Can somebody help me with this math question?

Answer:

B. e^x+3

Step-by-step explanation:

Y=e^x

the graph is moving 3 units up

y= y+3

y=e^x+3

answer = y=e^x+3

Answer: B

Step-by-step explanation:

Answer:

  a) 207 mph

  b) x = (1260-w)/1.17

  c) 1000 mb

Step-by-step explanation:

a) Put the pressure in the equation and solve.

  w(900) = -1.17(900) +1260 = 207

The wind speed for a hurricane with a pressure of 900 mb is 207 mph.

__

b) Solving for x, we have ...

  w = -1.17x +1260

  w -1260 = -1.17x

  x = (1260 -w)/1.17 . . . . inverse function

__

c) Evaluating the inverse function for w=90 gives ...

  x = (1260 -90)/1.17 = 1170/1.17 = 1000 . . . millibars

The approximate barometric pressure for a hurricane with a wind speed of 90 mph is 1000 millibars.

Answer:

2x+50

Step-by-step explanation:

Distributive property: 2(x)+2(25)

Simplify: 2x+50

Answer: 2x + 50

Step-by-step explanation: In this problem, the 2 distributes through the parenthses, multiplying by each of the terms inside.

So we have 2(x) + 2(25) which simplifies to 2x + 50.

Answer:

Option A.

Step-by-step explanation:

We need to find the amount of oil for a sports car.

We know that,

1 quart = 4 cups

1 gallon = 4 quarts = 16 cups

Since, quart and cup are small units and they are not sufficient for a sports car because sports car needs more oil, therefore the amount of oil for a sports car is 5 gallons.

Therefore, the correct option is A.

Answer:

[tex] 3x - y = 5 [/tex]

Step-by-step explanation:

The two pint equation of a line:

[tex] y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1) [/tex]

We have

[tex] x_1 = 4 [/tex]

[tex] x_2 = 3 [/tex]

[tex] y_1 = 7 [/tex]

[tex] y_2 = 4 [/tex]

[tex] y - 7 = \dfrac{4 - 7}{3 - 4}(x - 4) [/tex]

[tex] y - 7 = \dfrac{-3}{-1}(x - 4) [/tex]

[tex] y - 7 = 3(x - 4) [/tex]

[tex] y - 7 = 3x - 12 [/tex]

[tex] 5 = 3x - y [/tex]

[tex] 3x - y = 5 [/tex]

Answer:

[tex] g(x) = 2x+2[/tex]

Let's find g(a+h):

[tex] g(a+h)=2*(a+h) +2= 2a +2h +2[/tex]

And now let's find g(a)

[tex] g(a)= 2a+2[/tex]

And now finally:

[tex] g(a+h) = 2a +2h +2 -2a-2 = 2h +2-2= 2h[/tex]

Step-by-step explanation:

We have the following function given:

[tex] g(x) = 2x+2[/tex]

Let's find g(a+h):

[tex] g(a+h)=2*(a+h) +2= 2a +2h +2[/tex]

And now let's find g(a)

[tex] g(a)= 2a+2[/tex]

And now finally:

[tex] g(a+h) = 2a +2h +2 -2a-2 = 2h +2-2= 2h[/tex]

Answer:

HL (try HL, I believe that's the right answer)

Answer:

HL

Step-by-step explanation:

BRO TRUST ME

Answer:

C. We are 95% confident that the mean length of eggs for this particular bird population is between 45 mm and 60 mm.

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

For 95% confidence interval, it means that we are 95% confident that the mean of the population is between the given upper and lower bounds of the confidence interval.

For the case above, the interpretation of the 95% confidence interval is that we are 95% confident that the mean length of eggs for this particular bird population is between 45 mm and 60 mm.

Answer:

The temperature that separates the bottom 12% from the top 88% is 97.5°F.

Step-by-step explanation:

We are given that human body temperatures are normally distributed with a mean of 98.2°F and a standard deviation of 0.62°F.

Let X = human body temperatures

So, X ~ Normal([tex]\mu= 98.2,\sigma^{2} = 0.62^{2}[/tex])

The z-score probability distribution for the normal distribution is given by;

                            Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean human body temperature = 98.2°F

           [tex]\sigma[/tex] = stnadard deviation = 0.62°F

Now, we have to find the temperature that separates the bottom 12% from the top 88%, that means;

        P(X < x) = 0.12       {where x is the required temperature}

        P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{x-98.2}{0.62}[/tex] ) = 0.12

        P(Z < [tex]\frac{x-98.2}{0.62}[/tex] ) = 0.12

Now, the critical value of x that represents the bottom 12% of the area in the z table is given as -1.1835, that is;

                    [tex]\frac{x-98.2}{0.62} = -1.1835[/tex]

                    [tex]{x-98.2}= -1.1835\times 0.62[/tex]

                     [tex]x = 98.2 -0.734[/tex] = 97.5°F

Hence, the temperature that separates the bottom 12% from the top 88% is 97.5°F.

Answer:

A) Null and alternative hypothesis

[tex]H_0: \mu=2\\\\H_a:\mu\neq 2[/tex]

B) M = 2.2 hours

C) s = 0.52 hours

D) P-value = 0.255

E) At a significance level of 0.05, there is not enough evidence to support the claim that the mean tree-planting time significantly differs from two hours.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean tree-planting time significantly differs from two hours.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=2\\\\H_a:\mu\neq 2[/tex]

The significance level is 0.05.

The sample has a size n=10.

The sample mean is M=2.2.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.52.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.52}{\sqrt{10}}=0.1644[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.2-2}{0.1644}=\dfrac{0.2}{0.1644}=1.216[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=10-1=9[/tex]

This test is a two-tailed test, with 9 degrees of freedom and t=1.216, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=2\cdot P(t>1.216)=0.255[/tex]

As the P-value (0.255) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean tree-planting time significantly differs from two hours.

Sample mean and standard deviation:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{10}(1.7+1.5+2.6+. . .+2.3)\\\\\\M=\dfrac{22}{10}\\\\\\M=2.2\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{9}((1.7-2.2)^2+(1.5-2.2)^2+(2.6-2.2)^2+. . . +(2.3-2.2)^2)}\\\\\\s=\sqrt{\dfrac{2.4}{9}}\\\\\\s=\sqrt{0.27}=0.52\\\\\\[/tex]

Answer:

  both

Step-by-step explanation:

Both of the equations shown here are linear equations in standard form.

  5x + 3y = 210

  x + y = 60

Answer:True

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

Because it can but does not

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = [tex]\dfrac{\sqrt{3} }{4}s^2[/tex]

Side Length, s=6 Units

[tex]\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units[/tex]

Area of the Hexagon

[tex]= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)[/tex]

Answer:

a) E(X) = 16.09 ft³

E(X²) = 262.22 ft⁶

Var(X) = 3.27 ft⁶

b) E(22X) = 354 dollars

c) Var(22X) = 1,581 dollars

d) E(X - 0.01X²) = 13.470 ft³

Step-by-step explanation:

The complete Correct Question is presented in the attached image to this solution.

a) Compute E(X), E(X2), and V(X).

The expected value of a probability distribution is given as

E(X) = Σxᵢpᵢ

xᵢ = Each variable in the distribution

pᵢ = Probability of each distribution

Σxᵢpᵢ = (13.5×0.20) + (15.9×0.59) + (19.1×0.21)

= 2.70 + 9.381 + 4.011

= 16.092 = 16.09 ft³

E(X²) = Σxᵢ²pᵢ

Σxᵢ²pᵢ = (13.5²×0.20) + (15.9²×0.59) + (19.1²×0.21)

= 36.45 + 149.1579 + 76.6101

= 262.218 = 262.22 ft⁶

Var(X) = Σxᵢ²pᵢ - μ²

where μ = E(X) = 16.092

Σxᵢ²pᵢ = E(X²) = 262.218

Var(X) = 262.218 - 16.092²

= 3.265536 = 3.27 ft⁶

b) E(22X) = 22E(X) = 22 × 16.092 = 354.024 = 354 dollars to the nearest whole number.

c) Var(22X) = 22² × Var(X) = 22² × 3.265536 = 1,580.519424 = 1,581 dollars

d) E(X - 0.01X²) = E(X) - 0.01E(X²)

= 16.092 - (0.01×262.218)

= 16.0926- 2.62218

= 13.46982 = 13.470 ft³

Hope this helps!!!

Answer:

V = number of ounces

56 = 2V

Step-by-step explanation:

Answer:28

Step-by-step explanation:V times 2= 56

Answer:

Answer is option 2

Step-by-step explanation:

We know that Angle M = Angle G (given in diagram)

We also know that Angle L in triangle LMN is equal to Angle L in triangle LGH

As two angles are equal in both triangles they are similar.

But why is it Triangle LGH instead of Triangle HGL?

As we know M=G therefore they should be in the same place in the name Of the triangle. In triangle LMN M is in the middle therefore Angle G should also be in the middle

Answer:

x = 7

Step-by-step explanation:

[tex] 3^{x - 5} = 9 [/tex]

[tex] 3^{x - 5} = 3^2 [/tex]

[tex] x - 5 = 2 [/tex]

[tex] x = 7 [/tex]

Hey there! :)

Answer:

y = 1/4x - 3.

Step-by-step explanation:

Use the slope-formula to find the slope of the line:

[tex]m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Plug in two points from the line. Use the points (-4, -4) and (0, 3):

[tex]m = \frac{-3 - (-4)}{0 - (-4)}[/tex]

Simplify:

m = 1/4.

Slope-intercept form is y = mx + b.

Find the 'b' value by finding the y-value at which the graph intersects the y-axis. This is at y = -3. Therefore, the equation is:

y = 1/4x - 3.

Answer:

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)  

And replacing we got:

[tex]t=\frac{69.5-69}{\frac{11.2}{\sqrt{147}}}=0.541[/tex]  

Step-by-step explanation:

Information given

[tex]\bar X=69.5[/tex] represent the sample mean    

[tex]s=11.2[/tex] represent the sample standard deviation

[tex]n=69[/tex] sample size  

[tex]\mu_o =69[/tex] represent the value that we want to test

t would represent the statistic (variable of interest)  

Hypothesis to test

We want to check if the true mean is 69, the system of hypothesis would be:  

Null hypothesis:[tex]\mu =69[/tex]  

Alternative hypothesis:[tex]\mu \neq 69[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)  

And replacing we got:

[tex]t=\frac{69.5-69}{\frac{11.2}{\sqrt{147}}}=0.541[/tex]  

Answer:

$143,739

Step-by-step explanation:

We must apply the formula for P0 and solve for d, that is,

P0=d(1−(1+rk)−Nk(rk).

We have P0=$200,000,r=0.04,k=12,N=30, so substituting in the numbers into the formula gives

$200,000=d(1−(1+0.0412)−30⋅12)(0.0412),

that is,

$200,000=209.4612d⟹d=$954.83.

So our monthly repayments are d=$954.83. To calculate the total interest paid, we find out the entire amount that's paid and subtract the principal. The total amount paid is

Total Paid=$954.83×12×30=$343,738.80

and therefore the total amount of interest paid is

Total Interest=$343,738.80−$200,000=$143,738.80,

which is $143,739 to the nearest dollar.

The interest paid is 2912683 dollars.

Compound interest is calculated for the principle taken as well as previous interest paid.

According to the given question Principle amount (P) taken from the bank is 2000000 dollars.

The yearly interest rate (r) compounded monthly is 4%.

Time in years (n)  is 30.

We know, in the case of compound interest compounded yearly is  

A = P(1 + r/100)ⁿ.

So, Amount compounded monthly will be

A = P[ 1 + (r/12)/100]¹²ⁿ.

A = 2000000[ 1 + (4/12)/100]¹²ˣ³⁰.

A = 2000000[ 1 + 0.003]³⁶⁰.

A = 2000000[ 1.003]³⁰⁰.

A = 2000000(2.456).

A = 4912583.

∴ The total interest paid on the mortgage is (4912683 - 2000000) =  2912683.

earn more about compound interest here :

https://brainly.com/question/14295570

#SPJ2

Answer:

[tex]( x_1 , y_1 , z_1 ) = < -7 + 4\sqrt{3} , -4 + 2\sqrt{3} , 7 - 2\sqrt{3} >\\\\( x_2 , y_2 , z_2 ) = < -7 - 4\sqrt{3} , -4 - 2\sqrt{3} , 7 + 2\sqrt{3} >\\[/tex]

Step-by-step explanation:

Solution:-

- We are given a parametric form for the vector equation of line defined by ( t ).

- The line vector equation is:

                        L: < 3 + 2t , t + 1 , 2 -t >

- The same 3-dimensional space is occupied by a unit sphere defined by the following equation:

                          [tex]S: x^2 + y^2 + z^2 = 1[/tex]

- We are to determine the points of intersection of the line ( L ) and the unit sphere ( S ).

- We will substitute the parametric equation of line ( L ) into the equation defining the unit sphere ( S ) and solve for the values of the parameter ( t ):

                        [tex]( 3 + 2t )^2 + ( 1 + t )^2 + ( 2 - t)^2 = 1\\\\( 9 + 12t + 4t^2 ) + ( t^2 + 2t + 1 ) + ( 4 + t^2 -4t ) = 1\\\\t^2 + 10t + 13 = 0\\\\[/tex]

- Solve the quadratic equation for the parameter ( t ):

                       [tex]t = -5 + 2\sqrt{3} , -5 - 2\sqrt{3}[/tex]

- Plug in each of the parameter value in the given vector equation of line and determine a pair of intersecting coordinates:

                      [tex]( x_1 , y_1 , z_1 ) = < -7 + 4\sqrt{3} , -4 + 2\sqrt{3} , 7 - 2\sqrt{3} >\\\\( x_2 , y_2 , z_2 ) = < -7 - 4\sqrt{3} , -4 - 2\sqrt{3} , 7 + 2\sqrt{3} >\\[/tex]

Answer:

couldnt tell you

Step-by-step explanation:

jkj

Answer:

D. *6F

Step-by-step explanation:

C=(F-32)*5/9

30=(F-32)*5/9

F = (30*9)/5+32

F = 86

Answer:

20 years old.

Step-by-step explanation:

Let us say that the man's age is represented by x and the son's age is represented by y.

As of now, x = 2y.

In 20 years, both ages will increase by 20. We can have an equation where the son's age increased by 20 equals 2/3 of the man's age plus 20.

(y + 20) = 2/3(x + 20)

Since x = 2y...

y + 20 = 2/3(2y + 20)

3/2y + 30 = 2y + 20

2y + 20 = 3/2y + 30

1/2y = 10

y = 20

To check our work, the man's age is currently double his son's, so the man is 40 and the son is 20. In 20 years, the man will be 60 and the son will be 40. 40 / 60 = 2/3, so the son's age is 2/3 of his father's.

So, the son's present age is 20 years old.

Hope this helps!

Answer:

what's a bit

Step-by-step explanation:

Answer:

7,000,000,000

Step-by-step explanation:

since the closest number is less than 5 (1<5) you round down making the nearest billion 7

Answer:

7,000,000,000 OR 7 Billion

Step-by-step explanation:

Since the 1 is millions place and its less than 5, you need to round down meaning that 7,125,000,00 rounded to the nearest billion is 7 billion.

Answer:

C

Step-by-step explanation:

[tex]-5x-49\geq 113[/tex]

[tex]-5x\geq 162[/tex]

[tex]x\leq -32.4[/tex]

(Multiplying or dividing by a negative flips the sign).

Answer:

a) 24.82% probability that the mean annual return on common stocks over the next 36 years will exceed 11%

b) 13.57% probability that the mean return will be less than 5%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

[tex]\mu = 8.7, \sigma = 20.2, n = 36, s = \frac{20.2}{\sqrt{36}} = 3.3667[/tex]

(a) What is the probability (assuming that the past pattern of variation continues) that the mean annual return on common stocks over the next 36 years will exceed 11%?

This is 1 subtracted by the pvalue of Z when X = 11.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{11 - 8.7}{3.3667}[/tex]

[tex]Z = 0.68[/tex]

[tex]Z = 0.68[/tex] has a pvalue of 0.7518

1 - 0.7518 = 0.2482

24.82% probability that the mean annual return on common stocks over the next 36 years will exceed 11%

(b) What is the probability that the mean return will be less than 5%?

This is the pvalue of Z when X = 5.

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{5 - 8.7}{3.3667}[/tex]

[tex]Z = -1.1[/tex]

[tex]Z = -1.1[/tex] has a pvalue of 0.1357

13.57% probability that the mean return will be less than 5%