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If 200,000 machine‐hours are budgeted for variable overhead at a standard rate of $5/machine‐hour, but 220,000 machine‐hours were actually used at an actual rate of $6/machine‐hour, what is the variable overhead efficiency variance?

Answers

Answer 1

Answer:

Variable overhead efficiency variance= $100,000 unfavorable

Explanation:

Giving the following information:

200,000 machine‐hours are budgeted for variable overhead at a standard rate of $5/machine‐hour, but 220,000 machine‐hours were used.

To calculate the variable overhead efficiency variance, we need to use the following formula:

Variable overhead efficiency variance= (Standard Quantity - Actual Quantity)*Standard rate

Variable overhead efficiency variance= (200,000 - 220,000)*5

Variable overhead efficiency variance= $100,000 unfavorable

Answer 2

When the Variable overhead efficiency variance is = $100,000 unfavorable

What is the Efficiency variance?

Giving the following information are:

200,000 machine‐hours are budgeted for variable overhead at a standard rate of $5/machine‐hour, but [tex]220,000[/tex] machine‐hours were used. Now we calculate the variable overhead efficiency variance, Then we need to use the following formula are below mention. The variable overhead efficiency variance is= (Standard Quantity - Actual Quantity)*Standard rate. Then Variable overhead efficiency variance= [tex](200,000 - 220,000)*5[/tex]

Thus, Variable overhead efficiency variance= $100,000 unfavorable

Find out more information about Efficiency variance here:

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Related Questions

Rodriguez Company pays $310,000 for real estate plus $16,430 in closing costs. The real estate consists of land appraised at $215,000; land improvements appraised at $86,000; and a building appraised at $129,000.Required:1. Allocate the total cost among the three purchased assets.2. Prepare the journal entry to record the purchase.

Answers

Answer:

Required 1.

Land =  $163,215

Land improvements = $65,286

Buildings =  $97,929

Required 2.

Land  $163,215 (debit)

Land improvements $65,286 (credit)

Buildings $97,929 (credit)

Cash $310,000 (credit)

Explanation:

Allocation of the purchase cost must be made on the bases appraisal value.

Total Appraisal Value =  $215,000 + $86,000 + $129,000

                                    =  $430,000

Land = $215,000 /  $430,000 × $326,430

        = $163,215

Land improvements =  $86,000 / $430,000 × $326,430

                                 = $65,286

Buildings = $129,000 / $430,000 × $326,430

                = $97,929

7. A fast-food chain plans to expand by opening several new restaurants. The chain operates two types of
restaurants, drive-through and full-service. A drive-through restaurant costs RM 100.000 to construct,
requires 5 employees, and has an expected annual revenue of RM 200.000. A full service restaurant
costs RM 150.000 to construct, requires 15 employees, and has an expected annual revenue of RM
500,000. The chain has RM 2,400,000 in capital available for expansion. Labor contracts require that
they hire no more than 210 employees, and licensing restrictions require that they open no more than
20 new restaurants.
(a) How many restaurants of each type should the chain open in order to maximize the expected
revenue? [1 point)
​

Answers

≤

Explanation:

                               Drive through                Full Service

Annual revenue          200,000                       500,000

Cost                               100,000                        150,000

Income                           100,000                        350,000

Employee                            5                                   15

Income / employee         20,000                        23,333.33

Using simultaneous equation ,

Let X represent the drive through service  ,and Y represent the full service restaurant

Budget = 100,000x + 150,000y ≤ 2,400,000  (equation 1)

Employer = 5x + 15y ≤ 210   (equation 2)

(Divide equation 1 by 10 ,000)

                     10x+ 15y ≤ 240 (equation 3)

Using elimination method, multiply equation 2 by -2

                      10x +15y ≤240

                      -10x - 30y ≤-420

                        -15y ≤ -180

                             y≤ -180/-15

y = 12

substitute y = 12 in equation 3

10x + 15y≤240

10x +180 ≤240

10x≤240-180

10x≤60

x≤6

                   

12         1,800,000      180

6           600,000         30

6 drive through services and 12 full services should be opened.

                           6 Drive through                12 full service            20

Cost                             600,000                      1,800,000           2,400,000

Employees                      30                                 180

Net income                     600,000                    4,200,000

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