Answer:
50mL of the 0.1M acid are needed to neutralize the solution
Explanation:
To solve this question we have to calculate the moles of OH- present in the basic solution. Based on the reaction:
2OH- + H2CO3 → 2H2O + CO3²⁻
we can find the moles of carbonic acid (And its volume) required for the complete neutralization as follows:
Moles OH-:
pH = -log [H+]
10^-pH = [H+]
[H+] = 1x10⁻⁸M
As:
[OH-] = Kw / [H+]
[OH-] = 1x10⁻¹⁴ / 1x10⁻⁸
[OH⁻] = 1x10⁻⁶M
The moles in 10000L are:
10000L * (1x10⁻⁶moles OH- / L) = 0.01 moles OH-
Moles H₂CO₃ required:
0.01 moles OH- * (1mol H₂CO₃ / 2mol OH⁻) = 0.005 moles H₂CO₃
Volume:
0.005 moles H₂CO₃ * (1L / 0.1moles) = 0.05L =
50mL of the 0.1M acid are needed to neutralize the solutionbalance
Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
Equation balance:
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
2Al(OH)3+3H2SO4
H=12
SO4=3
O=6
Al=2
Al2(SO4)3+6H2O
H=12
SO4=3
O=6
Al=2
what were Lamarck's ideas about evolution and why were those ideas incorrect
What were Lamarck's ideas about evolution and Why were those ideas incorrect?
→ These and other examples show that Lamarck's theory does not explain how life formed and became the way it is. The other way that Lamarck's theory has been proven wrong is the study of genetics. Darwin knew that traits are passed on, but he never understood how they are passed on.
[tex]#CarryOnLearning[/tex]A molecule with one lone pair and three bond pair
▪︎Ammonia
▪︎carbon tetrachloride
choose correct option
It's ammonia (NH3).....
Answer:
A molecule with one lone pair and three bond pair
- Ammonia
chemical formula is given.
CO→C+O
What does the formula describe?
A.
It describes a mixture being separated by a physical process.
B
It describes an atom being separated by a chemical process.
C
It describes an element being broken down into the atoms from which it was formed.
D
It describes a compound being broken down into the elements from which it was formed.
Answer:
D . It describes a compound being broken down into the elements from which it was formed.
Explanation:
A compound consists of two or more elements chemically combined together in a chemical reaction. The compound carbon monoxide is represented by the chemical symbol, CO. This means that it contains 1 atom of the carbon element and 1 atom of the Oxygen element.
This compound is formed when carbon is directly oxidized in a limited supply of oxygen. In the above reaction, this compound is disintegrated into its individual components, namely, carbon and oxygen.
If 40 grams of NH3 are dissolved in 100 mL of water at 10 degrees Celsius, how many more grams of NH3 would I need to add to make this a saturated solution?
Which one is it?
25 g
30 g
20 g
0 g
What is the relative formula mass of a compound?
Answer:
To find the relative formula mass (M r) of a compound, you add together the relative atomic mass values (A r values) for all the atoms in its formula.
Explanation: Find the M r of carbon monoxide, CO. Find the M r of sodium oxide, Na 2O. The relative formula mass of a substance, shown in grams, is called one mole of that substance.
Gather data: experiment with a variety of initial concentrations of no2 and n2o4. for each set of initial concentrations, use the gizmo to determine the equilibrium concentrations of each substance. in the last column, find kc for that trial. run three trials for each set of initial conditions.
Solution :
[tex]$H_2 +I_2\rightleftharpoons 2HI$[/tex]
Initial concentration Equilibrium concentration [tex]$K_c=\frac{[HI]^2}{[H_2][I_2]}$[/tex]
(mol/L) (mol/L)
[tex]$[H_2]$[/tex] [tex]$[I_2]$[/tex] [tex]$[HI]$[/tex] [tex]$[H_2]$[/tex] [tex]$[I_2]$[/tex] [tex]$[HI]$[/tex]
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.38 \times 10^{-2}$[/tex] 0 [tex]$1.14 \times10^{-2}$[/tex] [tex]$0.12 \times 10^{-2}$[/tex] [tex]$2.52 \times 10^{-2}$[/tex] 46.42
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.68 \times 10^{-2}$[/tex] 0 [tex]$0.92 \times10^{-2}$[/tex] [tex]$0.20 \times 10^{-2}$[/tex] [tex]$2.96 \times 10^{-2}$[/tex] 47.61
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.98 \times 10^{-2}$[/tex] 0 [tex]$0.77 \times10^{-2}$[/tex] [tex]$0.31 \times 10^{-2}$[/tex] [tex]$3.34 \times 10^{-2}$[/tex] 46.73
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.76 \times 10^{-2}$[/tex] 0 [tex]$0.92 \times10^{-2}$[/tex] [tex]$0.22 \times 10^{-2}$[/tex] [tex]$3.08 \times 10^{-2}$[/tex] 46.86
[tex]$0$[/tex] [tex]$0$[/tex] [tex]$3.04 \times 10^{-2}$[/tex] [tex]$0.345 \times10^{-2}$[/tex] [tex]$0.345 \times 10^{-2}$[/tex] [tex]$2.35 \times 10^{-2}$[/tex] 46.39
[tex]$0$[/tex] [tex]$0$[/tex] [tex]$7.58 \times 10^{-2}$[/tex] [tex]$0.86 \times10^{-2}$[/tex] [tex]$0.86 \times 10^{-2}$[/tex] [tex]$5.86 \times 10^{-2}$[/tex] 46.42
Average [tex]$K_c=46.738$[/tex]
which of the four substances listed will dissolve in water and why?
Answer:
Sugar, sodium chloride, and hydrophilic proteins are all substances that dissolve in water. Oils, fats, and certain organic solvents do not dissolve in water because they are hydrophobic.
And, water is called the "universal solvent" because it dissolves more substances than any other liquid. ... Water molecules have a polar arrangement of the oxygen and hydrogen atoms—one side (hydrogen) has a positive electrical charge and the other side (oxygen) had a negative charge.
I don't see any options so there i hope it helps .
John is going on a summer trip and can either stay at the Banks hotel near the ocean, or the Diamond hotel which is far inland. John wants to have warm weather and no rain on his trip. Which hotel should John stay at? (2 points)
The Banks hotel, because water from the ocean warms up the surrounding air in the summer.
The Banks hotel, because the water from the ocean heats up faster than land in the summer.
The Diamond hotel, because inland regions have less precipitation and warm faster than areas near oceans.
The Diamond hotel, because the ocean will carry warm air towards the inland regions.
Answer:D
Explanation:
Answer: The Diamond hotel, because the ocean will carry warm air towards the inland regions.
Explanation: If Diamond hotel is inland then it will be the warmest, Its colder by the ocean and sometime summer isnt even warm by the ocean. The answer is D, or number 4
Hope this helps
The diagram shows the water cycle. At point 4, condensation is occurring. How is water changing?
A) Water vapor (gas) is becoming liquid.
B) Water is being stored in the atmosphere.
C) Liquid water in the atmosphere is becoming a gas.
D) Liquid water from the earth's surface is becoming water vapor (gas)
Answer:
water vapor (gas) is becoming liquid
PLEASE HELP ASAP!!!!!! WILL MARK!!!
Which of the following is an example of work.
O A pencil laying on top of a desk.
O A dog wagging its tail.
O A box sitting on the floor.
O A car that is parked.
Which of the following is NOT one of the three main global climate zones?
A. Tropical
B. Latitude
C. Polar
D.Temprate
If HA, an acid, is 15 percent dissociated in a 2.00 molar solution, what is the Ka for the solution?
A.5.3 × 10-2
B.6.4 × 10-3
C.1.1 × 10-2
D.1.2 × 10-2
Answer:
A. 5.3 X 10^-2
Explanation:
I got 100 on PLATO
At 298 K, the rate constant for a reaction is 0.0346 s-1. What is the rate constant at 350K if the Ea = 50.2kJ/mol
Answer:
0.702 /s
Explanation:
Rate constant at [tex][298 \mathrm{~K}, \mathrm{~K}_{1}=3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]
Rate constant at [tex]350 \mathrm{~K}, \mathrm{~K}_{2}=?[/tex]
[tex]T_{1}=298 \mathrm{~K}[/tex]
[tex]T_{2}=350 \mathrm{~K}[/tex]
Activation energy, [tex]\mathrm{Ea}=50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}[/tex]
Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]
Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]
[tex]\ln \frac{\mathrm{K}_{2}}{\mathrm{~K}_{1}}=\frac{\mathrm{Ea}}{\mathrm{R}}\left[\frac{1}{\mathrm{~T}_{1}}-\frac{1}{\mathrm{~T}_{2}}\right][/tex]
Therefore,
[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{1}{298 \mathrm{~K}}-\frac{1}{350 \mathrm{~K}}\right][/tex]
[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{52 \mathrm{~K}}{298 \mathrm{~K} \times 350 \mathrm{~K}}\right][/tex]
[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=\mathrm{e}^{3.01}[/tex]
[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=20.3[/tex]
[tex]K_{2} &=20.3 \times 3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]
[tex]&=0.702 \mathrm{~s}^{-1}[/tex]
hence, the rate constant at [tex]350 \mathrm{~K} [/tex] is 0.702[tex]\mathrm{~s}^{-1}[/tex]
what mass of chlorine gas is contained in a 10.0 L tank at 31.0° C and 3.50 atm?
Un profesor desea preparar una disolución de agua oxigenada al 20%v/v y dispone solamente de 50 cm3 h2o2 ¿qué volumen d disolución deberá preparar? Con procedimiento
Answer:
250cm³ de disolución se deben preparar
Explanation:
El porcentaje volumen volumen (%v/v) se define como el volumen de soluto -En este caso, H2O2- en 100cm³ de disolución.
Se desea preparar una solución que contenga 20cm³ de H2O2 por cada 100cm³
Como solamente se cuenta con 50cm³ de H2O2, el volumen que se debe preparar es:
50cm³ H2O2 * (100cm³ Disolución / 20cm³ H2O2) =
250cm³ de disolución se deben prepararhelp!!!!!!!!!!!!!!!!!!!!! i have less than 3 hours please help! image below!!!!
Answer:
friction
Explanation:
conduction doesn't really need much to start it. it basically has that reaction from the start so it's not conduction. Since heat is produced by friction in this situation it causes static to happen. so i think its friction
Glucose is a compound made from three elements: carbon, oxygen, and hydrogen. For glucose to be broken down into these elements, it must undergo _____.
A. filtration or distillation
B. an irreversible physical change, such as tearing or slicing
C. a reversible physical change, such as boiling or melting
D. a chemical change
Answer:
D ) Chemical Change
Explanation:
What is the specific heat capacity of silver metal if 110.00 g of the metal
absorbs 396 J of heat and the temperature rises 15.0°C ?
Answer:
"0.24 J/g.k" is the appropriate solution.
Explanation:
Mass of substance,
m = 110.00 g
Heat,
q = 396 J
Change in temperature,
ΔT = 15.0°C
Now,
The specific heat will be:
⇒ [tex]q=ms \Delta T[/tex]
On putting the given values, we get
⇒ [tex]396=110.00\times s\times 15.0[/tex]
⇒ [tex]396=s\times 1650[/tex]
⇒ [tex]s=\frac{396}{1650}[/tex]
⇒ [tex]=0.24 \ J/g.k[/tex]
Which of the following components of air pollution is not as a result of a human activities?
a.
methane from landfill waste
b.
dust particulates
c.
carbon monoxide from exhaust gases of vehicle engines
d.
sulfur dioxide from burning coal
e.
nitrogen oxides from burning stoves
Answer:
b
Explanation:
Human activities that are major sources of outdoor air pollution, include:
Fuel combustion from motor vehicles (e.g. cars and heavy duty vehicles)
Heat and power generation (e.g. oil and coal power plants and boilers)
Industrial facilities (e.g. manufacturing factories, mines, and oil refineries)
Can you pls answer This question
Answer:
a) pentane
b) 1,3-dimethyl butane
c) 3,4-diethyl-5-methlyl heptane
d) 1,3,5-triethyl-2,4,6-trimethyl cyclohexane
Explanation:
The essence of IUPAC nomenclature is to provide a generally accepted nomenclature for chemical compounds which enables the structure of a compound to be drawn from its name without ambiguity.
In order to name straight chain organic compounds, we have to identify the parent chain and then give numbers to the substituents or locants such that they have the lowest possible numbers in alphabetical order.
The correct names of the organic compounds in the question are;
a) pentane
b) 1,3-dimethyl butane
c) 3,4-diethyl-5-methlyl heptane
d) 1,3,5-triethyl-2,4,6-trimethyl cyclohexane
balance the following equations:
a. ____AgI + _____Na2S → _____Ag2S + _____NaI
b. ____Na3PO4 + ____HCl →_____NaCl + _____H3PO4
c. _____Ba3N2 + _____H2O →_____Ba(OH)2 + _____NH3
d. _____TiCl4 + _____H2O →_____TiO2 + _____HCl
e. _____CaCl2 + _____Na3PO4 →_____Ca3(PO4)2 + _____NaCl
Answer:
A. 2AgI + Na2S → Ag2S + 2NaI
B. Na3PO4 + 3HCl → 3NaCl + H3PO4
C. Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3
D. TiCl4 + 2H2O → TiO2 + 4HCl
E. 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
Explanation:
La rapidez de una reaccio es 0,450 mol/s ¡cuanto tiempo, en segundos, serán necesarios para que se consuman 0,323 mol de reactivos
Answer:
[tex]tiempo=0.72s[/tex]
Explanation:
¡Hola!
En este caso, como podemos observar, la relación entre la rapidez de reaction, las moles y el tiempo de reacción es:
[tex]rapidez=\frac{mol}{tiempo}[/tex]
De este modo, despejamos el tiempo en esta ecuación para obtener:
[tex]tiempo=\frac{mol}{rapidez}[/tex]
Así, reemplazamos la rapidez y moles dadas para obtener:
[tex]tiempo=\frac{0.323mol}{0.450mol/s}\\\\tiempo=0.72s[/tex]
¡Saludos!
How many moles of water can be produced with 4.3 moles of H2 and 5.6 moles of O2? Which reactant is limiting? How many moles of the excess reactant will be left after the reaction? 2 H2 + O2 2 H2O
Answer:
Hydrogen H₂ will be the limiting reagent.
The excess reactant that will be left after the reaction is 3.45 moles.
4.3 moles of water can be produced.
Explanation:
The balanced reation is:
2 H₂ + O₂ → 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
H₂: 2 moles O₂: 1 mole H₂O: 2 molesTo determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 1 mole of O₂ reacts with 2 moles of H₂, how much moles of H₂ will be needed if 5.6 moles of O₂ react?
[tex]moles of H_{2} =\frac{5.6 moles of O_{2} *2 mole of H_{2} }{1 mole of O_{2}}[/tex]
moles of H₂= 11.2 moles
But 11.2 moles of H₂ are not available, 4.3 moles are available. Since you have less moles than you need to react with 5.6 moles of O₂, hydrogen H₂ will be the limiting reagent and oxygen O₂ will be the excess reagent.
Then you can apply the following rules of three:
If by reaction stoichiometry 2 moles of H₂ react with 1 mole of O₂, 4.3 moles of H₂ will react with how many moles of O₂?[tex]moles of O_{2} =\frac{1 mole of O_{2} *4.3 mole of H_{2} }{2 mole of O_{2}}[/tex]
moles of O₂= 2.15 moles
The excess reactant that will be left after the reaction can be calculated as:
5.6 moles - 2.15 moles= 3.45 moles
The excess reactant that will be left after the reaction is 3.45 moles.
If by reaction stoichiometry 2 moles of H₂ produce 2 moles of H₂O, 4.3 moles of H₂ produce how many moles of H₂O?[tex]moles of H_{2}O =\frac{2 moles of H_{2}O *4.3 mole of H_{2} }{2 mole of H_{2}}[/tex]
moles of H₂O= 4.3 moles
4.3 moles of water can be produced.
The _______________________ regulates water quality, air pollution, and solid waste to protect Americans from significant risks to human health and the environment. F from the land, forming nitrogen-rich algae blooms
Answer:
EPA
Explanation:
In the United States of America, the agency which was established by US Congress and saddled with the responsibility of overseeing all aspects of pollution, environmental clean up, pesticide use, contamination, and hazardous waste spills is the Environmental Protection Agency (EPA). Also, EPA research solutions, policy development, and enforcement of regulations through the resource Conservation and Recovery Act.
In conclusion, the Environmental Protection Agency (EPA) regulates water quality, air pollution, and solid waste to protect Americans from significant risks to human health and the environment.
Name the layers of the atmosphere and one fact about each layer.
in the structure of an atom why are protons present in the centre and are not pulled outside by the electrons as both are positively charged with some unit of charge?
Answer:
Electrons and protons are not positively charged
Explanation:
Neutrons are the only ones positively charged in the structure of an atom.... Also like charges repel which means a -ive and a - ive will repel when together
HELP ASAPPP!!! ON EXAM!
The arrangement of electrons within an atom is called it's...
a
Electron Flow
b
Electron Configuration
c
Atomic Number
d
Ionization Energy
Answer:
The arrangement of electrons within an atom is called electron configuration
If I help you, will you help other people?
Actually "this is the worst question i've ever seen use the internet bud" why don't you do that.
What is the molarity of a sodium hydroxide solution if 25 mL of the solution is neutralized by 69.5 mL of 1.5 M HCl?
Answer:
4.17M
Explanation:
m1v1/m2v2=n1/n2
When something is hot , its atom has more energy
True or False
Will mark as brainliest if the answer is correct