Simplify 4^3(3^2+11)(7^4-7^4)(10^10) show work

Answer:

Step-by-step explanation:

2×πr² + 2πr×h =

= 2×π×4² + 2π×4×10.5 =

= 32π + 84π =

= 116π ≈

≈ 364.42 cm²

The total metal needed to make the can is 364.42 square centimeters if the soup can will have a radius of 4 cm and a height of 10.5 cm.

In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.

We have:

The radius of the soup can r = 4 cm

The height of the soup can h = 10.5 cm

We know the surface area of the cylinder:

[tex]\rm S = 2\pi r(r+h)[/tex]

[tex]\rm S = 2\pi \times 4(4+10.5)[/tex]

S = 364.42 square cm

Thus, the total metal needed to make the can is 364.42 square centimeters if the soup can will have a radius of 4 cm and a height of 10.5 cm.

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Answer:

1.4 · 10³

Step-by-step explanation:

6.58 · [tex]10^{6}[/tex] ÷ 4.7 · 10³

6.58 ÷ 4.7 = 1.4

[tex]10^{6}[/tex] - 10³ = 10³

1.4 · 10³

Answer:

3.0926 x 10^10

Step-by-step explanation:

Answer:

Multiply the radius, r, by 2. Keep the angle measure x.

Step-by-step explanation:

The area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².

A function is a relation between a dependent and independent variable.

Mathematically, we can write → y = f(x) = ax + b.

Given is that Mancuso wants to draw a sector whose area is 2 times the area of the sector shown.

The area of the sector given is -

A = {x/180} x πr²

For the area to be double, we can write the area of the sector as -

A{new} = 2 × {x/180} × πr²

A{new} = {x/90} × πr²

Therefore, the area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².

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Answer:

2m^4 - 11m³ + m + 8

Step-by-step explanation:

(2m - 5m³) - (5m + 3m³ - 7m^4) + (8 - 3m³ - 5m^4 + 4m)

2m - 5m³ - 5m - 3m³ + 7m^4 + 8 - 3m³ - 5m^4 + 4m

7m^4 - 5m^4 - 5m³ - 3m³ - 3m³ + 2m - 5m + 4m + 8

2m^4 - 11m³ + m + 8

Answer:

8 + m - 11m^3 + 2m^4

Step-by-step explanation:

Add and subtract like terms:

8 + (2m - 5m +4m) + (-5m^3 - 3m^3 - 3m^3) + (7m^4 - 5m^4) =

8 + m - 11m^3 + 2m^4

Answer: Use the app photo math, you just take a picture and it gives you the answer and shows you the steps:)

1) x> 5

2) x< 2

3) x<-6

4) x< 2

5) x> 2

6) x> - 7/2

Step-by-step explanation:

See the images below for the work:)  The images will be in order with the number the first problem will be the answer to the first.

Answer:

[tex]\sf 1)\:4x - 2 > 2x + 8[/tex]

Add 2 from both sides:

[tex]\sf 4x-2+2>2x+8+2[/tex]

[tex]\sf 4x>2x+10[/tex]

Subtract 2x from both sides:

[tex]\sf 4x-2x>2x+10-2x[/tex]

[tex]\sf 2x>10[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{10}{2}[/tex]

[tex]\boxed{\sf x>5}[/tex]

_______________________________

[tex]\sf 2)\: -3x - 6 > 4x - 20[/tex]

Add 6 from both sides:

[tex]\sf -3x-6+6>4x-20+6[/tex]

[tex]\sf -3x>4x-14[/tex]

Subtract 4x from both sides:

[tex]\sf -3x-4x>4x-14-4x[/tex]

[tex]\sf -7x>-14[/tex]

Multiply both sides by -1:

[tex]\sf\left(-7x\right)\left(-1\right)<\left(-14\right)\left(-1\right)[/tex]

[tex]\sf 7x<14[/tex]

Divide both sides by 7:

[tex]\sf \cfrac{7x}{7}<\cfrac{14}{7}[/tex]

[tex]\boxed{\sf x<2}[/tex]

_______________________________

[tex]\sf 3)\: 4(x + 1) < 3x - 2[/tex]

Apply distributive property:

[tex]\sf 4x+4<3x-2[/tex]

Subtract 4 from both sides:

[tex]\sf 4x+4-4<3x-2-4[/tex]

[tex]\sf 4x<3x-6[/tex]

Subtract 3x from both sides:

[tex]\sf 4x-3x<3x-6-3x[/tex]

[tex]\boxed{\sf x<-6}[/tex]

_______________________________

[tex]\sf 4)\: 2x + 3 + x < -2x + 1 + 12[/tex]

Combine like terms:

[tex]\sf (2x+x)= 3x[/tex]

[tex]\sf( 1+12)=13[/tex]

[tex]\sf 3x+3<-2x+13[/tex]

Subtract 3 from both sides:

[tex]\sf 3x+3-3<-2x+13-3[/tex]

[tex]\sf 3x<-2x+10[/tex]

Add 2x from both sides:

[tex]\sf 3x+2x<-2x+10+2x[/tex]

[tex]\sf 5x<10[/tex]

Divide both sides by 5:

[tex]\sf \cfrac{5x}{5}<\cfrac{10}{5}[/tex]

[tex]\boxed{\sf x<2}[/tex]

________________________________

[tex]\sf 5)\: 2(x - 1) > 4x + 4 - 5x[/tex]

Combine like terms:

[tex]\sf (4x-5x)=-x[/tex]

[tex]\sf 2\left(x-1\right)>-x+4[/tex]

Apply distributive property:

[tex]\sf 2x-2>-x+4[/tex]

Add 2 from both sides:

[tex]\sf 2x-2+2>-x+4+2[/tex]

[tex]\sf 2x>-x+6[/tex]

Add x from both sides:

[tex]\sf 2x+x>-x+6+x[/tex]

[tex]\sf 3x>6[/tex]

Divide both sides by 3:

[tex]\sf \cfrac{3x}{3}>\cfrac{6}{3}[/tex]

[tex]\boxed{\sf x>2}[/tex]

_______________________________

[tex]\sf 6)\: 2 + 4x -7 < 8x + 2 - 2x[/tex]

Subtract 2 from both sides:

[tex]\sf 2+4x-7-2<8x+2-2x-2[/tex]

[tex]\sf 4x-7<8x-2x[/tex]

Combine like terms:

[tex]\sf (8x-2x)=6x[/tex]

[tex]\sf 4x-7<6x[/tex]

Add 7 from both sides:

[tex]\sf 4x-7+7<6x+7[/tex]

[tex]\sf 4x<6x+7[/tex]

Subtract 6x from both sides:

[tex]\sf 4x-6x<6x+7-6x[/tex]

[tex]\sf -2x<7[/tex]

Multiply both sides by -1:

[tex]\sf \left(-2x\right)\left(-1\right)>7\left(-1\right)[/tex]

[tex]\sf 2x>-7[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{-7}{2}[/tex]

[tex]\boxed{\sf x>-\frac{7}{2}}[/tex]

_______________________________________

Answer:

-1

Step-by-step explanation:

Answer:

Is and his pay is always a multiple of 3

Step-by-step explanation:

I did the i-Ready

Answer: his pay is always a multiple of 3

Step-by-step explanation:

Answer:

Yes, they should increase the budget, because both 8 (Manuel) and 9 (Gretchen) are at least 8. 8 times per month is equivalent to 2 times per week.

Step-by-step explanation:

Answer from Plato

Hence, the answer is Plato.

What is the measurement?

Measurement is the process of finding a number that shows the amount of something. Time the ongoing sequence of events is time. We can measure time in seconds, minutes, hours, days, weeks, months, and years.

Here given that,

The club will base its decision about whether to increase the budget for the indoor rock climbing facility on

the analysis of its usage. The decision to increase the budget will depend on whether members are using

the indoor facility at least two times a week. Use the best measure of center for both of the original data

sets to determine whether the club should increase the budget.

As per this we get that,

Yes, they can increase the budget, because both Manuel has [tex]8[/tex] and Gretchen [tex]9[/tex] are at least [tex]8[/tex] and [tex]8[/tex] times per month is equivalent to the two times per week.

Hence, the answer is Plato.

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Answer:

[tex]x=-1[/tex]

Step-by-step explanation:

[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]

Step 1: Simplify both sides of the equation.

[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]

[tex](\frac{7}{2}x+\frac{1}{2}x)=\frac{9}{2}x+\frac{1}{2}[/tex]  (Combine Like Terms)

[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]

[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]

Step 2: Subtract [tex]\frac{9}{2}x[/tex] from both sides.

[tex]4x-\frac{9}{2}x=\frac{9}{2}x+\frac{1}{2}-\frac{9}{2}x[/tex]

[tex]\frac{-1}{2}x=\frac{1}{2}[/tex]

Step 3: Multiply both sides by [tex](\frac{2}{-1})[/tex].

[tex](\frac{2}{-1})*(\frac{-1}{2}x)=(\frac{2}{-1})*(\frac{1}{2})[/tex]

[tex]x=-1[/tex]

Therefore, [tex]x=-1[/tex] will be your final answer.

Sorry this took very long. I had to calculate all of this.