Answers
Answer:
If the ratio of edge lengths is 3:5, I'm going to assume that the perimeters are going with the same ratio.
Therefore, the ratio would be 345:575.
Hope this is right and helps :)
Related Questions
Consider the following expression and the simplified expression. Expression Simplified Expression 3 x squared + 5 y squared box + 3 box + 4 y squared + 6 9 x squared minus y squared + 9 Which terms could be in the boxes to make the expressions equivalent? Positive 6 x squared and Negative 6 y squared Positive 6 x squared and Negative 10 y squared Positive 9 x squared and Negative 10 y squared Positive 9 x squared and Negative 6 y squared
Answers
Answer:
The correct answer is:
[tex]+6x^{2}\\-9y^2[/tex]
Step-by-step explanation:
We are given the term:
[tex]3x^{2} +5y^{2} [\text{ \ }] +3 [\text{ \ }] +4y^{2} +6 = 9x^{2} -y^{2} +9[/tex]
We have to fill in to the empty spaces such that the above equation gets satisfied.
First of all, let us simplify the LHS (Left Hand Side):
[tex]3x^{2} +5y^{2} [\text{ \ }] +3 [\text{ \ }] +4y^{2} +6\\\Rightarrow 3x^{2} +5y^{2} +4y^{2} [\text{ \ }] [\text{ \ }] +6 +3\\\Rightarrow 3x^{2} +9y^{2} [\text{ \ }] [\text{ \ }] +9[/tex]
Now, let us equate the LHS and RHS (Right Hand Side):
[tex]\Rightarrow 3x^{2} +9y^{2} [\text{ \ }] [\text{ \ }] +9 = 9x^{2} -y^{2} +9[/tex]
Equating the coefficients of [tex]x^{2}\ and\ y^{2}[/tex] in LHS and RHS:
One box will have value = [tex]9x^{2} -3x^{2} =+6x^{2}[/tex]
Other box will have value = [tex]-y^{2} -9y^{2} =-10y^{2}[/tex]
The correct answer is:
[tex]+6x^{2}\\-9y^2[/tex]
So, if we fill the boxes with above values, the expression will be simplified as given.
Answer:
The correct answer is B. Positive 6 x squared and Negative 10 y squared
Step-by-step explanation:
intro to geometric sequences (help pls)
Answers
Answer:
Option B
Step-by-step explanation:
The formula for geometric sequence is given by:
[tex]a_{n} = a_{1}r^{n-1}[/tex]
Where,
[tex]a_{n}[/tex] = nth term of sequence
[tex]a_{1}[/tex] = 1st term of the sequence
[tex]r[/tex] = common ratio (ration of the second term to the first term)
So,
Here:
[tex]a_{1}[/tex] = 12
[tex]r[/tex] = 6/12 = 1/2
Plugging in the values of [tex]a_{1}[/tex] and r in the above formula:
=> [tex]a_{n} = 12 * (\frac{1}{2}) ^ {n-1}[/tex]