Can somebody solve this for me please?

Step-by-step explanation:

Answer: 39.1

Step-by-step explanation:

Answer:

Car A: Initial Charge = 20

Car B: Initial Charge = 30

Car A: Rate = 5

Car B: Rate = 0

At 2 miles, their charges will be the same

Step-by-step explanation:

Given

Car A

[tex]Base\ Charge = \$20[/tex]

[tex]Rate = \$5[/tex] per mile

Car B

[tex]Base\ Charge = \$30[/tex]

Solving (a): The initial charge

First, we get the  linear equation that represents both car's charges.

Represent number of miles with m.

So, the charges is:

Car A

[tex]A = Base\ Charge + Rate * m[/tex]

[tex]A = 20 + 5 * m[/tex]

[tex]A = 20 + 5m[/tex]

Set m to 0 to get the initial charge:

[tex]A = 20 + 5*0[/tex]

[tex]A=20[/tex]

and

[tex]Rate = 5[/tex]

Car B:

[tex]B = Base\ Charge + 0 * m[/tex] i.e. Rate is 0

[tex]B = 30+ 0 * m[/tex]

[tex]B = 30[/tex]

So:

[tex]Initial = 30[/tex] and [tex]Rate = 0[/tex]

Solving (b): When their charge wil be equal.

To do this, we set:

[tex]A = B[/tex]

[tex]20 + 5m = 30[/tex]

[tex]5m = 30- 20[/tex]

[tex]5m = 10[/tex]

[tex]m = 2[/tex]

At 2 miles, their charges will be equal

Answer: (2x - 1)(3x - 4)

(split -11x as -8x and -3x)

Step-by-step explanation:

I am assuming that it is actually 6x^2 - 11x + 4

To find out how to split the middle term: The two numbers should multiply to a*c (6*4 = 24) and add to b (-11)

-8, -3 works

(6x^2 - 8x) + (-3x + 4)

2x(3x - 4) + -1(3x - 4)

(2x - 1)(3x - 4)

Answer:

D

Step-by-step explanation:

It must first translate 1 unit to the left because quadrilateral F'G'H'I is one unit away from to y axis. It can then translate across the y-axis.

Answer:

ITS B!

Step-by-step explanation:

Ape x!

Answer:

[tex]x=\sqrt{14}[/tex]

Step-by-step explanation:

This triangle is a 45-45-90 triangle.

By using the image I posted, we can find x easily.

So, we have [tex]\sqrt{7}[/tex] as one of the sides.

They hypotenuse, which is x is just [tex]\sqrt{7} \sqrt{2}[/tex]

Simplify and we get x = [tex]\sqrt{14}[/tex]

Answer:

1001/1500

Step-by-step explanation:

The easiest method for doing this is to just average the two numbers.

e.g. to find a number x between the two numbers ab and cd

x=12[ab+cd]

=12[adbd+bcbd]

=ad+bc2bd

In this case…

x=(2×5)+(3×4)2×2×5=10+1230=2230=1115

You can easily see where that came from.

23=1015 and 45=1215

and the ‘common denominator’ means you just have to pick a value between 10 and 12 . i.e. 11

But you can also say…

23=100150 and 45=120150

and choose any of 101150,102150,...,119150

or

23=10001500 and 45=12001500

and choose any of 10011500,10021500,...,11991500

Answer:4/5 and 2/3 each have a common bottom of 15 so 4/5 is

12/15 and 2/3 will be 10/15

Step-by-step explanation:So than 12/15 forget the bottom don't subtract the bottom just look at it like [12-10] then you got 2 then you go back to the bottom and put it together so your answer is [2/15]

Answer:

Step-by-step explanation:

First: work out the difference (decrease) between the two numbers you are comparing.

Decrease = Original Number - New Number

Then: divide the decrease by the original number and multiply the answer by 100.

% Decrease = Decrease ÷ Original Number × 100

If your answer is a negative number, then this is a percentage increase

Answer: she would make 13.50 per hour for the 7th year you would solve it by .50x7 and add it to 10.00

Step-by-step explanation:

Answer:

The last one, 2x3x3x3

Step-by-step explanation:

Answer:

you're answer is definitely d

Answer:

Step-by-step explanation:

The proportion between the first two and the second two numbers are:

Simplifying the second fraction:

Comparing the fractions:

The answer is no

Answer:

1. [tex]x^{8}[/tex]

2. [tex]k^{45[/tex]

3. [tex]m^{6}n^{21}[/tex]

4. [tex]64w^{18}[/tex]

5. [tex]81y^{12}[/tex]

6. [tex]16x^{4}[/tex]

7. [tex]-125y^{9}[/tex]

8. [tex]a^{36}b^{4}[/tex]

9. [tex]\frac{1}{128} x^{28}[/tex]

10. [tex]54a^{6}[/tex]

11. [tex]8k^{10}[/tex]

12. [tex]-\frac{16}{9} p^{24}[/tex]

Step-by-step explanation:

Answer:

Cddd

Step-by-step explanation:

Number of green marbles in the bag is equals to [tex]56.[/tex]

" Number is defined as the count of any given quantity as per condition."

According to the question,

Given,

Total number of marbles [tex]= 84[/tex]

[tex]'x'[/tex] represents the number of red marbles

As per given condition,

[tex]'2x'[/tex] represents the number of green marbles

Required equation we have,

[tex]x + 2x = 84\\\\\implies 3x =84\\\\\implies x = \frac{84}{3} \\\\\implies x = 28[/tex]

Substitute the value of [tex]'x'[/tex] to get number of green marbles ,

Number of green marbles [tex]2x = 2\times 28[/tex]

                                                 [tex]= 56[/tex]

Hence, number of green marbles in the bag is equals to [tex]56.[/tex]

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Answer:

530.66 cm squared

Step-by-step Explanation:

Diameter of the circle = 26 cm

Radius of the circle (r) = 26/2 = 13 cm

[tex]A_{circle} = \pi {r}^{2} \\ \\ A_{circle} = 3.14 \times {(13)}^{2} \\ \\ A_{circle} = 3.14 \times 169 \\ \\ A_{circle} =530.66 \: {cm}^{2} [/tex]

Answer:

The area of 530.66 cm squared.

Option (a) 530.66 cm² is the correct answer.

Step-by-step explanation:

Given :

To Find :

Using Formulas :

[tex]\star{\small{\underline{\boxed{\sf{\red{R = \dfrac{D}{2}}}}}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = \pi{r}^{2}}}}}}}[/tex]

Solution :

Finding the radius of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Radius = \dfrac{D}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \dfrac{26}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \cancel{\dfrac{26}{2}}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = 13}}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{Radius = 13 \: cm}}}}}[/tex]

Hence, the radius of circle is 13 cm.

[tex]\rule{200}2[/tex]

Now, finding the area of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \pi{r}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 3.14 \times {(13)}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times {(13 \times 13)}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 169}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314 \times 169}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{53066}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 530.66}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = 530.66 \: {cm}^{2}}}}}}}[/tex]

Hence, the area of circle is 530.66 cm².

[tex]\rule{300}{1.5}[/tex]

Answer:

what in the math equations is this???

Step-by-step explanation:

Answer:

adult tickets = 118

student tickets = 354

Step-by-step explanation:

a = number of adult tickets

s = number of student tickets

a + s = 472

3a = s

substitute for s

a + 3a = 472

reduce

4a = 472

divide by 4

4a/4 = 472/4

a = 118

s = 354

Answer:

The answer is D slope = -3 y-intercept = -2

Step-by-step explanation:

Answer

D.

Step-by-step explanation:

The first part of the equation is -3 and the second part is -2. The number attached to the variable is the "slope" and the number coming after the variable is the y intercept.

Answer: d- they are not perpendicular because their slopes are not negative reciprocals.

Step-by-step explanation:

The statement best explains the relationship between lines FG and HJ is They are not perpendicular because their slopes are not negative reciprocals, the correct option is D.

The equation of the straight line has its slope and given point.

If we have a non-vertical line that passes through any point(x1, y1) has gradient m. then general point (x, y) must satisfy the equation

y-y₁ = m(x-x₁)

Which is the required equation of a line in a point-slope form.

We are given that;

The graph of line FG and HJ

Now,

The slope of line FG can be found by using the points (-4, 1) and (0, -2):

m = (-2 - 1) / (0 - (-4)) = -3 / 4

The slope of line HJ can be found by using the points (-4, -2) and (0, 4):

m = (4 - (-2)) / (0 - (-4)) = 6 / 4 = 3 / 2

The slopes of lines FG and HJ are not negative reciprocals of each other, since -3/4 is not equal to -1/(3/2) or 2/3. So, lines FG and HJ are not perpendicular.

Therefore, the answer will be they are not perpendicular because their slopes are not negative reciprocals.

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Answer:

x=12

Step-by-step explanation:

Let's solve your equation step-by-step.

34(16x+16)=37((438)(x)−21)

Step 1: Simplify both sides of the equation.

18x+12=158x−9

Step 2: Subtract 15/8x from both sides.

18x+12−158x=158x−9−158x

−74x+12=−9

Step 3: Subtract 12 from both sides.

−74x+12−12=−9−12

−74x=−21

Step 4: Multiply both sides by 4/(-7).

(4−7)*(−74x)=(4−7)*(−21)

x=12

Answer:

x=12

Answer:

x = 12

Step-by-step explanation:

34(16x + 16) = 37((438)(x) − 21)

18x + 12 = 158x − 9

18x + 12 − 158x = 158x − 9 − 158x

−74x + 12 = −9

−74x + 12 −12 = −9 −12

−74x = −21

(4−7) × (−74x) = (4−7) × (−21)

x = 12

Answer:

ben birşey anlamadım sorundan

Answer:

he is 36 months old or 3 years old, and he ways 82 kilograms.

Step-by-step explanation:

quick mafs

The point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

In a graph, the line which is horizontal is known as the x-axis of the graph. The vertical line in the graph is called the y-axis of it. These axis helps to read the data from graph in following way-

In the given graph, the x-axis is labeled with age in months and y-axis is labeled with weight of panda.

The point with coordinates (36,82) tells that the age of panda is 36 months and the weight of the panda is 82 kilograms.

Hence, the point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

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Answer:

3

Step-by-step explanation:

Answer:3

Step-by-step explanation:

-(-3=3

Answer:

20 cookies

Step-by-step explanation:

Range of a data set plotted on a box plot = the maximum value - the minimum value

The maximum value is indicated by the whisker to your extreme right = 25

The minimum value is indicated by the whisker to your extreme left = 5

Range = 25 - 5 = 20

Answer:

P(E) = 1/3

Step-by-step explanation:

Given that,

Red candies = 5

Purple candies = 7

Green candies = 3

We need to find the probability that a candy picked  at random is green.

The probability of getting an event is given by :

P(E) = favorable outcomes/total no of outcomes

Probability of getting a green candy,

P(E) = 5/(5+7+3)

P(E) = 5/15

P(E) = 1/3

Hence, the required probability is (1/3).

Answer:Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?

Answer:

a) the probability of (2 < X < 6) is 0.6247

b) the value of c is 3.878

c) the value of E[ x² ] is 13

Step-by-step explanation:

Given that;

mean μ = 3

variance = 4

standard deviation s = √variance  = √4 = 2

(a) Find the probability P(2 < X < 6)

P(2 < X < 6) = p( (x - μ / s ) < z <  (x - μ / s ) )

= p( (2 - 3 / 2 ) < z < (6 - 3 / 2 ) )

= p( -0.5  < z <  1.5)

from z-score table, 1.5; z = 0.9332 and -0.5; z = 0.3085

so

P(2 < X < 6)  = 0.9332 - 0.3085 = 0.6247

Therefore, the probability of (2 < X < 6) is 0.6247

b) Find the value c such that P(X > c) = 0.33

with p-value = 0.33, the corresponding z -score to the right is 0.439

we know that;

z = x - μ / s

we substitute

0.439 = x - 3 / 2

x - 3 = 2 × 0.439

x - 3 = 0.878

x = 0.878 + 3

x = 3.878

Therefore, the value of c is 3.878

c) Find E[ x² ].

Variance = E[ x² ] - [ mean ]²

E[ x² ]  = Variance + [ mean ]²

we substitute

E[ x² ]  = 4 + [ 3 ]²

E[ x² ]  = 4 + 9

E[ x² ]  = 13

Therefore, the value of E[ x² ] is 13

The distribution follows a normal distribution.

The given parameters are:

[tex]\mathbf{\mu = 3}[/tex] --- mean

[tex]\mathbf{\sigma^2= 4}[/tex] --- variance

(a) P(2 < x < 6)

Start by calculating the standard deviation

[tex]\mathbf{\sigma = \sqrt{\sigma^2}}[/tex]

This gives

[tex]\mathbf{\sigma = \sqrt{4}}[/tex]

[tex]\mathbf{\sigma =2}[/tex]

Calculate the z-scores for x = 2 and 6

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{z = \frac{2 - 3}{2} = -0.5}[/tex]

[tex]\mathbf{z = \frac{6 - 3}{2} = 1.5}[/tex]

So, the probability becomes

[tex]\mathbf{P(2 < x < 6) = P(-0.5 < z < 1.5)}[/tex]

Using z table of probabilities, we have:

[tex]\mathbf{P(2 < x < 6) =0.9332 - 0.3085}[/tex]

[tex]\mathbf{P(2 < x < 6) =0.6247}[/tex]

(b) Calculate c if P(X > c) = 0.33

Start by calculating the z-score for p-value = 0.33

From the z table, z = 0.439 when p-value = 0.33

Recall that:

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{0.439 = \frac{x - 3}{2}}[/tex]

Multiply both sides by 2

[tex]\mathbf{0.878= x - 3}[/tex]

Add 3 to both sides

[tex]\mathbf{3.878= x}[/tex]

Rewrite as:

[tex]\mathbf{x = 3.878}[/tex]

Replace x with c

[tex]\mathbf{c = 3.878}[/tex]

The value of c is 3.878

(c) Calculate E[x²]

The variance of a dataset is:

[tex]\mathbf{\sigma^2 =E(x^2) - \mu^2}[/tex]

Substitute known values

[tex]\mathbf{4 =E(x^2) - 3^2}[/tex]

[tex]\mathbf{4 =E(x^2) - 9}[/tex]

Add 9 to both sides

[tex]\mathbf{13 =E(x^2) }[/tex]

Rewrite as:

[tex]\mathbf{E(x^2) = 13 }[/tex]

Hence, the value of [tex]\mathbf{E(x^2) }[/tex] is 13

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Step-by-step explanation:

I think it's 15 but I'm not sure

Answer:

Jojo makes 1000 and Trish makes 250

Step-by-step explanation:

I hope this helped

Answer:

Trish makes $125 more than Jojo after 10 hours

Step-by-step explanation:

$125 jojo

$250 Trish