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Please I need help with this
Photosynthesis energy is stored in the cells of green plants through
process called ______?
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g ) Water is the working fluid in an ideal regenerative Rankine cycle with one closed feedwater heater. Superheated vapor enters the turbine at 16 MPa, 560 oC, and the condenser pressure is 8 kPa. The cycle has a closed feedwater heater using extracted steam at 1 MPa. Condensate drains from the feedwater heater as saturated liquid at 1 MPa and is trapped into the condenser. The feedwater leaves the heater at 16 MPa and a temperature equal to the saturation temperature at 1 MPa. The mass flow rate of steam entering the first-stage turbine is 120 kg/s. Determine (a) the net power developed, in kW.
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Answer:
146494 kw
Explanation:
Given data:
Turbine inlet pressure ( p1 ) = 16 MPa
Turbine inlet temperature ( T1 ) = 560°C
condenser pressure : P3 = 8Kpa
Extracted steam at pressure ( P2 ) = 1 MPa
mass flow rate of steam ( m ) = 120 kg/s
a) The net power developed
= 146494 kw
note: values of h1, h2, y, Wp are all calculated values not included in the solution to make the solution less cumbersome.
PLZ HELP I GIVE BRAINLIEST!!
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Consider a layer of insulation installed around a steam pipe. The radius of the pipe is R1 and the thickness of the insulation is R3-R1.The stream is maintained at a temperature TW and the air surrounding the insulation is at a temperature To and flows cross wise over the pipe. The air is flowed over the steam pipe at high enough velocity so a thermal boundary layer develops over the surface described by a heat transfer coefficient h.
Required:
Beginning with the heat equation, calculate the total quantity of heat being conducted per unit time (heat flow) through the insulation, Q (units: energy/time).
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Answer:
hmmmmmmmmmmmmmmmmmmmmmmmmmmm
Explanation:
........
We have a parallel-plate capacitor with plates of metal each having a width W and a length L. The plates are separated by the distance d. Assume that L and W are both much larger than d. The maximum voltage that can be applied is limited to V max =K d, in which K is called the breakdown strength of the dielectric. Derive an expression for the maximum energy that can be stored in the capacitor in terms of K and the volume of the dielectric. If we want to store the maximum energy per unit volume, does it matter what values are chosen for L, W, and d? What parameters are important?
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Answer:
max energy = [tex]W_{max} = \frac{1}{2}[/tex]*εo*εr*k^2
Explanation:
Given data:
weight of plates = W
length of plates = L
distance of separation = d
max voltage ( Vmax ) = Kd
Area ( A ) = WL
The values chosen for L, W, and d matters, although the maximum energy stored in the capacitor is independent of L, W, and d. but at a constant volume and a larger value for W and L which is > d, the value of the dielectric (εrK^2 ) should be a larger value '
The important parameters are : εrK^2 , k , d and Area
attached below is the remaining part of the solution