Calculate the number of moles of Na+ ions in 25g of sodium carbonate?​

Answers

Answer 1

Explanation:

First, we need to calculate the number of moles of sodium carbonate we have in a 25 g sample. To calculate this, we will

find the molar mass of sodium carbonate (Na2CO3):

⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen

⇒ 2 × 23 + 12 + 3 × 16

⇒ 46 + 12 + 48

⇒ 106g/mol

Thus, the molar mass of Na2CO3 is 106g/mol.

Therefore, number of moles = 25 ÷ 106

=> 0.2358 mol

Now, we know that every mole of Na2CO3 have 0.2358 moles of Na+ ions. Hence, total moles of Na2CO3 is 0.4716 moles

Number of ions present = 6.022 × 1023 × 0.4716 mol = 2.84 × 1023ions

Answer 2

The molar mass of sodium carbonate is 106 g/mol. One mole of sodium carbonate gives 2 Na+ ions. Thus number of moles in 25 g of sodium carbonate is 0.47 moles.

What is sodium ions?

Sodium ion Na+ is formed by the lose of one electron from the sodium metal. Sodium has one valence electron and it will reacts with other atoms by donating this electron and gaining a positive charge.

The molecular formula of sodium carbonate is Na₂CO₃. Therefore, one mole of sodium carbonate will give two moles of Na+ ions. The molar mass of sodium carbonate is 106 g/mol.

The number of moles of 25 g of sodium carbonate is calculated as follows:

Number of moles = 25 /106

                             =  0.235 moles.

It is clear that one mole of Na₂CO₃ gives two moles of sodium ions.Then, number of moles of sodium ions given by 0.235 moles of sodium carbonate is calculated as follows:

number of moles of Na+ = 0.235 × 2

                                         = 0.47 moles

Hence, the number of moles of Na+ ions produced by 25g of sodium carbonate is 0.47 moles.

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