Cab 1 charges $1 per kilometer. Cab 2 charges $0.50 per kilometer and a $4 base charge. Solve for the value of k(kilometers ) that the 2 cab companies would cost the same.

$14.40. And then you have the tax. :D

Have A Great Day.

The cost of 2 dozen pens will be "$14.4".

Given:

Cost of 6 pens,

As we know,

then,

                        = [tex]24[/tex]

Now,

→ The cost of 1 pen will be:

= [tex]\frac{3.60}{6}[/tex]

= [tex]0.6[/tex] ($)

hence,

→ The cost of 24 pens (2 dozen) will be:

= [tex]0.6\times 24[/tex]

= [tex]14.4[/tex] ($)

Thus the above solution is right.

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9514 1404 393

Answer:

  (x, y) = (2, 2)

Step-by-step explanation:

We can put the second equation into standard form by dividing by -2.

  x -2y = -2

Adding this to the first equation eliminates x

  (x -2y) +(-x -y) = (-2) +(-4)

  -3y = -6

  y = 2 . . . . . divide by -3

  -x -(2) = -4 . . . . substitute for x in the first equation

  2 = x . . . . . . . . add 4+x

The solution is (x, y) = (2, 2).

Answer:

wow!

Step-by-step explanation:

Answer:nice do it

Step-by-step explanation:

what is it about

show the problem

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

Answer:

0.9 = 90% probability that it arrived during the last 30 seconds of the 5-minute period.

Step-by-step explanation:

The car is equally as likely to arrive during each second of the interval, which means that the uniform distribution is used to solve this question.

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distribution has two bounds, a and b, and the probability of finding a value higher than x is given by:

[tex]P(X \geq x) = \frac{b - x}{b - a}[/tex]

5-minute period

This means that [tex]a = 0, b = 5*60 = 300[/tex]

Find the probability that it arrived during the last 30 seconds of the 5-minute period.

300 - 30 = 270. So

[tex]P(X \geq 270) = \frac{300 - 270}{300 - 0} = 0.9[/tex]

0.9 = 90% probability that it arrived during the last 30 seconds of the 5-minute period.

Answer:

[tex]E(x) = 4.500[/tex] --- Expected value

[tex]SD(x) = 2.872[/tex] --- Standard deviation

Step-by-step explanation:

Given

[tex]\begin{array}{ccccccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} & {6} & {7} & {8} & {9} \ \\ P(X=x) & {\frac{1}{10}} & {\frac{1}{10}} & {\frac{1}{10}} & {\frac{1}{10}} & {\frac{1}{10}}& {\frac{1}{10}} & {\frac{1}{10}} & {\frac{1}{10}} & {\frac{1}{10}} & {\frac{1}{10}} \ \end{array}[/tex]

Solving (a): Expected value

This is calculated using:

[tex]E(x) = \sum\limits^{9}_{i=0} x_i * P(X = x_i)[/tex]

Since they all have the same probability, the formula becomes:

[tex]E(x) = \frac{1}{10}\sum\limits^{9}_{i=0} x_i[/tex]

[tex]E(x) = \frac{1}{10}(0+1+2+3+4+5+6+7+8+9)[/tex]

[tex]E(x) = \frac{1}{10}*45[/tex]

[tex]E(x) = \frac{45}{10}[/tex]

[tex]E(x) = 4.500[/tex]

Solving (b): Standard Deviation

First, we calculate the variance using

[tex]Var(x) = E(x^2) - (E(x))^2[/tex]

In (a), we have:

[tex]E(x) = 4.500[/tex]

[tex]E(x^2)[/tex] is calculated as:

[tex]E(x^2) = \sum\limits^{9}_{i=0} x_i^2 * P(X = x_i)[/tex]

Since they all have the same probability, the formula becomes:

[tex]E(x^2) = \frac{1}{10}\sum\limits^{9}_{i=0} x_i^2[/tex]

So, we have:

[tex]E(x^2) = \frac{1}{10}(0^2+1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2+9^2)[/tex]

Using a calculator

[tex]E(x^2) = \frac{1}{10}(285)[/tex]

[tex]E(x^2) = 28.5[/tex]

So:

[tex]Var(x) = E(x^2) - (E(x))^2[/tex]

[tex]Var(x) = 28.5 - 4.5^2[/tex]

[tex]Var(x) = 28.5 - 20.25[/tex]

[tex]Var(x) = 8.25[/tex]

The standard deviation is then calculated as:

[tex]SD(x) = \sqrt{Var(x)}[/tex]

[tex]SD(x) = \sqrt{8.25}[/tex]

[tex]SD(x) = 2.872[/tex] ---- approximated

Answer:

First column 35

Second column 60

It is 91.6083916% likely that the soil sample contains organic matter

Step-by-step explanation:

700 -655= 35

300 -240= 60

655 +60 = 715

715÷655 = 0.916083916

0.916083916 x 100 = 91.6083916%

Answer:

Step-by-step explanation:

look up z-table

3 std div. = 0.00135

Answer:

14mm×20mm=280mm²

14mm×12mm/2=84mm²

3.14×10²mm=314mm²

280m²+84mm²+314mm²=678mm²

Answer:

521mm^2

Step-by-step explanation:

First, separate the shapes.

-Half circle= diameter of 20, radius 10

-Rectangle= 14x20

-Triangle= (32-20)x14= 12x14

Then, calculate

Circle equation= (pi)r^2= (pi)(10)^2= 314.16    -> divide by 2 for half circle= 157.1

Rectangle= 14x20=280

Triangle= (12x14)=168   ->  Divide by two because it's a triangle= 84

Add 157 + 280 + 84 and you get  521

Answer:

Step-by-step explanation:

Surface area of a cube of side-length 0.5m

= 6(0.5)^2 = 6(0.25) = 1.5 sq.m.

Answer:

SSS

Step-by-step explanation:

You can tell by the 2 dashes side and the one dash if that makes sense

Answer: SAS

Step-by-step explanation:

Answer:

i would say A

Step-by-step explanation:

The surface area of the right cone in terms of pi is 176π units².

A cone is simply a 3-dimensional geometric shape with a flat base and a curved surface pointed towards the top.

The surface area of a cone is expressed as;

Surface area  = πrl + πr²

Where r is the radius of the base, l is the slant height of the cone and π is constant pi.

From the diagram:

Radius r = 8 units

Slant height h = 14 units

Surface area =?

Plug the given values into the above formula and solve for surface area:

Surface area = πrl + πr²

Surface area = ( π × 8 × 14 ) + ( π × 8² )

Surface area = ( π × 112 ) + ( π × 64 )

Surface area = 112π + 64π

Surface area = 176π units²

Therefore, the surface area is 176π units².

Option A)176π units² is the correct answer.

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Answer:

389

Step-by-step explanation:

3*118 + 35

Answer:

? = 9.2

Step-by-step explanation:

The angle between a tangent and radius at the point of contact is 90°

Then the triangle shown is right with legs ? , 6.9 and hypotenuse = (6.9 + 4.2) = 11.5

Using Pythagoras' identity in the right triangle

?² + 6.9² = 11.5²

?² + 47.61 = 132.25 ( subtract 47.61 from both sides )

?² = 84.64 ( take the square root of both sides )

? = [tex]\sqrt{84.64}[/tex] = 9.2

Answer:

Solution given:

BC=BD=6.9 units

AD=4.6units

Now

AB=4.6+6.9=11.5units.

we have

<C=90°[the line from the tangent is perpendicular to the radius of circle]

we know that ∆ABC is a right angled triangle.

hypotenuse [h]=AB=11.5units

base[b]=BC=6.9 units

perpendicular [p]=x units

By using Pythagoras law

h²=p² +b²

11.5²=x²+6.9²

x²=11.5²-6.9²

x²=84.64

x=[tex] \sqrt{86.64} [/tex]=9.2

Sothe segment length indicated is 9.2 units.

Answer:

I'd recommended saying B, but they are asking YOU! Not us, so please answer this truthfully.

Answer:

I believe it’s option c!

Step-by-step explanation:

Correct me if I’m wrong!

Answer:

Ronald ran at a speed of 14.26 km / h, while Khalil did so at a speed of 9.35 km / h.

Step-by-step explanation:

Given that Ronald and Khalil had a 400 meter race, and Ronald's time was 1 minute and 51 seconds, and Khalil's time was 2 minutes and 34 seconds, to determine how much faster was Ronald time the Khalil’s, the following calculation must be performed:

400 x 2.5 = 1000

60 x 60 = 3600

1.51 = 101 x 2.5 = 252.5

2.34 = 154 x 2.5 = 385

252.5 = 1000

3600 = X

3600 x 1000 / 252.5 = X

14,257.43 = X

385 = 1000

3600 = X

3600 x 1000/385 = X

9,350.65 = X

14,257.43 / 1000 = 14.26

9,350.65 / 1000 = 9.35

Thus, Ronald ran at a speed of 14.26 km / h, while Khalil did so at a speed of 9.35 km / h.

Answer:

False.

Step-by-step explanation:

Time-series graph is a graph that relates something to the change of time, then the time is the single variable in this case.

Bar graphs relate a given quantity to a given variable, an example of this can be the population of a given city (represented by the height of each bar) for each different year (which is the single variable in this case)

Pie-chart is a circular graph with defined sections that represent a given proportion. This kind of graph is used to represent percentages, like in the case of a pie chart that describes the number of men and women in a city. (one section of the circle represents the percentage of women and the other section of the circle represents the percentage of men). In this type of graph, there are no variables, so this is not a single variable graph.

Then the statement:

"Examples of graphs of a single variable include pie charts, bar graphs, and time-series graphs."

Is false.

the answer is x=1/2+3y/4

Answer:

x:(1/2,0)

y:(0,-2/3)

this is the points in the graphic

Answer:

y = 5.66388 feet, (round that to whatever you need to round to)

Step-by-step explanation:

cos (51) = y/9

cos(51)*9=

y = 5.66388 feet

Answer:

here is the right answer

C- (2,4)

Answer:

Mixed Fraction

Step-by-step explanation:

A mixed fraction is a fraction with a whole number attached to it like 5 1/5 or 3 1/2

[tex]1\frac{4}{5}[/tex] is an example of a mixed fraction.

A fraction represented with its quotient and remainder is a mixed fraction. For example, 2 1/3 is a mixed fraction, where 2 is the quotient, 1 is the remainder. So, a mixed fraction is a combination of a whole number and a proper fraction.

A mixed number is a whole number, and a proper fraction represented together.  It generally represents a number between any two whole numbers.

A mixed number is formed by combining three parts: a whole number, a numerator, and a denominator. The numerator and denominator are part of the proper fraction that makes the mixed number.

Properties of Mixed Numbers :

1. It is partly a whole number.  

2. It is partly a fraction.

[tex]1\frac{4}{5}[/tex] is an example of a mixed fraction.

In [tex]1\frac{4}{5}[/tex] , 2 is the quotient, 4 is the remainder.

Find out more information about mixed fraction here

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Answer:

Step-by-step explanation:

The answer is B; 90°

Option C is the correct transformation to transform ABCD to A'B'C'D'.

Rotation involves moving an object about a fixed point. Each point on the object describes a circular path with the center, the center of rotation.

Translation involves moving an object such that only one of the three cartesian coordinates changes during the transformation.

here, we have,

Rotation

Rotate the square ABCD counterclockwise about the origin. Sides AD and BC of square ABCD will become parallel to the sides A'D' and B'C' respectively of the square A'B'C'D'. The square ABCD is, thus, oriented the same way as the square A'B'C'D'.

Vertical Translation

After the rotation, the side AB is 1 unit above the y-axis, which is the same as that of the square A'B'C'D'. So, the vertical position of the square ABCD is the same as that of the square A'B'C'D'.

Horizontal Translation

The side AD of the square ABCD is 5 units to the left of the x-axis. The side A'D' of the square A'B'C'D' is 8 units to the left of the x-axis. So, translate the square ABCD to the left by 3 units to coincide with the position of A'B'C'D'.

Thus, to obtain A'B'C'D' from ABCD first rotate it by 90° counterclockwise then, translate it to the left by 3 units.

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Answer:

C. 40,25,-16,-2 Celsius

Answer:

(- 2, 4 )

Step-by-step explanation:

Given the 2 equations

3x + 5y = 14 → (1)

y = [tex]\frac{1}{2}[/tex] x + 5 → (2)

Substitute y = [tex]\frac{1}{2}[/tex] x + 5 into (1)

3x + 5([tex]\frac{1}{2}[/tex] x + 5) = 14

3x + [tex]\frac{5}{2}[/tex] x + 25 = 14

[tex]\frac{11}{2}[/tex] x + 25 = 14 ( subtract 25 from both sides )

[tex]\frac{11}{2}[/tex] x = - 11 ( multiply both sides by 2 )

11x = - 22 ( divide both sides by 11 )

x = - 2

Substitute x = - 2 into (2) for corresponding value of y

y = [tex]\frac{1}{2}[/tex] × - 2 + 5 = - 1 + 5 = 4

solution is (- 2, 4 )

Answer:

5 5/6

Step-by-step explanation:

Multiply 2 1/3 by 2 1/2.  The easiest way (?!) is to change both mixed numbers to improper fractions (I dislike that name! It just means a numerator bigger than the denominator).

2 1/3 Multiply the denominator 3 by the whole number 2, add the numerator 1 to get 6+1 = 7.  Place that over the denominator, 3.  So 2 1/3 = 7/3.

2 1/2 Multiply the denominator 2 by the whole number 2, add the numerator 1 to get 4+1=5.  Place that over the denominator, 2.  So 2 1/2 = 5/2.

Multiply 7/3 by 5/2.

[tex]\frac{5}{2} \cdot \frac{7}{3}=\frac{35}{6}[/tex]

Finally, convert the improper fractioin 35/6 to a mixed number by dividing 35 by 6 (6 goes into 35 5 whole times with 5 "left over").  The whole number part is 5 and the left over fraction part is 5/6.

5 5/6

Answer:

C. The cone is ⅓ the volume of the cylinder

Step-by-step explanation:

Volume of a cylinder = πr²h

Volume of a cone = ⅓πr²h

Assuming they both have the same height (h) and radius (r), from the formula given above, we see that the cone is ⅓ of the volume of the cylinder (πr²h)

Let's demonstrate this with figures:

Hypothetically, let,

h = 3 cm

r = 3 cm

Let's plug these values into each formula for a cone and a cylinder:

Cylinder = π*3³*3 = 27π cm³

Cone = ⅓(π*3²*3) = ⅓(27π) = 9π cm³

As you can see, the volume of the cylinder (27π) is 3 times the volume of the cone (9π)

Therefore:

The cone is ⅓ the volume of the cylinder