03²) / 4 = 0.0028 / 4 = 0.0007 m²

The fractional length = Δl/l

Δl/l = F/AY

Δl/l = 2000 / 0.0007 * 2*10^11

Δl/l = 2000 / 1.4*10^8

Δl/l = 1.429*10^-5 m

Therefore, the fractional length is 1.429*10^-5 m long

Answer:

option (d)

Explanation:

Given,

1 ton of a particular item can be stack in= 3 man-hours

36 ton of a particular item can be stack in=  36 x 3 man-hours

                                                                     = 108man- hours

Number of hours = 6 hours

Number of people = [tex]\frac{108 \text{man-hours}}{6}[/tex]

                               = 18

Hence, the number of people required is 18.

Therefore, option (d) is correct.

Answer:

[tex]Position:(3.38m ,2.53m)[/tex]

[tex]Velocity=(1.72m/s,1.22m/s)[/tex]

Explanation:

From the question we are told that

Mass of particle 1  

 [tex]M_1=2.0kg[/tex]

Co-ordinate of particle 1 (2.0m,6.0m)

Velocity of Particle 1  

 [tex]V_1= (3.1 m / s , 2.6 m / s )[/tex]

Mass of particle 2  

[tex]M_2=4.5kg[/tex]

Co-ordinate of particle 2 (4.0m,1.0m)

Velocity of Particle 1  

[tex]V_2=( 1.1 m / s , 0.6 m / s )[/tex]

Generally the Position is mathematically given as  

[tex]X =\frac{ ((M_1 * Cx_1) + (M_2 *Cx_2)}{(M_1 + M_2)}[/tex]

 [tex]X=\frac{2*2+4.5*4}{2+4.5}[/tex]

[tex]X=3.38[/tex]

[tex]Y=\frac{(M_1* Cy_1 + M_2* Cy_2)}{(M_1 + M_2)}[/tex]

[tex]Y =\frac{(2 * 6 + 4.5 * 1)}{(2 + 4.5)}[/tex]

[tex]Y= 2.53 m[/tex]

Therefore the position is given as

[tex]Position:(3.38m ,2.53m)[/tex]

 Solving for Velocity

Generally the velocity of the system is mathematically Given as

[tex]V_x =\frac{ (M_1 * vx_1 + M_2 * Vx_2)}{(M_1 + M_2)}[/tex]

[tex]V_x=\frac{ (2 * 3.1 + 4.5 *1.1)}{(2 + 4.5)}[/tex]

[tex]V_x=1.72m/s[/tex]

For Y

[tex]V_y =\frac{(M_1* vy_1 + M_2* Vy_2)}{(M_1 + M_2)}[/tex]

[tex]V_y=\frac{ (2 * 2.6) + (4.5*0.6)}{(2 + 4.5)}[/tex]

[tex]V_y=1.22m/s[/tex]

Therefore Velocity

[tex]V=(1.72m/s,1.22m/s)[/tex]

Answer:

Explanation:

From the given information; the diagram below shows a clearer understanding.

The blood pressure in the brain [tex]P_{brain} = P_{heart} - \delta ( a - g ) h[/tex]

= 13300 - 1060 (12-9.81) 0.35

=  13300 -  1060 (2.19) 0.35

= 13300 - 812.49

= 12487.51  Pa

The blood pressure in the feet [tex]P_{feet} = P_{heart} + \delta (a + g) h[/tex]

= 13300 + 1060 (12 + 9.81) 1.45

= 13300 + 1060( 21.81 ) 1.45

= 13300 + 33521.97

= 46821.97 Pa

Answer:

Explanation:

[tex]P_brain = P_heart - y(a - g)h\\\\P_brain = 13300 - 1060 (12-9.81)0.35\\\\P_brain = 12487.51 pa\\\\[/tex]

[tex]P_feet = P_heart + y(a+g)*h_r\\\\P_feet = 13300 + 1060(12+9.81)*(1.8-0.35)\\\\P_feet = 46821.97pa[/tex]

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Answer:

As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.  

Explanation:

An electric switch is a device that interrupts the electron flow in a circuit. Switches are primarily binary devices: either fully on or off and light switches have a simple design. When the switch is turned off, the circuit breaks and the power flow is interrupted. Circuits consist of a source of power and load.

Answer:

[tex]magnetite[/tex]

[tex]hope \: helps...[/tex]

Answer:

  R_eq = 6 Ω

Explanation:

In a series circuit the current is constant throughout the circuit and the resistance is the sum of all the resistances in it.

          R_eq = ∑ [tex]R_{i}[/tex]

in this case we have

          R_eq = R₁1 + 3 R₂

where R₁ is the resistance of the fan and R₂ the resistance of each light, we must clarify that we will assume that the resistance of the lights does not change with temperature

let's calculate

           R_eq = 3 + 3 1

            R_eq = 6 Ω

Answer:

The awnser is 6 ohms.

Explanation:

Answer:

[tex]f'=504hz[/tex]

Explanation:

From the question we are told that

The B string on a guitar is 64 cm long

The B string tension tension of 74 N.

Frequency of 494 Hz

Pushed with a Force of 4.0 N

It moves 8.0 mm along the fret.

Generally the equation for frequency of ring under tension is mathematically given as

 [tex]2Lf=\sqrt{x\frac{T}{\mu} }[/tex]

 [tex]2*(64/100)*494=\sqrt{\frac{74}{m/0.64}[/tex]

 [tex](632.32)^2={\frac{74}{m/0.64}[/tex]

 [tex](632.32)^2=74*{\frac{0.64}{m}[/tex]

 [tex](632.32)^2={\frac{47.36}{m}[/tex]

 [tex]m=1.18450761*10^-^4[/tex]

Therefore finding the New frequency f'

  [tex]f'=\frac{(\sqrt{\frac{74+11}{(\frac{1.18450761*10^-^4}{0.642})}})}{2*0.642}[/tex]

  [tex]f'=\frac{(\sqrt{(\frac{74+11}{1})*(\frac{0.642}{1.18450761*10^-^4}})}{2*0.642}[/tex]

  [tex]f'=\frac{(\sqrt{(\frac{85}{1})*(\frac{0.642}{1.18450761*10^-^4}})}{2*0.642}[/tex]

  [tex]f'=\frac{(\sqrt{(\frac{54.57}{1.18450761*10^-^4}})}{2*0.642}[/tex]

 [tex]f'=\frac{678.7471973}{2*0.642}[/tex]

 [tex]f'=572.9111096hz[/tex]

Answer:

It depends on the medium is answer.

Explanation:

I hope it's helpful!

The energy of sound waves depends on the nature of medium it travels through. As the speed of the wave increases in the medium its energy increases. Hence, option d is correct.

Sound waves are type of mechanical waves passing through a medium. Sound waves are longitudinal waves hence, the oscillation of particles is in the same direction of of the wave propagation.

The energy of a wave is directly proportional to the frequency of the wave and inversely proportional to the wavelength. As the density of the medium increases, the speed of the wave decreases and thereby energy too.

Sound waves travels with higher speed through solids. As their energy increases, the waves moves with higher speed. Hence, the energy of sound waves depends on the nature of the medium.

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Answer:

[tex]a=4.19 m/s^{2}[/tex]

Explanation:

In order to solve this problem, we must first draw a free body diagram of the situation. (See attached picture)

from this diagram, we can do the following sum of forces:

[tex]\sum F=ma[/tex]

where m is the mass of the rocket and a is its acceleration.

[tex]F_{e}-mg=ma[/tex]

where [tex]F_{e}[/tex] is the force of exhaust. We can solve this for the acceleration, so we get:

[tex]a=\frac{F_{e}-mg}{m}[/tex]

we can find the force of exhaust by using the momentum formula:

Ft=mv

so we can solve this for the force:

[tex]F_{e}=\frac{mv}{t}[/tex]

the problem already tells us what m/t is equal to, so we can directly substitute:

[tex]F_{e}=(1.75x10^{4}kg/s)(2.40x10^3m/s)[/tex]

which yields:

[tex]F_{e}=42x10^6 N[/tex]

So we can now substitute:

[tex]a=\frac{42x10^6N-(3x10^6kg)(9.81m/s^{2})}{3x10^6kg}[/tex]

so:

[tex]a=4.19 m/s^{2}[/tex]

The girl's average velocity is 1.13 m/s

The formula used to determine average velocity is:

This means to determine the girl's average velocity is necessary to find out the total distance and the total time.

Distance:

As you can see there are two different distances and they are in different units (meters vs kilometers), let's convert the kilometers to meters so both distances are in the same unit.

Add the two distances:

Time

Let's convert the minutes into seconds:

Add the time:

Finally, calculate the average velocity:

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Answer:

D. Inverse square

Explanation:

According to the information you are giving me, you must be referring to Coulomb's law because the electrostatic force in proportion to the displacement of charged particles is [tex] F =\frac{kq_{1}q_{2}}{r²} [/tex].

As you can see, there is a reason as to why this is also referred to as Coulomb's inverse square law because the r² represents the displacement or distance relative to the position of the particles which is squared, and it is inverse because the force and the product of the distance squared is equal to the product of the two charges particles multiplied by coulomb's constant (k) which is approximately 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻².

The mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.

The electrostatic force is an attractive and repulsive force caused by the electric charges of particles. The electrostatic force is the electric force that exists between two stationary charged bodies. It is also known as Coulomb's force.

Hence,  electrostatic force inversely proportional to the distance between two charges. If two charges Q and q are separated by a distance r, the magnitude of electrostatic force between them is given by:

F = kQq/r²

So, the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.

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Answer:

5m

Explanation:

khan academy

Vertical displacement of the circus performer is 5 m.

Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.

A circus performer walked up and to the right for a total displacement of 10 m, start to end along a diagonal tightrope angled 30° degree above the ground.

Vertical displacement = 10 sin 30° = 5 m

Vertical displacement of the circus performer is 5 m.

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Answer:

The pressure exerted by the brick on the table is 18,933.3 N/m².

Explanation:

Given;

height of the brick, h = 0.1 m

density of the brick, ρ = 19,300 kg/m³

acceleration due to gravity, g = 9.81 m/s²

The pressure exerted by the brick on the table is calculated as;

P = ρgh

P = (19,300)(9.81)(0.1)

P = 18,933.3 N/m²

Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².

Answer:

Speed of ball as it leaves ramp is 2 m/s

Explanation:

From the question it is given that the average distance traveled by ball from point A to B is 2.0 m and the time taken is 1sec

one student is using stopwatch to calculate the time taken by ball and another student is using meter stick to calculate the distance traveled

since speed of ball is given by v = [tex]\frac{distance}{time}[/tex]  thus,

the speed = 2 m/s

now for minimizing the error of speed it is necessary to record the readings by single students at-least 5 times and take average

by doing this, the error of speed calculation will be minimum as the it decreases the error due to random error of system caused by taking the reading  by different students

Answer:

Power = 0.25 Watts

Explanation:

Given:

Work done = 0.50 Joule of work

Time taken = 2.0 second

Find:

Power

Computation:

Power = Work done / Time taken

Power = 0.50 J / 2

Power = 0.25 Watts

If the tired squirrel does all this work in 2 seconds with work of 0.5 J the power is 0.25 Watts.

Given:

Mass, m = 1 kg

Work, W = 0.5 J

Time, t = 2 s

The concept of power, which measures the pace at which work is done or the rate at which energy is transmitted or converted, is crucial to physics. It measures how quickly energy is produced or utilized in a system, to put it simply. In the International System of Units (SI), power is a scalar quantity and is measured in watts (W).

The power is given by:

Power  = Work ÷ Time

P = 0.50 Joules ÷ 2 seconds

P  = 0.25 Watts

Hence, the power exerted by the tired squirrel is 0.25 Watts.

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Answer:

B

Explanation:

Hhhhh

Answer:

The y-axis represents position relative to the starting point, and the x-axis represents time.

Explanation:

Answer:

True

Explanation: