Answer:
The total surface area of the pipe is 4123.31 cm²
Step-by-step explanation:
Total surface area (TSA) of a pipe is calculated as;
Outer area of the pipe + Inner area of the pipe + cross section of the two ends
TSA = 2πRL + 2πrL + 2π(R² - r²)
TSA = 2π(RL + rL + R² - r²)
where;
R is the outer radius
r is the inner radius
L is length of the pipe
Determine the length of the pipe
Outer surface area of the pipe is calculated as;
outer surface of the pipe = 2πRL
2514.2 = 2πRL
2514.2 = (2π x 5) L
2514.2 = 31.42 L
L = 2514.2 / 31.42
L = 80.02 cm
Finally, determine the total surface area of the pipe
TSA = 2π(RL + rL + R² - r²)
TSA = 2π(5x80.02 + 3x80.02 + 5² - 3²)
TSA = 2π(400.1 + 240.06 + 16)
TSA = 2π(656.16)
TSA = 4123.31 cm²
Therefore, the total surface area of the pipe is 4123.31 cm²
.Solve for x 5 x − 1 = 6 x − 9
Answer:
x = 8
Step-by-step explanation:
Step 1: Subtract 5x from both sides
-1 = x - 9
Step 2: Add 9 to both sides
x = 8
A box contains 5 blue, 4 red, and 3 yellow marbles. Two marbles are randomly drawn and not replaced. What is the probability of drawing a blue then a red marble?
Answer: Probability = 20/132
Step-by-step explanation: There is no replacement in the box, so, once the marble is taken out, there will be one less inside the bag:
Total = 5 + 4 + 3 = 12
Probability of Blue:
P(b) = 5/12
Probability of Red: Since the blue is already out, total will be one less:
P(r) = 4/11
Probability of taken one and then the other:
P(blue,red) = [tex]\frac{5}{12} . \frac{4}{11}[/tex]
P(blue,red) = [tex]\frac{20}{132}[/tex] ≈ 0.15
The probability of drawing a blue and then a red is 20/132.
Answer:
5/33
Step-by-step explanation:
50. Write the fraction or mixed number as a
decimal. Then tell whether the decimal is a
terminating decimal or repeating decimal.
23
33
Answer:
0.69, repeatingStep-by-step explanation:
23/33 =0.69repeating
Erika calculated that she would spend $115 on school supplies this year. She actually spent $82.50 on school supplies. What is Erika's percent of error?
Answer:
Percentage error is 39.39%
Step-by-step explanation:
It is given that,
The calculated value that Erika spend on school supplies this year is $115.
Actual value that she spent is $82.50.
We need to find Erika's percent of error. Percentage error is given by the formula as follows :
[tex]\%=\dfrac{\text{calculated value}-\text{actual value}}{\text{actual value}}\times 100\\\\\%=\dfrac{115-82.5}{82.5}\times 100\\\\\%=39.39\%[/tex]
So, Erika's percent of error is 39.39%.
Please answer this question now in two minutes
Answer:
u+43°=u_3°+u+3° (by exterior angle theorem)
u+43°= 2u
or, 2u_u=43°
or, u= 43°
is the value of u.....
PLEASE help me with this!! I need help!
Answer:
∠ BDG = 148°
Step-by-step explanation:
The tangent- chord angle BDG is half the measure of its intercepted arc DCG
The 2 arcs in the circle sum to 360°, thus
arc DCG = 360° - arc DG = 360° - 64° = 296° , thus
∠ BDG = 0.5 × 296° = 148°
Simple and easy question
please help
Answer:
A
Step-by-step explanation:
To find the volume we do 2 * 1.25 * 1.5 (i rewrote the fractions as decimals) which is 3.75 or 3 and 3/4 cubic inches.
Answer:
V = [tex]3 \frac{3}{4}[/tex]
Step-by-step explanation:
Hey there!
Well the volume "v" of a rectangular prism is,
V = l•w•h
Fill in
[tex]V = 2* 1 \frac{1}{4} * 1 \frac{1}{2}[/tex]
V = [tex]3 \frac{3}{4}[/tex]
Hope this helps :)
The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time for a container of the wheels during production is 0.25 day; average processing time is 0.15 day per container. Each container holds 200 wheels. The company uses 2000 wheels a day in the production of its products. Using a policy variable of 5%, calculate the number of Kanban containers needed for the wheels.
Answer:
4.2 kanban containers required
Step-by-step explanation:
Given the following information :
Waiting time = 0.25 days
Average peocessing time = 0.15 days / container
Daily usage (Demand rate) = 2000 per day
Container capacity = 200 wheels
Policy variable ( Alpha) = 5% = 0.05
Therefore, number of kanban containers needed for the wheels can be calculated using:
(Number of containers(x) * container size) = (Demand rate (waiting time + processing time)*(1 + alpha))
x * 200 = 2000(0.25 + 0.15)*(1 + 0.05)
200x = 2000(0.40)*(1.05)
200x = 840
x = 840 / 200
x = 4.2
4.2 kanban containers required
leo, Kush and Mai share some money in the ratio 3 : 5 : 8. Kush receives £750 more than Leo. Calculate the total amount of money that they shared?
Answer:
£6000
Step-by-step explanation:
3:5:8
3+5+8=16
5-3 =2
Therefore 2=750
Therefore 1=375
16*375=£6000
A fair 6-sided die numbered 1 to 6 is rolled once. Find the probability that the number obtained is either even or a prime number. Define the event ME or MNE. If you can help me, I would be so thankful.
Please help! Question two
Answer:
4y+6
Step-by-step explanation:
Perimeter is adding up the outside
so.. there are y+y = 2y
y+3 + y+3 = 2y+6
2y+6 + 2y = 4y+6
Hope this helps :)
La longitud de un rectángulo mide 3m mas que el doble de su ancho del rectángulo, escribe un polinomio que represente el perímetro del rectángulo y simplifica el polígono correspondiente.
Answer:
Step-by-step explanation:
El ancho es x, el largo es x+3
El perímetro es dos veces el largo más dos veces el ancho, es decir: 2(x) + 2(x+3) = 4x+6
El polinomio sería: P(x)=4x+6
Jenny has a $3,000 balance on her credit card with an 18% interest rate. If she makes no payments on her card and no late fees were charged how long will it take her debt to double?
Answer:
it would take about 4.2 years for her debt to double.
Step-by-step explanation:
With a principal of $3000, and an annual interest rate of 18%, the equation for accumulated debt as a function of time in years, would be given by the expression:
[tex]A(t)=3000\,(1+0.18)^t[/tex]
now, if we want to find when the debt would double, we replace A(t) with $6000, and solve for the time 't' using logarithms to bring down the unknown (t) that resides in the exponent:
[tex]A(t)=3000\,(1+0.18)^t\\6000=3000\,(1.18)^t\\2=(1.18)^t\\log(2)=t\, \, log(1.18)\\t=\frac{log(2)}{log(1.18)} \\t=4.1878\,\,years[/tex]
which we can round to approximately 4.2 years
the mean of five numbers is 8. when another number is added the mean is 7. find the number added
Answer:
[tex]\large \boxed{\sf \ \ 2 \ \ }[/tex]
Step-by-step explanation:
Hello,
The mean of five numbers is 8 so we can write
[tex]\dfrac{x_1+x_2+x_3+x_4+x_5}{5}=8[/tex]
When another number is added the mean is 7, let s note x the another number we can write
[tex]\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7[/tex]
From the first equation we can say
[tex]x_1+x_2+x_3+x_4+x_5=8*5=40[/tex]
So the second equation becomes
[tex]\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7\\\\<=> \dfrac{40+x}{6}=7\\\\<=>40 + x = 6*7=42\\\\<=> x = 42-40 = 2\\[/tex]
The solution is then 2
Hope this helps
some help a homie out in math
Answer:
1. A pentagonal Pyramid
2. Super Easy, tell me to draw one if you need but i am not gonna give in that much effort right now
A construction company covered 3\8 of a road which is 10km long with asphalt in the first week and covered 7\18of the road in the second week with asphalt. what length of the road remained to be covered with asphalt?
Answer:
2.36 km
Step-by-step explanation:
First they covered 3/8 of the road, so in figures that is;
= [tex]\frac{3}{8} * 10km[/tex]
=3.75 km
The second week they covered 7/18 of the road which is;
= [tex]\frac{7}{18} * 10km[/tex]
= 3.89 km
If we combine the two distances, we get;
= 3.75 km + 3.89 km
= 7.64 km
Subtract this from the total distance and you get
= 10 km - 7.64 km
= 2.36 km
Which means 2.36 km of the road is left to be covered with asphalt.
The length of a rectangle is a centimeters, the width of this rectangle is b centimeters. Write an expression for the perimeter of this rectangle.
Answer:
2a+2b
Step-by-step explanation:
I am pretty sure that if the length is a and width is b, you would add them twice together. I am actually not quite sure.
Hope this helped you
I am sorry if this was wrong, I am still a beginner at this
g(n)=80×(3/4)^n
complete the recursive formula of g(n)
g(1)=
g(n)= g(n-1) ×
Answer:
Step-by-step explanation:
Hello,
[tex]g(n)=80*(\dfrac{3}{4})^n \ So\\g(1)=80*\dfrac{3}{4}=20*3=60 \\\\ and \\\\\dfrac{g(n)}{g(n-1)}=\dfrac{80*(\dfrac{3}{4})^n}{80*(\dfrac{3}{4})^{n-1}}=\dfrac{3}{4} \ so \\\\g(n)=g(n-1)*\dfrac{3}{4}[/tex]
do not hesitate if you have any question
Find the area. will mark brainliest
Answer:
240
Step-by-step explanation:
16*8=128
3+3+8=14
14*16=224
224/2=112
112+128=240
240 is the answer
Step-by-step explanation:
area of a rectangle =l*b
8*16=128
area of a triangle =1/2*b*h
1/2*14*16=112
final area=128+112=240
please make me brainliest
Kadence is twice as likely to randomly pick a blue marble from a bag as she is to pick a red marble. If there are x red marbles and the bag contains
40 marbles, what is the probability that Kadence will pick a blue marble from the bag?
A. 16/40
B. x/10
C. x/20
D. x/40
D
Step-by-step explanation:
Probabilities are used to determine the chances of picking a marble
The probability of picking a blue marble is: x/20
The given parameters are:
[tex]\mathbf{Marbles = 40}[/tex]
[tex]\mathbf{Red = x}[/tex]
The probability of picking a red marble is calculated as:
[tex]\mathbf{Pr = \frac{Red}{Marbles}}[/tex]
Substitute values for Red and Marbles
[tex]\mathbf{Pr = \frac{x}{40}}[/tex]
He is twice as likely to randomly pick a blue marble from a bag as she is to pick a red marble
So, the probability of picking a blue marble is:
[tex]\mathbf{P(Blue) = 2 \times \frac x{40}}[/tex]
This gives
[tex]\mathbf{P(Blue) = \frac x{20}}[/tex]
Hence, the probability of picking a blue marble is: x/20
Read more about probabilities at:
https://brainly.com/question/11234923
A box contains 6 blue balls, 4 black balls and 5 red balls at the same size . A ball is selected at random from the box and then replaced . A second ball is then selected. Find the probability of obtaining ; (i) two red balls ; (ii) two blue balls or two black balls ; (iii) one black ball and one red balls.
Answer:
(i) 1/21
(ii) 1/10
(iii) Take a look at the explanation: Try this one yourself. I have given you some hints.
Step-by-step explanation:
(i) Two red balls:
To do this, we need to find the total amount of possible choices first. To do this, we multiply 15 by 14. This is our denominator:
15(14) = 210
Now, we need to find the total combinations of red balls. We solve 5 choose 2 for this one.
5 choose 2 = 5(4)/2! = 10
Our numerator is 10. Therefore, our probability is 10/210 = 1/21.
(ii) Two blue balls or two black balls:
To do this, we need to add the probabilities of getting a blue ball with a black ball. (Since there is an "or" sitting there. If there is an "and", we multiply)
So, let's calculate the probability of getting a blue ball first:
Blue:
We use the same denominator as before: 210.
Our numerator is now 6 choose 2, which is:
6 choose 2 = 6(5)/2! = 15.
Now, our fraction is 15/210, BUT, dont simplify, as we will need to add.
Black:
Same steps: denominator is 210, but the numerator is 4 choose 2.
Solving 4 choose 2:
4 choose 2 = 4(3)/2! = 6.
Our numberator is 6.
But, we cant forget to add them!
(15 + 6)/210 is 21/210, which is 1/10.
(iii) I'll let you try this one by yourself. Here is a hint:
Solve for the probability of chooseing a black ball and a red ball. Then, multiply.
Enjoy the process, and I hoped this helped you! (If you have any questions, feel free to ask)
rectangle ABCD and DEFG are similar. if AB is 6, DE is 15, DG is 21, what is the length of AD, rounded to the nearest tenth?
Answer:
Length of AD is 8.4 units.
Step-by-step explanation:
Given that:
There are two similar rectangles ABCD and DEFG.
AB = 6 units
DE = 15 units
DG = 21 units
To find:
AD = ?
Solution:
Please refer to the attached image for having a look at the two given rectangles.
First of all, let us learn about the similar rectangles.
If two rectangles are similar, then the ratio of their corresponding sides are always equal.
i.e.
[tex]\dfrac{AB}{AD} = \dfrac{DE}{DG}[/tex]
Putting values of AB, DE and DG to find out AD:
[tex]\dfrac{6}{AD} = \dfrac{15}{21}\\\Rightarrow \dfrac{6}{AD} = \dfrac{5}{7}\\\Rightarrow \dfrac{1}{AD} = \dfrac{5}{7\times 6}\\\Rightarrow \dfrac{1}{AD} = \dfrac{5}{42}\\\Rightarrow AD = \dfrac{42}{5}\\\Rightarrow AD = 8.4\ units[/tex]
So, value of AD is 8.4 units.
Aubreys kitchen countertop is 2/3 meter by 3 4/5 meters she solves 2/3 multiply 3 4/5 to find the area of the countertop in square meters. Enter numers to conplete aubreys calculations for the area
Answer:
[tex]2\frac{8}{15}[/tex] or 2.5333
Step-by-step explanation:
Just multiply the numbers. please mark brainliest
The length of a rectangle is twice it’s breadth. if the perimeter is 72 meters, find the length and breadth of the rectangle
Perimeter of a rectangle = 2l + 2b
where
l = length
b = breadth
The length is twice it's breadth which is written as
l = 2b
Perimeter = 2(2b) + 2b
72 = 4b + 2b
72= 6b
Divide both sides by 6
b = 12 meters
Since l = 2b
l = 2(12) = 24 meters
The length of the rectangle is 24 meters and it's breadth is 12 meters
Hope this helps
Answer:
If breadth of a rectangle is 19m and perimeter is 80m, find the length of the rectangle.
Step-by-step explanation:
An evergreen nursery usually sells a certain shrub after 5 years of growth and shaping. The growth rate during those 5 years is approximated by dh/dt = 1.5t + 4, where t is the time in years and h is the height in centimeters. The seedlings are 12 centimeters tall when planted (t = 0). (a) Find the height after t years.
Answer:
[tex]h(t) = 0.75t^2 + 4t + 12[/tex]
Step-by-step explanation:
The equation given calculates the derivative of the height in relation to the time, that is, the rate of change of the height. To find the equation for the height, we need to integrate this equation:
[tex]dh/dt = 1.5t + 4[/tex]
Multiplying both sides by 'dt', we have:
[tex]dh = (1.5t + 4)dt[/tex]
Using the integral in both sides:
[tex]\int dh = \int (1.5t + 4) dt[/tex]
[tex]h = 0.75t^2 + 4t + h(0)[/tex]
[tex]h = 0.75t^2 + 4t + 12[/tex]
So the height after t years is represented by this equation:
[tex]h(t) = 0.75t^2 + 4t + 12[/tex]
Twenty-eight people in student council are running for the offices of president and vice-president. In how many different ways can those offices be assigned?
378
55
756
Answer: 756
Step-by-step explanation:
The president can be elected in 28 different ways. After a student is elected president, there are 27 students left to elect a vice president from. So there are 28 x 27 = 756 different arrangements.
Hi can you help me with this please
Answer:
x=13 degrees
Step-by-step explanation:
Supplementary angles: 180 degrees.
180-98=82
Vertical angles: congruent
Corresponding angles: congruent
We have 2 angles of the triangle, so we can find the third. (Angles in a triangle add to 180 degrees)
x=13
determine (a) the volume and (b) the surface area of the three-dimensional figure. when appropriate, use pi key on your calculator.
Answer:
[tex] Volume = 150 yd^3 [/tex]
[tex] Surface Area = 150 yd^2 [/tex]
Step-by-step explanation:
Going by the dimensions of the given three-dimensional figure, we can conclude that the figure is that of a cube. The height, length and width are equal.
Volume of a cube is given as [tex] a^3 [/tex] , while surface area of a cube is given as [tex] 6a^2 [/tex]
Where, a = the side length = 5 yards
[tex] Volume = a^3 = 5^3 [/tex]
[tex] Volume = 150 yd^3 [/tex]
[tex] Surface Area = 6a^2 = 6(5)^2 [/tex]
[tex] Surface Area = 150 yd^2 [/tex]
7y - 12 / 5 minus y - 2/3 is equal to 1
Answer:
y = 61/90
Step-by-step explanation:
7y - 12/5 - y - 2/3 = 1
Combine like terms.
6y -46/15 = 1
Add 46/15 to both sides.
6y = 61/15
Divide both sides by 6.
y = 61/90
ANSWER FAST
please help me answer these following question A sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Oregon are: $295, $475, $345, $595, $538, $460. A second sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Washington are $495, $422, $370, $333, $370, $390. Using the Text Editor, answer the following questions: What is the median price of rent for the University of Oregon? What is the median price of rent for the University of Washington? What is the mean price of rent near the University of Oregon? What is the mean price of rent near the University of Washington? Describe the standard deviation for both Universities and explain how you determined this.
Answer:
The mean, median, and standard deviation of the University of Oregon are $451.33, $467.5, and $113.61 respectively.
The mean, median, and standard deviation of the University of Washington are $396.67, $380, and $56.27 respectively.
Step-by-step explanation:
We are given that a sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Oregon is: $295, $475, $345, $595, $538, $460.
A second sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Washington is: $495, $422, $370, $333, $370, $390.
Firstly, we will calculate the mean, median, and standard deviation for the data of the University of Oregon.
Arranging the data in ascending order we get;
X = $295, $345, $460, $475, $538, $595.
The mean of the above data is given by the following formula;
Mean, [tex]\bar X[/tex] = [tex]\frac{\sum X}{n}[/tex]
= [tex]\frac{\$295+ \$345+ \$460+\$475+ \$538+\$595}{6}[/tex]
= [tex]\frac{\$2708}{6}[/tex] = $451.33
So, the mean price of rent near the University of Oregon is $451.33.
For calculating the median, we first have to observe that the number of observations (n) in the data is even or odd.
If n is odd, then the formula for calculating median is given by;Median = [tex](\frac{n+1}{2} )^{th} \text{ obs.}[/tex]
If n is even, then the formula for calculating median is given by;Median = [tex]\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}[/tex]
Here, the number of observations is even, i.e. n = 6.
So, Median = [tex]\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}[/tex]
= [tex]\frac{(\frac{6}{2} )^{th} \text{ obs. } + (\frac{6}{2}+1 )^{th} \text{ obs.}}{2}[/tex]
= [tex]\frac{(3 )^{rd} \text{ obs. } + (4 )^{th} \text{ obs.}}{2}[/tex]
= [tex]\frac{\$460 +\$475}{2}[/tex] = $467.5
Hence, the median price of rent for the University of Oregon is $467.5.
Now, the standard deviation is calculated by using the following formula;
Standard deviation, S.D. = [tex]\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }[/tex]
= [tex]\sqrt{\frac{ (\$295 - \$451.33)^{2} +(\$345 - \$451.33)^{2} +......+(\$595 - \$451.33)^{2} }{6-1} }[/tex]
= $113.61
So, the standard deviation for the University of Oregon is $113.61.
Now, we will calculate the mean, median, and standard deviation for the data of the University of Washington.
Arranging the data in ascending order we get;
X = $333, $370, $370, $390, $422, $495.
The mean of the above data is given by the following formula;
Mean, [tex]\bar X[/tex] = [tex]\frac{\sum X}{n}[/tex]
= [tex]\frac{\$333+ \$370+ \$370+\$390+ \$422+\$495}{6}[/tex]
= [tex]\frac{\$2380}{6}[/tex] = $396.67
So, the mean price of rent near the University of Washington is $396.67.
For calculating the median, we first have to observe that the number of observations (n) in the data is even or odd.
If n is odd, then the formula for calculating median is given by;Median = [tex](\frac{n+1}{2} )^{th} \text{ obs.}[/tex]
If n is even, then the formula for calculating median is given by;Median = [tex]\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}[/tex]
Here, the number of observations is even, i.e. n = 6.
So, Median = [tex]\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}[/tex]
= [tex]\frac{(\frac{6}{2} )^{th} \text{ obs. } + (\frac{6}{2}+1 )^{th} \text{ obs.}}{2}[/tex]
= [tex]\frac{(3 )^{rd} \text{ obs. } + (4 )^{th} \text{ obs.}}{2}[/tex]
= [tex]\frac{\$370 +\$390}{2}[/tex] = $380
Hence, the median price of rent for the University of Washington is $380.
Now, the standard deviation is calculated by using the following formula;
Standard deviation, S.D. = [tex]\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }[/tex]
= [tex]\sqrt{\frac{ (\$333 - \$396.67)^{2} +(\$370 - \$396.67)^{2} +......+(\$495 - \$396.67)^{2} }{6-1} }[/tex]
= $56.27
So, the standard deviation for the University of Washington is $56.27.