Answer: A) Lessons learned from previous projects
Explanation:
Enterprise Environmental Factors (EEF) refers to all environmental factors that have a say in whether a project is successful or not. They include both internal factors such as company infrastructure, knowledge and capability (departments with the knowledge on project design and implementation) and internal project authorization systems as well as external factors such as Government standards and market conditions.
Lessons learned from previous projects, while important, are not included in this list and are not Enterprise Environmental Factors.
In order to find the future worth, F, from a present amount, P, 5 years from now at an interest rate of 6 % per year, compounded quarterly, what interest rate must be used in the F/P factor, (F/P,i%,n), when n is 20 quarters
Answer:
Interest rate = 1.5%
Explanation:
Given:
Future value = F
Present value = P
Number of Year (n) = 5 year × 4 quarters = 20
Interest rate = 6 % per year = 6 / 4 = 1.5% = 0.015
Computation:
Future value = Present value[tex](1+i)^n[/tex]
F/P = (1+0.015)²⁰
F/P = 1.34685501
When n = 20 quarters
F/P = (1+i)²⁰
1.34685501 = (1+i)²⁰
i = 0.015
Interest rate = 1.5%
If 200,000 machine‐hours are budgeted for variable overhead at a standard rate of $5/machine‐hour, but 220,000 machine‐hours were actually used at an actual rate of $6/machine‐hour, what is the variable overhead efficiency variance?
Answer:
Variable overhead efficiency variance= $100,000 unfavorable
Explanation:
Giving the following information:
200,000 machine‐hours are budgeted for variable overhead at a standard rate of $5/machine‐hour, but 220,000 machine‐hours were used.
To calculate the variable overhead efficiency variance, we need to use the following formula:
Variable overhead efficiency variance= (Standard Quantity - Actual Quantity)*Standard rate
Variable overhead efficiency variance= (200,000 - 220,000)*5
Variable overhead efficiency variance= $100,000 unfavorable
When the Variable overhead efficiency variance is = $100,000 unfavorable
What is the Efficiency variance?
Giving the following information are:
200,000 machine‐hours are budgeted for variable overhead at a standard rate of $5/machine‐hour, but [tex]220,000[/tex] machine‐hours were used. Now we calculate the variable overhead efficiency variance, Then we need to use the following formula are below mention. The variable overhead efficiency variance is= (Standard Quantity - Actual Quantity)*Standard rate. Then Variable overhead efficiency variance= [tex](200,000 - 220,000)*5[/tex]
Thus, Variable overhead efficiency variance= $100,000 unfavorable
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7. A fast-food chain plans to expand by opening several new restaurants. The chain operates two types of
restaurants, drive-through and full-service. A drive-through restaurant costs RM 100.000 to construct,
requires 5 employees, and has an expected annual revenue of RM 200.000. A full service restaurant
costs RM 150.000 to construct, requires 15 employees, and has an expected annual revenue of RM
500,000. The chain has RM 2,400,000 in capital available for expansion. Labor contracts require that
they hire no more than 210 employees, and licensing restrictions require that they open no more than
20 new restaurants.
(a) How many restaurants of each type should the chain open in order to maximize the expected
revenue? [1 point)
≤
Explanation:
Drive through Full Service
Annual revenue 200,000 500,000
Cost 100,000 150,000
Income 100,000 350,000
Employee 5 15
Income / employee 20,000 23,333.33
Using simultaneous equation ,
Let X represent the drive through service ,and Y represent the full service restaurant
Budget = 100,000x + 150,000y ≤ 2,400,000 (equation 1)
Employer = 5x + 15y ≤ 210 (equation 2)
(Divide equation 1 by 10 ,000)
10x+ 15y ≤ 240 (equation 3)
Using elimination method, multiply equation 2 by -2
10x +15y ≤240
-10x - 30y ≤-420
-15y ≤ -180
y≤ -180/-15
y = 12
substitute y = 12 in equation 3
10x + 15y≤240
10x +180 ≤240
10x≤240-180
10x≤60
x≤6
12 1,800,000 180
6 600,000 30
6 drive through services and 12 full services should be opened.
6 Drive through 12 full service 20
Cost 600,000 1,800,000 2,400,000
Employees 30 180
Net income 600,000 4,200,000
Rodriguez Company pays $310,000 for real estate plus $16,430 in closing costs. The real estate consists of land appraised at $215,000; land improvements appraised at $86,000; and a building appraised at $129,000.Required:1. Allocate the total cost among the three purchased assets.2. Prepare the journal entry to record the purchase.
Answer:
Required 1.
Land = $163,215
Land improvements = $65,286
Buildings = $97,929
Required 2.
Land $163,215 (debit)
Land improvements $65,286 (credit)
Buildings $97,929 (credit)
Cash $310,000 (credit)
Explanation:
Allocation of the purchase cost must be made on the bases appraisal value.
Total Appraisal Value = $215,000 + $86,000 + $129,000
= $430,000
Land = $215,000 / $430,000 × $326,430
= $163,215
Land improvements = $86,000 / $430,000 × $326,430
= $65,286
Buildings = $129,000 / $430,000 × $326,430
= $97,929
Tropetech Inc. has an expected net operating profit after taxes, EBIT(1 – T), of $2,400 million in the coming year. In addition, the firm is expected to have net capital expenditures of $360 million, and net operating working capital (NOWC) is expected to increase by $45 million. How much free cash flow (FCF) is Tropetech Inc. expected to generate over the next year?
Answer:
FCF = $1,995 million
Explanation:
DATA
EBIT(1-T) = $2,400 million
Net Capital Expenditure = $360 million
Net operating working capital (NOWC) = $45 million
Free cash flow (FCF) expected to generate over next year can be calculated as
FCF = EBIT(1-T) - Capital Expenditure - Net operating working capital (NOWC)
FCF = $2,400 million - $360 million - $45million
FCF = $1,995 million