Can any kind soul help me​

A. 30 m/s . . . speed

B. 30 m to the East  . . . displacement

C. 30 m/s to the East  . . . velocity

D. 30 m . . . distance

Answer:

800 kg

Explanation:

I just did it :)

Answer:

Miles is the distance unit. Hours is the time unit.

Explanation:

Answer:

Explanation:

Given

Height S = 8.4m

Initial velocity u = 24m/s

Required

Time it will take to reach the ground

Using the equation of motion

S = ut +1/2gt²

8.4 = 24t + 1/2(9.8)t²

8.4 = 24t+4.9t²

4.9t²+24t - 8.4 = 0

Multiply through by 10

49t²+240t-84 = 0

Factorize

t = -240±√240²-4(49(-84)/2(49)

t = -240±√57600+16464/98

t = -240±√74064/98

t = -240±272.15/98

t = 32.15/98

t = 0.328seconds

Hence it takes 0.328seconds before it lands on the ground below.

b) The horizontal distance is the range expressed as;

R = u²/g

R = 27²/9.8

R = 729/9.8.

R = 74.39m

a. The time it took before the motorcycle stunt driver lands on the ground below is 1.31 seconds.

b. The distance from the base of the cliff that the motorcycle stunt driver traveled while in  the air is 31.44 meters.

Given the following data:

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]

a. To determine how long (time) it took before the motorcycle stunt driver lands on the ground below:

At maximum height, time is given by the formula:

[tex]Time = \sqrt{\frac{2H}{g} }[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]Time = \sqrt{\frac{2\times 8.4}{9.8} }\\\\Time = \sqrt{\frac{16.8}{9.8} }\\\\Time =\sqrt{1.7413}[/tex]

Time = 1.31 seconds.

b. To determine how far (distance) away from the base of the cliff the motorcycle stunt driver traveled while in  the air:

[tex]Horizontal\;distance = horizontal\;speed \times time\\\\Horizontal\;distance = 24 \times 1.31[/tex]

Horizontal distance = 31.44 meters.

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Answer:

This question is incomplete, a possible question would be to calculate the work done by the ball.

Work done = 8J

Explanation:

Work done by an object is calculated my multiplying the force by the distance.

The weight of this ball is 2.0N, which also represents the force exerted by the ball. The ball travels through a distance of 4m

Hence, work done = F × d

Work done = 2N × 4m

Work done = 8Nm or 8J

Answer:

The distance is 45m. (s)

Acceleration is 9.8 m/s^2 (acceleration due to gravity). (a)

We have to find the time (t)

By the 3rd equation of motion,

s = ut + 1/2 at^2 (here u is the initial velocity of the ball)

Since the initial velocity was 0 m/s, the formula becomes s = 1/2 at^2.

(substituting the values in the formula)

45 = 1/2 x 9.8 x t^2

45 = 9.8/2 x t^2

45 = 4.9 x t^2 (9.8/2 = 4.9)

(divide 4.9 on both sides)

45/4.9 = 4.9 x t^2 / 4.9

9.1836 = t^2

3.030 = t

So it takes approximately 3 seconds for the ball to reach the surface of the earth (neglecting air resistance). You can try the same with 50 m .

The velocity of the ball the moment it hits the ground is equal to 31.3 m/s.

Equation of motion has established a relation between the velocity of the body and acceleration of the body when the body is moving with uniform acceleration along a straight line. The distance traveled in a specific time has expressed a set of equations termed equations of motion.

The first equation of motion can be expressed as follows:

v = u + at

The second equation of motion can be expressed as follows:

S= ut + (1/2)at²

Where u is the initial velocity of a body, v is the final velocity, S is the distance, a is the acceleration and t is the time.

Given, the distance traveled by the ball, S = 50 m

and, the initial velocity of the ball, u = 0 as ball is at rest initially.

From the second equation of motion, find the value of 't':

50 = (0) t + (1/2)× (9.8) ×(t²)

t = 3.19 sec

Now from the first equation of motion, find the value of the final velocity of the ball:

v = (0) + (9.8) (3.19)

v = 31.3 m/s

Therefore, the ball hits the ground with a velocity of 31/3 m/s.

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Answer:

60 km per hour

Explanation:

if you drive for 30 min and go 30km then if you drive for 60 min(1hr) then you would have driven 60km.

Answer:

60

Explanation:

hope this helps

Answer:

Yes

Explanation:

Its a good game.

Answer:

oof

Explanation:

Answer:

053.

Explanation:

Given that the radius of curvature of the path, R = 75 m.

Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]

The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v  on curved path having radiusR

Ris[tex]F_c = mv^2/R[/tex]

Gravitational force, [tex]F_g[/tex] = mg.

Let tha angle of superelevation is [tex]\theta.[/tex]

As the car does not skid even with zero friction, so

[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]

[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]

On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]  

As [tex]v_2[/tex] = 118 m/s is greater than   v_so the car tends to skid in upper direction and the frictional

force,f, will acts is downward direction.

As there is no skidding, so

[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]

[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]

where [tex]f= \mu N.[/tex]

[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]

Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.

[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]

From equation (ii)

[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]

[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]

[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]

[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]

=0.53

Hence, the minimum coefficient of friction is 0.53.

Answer:

P = 3000 Pa

Explanation:

Weight of Dorji, W = F = mg = 1500 N

The total surface area of soles of his feet is 0.5 m²

We need to find the pressure exerted by his body on the ground​. The pressure is equal to the force acting per unit area. So,

[tex]P=\dfrac{1500\ N}{0.5\ m^2}\\\\=3000\ Pa[/tex]

So, the pressure exerted by his body on the ground​ is 3000 Pa.

The answer is option c - It will divide in half to form two new cells..

Explanation:

The sentence that best describes what happened during cell growth is ;

( D ) It will become larger by taking in nutrients

As the yeast cells begin to grow ( i.e. cell growth ), they will require more nutrients and as they take in the necessary nutrients they will gradually increase in size ( becoming larger ) which is a vital sign of cell growth and development, which will be seen in the yeast cells as they undergo cell growth.

The production of offsprings with a mate does not describe an activity that occurs in cell growth.  

Hence we can conclude that The sentence that best describes what happened during cell growth is, It will become larger by taking in nutrients.

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Answer:

The resultant displacement of the airplane in 4 hours is 212.8 km.

Explanation:

The components of the airplane's velocity and wind's velocity are:

Airplane:

[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]

[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]

Wind:

[tex] v_{w_{x}} = 0 [/tex]

[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]

Now, to know the new velocity of the airplane we to find the result vector:

[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]

[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]  

Now, the magnitude of the new speed of the airplane is:

[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]

Finally, after 4 hours the resultant displacement of the airplane is:

[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]

Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.

I hope it helps you!                                        

In physics, the triangle symbol (∆) typically represents a change or difference in a particular quantity.



A triangle is often used to denote the difference between two values of a variable. For example, if we have two values of time, t1 and t2, the change or difference in time can be represented as Δt = t2 - t1, where Δt is the triangle symbol indicating the change in time. Similarly, it can be used to represent differences in other physical quantities such as displacement (∆x), velocity (∆v), or temperature (∆T). The triangle symbol (∆) is a shorthand notation commonly used in physics to indicate changes or differences.

In terms of change in displacement, the triangle symbol (∆) represents the difference between two positions or locations. It indicates the change in the object's position from an initial point to a final point.

For example, if an object initially starts at position x1 and then moves to position x2, the change in displacement (∆x) can be calculated as ∆x = x2 - x1. Here, ∆x represents the difference or change in the object's displacement.

The magnitude of ∆x gives the overall distance traveled by the object, and its sign indicates the direction of the displacement. A positive ∆x signifies a displacement in the positive direction (e.g., to the right or upward), while a negative ∆x represents a displacement in the negative direction (e.g., to the left or downward).

Therefore, The triangle symbol (∆) is commonly used in physics equations to denote changes or differences in various quantities, including displacement, velocity, time, and more. It helps us analyze and quantify the differences between two values of a physical quantity.

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Answer:

C.

Explanation:

the earth has a high greavitational pull

Answer: C the person and earth

Explanation: I just answered it on a p e x

Answer:

11 times the weight of Philip.

Explanation:

From the question given above, the following data were obtained:

Weight of Melissa (i.e cow) = 0.65 tons

Weight of Philip (i.e rabbit) = 192 ounces

Next, we shall express the weight of Philip (i.e the rabbit) in tons. This can be obtained as follow:

1 ounce = 3.125×10¯⁵ ton

Therefore,

192 ounce = 192 ounce × 3.125×10¯⁵ ton / 1 ounce

192 ounce = 0.06 ton

Thus, the weight of Philip (i.e the rabbit) in ton is 0.06 ton.

Next, we shall determine the ratio of the weight of Melissa (i.e the cow) to the weight of Philip (i.e the rabbit). This can be obtained as follow:

Weight of Melissa (i.e cow) = 0.65 ton

Weight of Philip (i.e rabbit) = 0.06 ton

Melissa /Philip = 0.65/0.06

Melissa /Philip = 11

Melissa = 11 × Phillip

Thus, it will take 11 times the weight of Philip to weigh as much as Melissa.

Small gaps which function as expansion joints are deliberately left between the rail ends to allow for expansion of the rails in hot weather. ... Because of these small gaps, when trains pass over jointed tracks they make a "clickety-clack" sound.

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of options. However, the charge of a nucleus was discovered by Ernest Rutherford. The nucleus is located in the centre of an atom and it contains protons and neutrons. The protons are positively charged while the neutrons have no charge, thus the charge of the nucleus is positive because the neutrality of the neutron does not affect the charge of the proton.

The charge of an electron was first measured by Robert Millikan. Electrons are negatively charged subatomic particles that balance out the positive charge of the protons.

Answer:

A compound is a substance that consists of two or more elements in a unique composition. The smallest particle of a compound is called a molecule. Chemical bonds hold together the atoms of molecules

Answer:

Mass, m = 32 kg

Explanation:

Given that,

Force, F = 2000 N

The change in velocity, (v-u) = 50 m/s

Time, t = 0.8 s

We need to find the mass of the ball. The net force acting on an object is given by :

F = ma

Where a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{(v-u)}\\\\m=\dfrac{2000\times 0.8}{50}\\\\m=32\ kg[/tex]

So, the mass of the ball is 32 kg.

Answer:

The force to get the plane moving, and to balance the friction so it does not stop, is provided by the propeller. However, the wheels provide the acceleration of the car.

Explanation:

Answer:D

Explanation:AP3X

The statement describes the interaction between the permanent magnets and the electromagnet in an electric motor is option D.

A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.

A bar is a magnet which can attract the particle which are charged. It has two poles North and South.

The permanent magnet create magnetic field very strong. The electromagnet is find in the electric motor. In the motor, loop made up of conductor is rotated by the effect of magnetic field of permanent magnet.

Thus, the correct option is D.

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La respuesta correcta es 180 centímetros cúbicos o 180 [tex]cm^{3}[/tex]

Explicación:

El primer paso para saber cuanto alcohol desaloja el prisma es calcular el volumen total del prisma. El volumen se puede encontrar usando la formula V (Volumen) = B (base) x h (altura). El proceso se muestra a continuación:

V  = B x h

V = 36 [tex]cm^{2}[/tex] x 10 cm

V= 360 [tex]cm^{3}[/tex]

Finalmente, el volumen total del prisma debe dividirse en 2 considerando que solo la mitad del prisma fue sumergida y esta mitad equivale al volumen del alcohol desplazado.

360 [tex]cm^{3}[/tex] ÷ 2 = 180 [tex]cm^{3}[/tex]  

El volumen de fluido desplazado es de 180 cm^3.

Sabemos que el objeto va a desplazar su propio volumen de fluido. Por lo tanto, necesitamos obtener el volumen del objeto a, este es el volumen del fluido que eventualmente será desplazado por el sólido.

El volumen del sólido es;

V = 36 cm^2 * 10 cm^2 = 360 cm^3

desde que se sumergió a la mitad, volumen de alcohol desplazado = 360 cm^3/2 = 180cm^3

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Answer: Assuming you are driving a car on the road, consider the motion of the car. As the wheels of the car spin backwards, they push the road backwards. In consequence, the road must push the wheels forward according to the third law of motion. It is this reaction force acting on the wheels causes the car to move forward.

Explanation: hope this helps!

Answer:

0.5m/s2

..............

Answer:

1) The velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Explanation:

1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:

Position

[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]

[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)

Velocity

[tex]v = v_{o}-g\cdot t[/tex] (2)

Where:

[tex]t[/tex] - Time, measured in seconds.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.

[tex]v[/tex] - Final velocity of the ball, measured in meters per second.

From (1), we get the time when the ball returns to the thrower's hand:

[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]

[tex]t = \frac{2\cdot v_{o}}{g}[/tex]

And then we apply this result in (2):

[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]

[tex]v = -v_{o}[/tex] (3)

Then, the velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:

[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)

If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:

[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]

The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Answer:

alright i responded

Explanation:

you didnt say i had to answer

Answer:

E

Explanation:

Elaphants and noodles+ramen and sushi